blocks|key|1590490|text|这与Java版本7及更早版本有关。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1590491|引用good+answer+to+the+same+question|offset|length|1590492|如果您希望稍后将其作为字符串返回，则可以调用getPath()。实际上，如果你真的想模仿Path.Combine，你可以写一些类似这样的代码：|1590493|public+static+String+combine+(String+path1,+String+path2)+{
++++File+file1+=+new+File(path1);
++++File+file2+=+new+File(file1,+path2);
++++return+file2.getPath();
}|code-block|syntax|javascript|1590494|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/412380/combine-paths-in-java/412495#412495^0|0|2|W|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@]|9|@$D|W|E|X|1|Y]]|A|$]]|$1|F|3|G|5|6|7|Z|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|10|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

This concerns Java versions 7 and earlier.

To quote a <a href="https://stackoverflow.com/questions/412380/combine-paths-in-java/412495#412495">good answer to the same question</a>:

If you want it back as a string later, you can call getPath(). Indeed, if you really wanted to mimic Path.Combine, you could just write something like:

<pre><code>public static String combine (String path1, String path2) {
 File file1 = new File(path1);
 File file2 = new File(file1, path2);
 return file2.getPath();
}
</code></pre>

blocks|key|1590569|text|一种方法是获取系统属性，为您提供操作系统的路径分隔符，this+tutorial解释了如何做到这一点。然后，您可以通过file.separator使用标准字符串联接。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1590570|entityMap|0|LINK|mutability|MUTABLE|url|http://java.sun.com/docs/books/tutorial/essential/environment/sysprop.html^0|1N|E|R|D|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]]|D|@$9|Q|A|R|1|S]]|E|$]]|$1|F|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

One way is to get system properties that give you the path separator for the operating system, <a href="http://java.sun.com/docs/books/tutorial/essential/environment/sysprop.html" rel="nofollow noreferrer">this tutorial</a> explains how. You can then use a standard string join using the <code>file.separator</code>.

blocks|key|1590639|text|这是一个开始，我认为它并不完全像你想要的那样工作，但它至少产生了一个一致的结果。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1590640|import+java.io.File;

public+class+Main
{
++++public+static+void+main(final+String[]+argv)
++++++++throws+Exception
++++{
++++++++System.out.println(pathJoin());
++++++++System.out.println(pathJoin(""));
++++++++System.out.println(pathJoin("a"));
++++++++System.out.println(pathJoin("a",+"b"));
++++++++System.out.println(pathJoin("a",+"b",+"c"));
++++++++System.out.println(pathJoin("a",+"b",+"",+"def"));
++++}

++++public+static+String+pathJoin(final+String+...+pathElements)
++++{
++++++++final+String+path;

++++++++if(pathElements+==+null+%7C%7C+pathElements.length+==+0)
++++++++{
++++++++++++path+=+File.separator;
++++++++}
++++++++else
++++++++{
++++++++++++final+StringBuilder+builder;

++++++++++++builder+=+new+StringBuilder();

++++++++++++for(final+String+pathElement+:+pathElements)
++++++++++++{
++++++++++++++++final+String+sanitizedPathElement;

++++++++++++++++//+the+"\\"+is+for+Windows...+you+will+need+to+come+up+with+the+
++++++++++++++++//+appropriate+regex+for+this+to+be+portable
++++++++++++++++sanitizedPathElement+=+pathElement.replaceAll("\\"+%2B+File.separator,+"");

++++++++++++++++if(sanitizedPathElement.length()+>+0)
++++++++++++++++{
++++++++++++++++++++builder.append(sanitizedPathElement);
++++++++++++++++++++builder.append(File.separator);
++++++++++++++++}
++++++++++++}

++++++++++++path+=+builder.toString();
++++++++}

++++++++return+(path);
++++}
}|code-block|syntax|javascript|1590641|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is a start, I don't think it works exactly as you intend, but it at least produces a consistent result.

<pre><code>import java.io.File;

public class Main
{
 public static void main(final String[] argv)
 throws Exception
 {
 System.out.println(pathJoin());
 System.out.println(pathJoin(""));
 System.out.println(pathJoin("a"));
 System.out.println(pathJoin("a", "b"));
 System.out.println(pathJoin("a", "b", "c"));
 System.out.println(pathJoin("a", "b", "", "def"));
 }

 public static String pathJoin(final String ... pathElements)
 {
 final String path;

 if(pathElements == null || pathElements.length == 0)
 {
 path = File.separator;
 }
 else
 {
 final StringBuilder builder;

 builder = new StringBuilder();

 for(final String pathElement : pathElements)
 {
 final String sanitizedPathElement;

 // the "\\" is for Windows... you will need to come up with the 
 // appropriate regex for this to be portable
 sanitizedPathElement = pathElement.replaceAll("\\" + File.separator, "");

 if(sanitizedPathElement.length() &gt; 0)
 {
 builder.append(sanitizedPathElement);
 builder.append(File.separator);
 }
 }

 path = builder.toString();
 }

 return (path);
 }
}
</code></pre>

blocks|key|1375418|text|尝试：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1375419|String+path1+=+"path1";
String+path2+=+"path2";

String+joinedPath+=+new+File(path1,+path2).toString();|code-block|syntax|javascript|1375420|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try:
<pre><code>String path1 = &quot;path1&quot;;
String path2 = &quot;path2&quot;;

String joinedPath = new File(path1, path2).toString();
</code></pre>

<h3>Exact Duplicate:</h3>
<a href="https://stackoverflow.com/questions/412380/">combine paths in java</a>
I would like to know if there is such a method in Java. Take this snippet as example :
<pre><code>// this will output a/b
System.out.println(path_join(&quot;a&quot;,&quot;b&quot;));
// a/b 
System.out.println(path_join(&quot;a&quot;,&quot;/b&quot;);
</code></pre>

Does Java have a path joining method?

Windows

Java

完全相同的副本：我想知道Java中是否有这样的方法。以下面的代码片段为例：// this will output a/bSystem.out.println(path_join("a","b"));// a/b System.out.println(path_join("a","/b");

问Java有路径连接方法吗？
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