blocks|key|571169|text|您可以使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|571170|string+extension+=+System.IO.Path.GetExtension(filename);|code-block|syntax|javascript|571171|然后手动删除扩展：|571172|string+result+=+filename.Substring(0,+filename.Length+-+extension.Length);|571173|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You can use

<pre><code>string extension = System.IO.Path.GetExtension(filename);
</code></pre>

And then remove the extension manually:

<pre><code>string result = filename.Substring(0, filename.Length - extension.Length);
</code></pre>

blocks|key|571239|text|Path.GetFileNameWithoutExtension方法为您提供作为参数传递的文件名，但不带扩展名，从名称可以明显看出这一点。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|571240|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/system.io.path.getfilenamewithoutextension.aspx^0|0|W|0|W|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]]|D|@$9|Q|A|R|1|S]]|E|$]]|$1|F|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

The <a href="http://msdn.microsoft.com/en-us/library/system.io.path.getfilenamewithoutextension.aspx" rel="noreferrer"><code>Path.GetFileNameWithoutExtension</code></a> method gives you the filename you pass as an argument without the extension, as should be obvious from the name.

blocks|key|787352|text|如果要使用字符串操作，则可以使用函数lastIndexOf(+)，该函数搜索字符或子字符串的最后一个匹配项。Java有许多字符串函数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|787353|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

if you want to use String operation then you can use the function lastIndexOf( ) which Searches for the last occurrence of a character or substring. Java has numerous string functions.

blocks|key|787385|text|String.LastIndexOf会起作用的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|787386|string+fileName=+"abc.123.txt";
int+fileExtPos+=+fileName.LastIndexOf(".");
if+(fileExtPos+>=+0+)
+fileName=+fileName.Substring(0,+fileExtPos);|code-block|syntax|javascript|787387|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

String.LastIndexOf would work.

<pre><code>string fileName= "abc.123.txt";
int fileExtPos = fileName.LastIndexOf(".");
if (fileExtPos &gt;= 0 )
 fileName= fileName.Substring(0, fileExtPos);
</code></pre>

blocks|key|571351|text|++++///+<summary>
++++///+Get+the+extension+from+the+given+filename
++++///+</summary>
++++///+<param+name="fileName">the+given+filename+ie:abc.123.txt</param>
++++///+<returns>the+extension+ie:txt</returns>
++++public+static+string+GetFileExtension(this+string+fileName)
++++{
++++++++string+ext+=+string.Empty;
++++++++int+fileExtPos+=+fileName.LastIndexOf(".",+StringComparison.Ordinal);
++++++++if+(fileExtPos+>=+0)
++++++++++++ext+=+fileName.Substring(fileExtPos,+fileName.Length+-+fileExtPos);

++++++++return+ext;
++++}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|571352|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code> /// &lt;summary&gt;
 /// Get the extension from the given filename
 /// &lt;/summary&gt;
 /// &lt;param name="fileName"&gt;the given filename ie:abc.123.txt&lt;/param&gt;
 /// &lt;returns&gt;the extension ie:txt&lt;/returns&gt;
 public static string GetFileExtension(this string fileName)
 {
 string ext = string.Empty;
 int fileExtPos = fileName.LastIndexOf(".", StringComparison.Ordinal);
 if (fileExtPos &gt;= 0)
 ext = fileName.Substring(fileExtPos, fileName.Length - fileExtPos);

 return ext;
 }
</code></pre>

blocks|key|787487|text|如果你想创建不带扩展名的完整路径，你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|787488|Path.Combine(+Path.GetDirectoryName(fullPath),+Path.GetFileNameWithoutExtension(fullPath))|code-block|syntax|javascript|787489|但我正在寻找一种更简单的方法。有谁知道吗？|787490|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

If you want to create full path without extension you can do something like this:

<pre><code>Path.Combine( Path.GetDirectoryName(fullPath), Path.GetFileNameWithoutExtension(fullPath))
</code></pre>

but I'm looking for simpler way to do that. Does anyone have any idea?

blocks|key|571484|text|框架中有一个用于此目的的方法，它将保留除扩展之外的完整路径。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|571485|System.IO.Path.ChangeExtension(path,+null);|code-block|syntax|javascript|571486|如果只需要文件名，请使用|571487|System.IO.Path.GetFileNameWithoutExtension(path);|571488|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

There's a method in the framework for this purpose, which will keep the full path except for the extension.

<pre><code>System.IO.Path.ChangeExtension(path, null);
</code></pre>

If only file name is needed, use

<pre><code>System.IO.Path.GetFileNameWithoutExtension(path);
</code></pre>

blocks|key|571501|text|++++++++private+void+btnfilebrowse_Click(object+sender,+EventArgs+e)
++++++++{
++++++++++++OpenFileDialog+dlg+=+new+OpenFileDialog();
++++++++++++//dlg.ShowDialog();
++++++++++++dlg.Filter+=+"CSV+files+(*.csv)%7C*.csv%7CXML+files+(*.xml)%7C*.xml";
++++++++++++if+(dlg.ShowDialog()+==+DialogResult.OK)
++++++++++++{
++++++++++++++++string+fileName;
++++++++++++++++fileName+=+dlg.FileName;
++++++++++++++++string+filecopy;
++++++++++++++++filecopy+=+dlg.FileName;
++++++++++++++++filecopy+=+Path.GetFileName(filecopy);
++++++++++++++++string+strFilename;
++++++++++++++++strFilename+=+filecopy;
+++++++++++++++++strFilename+=+strFilename.Substring(0,+strFilename.LastIndexOf('.'));
++++++++++++++++//fileName+=+Path.GetFileName(fileName);+++++++++++++

++++++++++++++++txtfilepath.Text+=+strFilename;

++++++++++++++++string+filedest+=+System.IO.Path.GetFullPath(".\\Excels_Read\\'"%2Btxtfilepath.Text%2B"'.csv");
+++++++++++++++//+filedest+=+"C:\\Users\\adm\\Documents\\Visual+Studio+2010\\Projects\\ConvertFile\\ConvertFile\\Excels_Read";
++++++++++++++++FileInfo+file+=+new+FileInfo(fileName);
++++++++++++++++file.CopyTo(filedest);
+++++++++++++//+File.Copy(fileName,+filedest,true);
++++++++++++++++MessageBox.Show("Import+Done!!!");
++++++++++++}
++++++++}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|571502|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code> private void btnfilebrowse_Click(object sender, EventArgs e)
 {
 OpenFileDialog dlg = new OpenFileDialog();
 //dlg.ShowDialog();
 dlg.Filter = "CSV files (*.csv)|*.csv|XML files (*.xml)|*.xml";
 if (dlg.ShowDialog() == DialogResult.OK)
 {
 string fileName;
 fileName = dlg.FileName;
 string filecopy;
 filecopy = dlg.FileName;
 filecopy = Path.GetFileName(filecopy);
 string strFilename;
 strFilename = filecopy;
 strFilename = strFilename.Substring(0, strFilename.LastIndexOf('.'));
 //fileName = Path.GetFileName(fileName); 

 txtfilepath.Text = strFilename;

 string filedest = System.IO.Path.GetFullPath(".\\Excels_Read\\'"+txtfilepath.Text+"'.csv");
 // filedest = "C:\\Users\\adm\\Documents\\Visual Studio 2010\\Projects\\ConvertFile\\ConvertFile\\Excels_Read";
 FileInfo file = new FileInfo(fileName);
 file.CopyTo(filedest);
 // File.Copy(fileName, filedest,true);
 MessageBox.Show("Import Done!!!");
 }
 }
</code></pre>

blocks|key|787583|text|这个实现应该是有效的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|787584|string+file+=+"abc.txt";
string+fileNoExtension+=+file.Replace(".txt",+"");|code-block|syntax|javascript|787585|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This implementation should work. 

<pre><code>string file = "abc.txt";
string fileNoExtension = file.Replace(".txt", "");
</code></pre>

blocks|key|787628|text|您可能不会问UWP+api。但在UWP中，file.DisplayName是没有扩展名的名称。希望对其他人有用。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|787629|entityMap^0|L|G|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

You maybe not asking the UWP api. 
But in UWP, <code>file.DisplayName</code> is the name without extensions. Hope useful for others.

blocks|key|787647|text|我知道这是一个老生常谈的问题，而Path.GetFileNameWithoutExtension是一个更好，也许更干净的选择。但就我个人而言，我已经将这两个方法添加到我的项目中，并希望分享它们。这需要C#+8.0，因为它使用范围和索引。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|787648|public+static+string+RemoveExtension(this+string+file)+=>+ReplaceExtension(file,+null);

public+static+string+ReplaceExtension(this+string+file,+string+extension)
{
++++var+split+=+file.Split('.');

++++if+(string.IsNullOrEmpty(extension))
++++++++return+string.Join(".",+split[..%5E1]);

++++split[%5E1]+=+extension;

++++return+string.Join(".",+split);
}|code-block|syntax|javascript|787649|entityMap^0|G|W|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

I know it's an old question and <code>Path.GetFileNameWithoutExtension</code>is a better and maybe cleaner option. But personally I've added this two methods to my project and wanted to share them. This requires C# 8.0 due to it using ranges and indices.

<pre><code>public static string RemoveExtension(this string file) =&gt; ReplaceExtension(file, null);

public static string ReplaceExtension(this string file, string extension)
{
 var split = file.Split('.');

 if (string.IsNullOrEmpty(extension))
 return string.Join(".", split[..^1]);

 split[^1] = extension;

 return string.Join(".", split);
}
</code></pre>

If I have a string saying <code>"abc.txt"</code>, is there a quick way to get a substring that is just <code>"abc"</code>?

I can't do an <code>fileName.IndexOf('.')</code> because the file name could be <code>"abc.123.txt"</code> or something and I obviously just want to get rid of the extension (i.e. <code>"abc.123"</code>).

Remove file extension from a file name string

Visual Studio

Java

如果我有一个表示"abc.txt"的字符串，有没有一种快速的方法来获得一个仅为"abc"的子字符串我不能执行fileName.IndexOf('.')，因为文件名可以是"abc.123.txt"或其他名称，而我显然只想去掉扩展名(即"abc.123")。

问从文件名字符串中删除文件扩展名
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