blocks|key|1773132|text|你必须建立一个新的列表。List<int>和List<string>的底层位表示完全不兼容--例如，在64位平台上，各个成员的大小甚至都不一样。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1773133|从理论上讲，可以将List<string>视为List<object>+--这会将您带入协方差和逆方差的激动人心的世界，目前C#或VB.NET还不支持它。|1773134|entityMap^0|C|9|M|C|0|9|C|N|C|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|I|$]]

You have to build a new list. The underlying bit representations of <code>List&lt;int&gt;</code> and <code>List&lt;string&gt;</code> are completely incompatible -- on a 64-bit platform, for instance, the individual members aren't even the same size.

It is theoretically possible to treat a <code>List&lt;string&gt;</code> as a <code>List&lt;object&gt;</code> -- this gets you into the exciting worlds of covariance and contravariance, and is not currently supported by C# or VB.NET.

blocks|key|1773179|text|.NET+2.0提供了ConvertAll方法，您可以在该方法中传入转换器函数：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1773180|List<int>++++l1+=+new+List<int>(new+int[]+{+1,+2,+3+}+);
List<string>+l2+=+l1.ConvertAll<string>(delegate(int+i)+{+return+i.ToString();+});|code-block|syntax|javascript|1773181|entityMap^0|B|A|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

.NET 2.0 has the <code>ConvertAll</code> method where you can pass in a converter function:

<pre><code>List&lt;int&gt; l1 = new List&lt;int&gt;(new int[] { 1, 2, 3 } );
List&lt;string&gt; l2 = l1.ConvertAll&lt;string&gt;(delegate(int i) { return i.ToString(); });
</code></pre>

blocks|key|1558039|text|2010年更新|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1558040|List<int>+l1+=+new+List<int>(new+int[]+{+1,2,3+}+);
List<string>+l2+=+l1.ConvertAll<string>(x+=>+x.ToString());|code-block|syntax|javascript|1558041|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Updated for 2010 

<pre><code>List&lt;int&gt; l1 = new List&lt;int&gt;(new int[] { 1,2,3 } );
List&lt;string&gt; l2 = l1.ConvertAll&lt;string&gt;(x =&gt; x.ToString());
</code></pre>

blocks|key|1558055|text|您可以使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1558056|List<int>+items+=+new+List<int>(new+int[]+{+1,2,3+}+);
List<string>+s+=+(from+i+in+items+select+i.ToString()).ToList();|code-block|syntax|javascript|1558057|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use:

<pre><code>List&lt;int&gt; items = new List&lt;int&gt;(new int[] { 1,2,3 } );
List&lt;string&gt; s = (from i in items select i.ToString()).ToList();
</code></pre>

blocks|key|1773274|text|result+=+listOfInt.Select(i+=>+i.ToString(CultureInfo.InvariantCulture)).ToList()|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1773275|将参数result和listOfInt替换为您的参数|1773276|entityMap^0|0|29|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|M|8|@]|D|@]|E|$]]|$1|H|3|-4|5|6|7|N|8|@]|D|@]|E|$]]]|I|$]]

<code>result = listOfInt.Select(i =&gt; i.ToString(CultureInfo.InvariantCulture)).ToList()</code>

replace the parameters result and listOfInt to your parameters

blocks|key|1558153|text|除了通常的ToString()之外，从整型列表到字符串列表的转换可以通过两种附加方法来完成。选择一个你更喜欢的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1558154|var+stringlist+=+intlist.Select(x=>""%2Bx).ToList();|code-block|syntax|javascript|1558155|或者也可以：|1558156|var+stringlist+=+intlist.Select(x=>$"{x}").ToList();|1558157|最后是传统的：|1558158|var+stringlist+=+intlist.Select(x=>x.ToString()).ToList();|1558159|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Converting from int List to string List can be done in two adittional ways besides the usual ToString(). Choose the one that pleases you more.
<pre><code>var stringlist = intlist.Select(x=&gt;&quot;&quot;+x).ToList();
</code></pre>
Or also:
<pre><code>var stringlist = intlist.Select(x=&gt;$&quot;{x}&quot;).ToList();
</code></pre>
And finally the traditional:
<pre><code>var stringlist = intlist.Select(x=&gt;x.ToString()).ToList();
</code></pre>

Can you cast a <code>List&lt;int&gt;</code> to <code>List&lt;string&gt;</code> somehow?

I know I could loop through and .ToString() the thing, but a cast would be awesome.

I'm in C# 2.0 (so no <a href="http://en.wikipedia.org/wiki/Language_Integrated_Query" rel="noreferrer">LINQ</a>).

Cast List<int> to List<string> in .NET 2.0

您能以某种方式将List<int>转换为List<string>吗？我知道我可以遍历和.ToString()这个东西，但是一个类型转换就太棒了。我使用的是C# 2.0 (所以没有)。

问在.NET 2.0中将List<int>转换为List<string>
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问在.NET 2.0中将List<int>转换为List<string>EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问在.NET 2.0中将List<int>转换为List<string>
EN