blocks|key|1270839|text|使用urllib.urlencode()。它获取键值对的字典，并将其转换为适合于网址的形式(例如，key1=val1&key2=val2)。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1270840|如果您使用的是Python3，请使用urllib.parse.urlencode()|1270841|如果你想创建一个带有重复参数的网址，比如：p=1&p=2&p=3，你有两个选择：|1270842|>>>+import+urllib
>>>+a+=+(('p',1),('p',2),+('p',+3))
>>>+urllib.urlencode(a)
'p=1&p=2&p=3'|code-block|syntax|javascript|1270843|或者，如果你想创建一个带有重复参数的url：|1270844|>>>+urllib.urlencode({'p':+[1,+2,+3]},+doseq=True)
'p=1&p=2&p=3'|1270845|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.python.org/library/urllib.html#urllib.urlencode|1|https://docs.python.org/3/library/urllib.parse.html#urllib.parse.urlencode^0|2|I|1D|J|2|I|0|0|I|O|I|O|1|0|L|B|0|0|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@$9|13|A|14|B|C]|$9|15|A|16|B|C]]|D|@$9|17|A|18|1|19]]|E|$]]|$1|F|3|G|5|6|7|1A|8|@$9|1B|A|1C|B|C]]|D|@$9|1D|A|1E|1|1F]]|E|$]]|$1|H|3|I|5|6|7|1G|8|@$9|1H|A|1I|B|C]]|D|@]|E|$]]|$1|J|3|K|5|L|7|1J|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|1K|8|@]|D|@]|E|$]]|$1|Q|3|R|5|L|7|1L|8|@]|D|@]|E|$M|N]]|$1|S|3|-4|5|6|7|1M|8|@]|D|@]|E|$]]]|T|$U|$5|V|W|X|E|$Y|Z]]|10|$5|V|W|X|E|$Y|11]]]]

Use <a href="http://docs.python.org/library/urllib.html#urllib.urlencode" rel="noreferrer"><code>urllib.urlencode()</code></a>. It takes a dictionary of key-value pairs, and converts it into a form suitable for a URL (e.g., <code>key1=val1&amp;key2=val2</code>).

If you are using Python3, use <a href="https://docs.python.org/3/library/urllib.parse.html#urllib.parse.urlencode" rel="noreferrer"><code>urllib.parse.urlencode()</code></a>

If you want to make a URL with repetitive params such as: <code>p=1&amp;p=2&amp;p=3</code> you have two options:

<pre><code>&gt;&gt;&gt; import urllib
&gt;&gt;&gt; a = (('p',1),('p',2), ('p', 3))
&gt;&gt;&gt; urllib.urlencode(a)
'p=1&amp;p=2&amp;p=3'
</code></pre>

or if you want to make a url with repetitive params:

<pre><code>&gt;&gt;&gt; urllib.urlencode({'p': [1, 2, 3]}, doseq=True)
'p=1&amp;p=2&amp;p=3'
</code></pre>

blocks|key|1270898|text|在我看来，这似乎更具Pythonic风格，并且没有使用任何其他模块：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1270899|x+=+'&'.join(["{}={}".format(k,+v)+for+k,+v+in+{'a':'A',+'b':'B'}.items()])|code-block|syntax|javascript|1270900|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This seems a bit more Pythonic to me, and doesn't use any other modules:

<pre><code>x = '&amp;'.join(["{}={}".format(k, v) for k, v in {'a':'A', 'b':'B'}.items()])
</code></pre>

blocks|key|1270958|text|对于Python3，urllib库发生了一些变化，现在您必须这样做：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1270959|import+urllib


params+=+{'a':'A',+'b':'B'}

urllib.parse.urlencode(params)|code-block|syntax|javascript|1270960|entityMap^0|A|6|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

For python 3, the <code>urllib</code> library has changed a bit, now you have to do:
<pre><code>import urllib


params = {'a':'A', 'b':'B'}

urllib.parse.urlencode(params)
</code></pre>

blocks|key|1270982|text|以下是在Python3中使用它的正确方法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1270983|from+urllib.parse+import+urlencode
params+=+{'a':'A',+'b':'B'}
print(urlencode(params))|code-block|syntax|javascript|1270984|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here is the correct way of using it in Python 3.
<pre><code>from urllib.parse import urlencode
params = {'a':'A', 'b':'B'}
print(urlencode(params))
</code></pre>

I am trying to convert a Python dictionary to a string for use as URL parameters. I am sure that there is a better, more <a href="http://en.wikipedia.org/wiki/Pythonic" rel="noreferrer">Pythonic</a> way of doing this. What is it?

<pre><code>x = ""
for key, val in {'a':'A', 'b':'B'}.items():
 x += "%s=%s&amp;" %(key,val)
x = x[:-1]
</code></pre>

Python Dictionary to URL Parameters

Python

我正在尝试将Python字典转换为用作URL参数的字符串。我相信有一种更好的，更的方式来做这件事。那是什么？x = ""for key, val in {'a':'A', 'b':'B'}.items():    x += "%s=%s&" %(key,val)x = x[:-1]

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