blocks|key|851896|text|如果您只想替换包含在%25中的位，那么这实际上不是一个XML问题。使用regex可以很容易地做到这一点：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|851897|import+re
xmlstring+=+open('myxmldocument.xml',+'r').read()
substitutions+=+{'SITEDESCR':+'myvalue',+...}
pattern+=+re.compile(r'%25([%5E%25]%2B)%25')
xmlstring+=+re.sub(pattern,+lambda+m:+substitutions[m.group(1)],+xmlstring)|code-block|syntax|javascript|851898|entityMap^0|A|1|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

If you just want to replace the bits enclosed with <code>%</code>, then this isn't really an XML problem. You can easily do it with regex:

<pre><code>import re
xmlstring = open('myxmldocument.xml', 'r').read()
substitutions = {'SITEDESCR': 'myvalue', ...}
pattern = re.compile(r'%([^%]+)%')
xmlstring = re.sub(pattern, lambda m: substitutions[m.group(1)], xmlstring)
</code></pre>

blocks|key|851952|text|要替换占位符，您只需逐行读取文件并替换：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|851953|for+line+in+open(template_file_name,'r'):
++output_line+=+line
++output_line+=+string.replace(output_line,+placeholder,+value)
++print+output_line+|code-block|syntax|javascript|851954|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To replace the placeholders all you need is to read the file line by line and replace:

<pre><code>for line in open(template_file_name,'r'):
 output_line = line
 output_line = string.replace(output_line, placeholder, value)
 print output_line 
</code></pre>

blocks|key|852014|text|基础知识：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|852015|from+xml.etree+import+ElementTree+as+et
tree+=+et.parse(datafile)
tree.find('idinfo/timeperd/timeinfo/rngdates/begdate').text+=+'1/1/2011'
tree.find('idinfo/timeperd/timeinfo/rngdates/enddate').text+=+'1/1/2011'
tree.write(datafile)|code-block|syntax|javascript|852016|如果标记名称是唯一的，则可以缩短路径。此语法查找树中任意深度级别的第一个节点。|852017|tree.find('.//begdate').text+=+'1/1/2011'
tree.find('.//enddate').text+=+'1/1/2011'|852018|此外，请阅读documentation，特别是用于定位节点的XPath支持。|offset|length|852019|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3/library/xml.etree.elementtree.html|1|https://docs.python.org/3/library/xml.etree.elementtree.html#xpath-support^0|0|0|0|0|6|D|0|U|5|1|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|12|8|@]|9|@$M|13|N|14|1|15]|$M|16|N|17|1|18]]|A|$]]|$1|O|3|-4|5|6|7|19|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]|W|$5|R|S|T|A|$U|X]]]]

The basics:
<pre><code>from xml.etree import ElementTree as et
tree = et.parse(datafile)
tree.find('idinfo/timeperd/timeinfo/rngdates/begdate').text = '1/1/2011'
tree.find('idinfo/timeperd/timeinfo/rngdates/enddate').text = '1/1/2011'
tree.write(datafile)
</code></pre>
You can shorten the path if the tag name is unique. This syntax finds the first node at any depth level in the tree.
<pre><code>tree.find('.//begdate').text = '1/1/2011'
tree.find('.//enddate').text = '1/1/2011'
</code></pre>
Also, read the <a href="https://docs.python.org/3/library/xml.etree.elementtree.html" rel="nofollow noreferrer">documentation</a>, esp. the <a href="https://docs.python.org/3/library/xml.etree.elementtree.html#xpath-support" rel="nofollow noreferrer">XPath</a> support for locating nodes.

blocks|key|635689|text|您可以就地修改，并且可以安全地使用xpath而不是完整路径或更糟糕的正则表达式进行修改。请参阅下面的内容，并查看etree上的文档|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|635690|from+lxml+import+etree
raw+=+"""
<node>
<begdate>%25begdate%25</begdate>
<begtime>unknown</begtime>
<enddate>%25enddate%25</enddate>
<endtime>unknown</endtime>
</node>"""
nodes+=+etree.fromstring(raw.strip())
shh+=+[setattr(x,+"text",+"DATE:+2021-01-01")+for+x+in+nodes.xpath(".//*[.='%25begdate%25']")]
nodes.xpath(".//begdate//text()")|code-block|syntax|javascript|635691|['DATE:+2021-01-01']|635692|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3/library/xml.etree.elementtree.html^0|H|5|1K|5|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@$9|X|A|Y|1|Z]]|E|$]]|$1|F|3|G|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|M|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

You can modify in place and safely do so with <code>xpath</code> rather than full paths or worse, regex. See below and check out the docs on <a href="https://docs.python.org/3/library/xml.etree.elementtree.html" rel="nofollow noreferrer">etree</a>
<pre class="lang-py prettyprint-override"><code>from lxml import etree
raw = &quot;&quot;&quot;
&lt;node&gt;
&lt;begdate&gt;%begdate%&lt;/begdate&gt;
&lt;begtime&gt;unknown&lt;/begtime&gt;
&lt;enddate&gt;%enddate%&lt;/enddate&gt;
&lt;endtime&gt;unknown&lt;/endtime&gt;
&lt;/node&gt;&quot;&quot;&quot;
nodes = etree.fromstring(raw.strip())
shh = [setattr(x, &quot;text&quot;, &quot;DATE: 2021-01-01&quot;) for x in nodes.xpath(&quot;.//*[.='%begdate%']&quot;)]
nodes.xpath(&quot;.//begdate//text()&quot;)
</code></pre>
<pre class="lang-py prettyprint-override"><code>['DATE: 2021-01-01']
</code></pre>

I am looking to edit XML files using python. I want to find and replace keywords in the tags. In the past, a co-worker had set up template XML files and used a "find and replace" program to replace these key words. I want to use python to find and replace these key words with values. I have been teaching myself the Elementtree module, but I am having trouble trying to do a find and replace. I have attached a snid-bit of my XML file. You will seen some variables surrounded by % (ie %SITEDESCR%) These are the words I want to replace and then save the XML to a new file. Any help or suggestions would be great.

Thanks,
Mike

<pre><code>&lt;metadata&gt;
&lt;idinfo&gt;
&lt;citation&gt;
&lt;citeinfo&gt;
 &lt;origin&gt;My Company&lt;/origin&gt;
 &lt;pubdate&gt;05/04/2009&lt;/pubdate&gt;
 &lt;title&gt;POLYGONS&lt;/title&gt;
 &lt;geoform&gt;vector digital data&lt;/geoform&gt;
 &lt;onlink&gt;\\C$\ArcGISDevelopment\Geodatabase\PDA_STD_05_25_2009.gdb&lt;/onlink&gt;
&lt;/citeinfo&gt;
&lt;/citation&gt;
 &lt;descript&gt;
 &lt;abstract&gt;This dataset represents the mapped polygons developed from the field data for the %SITEDESCR%.&lt;/abstract&gt;
 &lt;purpose&gt;This dataset was created to accompany some stuff.&lt;/purpose&gt;
 &lt;/descript&gt;
&lt;timeperd&gt;
&lt;timeinfo&gt;
&lt;rngdates&gt;
 &lt;begdate&gt;%begdate%&lt;/begdate&gt;
 &lt;begtime&gt;unknown&lt;/begtime&gt;
 &lt;enddate&gt;%enddate%&lt;/enddate&gt;
 &lt;endtime&gt;unknown&lt;/endtime&gt;
 &lt;/rngdates&gt;
 &lt;/timeinfo&gt;
 &lt;current&gt;ground condition&lt;/current&gt;
 &lt;/timeperd&gt;
</code></pre>

Find and Replace Values in XML using Python

我希望使用python编辑XML文件。我想查找和替换标签中的关键字。在过去，同事建立了模板XML文件，并使用“查找和替换”程序来替换这些关键字。我想使用python查找这些关键字并将其替换为值。我一直在自学Elementtree模块，但我在尝试查找和替换时遇到了麻烦。我附上了我的XML文件的snid位。您将看到一些由%...

问使用Python查找和替换XML中的值
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