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社区首页 >问答首页 >安卓多点触控-忽略Second Finger ACTION.MOVE

安卓多点触控-忽略Second Finger ACTION.MOVE
EN

Stack Overflow用户
提问于 2012-01-27 10:41:11
回答 1查看 10.2K关注 0票数 20

下面的代码是我一直尝试用于多点触控的代码。finger one设置正确,当我拖动手指时,它会四处移动。当我触摸和松开我的手指时,手指二会出现和消失,但它从来不会移动。知道出什么问题了吗?

我已经读过developers blog了,我仍然不明白问题是什么。

代码语言:javascript
复制
    @Override
    public boolean onTouchEvent(MotionEvent event) {
        int action = event.getAction() & MotionEvent.ACTION_MASK;
        int pointerIndex = (event.getAction() & MotionEvent.ACTION_POINTER_ID_MASK) >> MotionEvent.ACTION_POINTER_ID_SHIFT;
        int pointerId = event.getPointerId(pointerIndex);
        switch (action) {
        case MotionEvent.ACTION_DOWN:
        case MotionEvent.ACTION_POINTER_DOWN:
            if (pointerId == 0)
            {
                fingerOneDown = 1;
                fingerOneX = event.getX(pointerIndex);
                fingerOneY = event.getY(pointerIndex);
            }
            if (pointerId == 1)
            {
                fingerTwoDown = 1;
                fingerTwoX = event.getX(pointerIndex);
                fingerTwoY = event.getY(pointerIndex);
            }
            break;

        case MotionEvent.ACTION_UP:          
        case MotionEvent.ACTION_POINTER_UP:
        case MotionEvent.ACTION_CANCEL:
            if (pointerId == 0)
            {
                fingerOneDown = 0;
                fingerOneX = event.getX(pointerIndex);
                fingerOneY = event.getY(pointerIndex);
            }
            if (pointerId == 1)
            {
                fingerTwoDown = 0;
                fingerTwoX = event.getX(pointerIndex);
                fingerTwoY = event.getY(pointerIndex);
            }
            break;

        case MotionEvent.ACTION_MOVE:
            if (pointerId == 0)
            {
                fingerOneDown = 1;
                fingerOneX = event.getX(pointerIndex);
                fingerOneY = event.getY(pointerIndex);
            }
            if (pointerId == 1)
            {
                fingerTwoDown = 1;
                fingerTwoX = event.getX(pointerIndex);
                fingerTwoY = event.getY(pointerIndex);
            }

            break;
        }
        return true;
    }
EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2012-06-09 03:06:01

别管这个了。我修好了。出于某种奇怪的原因,ACTION.MOVE事件的pointerId总是为零。因此,您必须始终在事件内重新计算pointerId,如下所示:

代码语言:javascript
复制
       case MotionEvent.ACTION_MOVE:

        int pointerCount = event.getPointerCount();
        for(int i = 0; i < pointerCount; ++i)
        {
            pointerIndex = i;
            pointerId = event.getPointerId(pointerIndex);
            Log.d("pointer id - move",Integer.toString(pointerId));
            if(pointerId == 0)
            {
                fingerOneDown = 1;
                fingerOneX = event.getX(pointerIndex);
                fingerOneY = event.getY(pointerIndex);
            }
            if(pointerId == 1)
            {
                fingerTwoDown = 1;
                fingerTwoX = event.getX(pointerIndex);
                fingerTwoY = event.getY(pointerIndex);
            }
        }
        break;
票数 34
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/9028357

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