blocks|key|1434553|text|jQuery.inArray返回与您搜索的项目匹配的第一个索引，如果未找到，则返回-1：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1434554|if($.inArray(valueToMatch,+theArray)+>+-1)+alert("it's+in+there");|code-block|syntax|javascript|1434555|您不应该需要array.remove。使用拼接：|1434556|theArray.splice(startRemovingAtThisIndex,+numberOfItemsToRemove);|1434557|或者，您可以使用jQuery.grep实用程序执行“删除”：|1434558|var+valueToRemove+=+'someval';
theArray+=+$.grep(theArray,+function(val)+{+return+val+!=+valueToRemove;+});|1434559|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.jquery.com/Utilities/jQuery.inArray|1|http://docs.jquery.com/Utilities/jQuery.grep^0|0|E|0|0|0|0|0|8|B|1|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@$A|11|B|12|1|13]]|C|$]]|$1|D|3|E|5|F|7|14|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|15|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|16|8|@]|9|@]|C|$G|H]]|$1|M|3|N|5|6|7|17|8|@]|9|@$A|18|B|19|1|1A]]|C|$]]|$1|O|3|P|5|F|7|1B|8|@]|9|@]|C|$G|H]]|$1|Q|3|-4|5|6|7|1C|8|@]|9|@]|C|$]]]|R|$S|$5|T|U|V|C|$W|X]]|Y|$5|T|U|V|C|$W|Z]]]]

<a href="http://docs.jquery.com/Utilities/jQuery.inArray" rel="noreferrer">jQuery.inArray</a> returns the first index that matches the item you searched for or -1 if it is not found:

<pre><code>if($.inArray(valueToMatch, theArray) &gt; -1) alert("it's in there");
</code></pre>

You shouldn't need an array.remove. Use splice:

<pre><code>theArray.splice(startRemovingAtThisIndex, numberOfItemsToRemove);
</code></pre>

Or, you can perform a "remove" using the <a href="http://docs.jquery.com/Utilities/jQuery.grep" rel="noreferrer">jQuery.grep</a> util:

<pre><code>var valueToRemove = 'someval';
theArray = $.grep(theArray, function(val) { return val != valueToRemove; });
</code></pre>

blocks|key|1649260|text|如果您的列表包含一个元素列表，那么您可以使用jQuery.not或jQuery.filter来执行"array.remove“。(添加答案是因为你的原始问题在谷歌上的得分很高)。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1649261|entityMap|0|LINK|mutability|MUTABLE|url|http://api.jquery.com/not/|1|http://api.jquery.com/filter/^0|M|A|0|X|D|1|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@$A|O|B|P|1|Q]|$A|R|B|S|1|T]]|C|$]]|$1|D|3|-4|5|6|7|U|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]|L|$5|G|H|I|C|$J|M]]]]

If your list contains a list of elements, then you can use <a href="http://api.jquery.com/not/" rel="nofollow noreferrer">jQuery.not</a> or <a href="http://api.jquery.com/filter/" rel="nofollow noreferrer">jQuery.filter</a> to do your "array.remove". (Answer added because of the high google score of your original question).

blocks|key|1434624|text|我找到了移除对象的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1434625|foot+=+{+bar+:+'test'};
delete+foot[bar];|code-block|syntax|javascript|1434626|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I found way to remove object:

<pre><code>foot = { bar : 'test'};
delete foot[bar];
</code></pre>

blocks|key|1649299|text|这不是包含，但在一行代码中，您可以向数组添加一个方便的“jQuery”方法。我发现这有助于提高可读性(特别是对蟒蛇爱好者)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1649300|Array.prototype.contains+=+function(a){+return+this.indexOf(a)+!=+-1+}|code-block|syntax|javascript|1649301|示例用法|1649302|+>+var+a+=+[1,2,3]
+>+a.contains(1)
true
+>+a.contains(4)
false|1649303|与删除类似|1649304|Array.prototype.remove+=+function(a){if+(this.contains(a)){+this.splice(this.indexOf(a),1)};+return+this}

>+var+a+=+[1,2,3]
>+a.remove(2)
[1,3]|1649305|或者，如果您希望它返回被移除的对象，而不是更改后的数组，那么|1649306|Array.prototype.remove+=+function(a){if+(this.contains(a)){+return+this.splice(this.indexOf(a),1)}}

>+var+a+=+[1,2,3]
>+a.remove(2)
[2]
>+a
[1,3]|1649307|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|Y|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

This is not jQuery, but in one line you can add a handy 'contains' method to arrays. I find this helps with readability (especially for python folk).

<pre><code>Array.prototype.contains = function(a){ return this.indexOf(a) != -1 }
</code></pre>

example usage

<pre><code> &gt; var a = [1,2,3]
 &gt; a.contains(1)
true
 &gt; a.contains(4)
false
</code></pre>

Similarly for remove

<pre><code>Array.prototype.remove = function(a){if (this.contains(a)){ this.splice(this.indexOf(a),1)}; return this}

&gt; var a = [1,2,3]
&gt; a.remove(2)
[1,3]
</code></pre>

Or, if you want it to return the thing removed rather than the altered array, then

<pre><code>Array.prototype.remove = function(a){if (this.contains(a)){ return this.splice(this.indexOf(a),1)}}

&gt; var a = [1,2,3]
&gt; a.remove(2)
[2]
&gt; a
[1,3]
</code></pre>

Can jQuery test an array for the presence of an object (either as part of the core functionality or via an avaible plugin)?

Also, I'm looking for something like <code>array.remove</code>, which would remove a given object from an array. Can jQuery handle this for me?

jquery version of array.contains

jQuery

jQuery是否可以测试数组中是否存在对象(作为核心功能的一部分，或者通过可用的插件)？另外，我正在寻找像array.remove这样的东西，它可以从数组中删除给定的对象。jQuery能帮我处理这件事吗？

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