我有一个包含一些图像的div,当我单击这些图像时,我希望打开另一个包含我单击的图像的div。
JS
$('.examples img').click(function() {
var loc = $(this).attr("src");
$('#image-zoom').attr("src",loc);
});
HTML
<div class="container examples" >
<div id="image-zoom">
<img class="img-thumbnail zoom" src="" alt="dental">
</div>
<div class="row">
<div class="col-sm-12">
<img id="zoom" class="img-thumbnail zoom" src="images/01.png" alt="dental">
<img class="img-thumbnail zoom" src="images/02.png" alt="dental">
<img class="img-thumbnail zoom" src="images/03.png" alt="dental">
</div>
</div>
<div class="row">
<div class="col-sm-12">
<img class="img-thumbnail zoom" src="images/04.png" alt="dental">
<img class="img-thumbnail zoom" src="images/05.png" alt="dental">
<img class="img-thumbnail zoom" src="images/06.png" alt="dental">
</div>
</div>
</div>
当我试图隐藏div时,我认为它在工作,所以我在语法上有错误
https://stackoverflow.com/questions/22794641
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