blocks|key|1693233|text|你混合了不同的格式函数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1693234|旧式%25格式化使用%25代码进行格式化：|offset|length|style|CODE|1693235|'It+will+cost+$%25d+dollars.'+%25+95|code-block|syntax|javascript|1693236|新型{}格式使用{}代码和.format方法|1693237|'It+will+cost+${0}+dollars.'.format(95)|1693238|请注意，对于旧式格式，您必须使用元组指定多个参数：|1693239|'%25d+days+and+%25d+nights'+%25+(40,+40)|1693240|1693241|在您的示例中，由于您使用的是{}格式说明符，因此请使用.format|1693242|"'{0}'+is+longer+than+'{1}'".format(name1,+name2)|1693243|entityMap^0|0|2|1|8|1|0|0|2|2|8|2|D|7|0|0|0|0|0|E|2|R|7|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|12|8|@$D|13|E|14|F|G]|$D|15|E|16|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|17|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|18|8|@$D|19|E|1A|F|G]|$D|1B|E|1C|F|G]|$D|1D|E|1E|F|G]]|9|@]|A|$]]|$1|O|3|P|5|J|7|1F|8|@]|9|@]|A|$K|L]]|$1|Q|3|R|5|6|7|1G|8|@]|9|@]|A|$]]|$1|S|3|T|5|J|7|1H|8|@]|9|@]|A|$K|L]]|$1|U|3|-4|5|6|7|1I|8|@]|9|@]|A|$]]|$1|V|3|W|5|6|7|1J|8|@$D|1K|E|1L|F|G]|$D|1M|E|1N|F|G]]|9|@]|A|$]]|$1|X|3|Y|5|J|7|1O|8|@]|9|@]|A|$K|L]]|$1|Z|3|-4|5|6|7|1P|8|@]|9|@]|A|$]]]|10|$]]

You're mixing different format functions.

The old-style <code>%</code> formatting uses <code>%</code> codes for formatting:

<pre><code>'It will cost $%d dollars.' % 95
</code></pre>

The new-style <code>{}</code> formatting uses <code>{}</code> codes and the <code>.format</code> method

<pre><code>'It will cost ${0} dollars.'.format(95)
</code></pre>

Note that with old-style formatting, you have to specify multiple arguments using a tuple:

<pre><code>'%d days and %d nights' % (40, 40)
</code></pre>

<hr>

In your case, since you're using <code>{}</code> format specifiers, use <code>.format</code>:

<pre><code>"'{0}' is longer than '{1}'".format(name1, name2)
</code></pre>

blocks|key|1906704|text|错误在您的字符串格式中。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1906705|使用'%25‘运算符使用传统字符串格式的正确方法是使用printf样式的字符串(Python文档在这里：http://docs.python.org/2/library/string.html#format-string-syntax)：|offset|length|1906706|"'%25s'+is+longer+than+'%25s'"+%25+(name1,+name2)|code-block|syntax|javascript|1906707|但是，'%25‘运算符will+probably+be+deprecated+in+the+future。新的PEP+3101工作方式是这样的：|1906708|"'{0}'+is+longer+than+'{1}'".format(name1,+name2)|1906709|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.python.org/2/library/string.html#format-string-syntax|1|http://docs.python.org/3.0/whatsnew/3.0.html|2|http://www.python.org/dev/peps/pep-3101/^0|0|1E|1T|0|0|0|9|15|1|1H|8|2|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|11|8|@]|9|@$D|12|E|13|1|14]]|A|$]]|$1|F|3|G|5|H|7|15|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|16|8|@]|9|@$D|17|E|18|1|19]|$D|1A|E|1B|1|1C]]|A|$]]|$1|M|3|N|5|H|7|1D|8|@]|9|@]|A|$I|J]]|$1|O|3|-4|5|6|7|1E|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]|W|$5|R|S|T|A|$U|X]]|Y|$5|R|S|T|A|$U|Z]]]]

The error is in your string formatting.

The correct way to use traditional string formatting using the '%' operator is to use a printf-style format string (Python documentation for this here: <a href="http://docs.python.org/2/library/string.html#format-string-syntax">http://docs.python.org/2/library/string.html#format-string-syntax</a>):

<pre><code>"'%s' is longer than '%s'" % (name1, name2)
</code></pre>

However, the '%' operator <a href="http://docs.python.org/3.0/whatsnew/3.0.html">will probably be deprecated in the future</a>. The new <a href="http://www.python.org/dev/peps/pep-3101/">PEP 3101</a> way of doing things is like this:

<pre><code>"'{0}' is longer than '{1}'".format(name1, name2)
</code></pre>

blocks|key|1906731|text|除了其他两个答案之外，我认为后两个条件中的缩进也是不正确的。条件是一个名字比另一个名字长，它们需要以'elif‘开头，并且没有缩进。如果你把它放在第一个条件下(从页边开始缩进四个)，结果就是矛盾的，因为两个名字的长度不能同时相等和不同。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1906732|++++else:
++++++++print+("The+names+are+different,+but+are+the+same+length")
elif+len(name1)+>+len(name2):
++++print+("{0}+is+longer+than+{1}".format(name1,+name2))|code-block|syntax|javascript|1906733|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In addition to the other two answers, I think the indentations are also incorrect in the last two conditions.
The conditions are that one name is longer than the other and they need to start with 'elif' and with no indentations. If you put it within the first condition (by giving it four indentations from the margin), it ends up being contradictory because the lengths of the names cannot be equal and different at the same time. 

<pre><code> else:
 print ("The names are different, but are the same length")
elif len(name1) &gt; len(name2):
 print ("{0} is longer than {1}".format(name1, name2))
</code></pre>

blocks|key|1693364|text|在我的例子中，这是因为我只需要一个%25s，所以我缺少值输入。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1693365|entityMap^0|H|2|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

In my case, it's because I need only a single <code>%s</code>, i missing values input.

blocks|key|1906924|text|我也遇到了这个错误，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1906925|_mysql_exceptions.ProgrammingError:+not+all+arguments+converted+during+string+formatting+|code-block|syntax|javascript|1906926|但是list+args运行得很好。|1906927|我使用mysqlclient+python+lib。库看起来不接受元组参数。要传递像['arg1',+'arg2']这样的列表参数将会起作用。|offset|length|style|CODE|1906928|entityMap^0|0|0|0|16|G|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|T|8|@$K|U|L|V|M|N]]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

I encounter the error as well, 

<pre><code>_mysql_exceptions.ProgrammingError: not all arguments converted during string formatting 
</code></pre>

But list args work well.

I use mysqlclient python lib. The lib looks like not to accept tuple args. To pass list args like <code>['arg1', 'arg2']</code> will work.

blocks|key|1907011|text|对我来说，因为我在一次print调用中存储了许多值，所以解决方案是创建一个单独的变量来将数据存储为一个元组，然后调用print函数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1907012|x+=+(f"{id}",+f"{name}",+f"{age}")
print(x)+|code-block|syntax|javascript|1907013|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

For me, as I was storing many values within a single print call, the solution was to create a separate variable to store the data as a tuple and then call the print function.

<pre><code>x = (f"{id}", f"{name}", f"{age}")
print(x) 
</code></pre>

blocks|key|1693562|text|最简单的方法是将字符串数转换为整数|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1693563|number=89
number=int(89)|code-block|syntax|javascript|1693564|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Most Easy way typecast string number to integer
<pre><code>number=89
number=int(89)
</code></pre>

blocks|key|1693587|text|请记住，此错误也可能是由于忘记引用变量造成的|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1693588|"this+is+a+comment"+%25+comment+#ERROR|code-block|syntax|javascript|1693589|而不是|1693590|"this+is+a+comment:+%25s"+%25+comment|1693591|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Keep in mind this error could also be caused by forgetting to reference the variable
<pre><code>&quot;this is a comment&quot; % comment #ERROR
</code></pre>
instead of
<pre><code>&quot;this is a comment: %s&quot; % comment
</code></pre>

The program is supposed to take in two names, and if they are the same length it should check if they are the same word. If it's the same word it will print "The names are the same". If they are the same length but with different letters it will print "The names are different but the same length". The part I'm having a problem with is in the bottom 4 lines.

<pre><code>#!/usr/bin/env python
# Enter your code for "What's In (The Length Of) A Name?" here.
name1 = input("Enter name 1: ")
name2 = input("Enter name 2: ")
len(name1)
len(name2)
if len(name1) == len(name2):
 if name1 == name2:
 print ("The names are the same")
 else:
 print ("The names are different, but are the same length")
 if len(name1) &gt; len(name2):
 print ("'{0}' is longer than '{1}'"% name1, name2)
 elif len(name1) &lt; len(name2):
 print ("'{0}'is longer than '{1}'"% name2, name1)
</code></pre>

When I run this code it displays:

<pre><code>Traceback (most recent call last):
 File "program.py", line 13, in &lt;module&gt;
 print ("'{0}' is longer than '{1}'"% name1, name2)
TypeError: not all arguments converted during string formatting
</code></pre>

Any suggestions are highly appreciated.

TypeError: not all arguments converted during string formatting python

数据存储

Python

程序应该接受两个名字，如果它们的长度相同，它应该检查它们是否是相同的单词。如果是相同的单词，它会打印“名字是相同的”。如果它们的长度相同但字母不同，则会打印“名称不同但长度相同”。我有问题的部分是在最下面的4行。#!/usr/bin/env python# Enter your code for "What's In ...

问TypeError:在设置字符串格式的过程中并非所有参数都已转换
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