blocks|key|1373984|text|您可以使用strrev来反转字符串，然后反转结果：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1373985|$split_point+=+'+-+';
$string+=+'this+is+my+-+string+-+and+more';

$result+=+array_map('strrev',+explode($split_point,+strrev($string)));|code-block|syntax|javascript|1373986|不过，我不确定这是不是最好的解决方案。|1373987|entityMap|0|LINK|mutability|MUTABLE|url|http://us.php.net/strrev^0|5|6|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|F|7|W|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|X|8|@]|9|@]|C|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

You may use <a href="http://us.php.net/strrev" rel="noreferrer">strrev</a> to reverse the string, and then reverse the results back:

<pre><code>$split_point = ' - ';
$string = 'this is my - string - and more';

$result = array_map('strrev', explode($split_point, strrev($string)));
</code></pre>

Not sure if this is the best solution though.

blocks|key|1589233|text|这样如何：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1589234|$parts+=+explode($split_point,+$string);
$last+=+array_pop($parts);
$item+=+array(implode($split_point,+$parts),+$last);|code-block|syntax|javascript|1589235|不会赢得任何高尔夫奖项，但我认为它表现出了意图和良好的效果。|1589236|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

How about this:

<pre><code>$parts = explode($split_point, $string);
$last = array_pop($parts);
$item = array(implode($split_point, $parts), $last);
</code></pre>

Not going to win any golf awards, but it shows intent and works well, I think.

blocks|key|1374239|text|这是另一种方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1374240|$split_point+=+'+-+';
$string+=+'this+is+my+-+string+-+and+more';

$stringpos+=+strrpos($string,+$split_point,+-1);
$finalstr+=+substr($string,0,$stringpos);|code-block|syntax|javascript|1374241|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here is another way of doing it:

<pre><code>$split_point = ' - ';
$string = 'this is my - string - and more';

$stringpos = strrpos($string, $split_point, -1);
$finalstr = substr($string,0,$stringpos);
</code></pre>

blocks|key|1373947|text|如果我没理解错的话，你想让这个例子告诉你('this+is+my+-+string'，'and+more')？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1373948|内置的拆分/分解似乎是只向前的--你可能必须自己用strrpos来实现它。(从右到左搜索)|1373949|$idx+=+strrpos($string,+$split_point);
$parts+=+array(substr($string,+0,+$idx),+substr($string,+$idx%2Bstrlen($split_point)))|code-block|syntax|javascript|1373950|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

If I understand correctly, you want the example case to give you ('this is my - string', 'and more')?

Built-in split/explode seems to be forwards-only - you'll probably have to implement it yourself with strrpos. (right-left search)

<pre><code>$idx = strrpos($string, $split_point);
$parts = array(substr($string, 0, $idx), substr($string, $idx+strlen($split_point)))
</code></pre>

blocks|key|1589173|text|为什么不在‘-’上拆分，而是将你重新组合在一起的前两个数组条目连接起来呢？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1589174|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Why not split on ' - ', but then join the first two array entries that you get back together?

blocks|key|1589334|text|我偶然发现了同样的东西，并像这样修复它：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1589335|$split_point+=+'+-+';
$string+=+'this+is+my+-+string+-+and+more';

$reverse_explode+=+array_reverse(explode($split_point,+$string));|code-block|syntax|javascript|1589336|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I've stumbled uppon the same, and fixed it like so:

<pre><code>$split_point = ' - ';
$string = 'this is my - string - and more';

$reverse_explode = array_reverse(explode($split_point, $string));
</code></pre>

blocks|key|1374312|text|我喜欢Moff的答案，但我改进了它，将元素的数量限制为2，并重新反转数组：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1374313|$split_point+=+'+-+';
$string+=+'this+is+my+-+string+-+and+more';

$result+=+array_reverse(array_map('strrev',+explode($split_point,+strrev($string),2)));|code-block|syntax|javascript|1374314|那么$result将是：|1374315|Array+(+[0]+=>+this+is+my+-+string+[1]+=>+and+more+)|1374316|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

I liked Moff's answer, but I improved it by limiting the number of elements to 2 and re-reversing the array:

<pre><code>$split_point = ' - ';
$string = 'this is my - string - and more';

$result = array_reverse(array_map('strrev', explode($split_point, strrev($string),2)));
</code></pre>

Then $result will be :

<pre><code>Array ( [0] =&gt; this is my - string [1] =&gt; and more )
</code></pre>

blocks|key|1589297|text|假设您只希望忽略第一次出现的$split_point，这对您来说应该是可行的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1589298|#+retrieve+first+$split_point+position
$first+=+strpos($string,+$split_point);
#+retrieve+second+$split_point+positon
$second+=+strpos($string,+$split_point,+$first%2Bstrlen($split_point));
#+extract+from+the+second+$split_point+onwards+(with+$split_point)
$substr+=+substr($string,+$second);

#+explode+$substr,+first+element+should+be+empty
$array+=+explode($split_point,+$substr);

#+set+first+element+as+beginning+of+string+to+the+second+$split_point
$array[0]+=+substr_replace($string,+'',+strpos($string,+$substr));|code-block|syntax|javascript|1589299|这将允许您在第二次出现$split_point之后(包括第二次)对每次出现的$split_point进行拆分。|1589300|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Assuming you only want the first occurrence of $split_point to be ignored, this should work for you:

<pre><code># retrieve first $split_point position
$first = strpos($string, $split_point);
# retrieve second $split_point positon
$second = strpos($string, $split_point, $first+strlen($split_point));
# extract from the second $split_point onwards (with $split_point)
$substr = substr($string, $second);

# explode $substr, first element should be empty
$array = explode($split_point, $substr);

# set first element as beginning of string to the second $split_point
$array[0] = substr_replace($string, '', strpos($string, $substr));
</code></pre>

This will allow you to split on every occurrence of $split_point after (and including) the second occurrence of $split_point.

blocks|key|1374344|text|不知道为什么没有人发布一个支持$limit的工作函数，尽管这里是给那些知道他们将经常使用它的人：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1374345|<?php
function+explode_right($boundary,+$string,+$limit)
{
+return+array_reverse(array_map('strrev',+explode(strrev($boundary),+strrev($string),+$limit)));
}

$string+=+'apple1orange1banana1cupuacu1cherimoya1mangosteen1durian';
echo+$string.'<br+/><pre>'.print_r(explode_right(1,+$string,+3),1).'</pre>';
?>|code-block|syntax|javascript|1374346|entityMap^0|F|6|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Not sure why no one posted a working function with <code>$limit</code> support though here it is for those who know that they'll be using this frequently:
<pre><code>&lt;?php
function explode_right($boundary, $string, $limit)
{
 return array_reverse(array_map('strrev', explode(strrev($boundary), strrev($string), $limit)));
}

$string = 'apple1orange1banana1cupuacu1cherimoya1mangosteen1durian';
echo $string.'&lt;br /&gt;&lt;pre&gt;'.print_r(explode_right(1, $string, 3),1).'&lt;/pre&gt;';
?&gt;
</code></pre>

blocks|key|1589580|text|我对所有过度设计的答案都不感兴趣，这些过度设计的答案调用了许多函数和/或多次迭代数据。所有这些字符串和数组反转函数使得这项技术很难理解。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1589581|在这种情况下，正则表达式非常优雅。这正是我在专业应用程序中所要做的：|1589582|代码：(Demo)|offset|length|1589583|$string+=+'this+is+my+-+string+-+and+more';
var_export(preg_split('~.*\K+-+~',+$string));|code-block|syntax|javascript|1589584|输出：|1589585|array+(
++0+=>+'this+is+my+-+string',
++1+=>+'and+more',
)|1589586|通过贪婪地匹配字符(.*)，然后重新启动全字符串匹配(\K)，然后匹配最后出现的分隔子字符串(“-+")，可以确保只将最后一个子字符串与字符串分开。|style|CODE|1589587|entityMap|0|LINK|mutability|MUTABLE|url|https://3v4l.org/SKEG9^0|0|0|4|4|0|0|0|0|0|A|2|R|2|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|13|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|14|8|@]|9|@$F|15|G|16|1|17]]|A|$]]|$1|H|3|I|5|J|7|18|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|19|8|@]|9|@]|A|$]]|$1|O|3|P|5|J|7|1A|8|@]|9|@]|A|$K|L]]|$1|Q|3|R|5|6|7|1B|8|@$F|1C|G|1D|S|T]|$F|1E|G|1F|S|T]]|9|@]|A|$]]|$1|U|3|-4|5|6|7|1G|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|11]]]]

I am underwhelmed by all of the over-engineered answers which are calling many functions and/or iterating over data multiple times. All of those string and array reversing functions make the technique very hard to comprehend.
Regex is powerfully elegant in this case. This is exactly how I would do it in a professional application:
Code: (<a href="https://3v4l.org/SKEG9" rel="nofollow noreferrer">Demo</a>)
<pre><code>$string = 'this is my - string - and more';
var_export(preg_split('~.*\K - ~', $string));
</code></pre>
Output:
<pre><code>array (
 0 =&gt; 'this is my - string',
 1 =&gt; 'and more',
)
</code></pre>
By greedily matching characters (<code>.*</code>), then restarting the fullstring match (<code>\K</code>), then matching the last occurring delimiting substring (&quot; - &quot;), you are assured to only separate the final substring from the string.

blocks|key|1374255|text|$split_point+=+'+-+';
$string+=+'this+is+my+-+string+-+and+more';
$result+=+end(explode($split_point,+$string));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1374256|这个运行得很好。|unstyled|1374257|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>$split_point = ' - ';
$string = 'this is my - string - and more';
$result = end(explode($split_point, $string));
</code></pre>

This is working fine

<pre><code>$split_point = ' - ';
$string = 'this is my - string - and more';
</code></pre>
How can I make a split using the second instance of <code>$split_point</code> and not the first one. Can I specify somehow a right to left search?
Basically how do I explode from right to left. I want to pick up only the last instance of &quot; - &quot;.
Result I need:
<pre><code>$item[0]='this is my - string';
$item[1]='and more';
</code></pre>
and not:
<pre><code>$item[0]='this is my';
$item[1]='string - and more';
</code></pre>

How to explode only on the last occurring delimiter?

$split_point = ' - ';$string = 'this is my - string - and more';如何使用$split_point的第二个实例而不是第一个实例进行拆分。我能以某种方式指定从右到左的搜索吗？基本上我是如何从右向左爆炸的。我只想拿起“-”的最后一个实例。我需要的结果是：$item[0]='this is my - string';$item[1]='and

问如何只在最后出现的分隔符上分解？
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问如何只在最后出现的分隔符上分解？EN

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问如何只在最后出现的分隔符上分解？
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