blocks|key|4672523|text|非常简单：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4672524|scala>+"FooN00b".filterNot(_+==+'0')
res0:+String+=+FooNb|code-block|syntax|javascript|4672525|要用其他字符替换某些字符，请执行以下操作：|4672526|scala>+"FooN00b"+map+{+case+'0'+=>+'o'++case+'N'+=>+'D'++case+c+=>+c+}
res1:+String+=+FooDoob|4672527|要用任意数量的字符替换一个字符，请执行以下操作：|4672528|scala>+"FooN00b"+flatMap+{+case+'0'+=>+"oOo"++case+'N'+=>+""++case+c+=>+s"$c"+}
res2:+String+=+FoooOooOob|4672529|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Very simple:

<pre><code>scala&gt; "FooN00b".filterNot(_ == '0')
res0: String = FooNb
</code></pre>

To replace some characters with others:

<pre><code>scala&gt; "FooN00b" map { case '0' =&gt; 'o' case 'N' =&gt; 'D' case c =&gt; c }
res1: String = FooDoob
</code></pre>

To replace one character with some arbitrary number of characters:

<pre><code>scala&gt; "FooN00b" flatMap { case '0' =&gt; "oOo" case 'N' =&gt; "" case c =&gt; s"$c" }
res2: String = FoooOooOob
</code></pre>

blocks|key|4672564|text|您可以直接映射字符串：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4672565|def+removeZero(s:+String)+=+s.map(c+=>+if(c+==+'0')+'+'+else+c)|code-block|syntax|javascript|4672566|或者，您可以使用replace|offset|length|style|CODE|4672567|s.replace('0',+'+')|4672568|entityMap^0|0|0|8|7|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

You can map strings directly:

<pre><code>def removeZero(s: String) = s.map(c =&gt; if(c == '0') ' ' else c)
</code></pre>

alternatively you could use <code>replace</code>:

<pre><code>s.replace('0', ' ')
</code></pre>

blocks|key|4672586|text|根据Ignacio+Alorre的说法，如果您想将其他字符替换为字符串：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4672587|def+replaceChars+(str:+String)+=+str.map(c+=>+if+(c+==+'0')+'+'+else+if+(c+=='T')+'_'+else+if+(c=='-')+'_'+else+if(c=='Z')+'.'+else+c)

val+charReplaced+=+replaceChars("N000TZ")|code-block|syntax|javascript|4672588|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

According to Ignacio Alorre, if you want to replace others chars into string:

<pre><code>def replaceChars (str: String) = str.map(c =&gt; if (c == '0') ' ' else if (c =='T') '_' else if (c=='-') '_' else if(c=='Z') '.' else c)

val charReplaced = replaceChars("N000TZ")
</code></pre>

blocks|key|166663|text|/**
+++how+to+replace+a+empty+chachter+in+string
**/
val+name="Jeeta"
val+afterReplace=name.replace(""%2B'a',"")|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|166664|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>/**
 how to replace a empty chachter in string
**/
val name="Jeeta"
val afterReplace=name.replace(""+'a',"")
</code></pre>

blocks|key|4672621|text|最好的方法是使用s.replace('0',+'+')|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4672622|仅仅出于训练的目的，您也可以使用尾递归来实现这一点。|4672623|def+replace(s:+String):+String+=+{
++def+go(chars:+List[Char],+acc:+List[Char]):+List[Char]+=+chars+match+{
++++case+Nil+=>+acc.reverse
++++case+'0'+::+xs+=>+go(xs,+'+'+::+acc)
++++case+x+::+xs+=>+go(xs,+x+::+acc)
++}

++go(s.toCharArray.toList,+Nil).mkString
}

replace("01230123")+//+"+123+123"|code-block|syntax|javascript|4672624|更普遍的是：|4672625|def+replace(s:+String,+find:+Char,+replacement:+Char):+String+=+{
++def+go(chars:+List[Char],+acc:+List[Char]):+List[Char]+=+chars+match+{
++++case+Nil+=>+acc.reverse
++++case+`find`+::+xs+=>+go(xs,+replacement+::+acc)
++++case+x+::+xs+=>+go(xs,+x+::+acc)
++}

++go(s.toCharArray.toList,+Nil).mkString
}

replace("01230123",+'0',+'+')+//+"+123+123"|4672626|entityMap^0|8|J|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|W|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|X|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|Y|8|@]|D|@]|E|$K|L]]|$1|Q|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|R|$]]

The go-to way to do it is to use <code>s.replace('0', ' ')</code>

Just for training purposes you might use tail-recursion to achieve that as well.

<pre><code>def replace(s: String): String = {
 def go(chars: List[Char], acc: List[Char]): List[Char] = chars match {
 case Nil =&gt; acc.reverse
 case '0' :: xs =&gt; go(xs, ' ' :: acc)
 case x :: xs =&gt; go(xs, x :: acc)
 }

 go(s.toCharArray.toList, Nil).mkString
}

replace("01230123") // " 123 123"
</code></pre>

and more generally:

<pre><code>def replace(s: String, find: Char, replacement: Char): String = {
 def go(chars: List[Char], acc: List[Char]): List[Char] = chars match {
 case Nil =&gt; acc.reverse
 case `find` :: xs =&gt; go(xs, replacement :: acc)
 case x :: xs =&gt; go(xs, x :: acc)
 }

 go(s.toCharArray.toList, Nil).mkString
}

replace("01230123", '0', ' ') // " 123 123"
</code></pre>

I am trying to create a method to convert characters within a String, specifically converting all '0' to ' '. This is the code that I am using:

<pre><code>def removeZeros(s: String) = {
 val charArray = s.toCharArray
 charArray.map( c =&gt; if(c == '0') ' ')
 new String(charArray)
}
</code></pre>

Is there a simpler way to do it? This syntax is not valid:

<pre><code>def removeZeros(s: String) = 
 new String(s.toCharArray.map( c =&gt; if(c == '0') ' '))
</code></pre>

Replacing characters in a String in Scala

我正在尝试创建一个方法来转换字符串中的字符，特别是将所有'0‘转换为’‘。这是我使用的代码：def removeZeros(s: String) = {    val charArray = s.toCharArray    charArray.map( c => if(c == '0') ' ')    new St...

问在Scala中替换字符串中的字符
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