计算java中的日期/时间差
计算java中的日期/时间差
提问于 2011-03-18 19:43:08
我想用小时/分钟/秒来计算两个日期之间的差值。
我的代码有一个小问题，它是：
String dateStart = "11/03/14 09:29:58";
String dateStop = "11/03/14 09:33:43";
// Custom date format
SimpleDateFormat format = new SimpleDateFormat("yy/MM/dd HH:mm:ss");
Date d1 = null;
Date d2 = null;
try {
d1 = format.parse(dateStart);
d2 = format.parse(dateStop);
} catch (ParseException e) {
e.printStackTrace();
}
// Get msec from each, and subtract.
long diff = d2.getTime() - d1.getTime();
long diffSeconds = diff / 1000;
long diffMinutes = diff / (60 * 1000);
long diffHours = diff / (60 * 60 * 1000);
System.out.println("Time in seconds: " + diffSeconds + " seconds.");
System.out.println("Time in minutes: " + diffMinutes + " minutes.");
System.out.println("Time in hours: " + diffHours + " hours."); 这应该会产生：
Time in seconds: 45 seconds.
Time in minutes: 3 minutes.
Time in hours: 0 hours.然而，我得到了这个结果：
Time in seconds: 225 seconds.
Time in minutes: 3 minutes.
Time in hours: 0 hours.有没有人看到我做错了什么？
回答 17
Stack Overflow用户
回答已采纳
发布于 2011-03-18 19:46:01
试一试
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000);注意:这里假设diff是非负的。
Stack Overflow用户
发布于 2013-11-15 18:10:56
我更喜欢使用推荐的java.util.concurrent.TimeUnit类。
long diff = d2.getTime() - d1.getTime();//as given
long seconds = TimeUnit.MILLISECONDS.toSeconds(diff);
long minutes = TimeUnit.MILLISECONDS.toMinutes(diff); Stack Overflow用户
发布于 2011-03-18 19:51:42
如果您能够使用外部库，我建议您使用Joda-Time，请注意：
Joda time是JavaSE8之前的
事实上的标准日期和时间库，现在要求用户迁移到java.time (JSR310)。
between计算示例：
Seconds.between(startDate, endDate);
Days.between(startDate, endDate);页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/5351483
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