我读了很多关于'Access-Control-Allow-Origin‘错误的文章,但我不明白我必须修复什么:(
我正在玩谷歌版主应用程序接口,但当我尝试add new serie时,我收到了:
XMLHttpRequest cannot load
https://www.googleapis.com/moderator/v1/series?key=[key]
&data%5Bdescription%5D=Share+and+rank+tips+for+eating+healthily+on+the+cheaps!
&data%5Bname%5D=Eating+Healthy+%26+Cheap
&data%5BvideoSubmissionAllowed%5D=false.
Origin [my_domain] is not allowed by Access-Control-Allow-Origin.
我尝试使用和不使用回调参数,我尝试在头部添加'Access-Control-Allow-Origin *‘。我不知道如何在这里使用$.getJSON,因为我必须添加Authorization头,并且我不知道如何在没有来自$.ajax的beforeCall的情况下完成这项工作:/
有光照亮这黑暗的大学吗?
这就是代码:
<script src="http://www.google.com/jsapi"></script>
<script type="text/javascript">
var scope = "https://www.googleapis.com/auth/moderator";
var token = '';
function create(){
if (token == '')
token = doCheck();
var myData = {
"data": {
"description": "Share and rank tips for eating healthily on the cheaps!",
"name": "Eating Healthy & Cheap",
"videoSubmissionAllowed": false
}
};
$.ajax({
url: 'https://www.googleapis.com/moderator/v1/series?key='+key,
type: 'POST',
callback: '?',
data: myData,
datatype: 'application/json',
success: function() { alert("Success"); },
error: function() { alert('Failed!'); },
beforeSend: setHeader
});
}
function setHeader(xhr) {
xhr.setRequestHeader('Authorization', token);
}
function doLogin(){
if (token == ''){
token = google.accounts.user.login(scope);
}else{
alert('already logged');
}
}
function doCheck(){
token = google.accounts.user.checkLogin(scope);
return token;
}
</script>
...
...
<div data-role="content">
<input type="button" value="Login" onclick="doLogin();">
<input type="button" value="Get data" onclick="getModerator();">
<input type="button" value="Create" onclick="create();">
</div><!-- /content -->
发布于 2012-10-10 19:24:12
我有完全相同的问题,它不是跨域的,而是相同的域。我只是将这一行添加到处理ajax请求的php文件中。
<?php header('Access-Control-Allow-Origin: *'); ?>
它就像一个护身符一样有效。多亏了海报
发布于 2012-04-13 01:30:28
是的,当jQuery发现URL属于不同的域时,它会假设该调用是跨域调用,因此这里不需要crossdomain:true
。
此外,重要的是要注意,如果您的URL属于不同的域(跨域)或者您正在使用$.ajax
,则不能使用JSONP进行同步调用。只允许异步调用。
注意:如果您在请求中指定了async:false
,则可以同步调用服务。
发布于 2020-09-07 13:57:10
在JavaScript中试用我的代码
var settings = {
"url": "https://myinboxhub.co.in/example",
"method": "GET",
"timeout": 0,
"headers": {},
};
$.ajax(settings).done(function (response) {
console.log(response);
if (response.auth) {
console.log('on success');
}
}).fail(function (jqXHR, exception) {
var msg = '';
if (jqXHR.status === '(failed)net::ERR_INTERNET_DISCONNECTED') {
msg = 'Uncaught Error.\n' + jqXHR.responseText;
}
if (jqXHR.status === 0) {
msg = 'Not connect.\n Verify Network.';
} else if (jqXHR.status == 413) {
msg = 'Image size is too large.';
} else if (jqXHR.status == 404) {
msg = 'Requested page not found. [404]';
} else if (jqXHR.status == 405) {
msg = 'Image size is too large.';
} else if (jqXHR.status == 500) {
msg = 'Internal Server Error [500].';
} else if (exception === 'parsererror') {
msg = 'Requested JSON parse failed.';
} else if (exception === 'timeout') {
msg = 'Time out error.';
} else if (exception === 'abort') {
msg = 'Ajax request aborted.';
} else {
msg = 'Uncaught Error.\n' + jqXHR.responseText;
}
console.log(msg);
});;
在PHP中
header('Content-type: application/json');
header("Access-Control-Allow-Origin: *");
header("Access-Control-Allow-Methods: GET");
header("Access-Control-Allow-Methods: GET, OPTIONS");
header("Access-Control-Allow-Headers: Content-Type, Content-Length, Accept-Encoding");
https://stackoverflow.com/questions/6114436
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