blocks|key|659334|text|var+streetaddress=+addy.substr(0,+addy.indexOf(','));+|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|659335|虽然w3schools.com不是提供有关每种方法作用的明确信息的最佳场所(mozilla+developer+network在这方面更好)，但它很适合向您介绍语法。|unstyled|offset|length|659336|entityMap|0|LINK|mutability|MUTABLE|url|http://www.w3schools.com/js/default.asp|1|https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/String^0|0|2|D|0|12|P|1|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|T|8|@]|9|@$G|U|H|V|1|W]|$G|X|H|Y|1|Z]]|A|$]]|$1|I|3|-4|5|F|7|10|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]|Q|$5|L|M|N|A|$O|R]]]]

<pre><code>var streetaddress= addy.substr(0, addy.indexOf(',')); 
</code></pre>

While it's not the best place for definitive information on what each method does (<a href="https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/String" rel="noreferrer">mozilla developer network</a> is better for that) <a href="http://www.w3schools.com/js/default.asp" rel="noreferrer">w3schools.com</a> is good for introducing you to syntax.

blocks|key|445065|text|var+streetaddress+=+addy.split(',')[0];|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|445066|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>var streetaddress = addy.split(',')[0];
</code></pre>

blocks|key|444895|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|444896|streetaddress.substring(0,+streetaddress.indexOf(','));|code-block|syntax|javascript|444897|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

try this:

<pre><code>streetaddress.substring(0, streetaddress.indexOf(','));
</code></pre>

blocks|key|445082|text|//split+string+into+an+array+and+grab+the+first+item

var+streetaddress+=+addy.split(',')[0];|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|445083|此外，我建议使用驼峰大小写(StreetAddress)来命名变量，以获得更好的可读性。|unstyled|445084|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>//split string into an array and grab the first item

var streetaddress = addy.split(',')[0];
</code></pre>

Also, I'd recommend naming your variables with camel-case(streetAddress) for better readability.

blocks|key|659361|text|如果您喜欢简短，只需使用RegExp|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|659362|var+streetAddress+=+/[%5E,]*/.exec(addy)[0];|code-block|syntax|javascript|659363|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Regular_Expressions^0|C|6|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

If you like it short simply use a <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Regular_Expressions" rel="noreferrer">RegExp</a>:

<pre><code>var streetAddress = /[^,]*/.exec(addy)[0];
</code></pre>

blocks|key|444859|text|var+streetaddress+=+addy.substr(0,+addy.indexOf('.'));+|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|444860|(您应该通读javascript+tutorial，特别是关于String+functions的部分)|unstyled|offset|length|444861|entityMap|0|LINK|mutability|MUTABLE|url|http://www.w3schools.com/js/js_obj_string.asp|1|http://www.w3schools.com/jsref/jsref_obj_string.asp^0|0|6|J|0|V|G|1|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|T|8|@]|9|@$G|U|H|V|1|W]|$G|X|H|Y|1|Z]]|A|$]]|$1|I|3|-4|5|F|7|10|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]|Q|$5|L|M|N|A|$O|R]]]]

<pre><code>var streetaddress = addy.substr(0, addy.indexOf('.')); 
</code></pre>

(You should read through a <a href="http://www.w3schools.com/js/js_obj_string.asp" rel="noreferrer">javascript tutorial</a>, esp. the part about <a href="http://www.w3schools.com/jsref/jsref_obj_string.asp" rel="noreferrer">String functions</a>)

blocks|key|444870|text|var+newString+=+string.substr(0,string.indexOf(','));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|444871|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>var newString = string.substr(0,string.indexOf(','));
</code></pre>

blocks|key|445040|text|如果您想原封不动地返回原始字符串，如果它不包含搜索字符，那么您可以使用匿名函数(闭包)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|445041|var+streetaddress=(function(s){var+i=s.indexOf(',');
+++return+i==-1+?+s+:+s.substr(0,i);})(addy);|code-block|syntax|javascript|445042|这可以变得更通用：|445043|var+streetaddress=(function(s,c){var+i=s.indexOf(c);
+++return+i==-1+?+s+:+s.substr(0,i);})(addy,',');|445044|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

If you want to return the original string untouched if it does not contain the search character then you can use an anonymous function (a closure):

<pre><code>var streetaddress=(function(s){var i=s.indexOf(',');
 return i==-1 ? s : s.substr(0,i);})(addy);
</code></pre>

This can be made more generic:

<pre><code>var streetaddress=(function(s,c){var i=s.indexOf(c);
 return i==-1 ? s : s.substr(0,i);})(addy,',');
</code></pre>

blocks|key|445142|text|您可以使用正则表达式，因为如果字符串符合要求，它将为您提供该字符串。代码应该类似于：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|445143|const+address+=+"1345+albany+street,+Bellevue+WA+42344";
const+regex+=+/[1-9][0-9]*+[a-zA-Z]%2B+[a-zA-Z]%2B/;
const+matchedResult+=+address.match(regex);

console.log(matchedResult[0]);+//+This+will+give+you+1345+albany+street.|code-block|syntax|javascript|445144|所以要分解代码。[1-9][0-9]*基本上意味着第一个数字不能是零，必须是介于1-9和0-9之间的数字，下一个数字可以是0-9中的任何数字，可以出现零次或多次，因为有时数字只有一个数字，然后它匹配一个空格。[a-zA-Z]基本上将所有大写字母与小写字母相匹配，并且必须出现一次或多次，并且这一过程会重复。|offset|length|style|CODE|445145|entityMap^0|0|0|8|B|14|3|18|3|1P|3|2W|8|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]|$I|V|J|W|K|L]|$I|X|J|Y|K|L]|$I|Z|J|10|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$]]

You could use regex as this will give you the string if it matches the requirements. The code would be something like:

<pre><code>const address = "1345 albany street, Bellevue WA 42344";
const regex = /[1-9][0-9]* [a-zA-Z]+ [a-zA-Z]+/;
const matchedResult = address.match(regex);

console.log(matchedResult[0]); // This will give you 1345 albany street.
</code></pre>

So to break the code down. <code>[1-9][0-9]*</code> basically means the first number cannot be a zero and has to be a number between <code>1-9</code> and the next number can be any number from <code>0-9</code> and can occur zero or more times as sometimes the number is just one digit and then it matches a space. <code>[a-zA-Z]</code> basically matches all capital letters to small letters and has to occur one or more times and this is repeated.

I am trying to extract everything before the ',' comma. How do I do this in JavaScript or jQuery? I tried this and not working..

<pre><code>1345 albany street, Bellevue WA 42344
</code></pre>

I just want to grab the street address.

<pre><code>var streetaddress= substr(addy, 0, index(addy, '.')); 
</code></pre>

How to grab substring before a specified character jQuery or JavaScript

jQuery

我正在尝试提取逗号之前的所有内容。如何在JavaScript或jQuery中执行此操作？我试过了，但不起作用。1345 albany street, Bellevue WA 42344我只想拿到街道地址。var streetaddress= substr(addy, 0, index(addy, '.')); 

问如何在指定字符jQuery或JavaScript前抓取子字符串
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