blocks|key|220553|text|这应该是可行的：myDict+=+dict(queryDict.iterlists())|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|220554|entityMap^0|8|10|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

This should work: <code>myDict = dict(queryDict.iterlists())</code>

blocks|key|438704|text|Django+>=+1.4中的新特性。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|438705|QueryDict.dict()|offset|length|style|CODE|438706|https://docs.djangoproject.com/en/stable/ref/request-response/#django.http.QueryDict.dict|438707|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|G|0|0|2H|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@$D|S|E|T|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|U|8|@]|9|@$D|V|E|W|1|X]]|A|$]]|$1|J|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|K|$L|$5|M|N|O|A|$P|I]]]]

New in Django >= 1.4.

<code>QueryDict.dict()</code>

<a href="https://docs.djangoproject.com/en/stable/ref/request-response/#django.http.QueryDict.dict" rel="noreferrer">https://docs.djangoproject.com/en/stable/ref/request-response/#django.http.QueryDict.dict</a>

blocks|key|438796|text|from+django.utils+import+six+
post_dict+=+dict(six.iterlists(request.POST))|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|438797|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>from django.utils import six 
post_dict = dict(six.iterlists(request.POST))
</code></pre>

blocks|key|438745|text|如果您不想将值作为数组，可以执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|438746|#+request+=+<QueryDict:+{u'key':+[u'123ABC']}>
dict(zip(request.GET.keys(),+request.GET.values()))
{u'key':+u"123ABC"+}

#+Only+work+for+single+item+lists
#+request+=+<QueryDict:+{u'key':+[u'123ABC',U+'CDEF']}>
dict(zip(request.GET.keys(),+request.GET.values()))
{u'key':+u"CDEF"+}+|code-block|syntax|javascript|438747|zip是一个强大的工具，点击这里了解更多信息http://docs.python.org/2/library/functions.html#zip|offset|length|438748|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.python.org/2/library/functions.html#zip^0|0|0|M|1F|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

If you do not want the values as Arrays you can do the following:

<pre><code># request = &lt;QueryDict: {u'key': [u'123ABC']}&gt;
dict(zip(request.GET.keys(), request.GET.values()))
{u'key': u"123ABC" }

# Only work for single item lists
# request = &lt;QueryDict: {u'key': [u'123ABC',U 'CDEF']}&gt;
dict(zip(request.GET.keys(), request.GET.values()))
{u'key': u"CDEF" } 
</code></pre>

zip is a powerful tool read more about it here <a href="http://docs.python.org/2/library/functions.html#zip" rel="noreferrer">http://docs.python.org/2/library/functions.html#zip</a>

blocks|key|438917|text|只需简单地添加|type|unstyled|depth|inlineStyleRanges|entityRanges|data|438918|queryDict=dict(request.GET)或queryDict=dict(QueryDict)|offset|length|style|CODE|438919|在您的视图中，数据将作为python+Dict保存在querDict中。|438920|entityMap^0|0|0|R|S|P|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@$D|N|E|O|F|G]|$D|P|E|Q|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|R|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|K|$]]

just simply add 

<code>queryDict=dict(request.GET)</code>
or <code>queryDict=dict(QueryDict)</code>

In your view and data will be saved in querDict as python Dict.

blocks|key|438789|text|我遇到了一个类似的问题，希望将表单中的任意值保存为序列化的值。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|438790|我的答案是避免显式地迭代字典内容：dict(querydict.iterlists())|offset|length|style|CODE|438791|为了检索与原始值类似的字典值，逆向函数使用QueryDict.setlist()填充新的QueryDict值。在这种情况下，我不认为显式迭代是可以避免的。|438792|我的helper函数如下所示：|438793|from+django.http+import+QueryDict

def+querydict_dict(querydict):
++++"""
++++Converts+a+Django+QueryDict+value+to+a+regular+dictionary,+preserving+multiple+items.
++++"""
++++return+dict(querydict.iterlists())

def+dict_querydict(dict_):
++++"""
++++Converts+a+value+created+by+querydict_dict+back+into+a+Django+QueryDict+value.
++++"""
++++q+=+QueryDict("",+mutable=True)
++++for+k,+v+in+dict_.iteritems():
++++++++q.setlist(k,+v)
++++q._mutable+=+False
++++return+q|code-block|syntax|javascript|438794|entityMap^0|0|H|R|0|L|J|18|9|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@$D|U|E|V|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|W|8|@$D|X|E|Y|F|G]|$D|Z|E|10|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|11|8|@]|9|@]|A|$]]|$1|L|3|M|5|N|7|12|8|@]|9|@]|A|$O|P]]|$1|Q|3|-4|5|6|7|13|8|@]|9|@]|A|$]]]|R|$]]

I ran into a similar problem, wanting to save arbitrary values from a form as serialized values.

My answer avoids explicitly iterating the dictionary contents: <code>dict(querydict.iterlists())</code>

In order to retrieve a dictionary-like value that functions as the original, an inverse function uses <code>QueryDict.setlist()</code> to populate a new <code>QueryDict</code> value. In this case, I don't think the explicit iteration is avoidable.

My helper functions look like this:

<pre><code>from django.http import QueryDict

def querydict_dict(querydict):
 """
 Converts a Django QueryDict value to a regular dictionary, preserving multiple items.
 """
 return dict(querydict.iterlists())

def dict_querydict(dict_):
 """
 Converts a value created by querydict_dict back into a Django QueryDict value.
 """
 q = QueryDict("", mutable=True)
 for k, v in dict_.iteritems():
 q.setlist(k, v)
 q._mutable = False
 return q
</code></pre>

blocks|key|438823|text|dict(request.POST)返回一个带有数组包装值的奇怪的python字典。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|438824|{'start':+['2017-01-14T21:00'],+'stop':+['2017-01-14T22:00'],+'email':+['sandeep@sakethtech.com']}|code-block|syntax|javascript|438825|其中as+{x:request.POST.get(x)+for+x+in+request.POST.keys()}返回预期的输出。|438826|{'start':+'2017-01-14T21:00',+'stop':+'2017-01-14T22:00',+'email':+'sandeep@sakethtech.com'}|438827|entityMap^0|0|I|0|0|5|1G|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|P|$]]

<code>dict(request.POST)</code> returns a weird python dictionary with array wrapped values.

<pre><code>{'start': ['2017-01-14T21:00'], 'stop': ['2017-01-14T22:00'], 'email': ['sandeep@sakethtech.com']}
</code></pre>

where as <code>{x:request.POST.get(x) for x in request.POST.keys()}</code> returns expected output.

<pre><code>{'start': '2017-01-14T21:00', 'stop': '2017-01-14T22:00', 'email': 'sandeep@sakethtech.com'}
</code></pre>

blocks|key|438840|text|这就是我解决这个问题的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|438841|dict_+=+{k:+q.getlist(k)+if+len(q.getlist(k))>1+else+v+for+k,+v+in+q.items()}|code-block|syntax|javascript|438842|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is how I solved that problem:

<pre><code>dict_ = {k: q.getlist(k) if len(q.getlist(k))&gt;1 else v for k, v in q.items()}
</code></pre>

blocks|key|438884|text|和我一样，您可能更熟悉python中的Dict()方法。但是，QueryDict()也是一个易于使用的对象。例如，您可能想要从request.GET+QueryDict()中获取值。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|438885|你可以这样做：request.GET.__getitem__(<key>)。|438886|QueryDict()文档：https://docs.djangoproject.com/en/2.0/ref/request-response/#django.http.QueryDict|438887|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.djangoproject.com/en/2.0/ref/request-response/#django.http.QueryDict^0|J|6|V|B|1R|N|0|7|U|0|0|B|E|29|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]|$9|U|A|V|B|C]|$9|W|A|X|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|11|8|@$9|12|A|13|B|C]]|D|@$9|14|A|15|1|16]]|E|$]]|$1|J|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|K|$L|$5|M|N|O|E|$P|Q]]]]

Like me, you probably are more familiar with <code>Dict()</code> methods in python. However, the <code>QueryDict()</code> is also an easy object to use. For example, perhaps you wanted to get the value from the <code>request.GET QueryDict()</code>.

You can do this like so: <code>request.GET.__getitem__(&lt;key&gt;)</code>.

<code>QueryDict()</code> documentation: <a href="https://docs.djangoproject.com/en/2.0/ref/request-response/#django.http.QueryDict" rel="nofollow noreferrer">https://docs.djangoproject.com/en/2.0/ref/request-response/#django.http.QueryDict</a>

blocks|key|438929|text|我尝试了dict(request.POST)和request.POST.dict()，并意识到如果list值(例如'var1':['value1',+'value2']+)嵌套在您的request.POST中，则后者(request.POST.dict())只允许我访问嵌套列表中的最后一项，而前者(dict(request.POST))允许我访问嵌套列表中的所有项。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|438930|我希望这对某些人有帮助。|438931|entityMap^0|4|I|N|J|1D|4|1L|R|2J|C|31|J|46|I|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]|$9|Q|A|R|B|C]|$9|S|A|T|B|C]|$9|U|A|V|B|C]|$9|W|A|X|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Y|8|@]|D|@]|E|$]]|$1|H|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|I|$]]

I tried out both <code>dict(request.POST)</code> and <code>request.POST.dict()</code> and realised that if you have <code>list</code> values for example <code>'var1':['value1', 'value2']</code> nested in your <code>request.POST</code>, the later(<code>request.POST.dict()</code>) only gave me access to the last item in a nested list while the former(<code>dict(request.POST)</code>) allowed me to access all items in a nested list.

I hope this helps someone.

blocks|key|438952|text|你可以使用一个简单的技巧|type|unstyled|depth|inlineStyleRanges|entityRanges|data|438953|queryDict._mutable+=+False
#+Change+queryDict
your_dict+=+{'num':+[0],+'var1':['value1',+'value2'],+'var2':['8']}
queryDict.upate(your_dict)
#+reset+the+state
queryDict._mutable+=+True+|code-block|syntax|javascript|438954|我认为这会更好地帮助你：This+QueryDict+instance+is+immutable|offset|length|438955|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/44717442/this-querydict-instance-is-immutable/#51196932^0|0|0|C|10|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

You can use a simple trick just
<pre><code>queryDict._mutable = False
# Change queryDict
your_dict = {'num': [0], 'var1':['value1', 'value2'], 'var2':['8']}
queryDict.upate(your_dict)
# reset the state
queryDict._mutable = True 
</code></pre>
I think this will help you better:
<a href="https://stackoverflow.com/questions/44717442/this-querydict-instance-is-immutable/#51196932">This QueryDict instance is immutable</a>

Let's pretend I have the following QueryDict: 

<pre><code>&lt;QueryDict: {u'num': [0], u'var1': [u'value1', u'value2'], u'var2': [u'8']}&gt;
</code></pre>

I'd like to have a dictionary out of this, eg:

<pre><code>{'num': [0], 'var1':['value1', 'value2'], 'var2':['8']}
</code></pre>

(I don't care if the unicode symbol <code>u</code> stays or goes.)

If I do <code>queryDict.dict()</code>, as suggested by the <a href="https://docs.djangoproject.com/en/dev/ref/request-response/#django.http.QueryDict.dict">django site</a>, I lose the extra values belonging to <code>var1</code>, eg:

<pre><code>{'num': [0], 'var1':['value2'], 'var2':['8']}
</code></pre>

I was thinking of doing this:

<pre><code>myDict = {}
for key in queryDict.iterkeys():
 myDict[key] = queryDict.getlist(key)
</code></pre>

Is there a better way?

How to change a django QueryDict to Python Dict?

Django

假设我有以下QueryDict：<QueryDict: {u'num': [0], u'var1': [u'value1', u'value2'], u'var2': [u'8']}>我想要一本字典，例如：{'num': [0], 'var1':['value1', 'value2'], 'var2':['8']}(我不关心unicode符号u的去留。)如果按照的建议执行queryDict.dic

问如何将django QueryDict更改为Python Dict？
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问如何将django QueryDict更改为Python Dict？
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