blocks|key|1106253|text|TelephonyManager+tManager+=+(TelephonyManager)myActivity.getSystemService(Context.TELEPHONY_SERVICE);
String+uid+=+tManager.getDeviceId();|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1106254|getSystemService是Activity类中的一个方法。getDeviceID()将根据电话使用的无线电(GSM或CDMA)返回设备的MDN或MEID。|unstyled|1106255|每个设备必须在这里返回一个唯一的值(假设它是一部电话)。这应该适用于任何带有sim卡或CDMA无线电的Android设备。你可以自己使用Android供电的微波炉;-)|1106256|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>TelephonyManager tManager = (TelephonyManager)myActivity.getSystemService(Context.TELEPHONY_SERVICE);
String uid = tManager.getDeviceId();
</code></pre>

getSystemService is a method from the Activity class. getDeviceID() will return the MDN or MEID of the device depending on which radio the phone uses (GSM or CDMA). 

Each device MUST return a unique value here (assuming it's a phone). This should work for any Android device with a sim slot or CDMA radio. You're on your own with that Android powered microwave ;-)

blocks|key|1106298|text|String+serial+=+null;+

try+{
++++Class<?>+c+=+Class.forName("android.os.SystemProperties");
++++Method+get+=+c.getMethod("get",+String.class);
++++serial+=+(String)+get.invoke(c,+"ro.serialno");
}+catch+(Exception+ignored)+{
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1106299|此代码使用隐藏的Android+API返回设备序列号。|unstyled|1106300|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>String serial = null; 

try {
 Class&lt;?&gt; c = Class.forName("android.os.SystemProperties");
 Method get = c.getMethod("get", String.class);
 serial = (String) get.invoke(c, "ro.serialno");
} catch (Exception ignored) {
}
</code></pre>

This code returns device serial number using a hidden Android API.

blocks|key|1321251|text|String+deviceId+=+Settings.System.getString(getContentResolver(),
++++++++++++++++++++++++++++++++Settings.System.ANDROID_ID);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1321252|然而，不能保证Android+ID将是唯一的标识符。|unstyled|1321253|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>String deviceId = Settings.System.getString(getContentResolver(),
 Settings.System.ANDROID_ID);
</code></pre>

Although, it is not guaranteed that the Android ID will be an unique identifier.

blocks|key|1106564|text|对于设备唯一且在其生命周期内为常量的简单数字(出厂重置或黑客攻击除外)，请使用Settings.Secure.ANDROID_ID。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1106565|String+id+=+Secure.getString(getContentResolver(),+Secure.ANDROID_ID);|code-block|syntax|javascript|1106566|要使用设备序列号(如“系统设置/关于/状态”中所示)并回退到Android+ID：|1106567|String+serialNumber+=+Build.SERIAL+!=+Build.UNKNOWN+?+Build.SERIAL+:+Secure.getString(getContentResolver(),+Secure.ANDROID_ID);|1106568|entityMap|0|LINK|mutability|MUTABLE|url|http://developer.android.com/reference/android/provider/Settings.Secure.html^0|13|Q|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|Z|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|10|8|@]|9|@]|C|$G|H]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]]]

For a simple number that is unique to the device and constant for its lifetime (barring a factory reset or hacking), use <a href="http://developer.android.com/reference/android/provider/Settings.Secure.html">Settings.Secure.ANDROID_ID</a>.

<pre><code>String id = Secure.getString(getContentResolver(), Secure.ANDROID_ID);
</code></pre>

To use the device serial number (the one shown in "System Settings / About / Status") if available and fall back to Android ID:

<pre><code>String serialNumber = Build.SERIAL != Build.UNKNOWN ? Build.SERIAL : Secure.getString(getContentResolver(), Secure.ANDROID_ID);
</code></pre>

blocks|key|1321405|text|IMEI很好，但只能在带手机的Android设备上使用。你应该考虑支持平板电脑或其他没有手机的Android设备。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1321406|您有一些替代方案，如:构建类成员、BT+MAC、WLAN+MAC，甚至更好-所有这些的组合。|1321407|我已经在我的博客上的一篇文章中解释了这些细节，参见：http://www.pocketmagic.net/?p=1662|offset|length|1321408|entityMap|0|LINK|mutability|MUTABLE|url|http://www.pocketmagic.net/?p=1662^0|0|0|Q|Y|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Q|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|R|8|@]|9|@$F|S|G|T|1|U]]|A|$]]|$1|H|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|I|$J|$5|K|L|M|A|$N|O]]]]

The IMEI is good but only works on Android devices with phone. You should consider support for Tablets or other Android devices as well, that do not have a phone.

You have some alternatives like: Build class members, BT MAC, WLAN MAC, or even better - a combination of all these. 

I have explained these details in an article on my blog, see: 
<a href="http://www.pocketmagic.net/?p=1662" rel="noreferrer">http://www.pocketmagic.net/?p=1662</a>

blocks|key|1321613|text|上述所有方法都存在问题。在Google+i/o上，Reto+Meier发布了一个关于如何实现这一目标的强大答案，这应该可以满足大多数开发人员在不同安装环境下跟踪用户的需求。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1321614|这种方法将为您提供一个匿名的、安全的用户ID，该ID将在不同设备(包括平板电脑，基于主要Google帐户)和同一设备上的安装之间持久存在。基本方法是生成一个随机的用户ID，并将其存储在应用程序的共享首选项中。然后使用Google的备份代理将链接到Google帐户的共享首选项存储在云中。|1321615|让我们来看看完整的方法。首先，我们需要使用安卓备份服务为我们的SharedPreferences创建一个备份。首先通过以下链接注册您的应用程序：http://developer.android.com/google/backup/signup.html|offset|length|1321616|Google会给你一个备份服务密钥，你需要将它添加到清单中。您还需要告诉应用程序使用BackupAgent，如下所示：|1321617|<application+android:label="MyApplication"
+++++++++android:backupAgent="MyBackupAgent">
++++...
++++<meta-data+android:name="com.google.android.backup.api_key"
++++++++android:value="your_backup_service_key"+/>
</application>|code-block|syntax|javascript|1321618|然后，您需要创建备份代理，并告诉它使用sharedpreferences的辅助代理：|1321619|public+class+MyBackupAgent+extends+BackupAgentHelper+{
++++//+The+name+of+the+SharedPreferences+file
++++static+final+String+PREFS+=+"user_preferences";

++++//+A+key+to+uniquely+identify+the+set+of+backup+data
++++static+final+String+PREFS_BACKUP_KEY+=+"prefs";

++++//+Allocate+a+helper+and+add+it+to+the+backup+agent
++++@Override
++++public+void+onCreate()+{
++++++++SharedPreferencesBackupHelper+helper+=+new+SharedPreferencesBackupHelper(this,++++++++++PREFS);
++++++++addHelper(PREFS_BACKUP_KEY,+helper);
++++}
}|1321620|要完成备份，您需要在主要活动中创建一个BackupManager实例：|1321621|BackupManager+backupManager+=+new+BackupManager(context);|1321622|最后，如果用户ID不存在，则创建它，并将其存储在SharedPreferences中：|1321623|++public+static+String+getUserID(Context+context)+{
++++++++++++private+static+String+uniqueID+=+null;
++++++++private+static+final+String+PREF_UNIQUE_ID+=+"PREF_UNIQUE_ID";
++++if+(uniqueID+==+null)+{
++++++++SharedPreferences+sharedPrefs+=+context.getSharedPreferences(
++++++++++++++++MyBackupAgent.PREFS,+Context.MODE_PRIVATE);
++++++++uniqueID+=+sharedPrefs.getString(PREF_UNIQUE_ID,+null);
++++++++if+(uniqueID+==+null)+{
++++++++++++uniqueID+=+UUID.randomUUID().toString();
++++++++++++Editor+editor+=+sharedPrefs.edit();
++++++++++++editor.putString(PREF_UNIQUE_ID,+uniqueID);
++++++++++++editor.commit();

++++++++++++//backup+the+changes
++++++++++++BackupManager+mBackupManager+=+new+BackupManager(context);
++++++++++++mBackupManager.dataChanged();
++++++++}
++++}

++++return+uniqueID;
}|1321624|现在，即使用户切换设备，此User_ID也将在安装过程中保持不变。|1321625|有关此方法的更多信息，请参阅Reto的talk+here+http://www.google.com/events/io/2011/sessions/android-protips-advanced-topics-for-expert-android-app-developers.html|1321626|有关如何实现备份代理的完整详细信息，请参阅开发人员网站：http://developer.android.com/guide/topics/data/backup.html我特别推荐底部关于测试的部分，因为备份不是即时发生的，因此要进行测试，您必须强制备份。|1321627|entityMap|0|LINK|mutability|MUTABLE|url|http://developer.android.com/google/backup/signup.html|1|http://www.google.com/events/io/2011/sessions/android-protips-advanced-topics-for-expert-android-app-developers.html|2|http://developer.android.com/guide/topics/data/backup.html^0|0|0|20|1I|0|0|0|0|0|0|0|0|0|0|0|T|38|1|0|S|1M|2|0^^$0|@$1|2|3|4|5|6|7|1I|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|1J|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|1K|8|@]|9|@$F|1L|G|1M|1|1N]]|A|$]]|$1|H|3|I|5|6|7|1O|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|1P|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|1Q|8|@]|9|@]|A|$]]|$1|Q|3|R|5|L|7|1R|8|@]|9|@]|A|$M|N]]|$1|S|3|T|5|6|7|1S|8|@]|9|@]|A|$]]|$1|U|3|V|5|L|7|1T|8|@]|9|@]|A|$M|N]]|$1|W|3|X|5|6|7|1U|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|L|7|1V|8|@]|9|@]|A|$M|N]]|$1|10|3|11|5|6|7|1W|8|@]|9|@]|A|$]]|$1|12|3|13|5|6|7|1X|8|@]|9|@$F|1Y|G|1Z|1|20]]|A|$]]|$1|14|3|15|5|6|7|21|8|@]|9|@$F|22|G|23|1|24]]|A|$]]|$1|16|3|-4|5|6|7|25|8|@]|9|@]|A|$]]]|17|$18|$5|19|1A|1B|A|$1C|1D]]|1E|$5|19|1A|1B|A|$1C|1F]]|1G|$5|19|1A|1B|A|$1C|1H]]]]

There are problems with all the above approaches. At Google i/o Reto Meier released a robust answer to how to approach this which should meet most developers needs to track users across installations. 

This approach will give you an anonymous, secure user ID which will be persistent for the user across different devices (including tablets, based on primary Google account) and across installs on the same device. The basic approach is to generate a random user ID and to store this in the apps shared preferences. You then use Google's backup agent to store the shared preferences linked to the Google account in the cloud.

Lets go through the full approach. First we need to create a backup for our SharedPreferences using the Android Backup Service. Start by registering your app via this link: <a href="http://developer.android.com/google/backup/signup.html" rel="nofollow">http://developer.android.com/google/backup/signup.html</a>

Google will give you a backup service key which you need to add to the manifest. You also need to tell the application to use the BackupAgent as follows:

<pre><code>&lt;application android:label="MyApplication"
 android:backupAgent="MyBackupAgent"&gt;
 ...
 &lt;meta-data android:name="com.google.android.backup.api_key"
 android:value="your_backup_service_key" /&gt;
&lt;/application&gt;
</code></pre>

Then you need to create the backup agent and tell it to use the helper agent for sharedpreferences:

<pre><code>public class MyBackupAgent extends BackupAgentHelper {
 // The name of the SharedPreferences file
 static final String PREFS = "user_preferences";

 // A key to uniquely identify the set of backup data
 static final String PREFS_BACKUP_KEY = "prefs";

 // Allocate a helper and add it to the backup agent
 @Override
 public void onCreate() {
 SharedPreferencesBackupHelper helper = new SharedPreferencesBackupHelper(this, PREFS);
 addHelper(PREFS_BACKUP_KEY, helper);
 }
}
</code></pre>

To complete the backup you need to create an instance of BackupManager in your main Activity:

<pre><code>BackupManager backupManager = new BackupManager(context);
</code></pre>

Finally create a user ID, if it doesn't already exist, and store it in the SharedPreferences:

<pre><code> public static String getUserID(Context context) {
 private static String uniqueID = null;
 private static final String PREF_UNIQUE_ID = "PREF_UNIQUE_ID";
 if (uniqueID == null) {
 SharedPreferences sharedPrefs = context.getSharedPreferences(
 MyBackupAgent.PREFS, Context.MODE_PRIVATE);
 uniqueID = sharedPrefs.getString(PREF_UNIQUE_ID, null);
 if (uniqueID == null) {
 uniqueID = UUID.randomUUID().toString();
 Editor editor = sharedPrefs.edit();
 editor.putString(PREF_UNIQUE_ID, uniqueID);
 editor.commit();

 //backup the changes
 BackupManager mBackupManager = new BackupManager(context);
 mBackupManager.dataChanged();
 }
 }

 return uniqueID;
}
</code></pre>

This User_ID will now be persistent across installations, even if the user switches devices.

For more information on this approach see Reto's talk here <a href="http://www.google.com/events/io/2011/sessions/android-protips-advanced-topics-for-expert-android-app-developers.html" rel="nofollow">http://www.google.com/events/io/2011/sessions/android-protips-advanced-topics-for-expert-android-app-developers.html</a>

And for full details of how to implement the backup agent see the developer site here: <a href="http://developer.android.com/guide/topics/data/backup.html" rel="nofollow">http://developer.android.com/guide/topics/data/backup.html</a> 
I particularly recommend the section at the bottom on testing as the backup does not happen instantaneously and so to test you have to force the backup.

blocks|key|1321527|text|正如@haserman所说：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1321528|TelephonyManager+tManager+=+(TelephonyManager)myActivity.getSystemService(Context.TELEPHONY_SERVICE);
String+uid+=+tManager.getDeviceId();|code-block|syntax|javascript|1321529|但在清单文件中包含权限是必要的：|1321530|<uses-permission+android:name="android.permission.READ_PHONE_STATE"/>|1321531|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

As @haserman says:

<pre><code>TelephonyManager tManager = (TelephonyManager)myActivity.getSystemService(Context.TELEPHONY_SERVICE);
String uid = tManager.getDeviceId();
</code></pre>

But it's necessary including the permission in the manifest file:

<pre><code>&lt;uses-permission android:name="android.permission.READ_PHONE_STATE"/&gt;
</code></pre>

blocks|key|1321722|text|Android+OS设备的唯一设备ID，以字符串表示。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1321723|String+deviceId;
++++final+TelephonyManager+mTelephony+=+(TelephonyManager)+getSystemService(Context.TELEPHONY_SERVICE);
++++++++if+(mTelephony.getDeviceId()+!=+null){
++++++++++++deviceId+=+mTelephony.getDeviceId();+
+++++++++}
++++++++else{
++++++++++++deviceId+=+Secure.getString(getApplicationContext().getContentResolver(),+++Secure.ANDROID_ID);+
+++++++++}|code-block|syntax|javascript|1321724|但我强烈推荐Google推荐的这个方法：|1321725|Identifying+App+Installations|offset|length|1321726|entityMap|0|LINK|mutability|MUTABLE|url|http://android-developers.blogspot.mx/2011/03/identifying-app-installations.html^0|0|0|0|0|T|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|X|8|@]|9|@$K|Y|L|Z|1|10]]|A|$]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

Unique device ID of Android OS Device as String.

<pre><code>String deviceId;
 final TelephonyManager mTelephony = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
 if (mTelephony.getDeviceId() != null){
 deviceId = mTelephony.getDeviceId(); 
 }
 else{
 deviceId = Secure.getString(getApplicationContext().getContentResolver(), Secure.ANDROID_ID); 
 }
</code></pre>

but I strngly recommend this method suggested by Google::

<a href="http://android-developers.blogspot.mx/2011/03/identifying-app-installations.html" rel="nofollow">Identifying App Installations</a>

blocks|key|1321823|text|Build.SERIAL是最简单的方法，尽管它并不完全可靠，因为它can+be+empty或者有时返回一个与你在设备设置中看到的值不同的值(proof+1，proof+2)。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1321824|根据设备制造商和安卓版本的不同，有几种方法可以获得这个数字，所以我决定在一个gist中编译我能找到的每一个可能的解决方案。这是它的一个简化版本：|1321825|public+static+String+getSerialNumber()+{
++++String+serialNumber;

++++try+{
++++++++Class<?>+c+=+Class.forName("android.os.SystemProperties");
++++++++Method+get+=+c.getMethod("get",+String.class);

++++++++serialNumber+=+(String)+get.invoke(c,+"gsm.sn1");
++++++++if+(serialNumber.equals(""))
++++++++++++serialNumber+=+(String)+get.invoke(c,+"ril.serialnumber");
++++++++if+(serialNumber.equals(""))
++++++++++++serialNumber+=+(String)+get.invoke(c,+"ro.serialno");
++++++++if+(serialNumber.equals(""))
++++++++++++serialNumber+=+(String)+get.invoke(c,+"sys.serialnumber");
++++++++if+(serialNumber.equals(""))
++++++++++++serialNumber+=+Build.SERIAL;

++++++++//+If+none+of+the+methods+above+worked
++++++++if+(serialNumber.equals(""))
++++++++++++serialNumber+=+null;
++++}+catch+(Exception+e)+{
++++++++e.printStackTrace();
++++++++serialNumber+=+null;
++++}

++++return+serialNumber;
}|code-block|syntax|javascript|1321826|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/16929647/1276306|1|https://stackoverflow.com/questions/33079734/android-get-serial-number|2|https://stackoverflow.com/questions/11794749/how-to-decode-android-os-build-serial|3|https://gist.github.com/flawyte/efd23dd520fc2320f94ba003b9aabfce^0|0|C|X|C|0|1Y|7|1|26|7|2|0|12|4|3|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@$9|13|A|14|1|15]|$9|16|A|17|1|18]|$9|19|A|1A|1|1B]]|E|$]]|$1|F|3|G|5|6|7|1C|8|@]|D|@$9|1D|A|1E|1|1F]]|E|$]]|$1|H|3|I|5|J|7|1G|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|1H|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]|U|$5|P|Q|R|E|$S|V]]|W|$5|P|Q|R|E|$S|X]]|Y|$5|P|Q|R|E|$S|Z]]]]

<code>Build.SERIAL</code> is the simplest way to go, although not entirely reliable as it <a href="https://stackoverflow.com/a/16929647/1276306">can be empty</a> or sometimes return a different value (<a href="https://stackoverflow.com/questions/33079734/android-get-serial-number">proof 1</a>, <a href="https://stackoverflow.com/questions/11794749/how-to-decode-android-os-build-serial">proof 2</a>) than what you can see in your device's settings.

There are several ways to get that number depending on the device's manufacturer and Android version, so I decided to compile every possible solution I could found in a single <a href="https://gist.github.com/flawyte/efd23dd520fc2320f94ba003b9aabfce" rel="nofollow noreferrer">gist</a>. Here's a simplified version of it :

<pre><code>public static String getSerialNumber() {
 String serialNumber;

 try {
 Class&lt;?&gt; c = Class.forName("android.os.SystemProperties");
 Method get = c.getMethod("get", String.class);

 serialNumber = (String) get.invoke(c, "gsm.sn1");
 if (serialNumber.equals(""))
 serialNumber = (String) get.invoke(c, "ril.serialnumber");
 if (serialNumber.equals(""))
 serialNumber = (String) get.invoke(c, "ro.serialno");
 if (serialNumber.equals(""))
 serialNumber = (String) get.invoke(c, "sys.serialnumber");
 if (serialNumber.equals(""))
 serialNumber = Build.SERIAL;

 // If none of the methods above worked
 if (serialNumber.equals(""))
 serialNumber = null;
 } catch (Exception e) {
 e.printStackTrace();
 serialNumber = null;
 }

 return serialNumber;
}
</code></pre>

blocks|key|1321760|text|我知道这个问题很老，但它可以在一行代码中完成。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1321761|String+deviceID+=+Build.SERIAL;|offset|length|style|CODE|1321762|entityMap^0|0|0|V|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

I know this question is old but it can be done in one line of code

<code>String deviceID = Build.SERIAL;</code>

blocks|key|1321839|text|从安卓10开始，应用程序必须拥有READ_PRIVILEGED_PHONE_STATE特权权限，才能访问设备的不可重置标识符，包括IMEI和序列号。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1321840|受影响的方法包括：|1321841|Build+getSerial()+TelephonyManager+getImei()+getDeviceId()+getMeid()+getSimSerialNumber()+getSubscriberId()|1321842|READ_PRIVILEGED_PHONE_STATE仅适用于平台|1321843|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|L|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|M|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

Starting in Android 10, apps must have the READ_PRIVILEGED_PHONE_STATE privileged permission in order to access the device's non-resettable identifiers, which include both IMEI and serial number.
Affected methods include the following:
Build
getSerial()
TelephonyManager
getImei()
getDeviceId()
getMeid()
getSimSerialNumber()
getSubscriberId()
READ_PRIVILEGED_PHONE_STATE is available for platform only

blocks|key|1321887|text|public+static+String+getManufacturerSerialNumber()+{
++String+serial+=+null;+
++try+{
++++++Class<?>+c+=+Class.forName("android.os.SystemProperties");
++++++Method+get+=+c.getMethod("get",+String.class,+String.class);
++++++serial+=+(String)+get.invoke(c,+"ril.serialnumber",+"unknown");
++}+catch+(Exception+ignored)+{}
++return+serial;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1321888|在API+29和API+30上工作，在三星galaxy+s7+s9+Xcover上测试。|unstyled|1321889|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>public static String getManufacturerSerialNumber() {
 String serial = null; 
 try {
 Class&lt;?&gt; c = Class.forName(&quot;android.os.SystemProperties&quot;);
 Method get = c.getMethod(&quot;get&quot;, String.class, String.class);
 serial = (String) get.invoke(c, &quot;ril.serialnumber&quot;, &quot;unknown&quot;);
 } catch (Exception ignored) {}
 return serial;
}
</code></pre>
Works on API 29 and 30, tested on Samsung galaxy s7 s9 Xcover

blocks|key|1321481|text|我发现上面@emmby发布的example类是一个很好的起点。但它也有一些缺陷，正如其他帖子所提到的那样。主要的一点是，它不必要地将UUID持久化到XML文件中，然后总是从该文件中检索它。这使得这个类很容易被黑客攻击:拥有根电话的任何人都可以编辑XML文件，为自己提供一个新的UUID。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1321482|我已经更新了代码，以便只有在绝对必要的情况下(即使用随机生成的UUID时)才会持久化到XML，并按照@Brill+Pappin的回答重构逻辑：|1321483|import+android.content.Context;
import+android.content.SharedPreferences;
import+android.provider.Settings.Secure;
import+android.telephony.TelephonyManager;

import+java.io.UnsupportedEncodingException;
import+java.util.UUID;

public+class+DeviceUuidFactory+{
++++protected+static+final+String+PREFS_FILE+=+"device_id.xml";
++++protected+static+final+String+PREFS_DEVICE_ID+=+"device_id";

++++protected+static+UUID+uuid;

++++public+DeviceUuidFactory(Context+context)+{

++++++++if(+uuid+==null+)+{
++++++++++++synchronized+(DeviceUuidFactory.class)+{
++++++++++++++++if(+uuid+==+null)+{
++++++++++++++++++++final+SharedPreferences+prefs+=+context.getSharedPreferences(+PREFS_FILE,+0);
++++++++++++++++++++final+String+id+=+prefs.getString(PREFS_DEVICE_ID,+null+);

++++++++++++++++++++if+(id+!=+null)+{
++++++++++++++++++++++++//+Use+the+ids+previously+computed+and+stored+in+the+prefs+file
++++++++++++++++++++++++uuid+=+UUID.fromString(id);

++++++++++++++++++++}+else+{

++++++++++++++++++++++++final+String+androidId+=+Secure.getString(context.getContentResolver(),+Secure.ANDROID_ID);

++++++++++++++++++++++++//+Use+the+Android+ID+unless+it's+broken,+in+which+case+fallback+on+deviceId,
++++++++++++++++++++++++//+unless+it's+not+available,+then+fallback+on+a+random+number+which+we+store
++++++++++++++++++++++++//+to+a+prefs+file
++++++++++++++++++++++++try+{
+++++++++++++++++++++++++++++if+(+"9774d56d682e549c".equals(androidId)+%7C%7C+(androidId+==+null)+)+{
++++++++++++++++++++++++++++++++final+String+deviceId+=+((TelephonyManager)+context.getSystemService(+Context.TELEPHONY_SERVICE+)).getDeviceId();

++++++++++++++++++++++++++++++++if+(deviceId+!=+null)
++++++++++++++++++++++++++++++++{
++++++++++++++++++++++++++++++++++++uuid+=+UUID.nameUUIDFromBytes(deviceId.getBytes("utf8"));
++++++++++++++++++++++++++++++++}
++++++++++++++++++++++++++++++++else
++++++++++++++++++++++++++++++++{
++++++++++++++++++++++++++++++++++++uuid+=+UUID.randomUUID();

++++++++++++++++++++++++++++++++++++//+Write+the+value+out+to+the+prefs+file+so+it+persists
++++++++++++++++++++++++++++++++++++prefs.edit().putString(PREFS_DEVICE_ID,+uuid.toString()+).commit();
++++++++++++++++++++++++++++++++}
++++++++++++++++++++++++++++}
++++++++++++++++++++++++++++else
++++++++++++++++++++++++++++{
++++++++++++++++++++++++++++++++uuid+=+UUID.nameUUIDFromBytes(androidId.getBytes("utf8"));
++++++++++++++++++++++++++++}+
++++++++++++++++++++++++}+catch+(UnsupportedEncodingException+e)+{
++++++++++++++++++++++++++++throw+new+RuntimeException(e);
++++++++++++++++++++++++}



++++++++++++++++++++}

++++++++++++++++}
++++++++++++}
++++++++}

++++}


++++/**
+++++*+Returns+a+unique+UUID+for+the+current+android+device.++As+with+all+UUIDs,+this+unique+ID+is+"very+highly+likely"
+++++*+to+be+unique+across+all+Android+devices.++Much+more+so+than+ANDROID_ID+is.
+++++*
+++++*+The+UUID+is+generated+by+using+ANDROID_ID+as+the+base+key+if+appropriate,+falling+back+on
+++++*+TelephonyManager.getDeviceID()+if+ANDROID_ID+is+known+to+be+incorrect,+and+finally+falling+back
+++++*+on+a+random+UUID+that's+persisted+to+SharedPreferences+if+getDeviceID()+does+not+return+a
+++++*+usable+value.
+++++*
+++++*+In+some+rare+circumstances,+this+ID+may+change.++In+particular,+if+the+device+is+factory+reset+a+new+device+ID
+++++*+may+be+generated.++In+addition,+if+a+user+upgrades+their+phone+from+certain+buggy+implementations+of+Android+2.2
+++++*+to+a+newer,+non-buggy+version+of+Android,+the+device+ID+may+change.++Or,+if+a+user+uninstalls+your+app+on
+++++*+a+device+that+has+neither+a+proper+Android+ID+nor+a+Device+ID,+this+ID+may+change+on+reinstallation.
+++++*
+++++*+Note+that+if+the+code+falls+back+on+using+TelephonyManager.getDeviceId(),+the+resulting+ID+will+NOT
+++++*+change+after+a+factory+reset.++Something+to+be+aware+of.
+++++*
+++++*+Works+around+a+bug+in+Android+2.2+for+many+devices+when+using+ANDROID_ID+directly.
+++++*
+++++*+@see+http://code.google.com/p/android/issues/detail?id=10603
+++++*
+++++*+@return+a+UUID+that+may+be+used+to+uniquely+identify+your+device+for+most+purposes.
+++++*/
++++public+UUID+getDeviceUuid()+{
++++++++return+uuid;
++++}|code-block|syntax|javascript|1321484|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I found the example class posted by @emmby above to be a great starting point. But it has a couple of flaws, as mentioned by other posters. The major one is that it persists the UUID to an XML file unnecessarily and thereafter always retrieves it from this file. This lays the class open to an easy hack: anyone with a rooted phone can edit the XML file to give themselves a new UUID.

I've updated the code so that it only persists to XML if absolutely necessary (i.e. when using a randomly generated UUID) and re-factored the logic as per @Brill Pappin's answer:

<pre><code>import android.content.Context;
import android.content.SharedPreferences;
import android.provider.Settings.Secure;
import android.telephony.TelephonyManager;

import java.io.UnsupportedEncodingException;
import java.util.UUID;

public class DeviceUuidFactory {
 protected static final String PREFS_FILE = "device_id.xml";
 protected static final String PREFS_DEVICE_ID = "device_id";

 protected static UUID uuid;

 public DeviceUuidFactory(Context context) {

 if( uuid ==null ) {
 synchronized (DeviceUuidFactory.class) {
 if( uuid == null) {
 final SharedPreferences prefs = context.getSharedPreferences( PREFS_FILE, 0);
 final String id = prefs.getString(PREFS_DEVICE_ID, null );

 if (id != null) {
 // Use the ids previously computed and stored in the prefs file
 uuid = UUID.fromString(id);

 } else {

 final String androidId = Secure.getString(context.getContentResolver(), Secure.ANDROID_ID);

 // Use the Android ID unless it's broken, in which case fallback on deviceId,
 // unless it's not available, then fallback on a random number which we store
 // to a prefs file
 try {
 if ( "9774d56d682e549c".equals(androidId) || (androidId == null) ) {
 final String deviceId = ((TelephonyManager) context.getSystemService( Context.TELEPHONY_SERVICE )).getDeviceId();

 if (deviceId != null)
 {
 uuid = UUID.nameUUIDFromBytes(deviceId.getBytes("utf8"));
 }
 else
 {
 uuid = UUID.randomUUID();

 // Write the value out to the prefs file so it persists
 prefs.edit().putString(PREFS_DEVICE_ID, uuid.toString() ).commit();
 }
 }
 else
 {
 uuid = UUID.nameUUIDFromBytes(androidId.getBytes("utf8"));
 } 
 } catch (UnsupportedEncodingException e) {
 throw new RuntimeException(e);
 }



 }

 }
 }
 }

 }


 /**
 * Returns a unique UUID for the current android device. As with all UUIDs, this unique ID is "very highly likely"
 * to be unique across all Android devices. Much more so than ANDROID_ID is.
 *
 * The UUID is generated by using ANDROID_ID as the base key if appropriate, falling back on
 * TelephonyManager.getDeviceID() if ANDROID_ID is known to be incorrect, and finally falling back
 * on a random UUID that's persisted to SharedPreferences if getDeviceID() does not return a
 * usable value.
 *
 * In some rare circumstances, this ID may change. In particular, if the device is factory reset a new device ID
 * may be generated. In addition, if a user upgrades their phone from certain buggy implementations of Android 2.2
 * to a newer, non-buggy version of Android, the device ID may change. Or, if a user uninstalls your app on
 * a device that has neither a proper Android ID nor a Device ID, this ID may change on reinstallation.
 *
 * Note that if the code falls back on using TelephonyManager.getDeviceId(), the resulting ID will NOT
 * change after a factory reset. Something to be aware of.
 *
 * Works around a bug in Android 2.2 for many devices when using ANDROID_ID directly.
 *
 * @see http://code.google.com/p/android/issues/detail?id=10603
 *
 * @return a UUID that may be used to uniquely identify your device for most purposes.
 */
 public UUID getDeviceUuid() {
 return uuid;
 }
</code></pre>

I need to use a unique ID for an Android app and I thought the serial number for the device would be a good candidate. How do I retrieve the serial number of an Android device in my app ?

How to find serial number of Android device?

Android

我需要为Android应用程序使用唯一的ID，我认为设备的序列号将是一个很好的候选者。如何在我的应用中检索Android设备的序列号？

问如何查找Android设备的序列号？
EN

回答 13

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问如何查找Android设备的序列号？EN

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问如何查找Android设备的序列号？
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