blocks|key|1217358|text|如果你想要去掉的引用总是像你说的那样是“第一次和最后一次”，那么你可以简单地使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1217359|string+=+string[1:-1]|offset|length|style|CODE|1217360|entityMap^0|0|0|L|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

If the quotes you want to strip are always going to be "first and last" as you said, then you could simply use:

<code>string = string[1:-1]</code>

blocks|key|1217533|text|要删除第一个和最后一个字符，并且在每种情况下，仅当有问题的字符是双引号时才执行删除：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1217534|import+re

s+=+re.sub(r'%5E"%7C"$',+'',+s)|code-block|syntax|javascript|1217535|请注意，RE模式与您给出的模式不同，并且操作是用一个空的替换字符串替换(“sub”)+(strip是一个字符串方法，但做的事情与您的需求完全不同，正如其他答案所指出的那样)。|offset|length|style|CODE|1217536|entityMap^0|0|0|11|3|18|5|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|N|$]]

To remove the first and last characters, and in each case do the removal only if the character in question is a double quote:

<pre><code>import re

s = re.sub(r'^"|"$', '', s)
</code></pre>

Note that the RE pattern is different than the one you had given, and the operation is <code>sub</code> ("substitute") with an empty replacement string (<code>strip</code> is a string method but does something pretty different from your requirements, as other answers have indicated).

blocks|key|1217381|text|如果字符串始终如您所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1217382|string[1:-1]|code-block|syntax|javascript|1217383|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If string is always as you show:

<pre><code>string[1:-1]
</code></pre>

blocks|key|1217452|text|如果您确定在开头和结尾有一个“，您想要删除它，只需执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1217453|string+=+string[1:len(string)-1]|code-block|syntax|javascript|1217454|或|1217455|string+=+string[1:-1]|1217456|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

If you are sure there is a " at the beginning and at the end, which you want to remove, just do:

<pre><code>string = string[1:len(string)-1]
</code></pre>

or 

<pre><code>string = string[1:-1]
</code></pre>

blocks|key|1003448|text|从字符串的start和end中删除确定的字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1003449|s+=+'""Hello+World""'
s.strip('""')

>+'Hello+World'|code-block|syntax|javascript|1003450|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Remove a determinated string from start and end from a string.

<pre><code>s = '""Hello World""'
s.strip('""')

&gt; 'Hello World'
</code></pre>

blocks|key|1003480|text|从Python+3.9开始，您可以使用removeprefix和removesuffix|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1003481|'""+"+"+""\\1"+"+""+""'.removeprefix('"').removesuffix('"')
#+'"+"+"+""\\1"+"+""+"'|code-block|syntax|javascript|1003482|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3.9/library/stdtypes.html?highlight=removeprefix#str.removeprefix|1|https://docs.python.org/3.9/library/stdtypes.html?highlight=removeprefix#str.removesuffix^0|1|A|J|C|W|C|J|C|0|W|C|1|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@$9|11|A|12|1|13]|$9|14|A|15|1|16]]|E|$]]|$1|F|3|G|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]|S|$5|N|O|P|E|$Q|T]]]]

Starting in <code>Python 3.9</code>, you can use <a href="https://docs.python.org/3.9/library/stdtypes.html?highlight=removeprefix#str.removeprefix" rel="nofollow noreferrer"><code>removeprefix</code></a> and <a href="https://docs.python.org/3.9/library/stdtypes.html?highlight=removeprefix#str.removesuffix" rel="nofollow noreferrer"><code>removesuffix</code></a>:

<pre><code>'"" " " ""\\1" " "" ""'.removeprefix('"').removesuffix('"')
# '" " " ""\\1" " "" "'
</code></pre>

blocks|key|1217649|text|我有一些代码需要去掉单引号或双引号，我不能简单地ast.literal_eval它。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1217650|if+len(arg)+>+1+and+arg[0]+in+('"\'')+and+arg[-1]+==+arg[0]:
++++arg+=+arg[1:-1]|code-block|syntax|javascript|1217651|这与ToolmakerSteve的答案类似，但它允许0长度的字符串，并且不会将单个字符的"转换为空字符串。|offset|length|style|CODE|1217652|entityMap^0|0|0|18|1|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

I have some code that needs to strip single or double quotes, and I can't simply ast.literal_eval it.

<pre class="lang-py prettyprint-override"><code>if len(arg) &gt; 1 and arg[0] in ('"\'') and arg[-1] == arg[0]:
 arg = arg[1:-1]
</code></pre>

This is similar to ToolmakerSteve's answer, but it allows 0 length strings, and doesn't turn the single character <code>"</code> into an empty string.

blocks|key|1217692|text|在您的示例中，您可以使用strip，但您必须提供空间|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1217693|string+=+'""+"+"+""\\1"+"+""+""'
string.strip('"+')++#+output+'\\1'|code-block|syntax|javascript|1217694|请注意，输出中的\‘是字符串输出的标准python引号|1217695|变量的值为'\1‘|1217696|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

in your example you could use strip but you have to provide the space

<pre><code>string = '"" " " ""\\1" " "" ""'
string.strip('" ') # output '\\1'
</code></pre>

note the \' in the output is the standard python quotes for string output

the value of your variable is '\\1'

blocks|key|1217757|text|下面的函数将去掉空的空格并返回不带引号的字符串。如果没有引号，它将返回相同的字符串(已剥离)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1217758|def+removeQuote(str):
str+=+str.strip()
if+re.search("%5E[\'\"].*[\'\"]$",str):
++++str+=+str[1:-1]
++++print("Removed+Quotes",str)
else:
++++print("Same+String",str)
return+str|code-block|syntax|javascript|1217759|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Below function will strip the empty spces and return the strings without quotes. If there are no quotes then it will return same string(stripped)

<pre><code>def removeQuote(str):
str = str.strip()
if re.search("^[\'\"].*[\'\"]$",str):
 str = str[1:-1]
 print("Removed Quotes",str)
else:
 print("Same String",str)
return str
</code></pre>

blocks|key|1003247|text|查找字符串中第一个和最后一个“的位置|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1003248|>>>+s+=+'""+"+"+""\\1"+"+""+""'
>>>+l+=+s.find('"')
>>>+r+=+s.rfind('"')

>>>+s[l%2B1:r]
'"+"+"+""\\1"+"+""+"'|code-block|syntax|javascript|1003249|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

find the position of the first and the last " in your string

<pre><code>&gt;&gt;&gt; s = '"" " " ""\\1" " "" ""'
&gt;&gt;&gt; l = s.find('"')
&gt;&gt;&gt; r = s.rfind('"')

&gt;&gt;&gt; s[l+1:r]
'" " " ""\\1" " "" "'
</code></pre>

I want to strip double quotes from:

<pre><code>string = '"" " " ""\\1" " "" ""'
</code></pre>

to obtain:

<pre><code>string = '" " " ""\\1" " "" "'
</code></pre>

I tried to use <code>rstrip</code>, <code>lstrip</code> and <code>strip('[^\"]|[\"$]')</code> but it did not work.

How can I do this?

How can I strip first and last double quotes?

Python

我想去掉下面的双引号：string = '"" " " ""\\1" " "" ""'要获得以下信息：string = '" " " ""\\1" " "" "'我尝试使用rstrip、lstrip和strip('[^\"]|[\"$]')，但都不起作用。我该怎么做呢？

问如何去掉首尾双引号？
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问如何去掉首尾双引号？EN

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问如何去掉首尾双引号？
EN