blocks|key|1238727|text|我认为您可以尝试使用awk|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1238728|awk+-v+OFS="\t"+'$1=$1'+file1|code-block|syntax|javascript|1238729|如果您愿意，也可以选择SED|1238730|sed+'s/[:blank:]%2B/,/g'+thefile.txt+>+the_modified_copy.txt|1238731|或者甚至是树|1238732|tr+-s+'\t'+<+thefile.txt+%7C+tr+'\t'+'+'+>+the_modified_copy.txt|1238733|或者是Sam+Bisbee建议的tr解决方案的简化版本|1238734|tr+'+'+\\t+<+someFile+>+someFile|1238735|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|Y|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

I think you can try with awk

<pre><code>awk -v OFS="\t" '$1=$1' file1
</code></pre>

or SED if you preffer

<pre><code>sed 's/[:blank:]+/,/g' thefile.txt &gt; the_modified_copy.txt
</code></pre>

or even tr

<pre><code>tr -s '\t' &lt; thefile.txt | tr '\t' ' ' &gt; the_modified_copy.txt
</code></pre>

or a simplified version of the tr solution sugested by Sam Bisbee 

<pre><code>tr ' ' \\t &lt; someFile &gt; someFile
</code></pre>

blocks|key|1238922|text|下载并运行以下脚本，以递归方式将软制表符转换为纯文本文件中的硬制表符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1238923|从包含纯文本文件的文件夹中放置并执行脚本。|1238924|#!/bin/bash

find+.+-type+f+-and+-not+-path+'./.git/*'+-exec+grep+-Iq+.+{}+\;+-and+-print+%7C+while+read+-r+file;+do+{
++++echo+"Converting...+"$file"";
++++data=$(unexpand+--first-only+-t+4+"$file");
++++rm+"$file";
++++echo+"$data"+>+"$file";
};+done;|code-block|syntax|javascript|1238925|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Download and run the following script to recursively convert soft tabs to hard tabs in plain text files.

Place and execute the script from inside the folder which contains the plain text files.

<pre><code>#!/bin/bash

find . -type f -and -not -path './.git/*' -exec grep -Iq . {} \; -and -print | while read -r file; do {
 echo "Converting... "$file"";
 data=$(unexpand --first-only -t 4 "$file");
 rm "$file";
 echo "$data" &gt; "$file";
}; done;
</code></pre>

blocks|key|1453681|text|将当前目录下的每个.js文件转换为制表符的示例命令(仅转换前导空格)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1453682|find+.+-name+"*.js"+-exec+bash+-c+'unexpand+-t+4+--first-only+"$0"+>+/tmp/totabbuff+&&+mv+/tmp/totabbuff+"$0"'+{}+\;|code-block|syntax|javascript|1453683|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Example command for converting each .js file under the current dir to tabs (only leading spaces are converted):

<pre><code>find . -name "*.js" -exec bash -c 'unexpand -t 4 --first-only "$0" &gt; /tmp/totabbuff &amp;&amp; mv /tmp/totabbuff "$0"' {} \;
</code></pre>

blocks|key|1238778|text|您也可以使用astyle。我发现它非常有用，它也有几个选项：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1238779|Tab+and+Bracket+Options:
+++If++no++indentation++option+is+set,+the+default+option+of+4+spaces+will+be+used.+Equivalent+to+-s4+--indent=spaces=4.++If+no+brackets+option+is+set,+the
+++brackets+will+not+be+changed.

+++--indent=spaces,+--indent=spaces=#,+-s,+-s#
++++++++++Indent+using+#+spaces+per+indent.+Between+1+to+20.++Not+specifying+#+will+result+in+a+default+of+4+spaces+per+indent.

+++--indent=tab,+--indent=tab=#,+-t,+-t#
++++++++++Indent+using+tab+characters,+assuming+that+each+tab+is+#+spaces+long.++Between+1+and+20.+Not+specifying+#+will+result+in+a+default+assumption++of
++++++++++4+spaces+per+tab.`|code-block|syntax|javascript|1238780|entityMap^0|6|6|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You can also use <code>astyle</code>. I found it quite useful and it has several options too:

<pre><code>Tab and Bracket Options:
 If no indentation option is set, the default option of 4 spaces will be used. Equivalent to -s4 --indent=spaces=4. If no brackets option is set, the
 brackets will not be changed.

 --indent=spaces, --indent=spaces=#, -s, -s#
 Indent using # spaces per indent. Between 1 to 20. Not specifying # will result in a default of 4 spaces per indent.

 --indent=tab, --indent=tab=#, -t, -t#
 Indent using tab characters, assuming that each tab is # spaces long. Between 1 and 20. Not specifying # will result in a default assumption of
 4 spaces per tab.`
</code></pre>

blocks|key|1453854|text|如果您正在讨论用制表符替换一行中所有连续的空格，那么使用tr+-s+'[:blank:]'+'\t'。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1453855|[root@sysresccd+/run/archiso/img_dev]#+sfdisk+-l+-q+-o+Device,Start+/dev/sda
Device+++++++++Start
/dev/sda1+++++++2048
/dev/sda2+++++411648
/dev/sda3++++2508800
/dev/sda4+++10639360
/dev/sda5+++75307008
/dev/sda6+++96278528
/dev/sda7++115809778
[root@sysresccd+/run/archiso/img_dev]#+sfdisk+-l+-q+-o+Device,Start+/dev/sda+%7C+tr+-s+'[:blank:]'+'\t'
Device++Start
/dev/sda1+++++++2048
/dev/sda2+++++++411648
/dev/sda3+++++++2508800
/dev/sda4+++++++10639360
/dev/sda5+++++++75307008
/dev/sda6+++++++96278528
/dev/sda7+++++++115809778|code-block|syntax|javascript|1453856|如果您正在讨论替换所有空格(例如空格、制表符、换行符等)然后是tr+-s+'[:space:]'。|1453857|[root@sysresccd+/run/archiso/img_dev]#+sfdisk+-l+-q+-o+Device,Start+/dev/sda+%7C+tr+-s+'[:space:]'+'\t'
Device++Start+++/dev/sda1+++++++2048++++/dev/sda2+++++++411648++/dev/sda3+++++++2508800+/dev/sda4+++++++10639360++++++++/dev/sda5+++++++75307008++++++++/dev/sda6+++++96278528++++++++/dev/sda7+++++++115809778++|1453858|如果您正在讨论修复选项卡损坏的文件，请使用其他答案中提到的expand和unexpand。|1453859|entityMap^0|S|M|0|0|V|H|0|0|T|6|10|8|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|10|8|@$9|11|A|12|B|C]|$9|13|A|14|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|15|8|@]|D|@]|E|$]]]|R|$]]

If you are talking about replacing all consecutive spaces on a line with a tab then <code>tr -s '[:blank:]' '\t'</code>.

<pre><code>[root@sysresccd /run/archiso/img_dev]# sfdisk -l -q -o Device,Start /dev/sda
Device Start
/dev/sda1 2048
/dev/sda2 411648
/dev/sda3 2508800
/dev/sda4 10639360
/dev/sda5 75307008
/dev/sda6 96278528
/dev/sda7 115809778
[root@sysresccd /run/archiso/img_dev]# sfdisk -l -q -o Device,Start /dev/sda | tr -s '[:blank:]' '\t'
Device Start
/dev/sda1 2048
/dev/sda2 411648
/dev/sda3 2508800
/dev/sda4 10639360
/dev/sda5 75307008
/dev/sda6 96278528
/dev/sda7 115809778
</code></pre>

If you are talking about replacing all whitespace (e.g. space, tab, newline, etc.) then <code>tr -s '[:space:]'</code>.

<pre><code>[root@sysresccd /run/archiso/img_dev]# sfdisk -l -q -o Device,Start /dev/sda | tr -s '[:space:]' '\t'
Device Start /dev/sda1 2048 /dev/sda2 411648 /dev/sda3 2508800 /dev/sda4 10639360 /dev/sda5 75307008 /dev/sda6 96278528 /dev/sda7 115809778 
</code></pre>

If you are talking about fixing a tab-damaged file then use <code>expand</code> and <code>unexpand</code> as mentioned in other answers.

blocks|key|1238997|text|sed+'s/[[:blank:]]\%2B/\t/g'+original.out+>+fixed_file.out|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1238998|例如，这将减少选项卡的数量。或空格放入单个选项卡中。|unstyled|1238999|对于多个空格/制表符为一个空格的情况，您也可以这样做：|1239000|sed+'s/[[:blank:]]\%2B/+/g'+original.out+>+fixed_file.out|1239001|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$B|C]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>sed 's/[[:blank:]]\+/\t/g' original.out &gt; fixed_file.out
</code></pre>
This will for example reduce the amount of tabs.. or spaces into one single tab.
You can also do it for situations of multiple spaces/tabs into one space:
<pre><code>sed 's/[[:blank:]]\+/ /g' original.out &gt; fixed_file.out
</code></pre>

blocks|key|1238824|text|这将用一个空格替换连续的空格(而不是制表符)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1238825|tr+-s+'[:blank:]'|code-block|syntax|javascript|1238826|这将用制表符替换连续的空格。|1238827|tr+-s+'[:blank:]'+'\t'|1238828|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

This will replace consecutive spaces with one space (but not tab).

<pre><code>tr -s '[:blank:]'
</code></pre>

This will replace consecutive spaces with a tab.

<pre><code>tr -s '[:blank:]' '\t'
</code></pre>

How do I replace whitespaces with tabs in linux in a given text file?

Replace whitespaces with tabs in linux

如何在给定的文本文件中将linux中的空格替换为制表符？

问在linux中用制表符替换空格
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