blocks|key|232941|text|如果您希望修改原始数组而不是返回新数组，请使用.push()...|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|232942|array1.push.apply(array1,+array2);
array1.push.apply(array1,+array3);|code-block|syntax|javascript|232943|我使用.apply一次性推送数组2和3的各个成员。|232944|或者..。|232945|array1.push.apply(array1,+array2.concat(array3));|232946|232947|要处理大型数组，可以分批处理。|232948|for+(var+n+=+0,+to_add+=+array2.concat(array3);+n+<+to_add.length;+n%2B=300)+{
++++array1.push.apply(array1,+to_add.slice(n,+n%2B300));
}|232949|232950|如果您经常这样做，请创建一个方法或函数来处理它。|232951|var+push_apply+=+Function.apply.bind([].push);
var+slice_call+=+Function.call.bind([].slice);

Object.defineProperty(Array.prototype,+"pushArrayMembers",+{
++++value:+function()+{
++++++++for+(var+i+=+0;+i+<+arguments.length;+i%2B%2B)+{
++++++++++++var+to_add+=+arguments[i];
++++++++++++for+(var+n+=+0;+n+<+to_add.length;+n%2B=300)+{
++++++++++++++++push_apply(this,+slice_call(to_add,+n,+n%2B300));
++++++++++++}
++++++++}
++++}
});|232952|并像这样使用它：|232953|array1.pushArrayMembers(array2,+array3);|232954|​|232955|var+push_apply+=+Function.apply.bind([].push);
var+slice_call+=+Function.call.bind([].slice);

Object.defineProperty(Array.prototype,+"pushArrayMembers",+{
++++value:+function()+{
++++++++for+(var+i+=+0;+i+<+arguments.length;+i%2B%2B)+{
++++++++++++var+to_add+=+arguments[i];
++++++++++++for+(var+n+=+0;+n+<+to_add.length;+n%2B=300)+{
++++++++++++++++push_apply(this,+slice_call(to_add,+n,+n%2B300));
++++++++++++}
++++++++}
++++}
});

var+array1+=+['a','b','c'];
var+array2+=+['d','e','f'];
var+array3+=+['g','h','i'];

array1.pushArrayMembers(array2,+array3);

document.body.textContent+=+JSON.stringify(array1,+null,+4);|232956|232957|entityMap^0|N|7|0|0|3|6|G|1|I|1|0|0|0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|1B|8|@$9|1C|A|1D|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1E|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1F|8|@$9|1G|A|1H|B|C]|$9|1I|A|1J|B|C]|$9|1K|A|1L|B|C]]|D|@]|E|$]]|$1|M|3|N|5|6|7|1M|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|1N|8|@]|D|@]|E|$I|J]]|$1|Q|3|-4|5|6|7|1O|8|@]|D|@]|E|$]]|$1|R|3|S|5|6|7|1P|8|@]|D|@]|E|$]]|$1|T|3|U|5|H|7|1Q|8|@]|D|@]|E|$I|J]]|$1|V|3|-4|5|6|7|1R|8|@]|D|@]|E|$]]|$1|W|3|X|5|6|7|1S|8|@]|D|@]|E|$]]|$1|Y|3|Z|5|H|7|1T|8|@]|D|@]|E|$I|J]]|$1|10|3|11|5|6|7|1U|8|@]|D|@]|E|$]]|$1|12|3|13|5|H|7|1V|8|@]|D|@]|E|$I|J]]|$1|14|3|15|5|6|7|1W|8|@]|D|@]|E|$]]|$1|16|3|17|5|H|7|1X|8|@]|D|@]|E|$I|J]]|$1|18|3|15|5|6|7|1Y|8|@]|D|@]|E|$]]|$1|19|3|-4|5|6|7|1Z|8|@]|D|@]|E|$]]]|1A|$]]

If you want to modify the original array instead of returning a new array, use <code>.push()</code>...

<pre><code>array1.push.apply(array1, array2);
array1.push.apply(array1, array3);
</code></pre>

I used <code>.apply</code> to push the individual members of arrays <code>2</code> and <code>3</code> at once.

or...

<pre><code>array1.push.apply(array1, array2.concat(array3));
</code></pre>

<hr>

To deal with large arrays, you can do this in batches.

<pre><code>for (var n = 0, to_add = array2.concat(array3); n &lt; to_add.length; n+=300) {
 array1.push.apply(array1, to_add.slice(n, n+300));
}
</code></pre>

<hr>

If you do this a lot, create a method or function to handle it.

<pre><code>var push_apply = Function.apply.bind([].push);
var slice_call = Function.call.bind([].slice);

Object.defineProperty(Array.prototype, "pushArrayMembers", {
 value: function() {
 for (var i = 0; i &lt; arguments.length; i++) {
 var to_add = arguments[i];
 for (var n = 0; n &lt; to_add.length; n+=300) {
 push_apply(this, slice_call(to_add, n, n+300));
 }
 }
 }
});
</code></pre>

and use it like this:

<pre><code>array1.pushArrayMembers(array2, array3);
</code></pre>

<div class="snippet" data-lang="js" data-hide="true" data-console="false" data-babel="false">
<div class="snippet-code snippet-currently-hidden">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var push_apply = Function.apply.bind([].push);
var slice_call = Function.call.bind([].slice);

Object.defineProperty(Array.prototype, "pushArrayMembers", {
 value: function() {
 for (var i = 0; i &lt; arguments.length; i++) {
 var to_add = arguments[i];
 for (var n = 0; n &lt; to_add.length; n+=300) {
 push_apply(this, slice_call(to_add, n, n+300));
 }
 }
 }
});

var array1 = ['a','b','c'];
var array2 = ['d','e','f'];
var array3 = ['g','h','i'];

array1.pushArrayMembers(array2, array3);

document.body.textContent = JSON.stringify(array1, null, 4);</code></pre>
</div>
</div>

<blockquote>
This question is an exact duplicate of: 
<a href="https://stackoverflow.com/questions/1374126/how-to-append-an-array-to-an-existing-javascript-array">How to append an array to an existing JavaScript Array?</a>
</blockquote>

How do you append an array to another array in JavaScript?
Other ways that a person might word this question:
<ul>
<li>Add an array to another</li>
<li>Concat / Concatenate arrays</li>
<li>Extend an array with another array</li>
<li>Put the contents of one array into another array</li>
</ul>
I spent some time looking for the answer to this question. Sometimes the simplest ones like these are the hardest to find answers to, so I am adding the question here hopefully with plenty of key words and phrases as per this <a href="https://blog.stackoverflow.com/2011/07/its-ok-to-ask-and-answer-your-own-questions/">blog post</a>. Please feel free to answer this question with any other helpful information or edit the key words and phrases below.

Append an array to another array in JavaScript

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 此问题与：完全相同在JavaScript中如何将一个数组追加到另一个数组中？人们可能会用其他方式表达这个问题：将一个数组添加到另一个串联/串联数组使用另一个数组扩展数组将一个数组的内容放入另一个数组我花了一些时间寻找这个问题的答案。有时候，像这样最简单的问题是最难找到答案的，所以我希望在这里添加这个问题，并根据这篇提...

问将一个数组追加到JavaScript中的另一个数组
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