可能重复:
Determine device (iPhone, iPod Touch) with iOS
我正在制作一款利用iPhone (可能还有第二代iPod touch )的点对点蓝牙功能的游戏。然而,为了阻止用户尝试在第一代iPod和iPhone 2G上玩多人游戏,我需要检查特定的设备型号。
[UIDevice currentDevice型号]只会告诉我设备是"iPhone“还是"iPod touch”。有没有办法检查具体的设备型号,比如:"iPhone 3GS","iPod touch for“之类的。
编辑:
UIDevice有一个类别(我认为它是由Erica Sadun创建的,我不认为是它的功劳),它使用以下代码来获取特定的设备型号。你可以在这里找到整个类别以及其他有用的东西:https://github.com/erica/uidevice-extension
#include <sys/types.h>
#include <sys/sysctl.h>
@implementation UIDevice (Hardware)
/*
Platforms
iPhone1,1 -> iPhone 1G
iPhone1,2 -> iPhone 3G
iPod1,1 -> iPod touch 1G
iPod2,1 -> iPod touch 2G
*/
- (NSString *) platform
{
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *machine = malloc(size);
sysctlbyname("hw.machine", machine, &size, NULL, 0);
NSString *platform = [NSString stringWithCString:machine encoding:NSUTF8StringEncoding];
free(machine);
return platform;
}
这是可行的,使用它的应用程序最近已经在AppStore中获得批准。
发布于 2010-07-30 01:32:35
最完整的UIDevice (硬件)类别可能是http://github.com/erica/uidevice-extension/ (由Erica Sadun编写):
[[UIDevice currentDevice] platformType] // ex: UIDevice4GiPhone
[[UIDevice currentDevice] platformString] // ex: @"iPhone 4G"
发布于 2011-12-13 01:59:08
这段代码如何,如果发布了新版本,您将使用最新的设备进行标识
#include <sys/types.h>
#include <sys/sysctl.h>
- (NSString *)getModel {
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *model = malloc(size);
sysctlbyname("hw.machine", model, &size, NULL, 0);
NSString *sDeviceModel = [NSString stringWithCString:model encoding:NSUTF8StringEncoding];
free(model);
if ([sDeviceModel isEqual:@"i386"]) return @"Simulator"; //iPhone Simulator
if ([sDeviceModel isEqual:@"iPhone1,1"]) return @"iPhone1G"; //iPhone 1G
if ([sDeviceModel isEqual:@"iPhone1,2"]) return @"iPhone3G"; //iPhone 3G
if ([sDeviceModel isEqual:@"iPhone2,1"]) return @"iPhone3GS"; //iPhone 3GS
if ([sDeviceModel isEqual:@"iPhone3,1"]) return @"iPhone4 AT&T"; //iPhone 4 - AT&T
if ([sDeviceModel isEqual:@"iPhone3,2"]) return @"iPhone4 Other"; //iPhone 4 - Other carrier
if ([sDeviceModel isEqual:@"iPhone3,3"]) return @"iPhone4"; //iPhone 4 - Other carrier
if ([sDeviceModel isEqual:@"iPhone4,1"]) return @"iPhone4S"; //iPhone 4S
if ([sDeviceModel isEqual:@"iPhone5,1"]) return @"iPhone5"; //iPhone 5 (GSM)
if ([sDeviceModel isEqual:@"iPod1,1"]) return @"iPod1stGen"; //iPod Touch 1G
if ([sDeviceModel isEqual:@"iPod2,1"]) return @"iPod2ndGen"; //iPod Touch 2G
if ([sDeviceModel isEqual:@"iPod3,1"]) return @"iPod3rdGen"; //iPod Touch 3G
if ([sDeviceModel isEqual:@"iPod4,1"]) return @"iPod4thGen"; //iPod Touch 4G
if ([sDeviceModel isEqual:@"iPad1,1"]) return @"iPadWiFi"; //iPad Wifi
if ([sDeviceModel isEqual:@"iPad1,2"]) return @"iPad3G"; //iPad 3G
if ([sDeviceModel isEqual:@"iPad2,1"]) return @"iPad2"; //iPad 2 (WiFi)
if ([sDeviceModel isEqual:@"iPad2,2"]) return @"iPad2"; //iPad 2 (GSM)
if ([sDeviceModel isEqual:@"iPad2,3"]) return @"iPad2"; //iPad 2 (CDMA)
NSString *aux = [[sDeviceModel componentsSeparatedByString:@","] objectAtIndex:0];
//If a newer version exist
if ([aux rangeOfString:@"iPhone"].location!=NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPhone" withString:@""] intValue];
if (version == 3) return @"iPhone4"
if (version >= 4) return @"iPhone4s";
}
if ([aux rangeOfString:@"iPod"].location!=NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPod" withString:@""] intValue];
if (version >=4) return @"iPod4thGen";
}
if ([aux rangeOfString:@"iPad"].location!=NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPad" withString:@""] intValue];
if (version ==1) return @"iPad3G";
if (version >=2) return @"iPad2";
}
//If none was found, send the original string
return sDeviceModel;
}
发布于 2010-12-04 21:01:10
BOOL hasHighResScreen = NO;
if ([UIScreen instancesRespondToSelector:@selector(scale)]) {
CGFloat scale = [[UIScreen mainScreen] scale];
if (scale > 1.0) {
hasHighResScreen = YES;
}
}
https://stackoverflow.com/questions/1108859
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