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社区首页 >问答首页 >检测特定的iPhone/iPod touch型号

检测特定的iPhone/iPod touch型号
EN

Stack Overflow用户
提问于 2009-07-10 10:40:36
回答 5查看 86.2K关注 0票数 107

可能重复:

Determine device (iPhone, iPod Touch) with iOS

我正在制作一款利用iPhone (可能还有第二代iPod touch )的点对点蓝牙功能的游戏。然而,为了阻止用户尝试在第一代iPod和iPhone 2G上玩多人游戏,我需要检查特定的设备型号。

[UIDevice currentDevice型号]只会告诉我设备是"iPhone“还是"iPod touch”。有没有办法检查具体的设备型号,比如:"iPhone 3GS","iPod touch for“之类的。

编辑:

UIDevice有一个类别(我认为它是由Erica Sadun创建的,我不认为是它的功劳),它使用以下代码来获取特定的设备型号。你可以在这里找到整个类别以及其他有用的东西:https://github.com/erica/uidevice-extension

代码语言:javascript
复制
#include <sys/types.h>
#include <sys/sysctl.h>

@implementation UIDevice (Hardware)

/*
 Platforms
 iPhone1,1 -> iPhone 1G
 iPhone1,2 -> iPhone 3G 
 iPod1,1   -> iPod touch 1G 
 iPod2,1   -> iPod touch 2G 
*/

- (NSString *) platform
{
  size_t size;
  sysctlbyname("hw.machine", NULL, &size, NULL, 0);
  char *machine = malloc(size);
    sysctlbyname("hw.machine", machine, &size, NULL, 0);
    NSString *platform = [NSString stringWithCString:machine encoding:NSUTF8StringEncoding];
  free(machine);
  return platform;
}

这是可行的,使用它的应用程序最近已经在AppStore中获得批准。

EN

回答 5

Stack Overflow用户

回答已采纳

发布于 2010-07-30 01:32:35

最完整的UIDevice (硬件)类别可能是http://github.com/erica/uidevice-extension/ (由Erica Sadun编写):

代码语言:javascript
复制
[[UIDevice currentDevice] platformType]   // ex: UIDevice4GiPhone
[[UIDevice currentDevice] platformString] // ex: @"iPhone 4G"
票数 66
EN

Stack Overflow用户

发布于 2011-12-13 01:59:08

这段代码如何,如果发布了新版本,您将使用最新的设备进行标识

代码语言:javascript
复制
#include <sys/types.h>
#include <sys/sysctl.h>

- (NSString *)getModel {
    size_t size;
    sysctlbyname("hw.machine", NULL, &size, NULL, 0);
    char *model = malloc(size);
    sysctlbyname("hw.machine", model, &size, NULL, 0);
    NSString *sDeviceModel = [NSString stringWithCString:model encoding:NSUTF8StringEncoding];
    free(model);                              
    if ([sDeviceModel isEqual:@"i386"])      return @"Simulator";  //iPhone Simulator
    if ([sDeviceModel isEqual:@"iPhone1,1"]) return @"iPhone1G";   //iPhone 1G
    if ([sDeviceModel isEqual:@"iPhone1,2"]) return @"iPhone3G";   //iPhone 3G
    if ([sDeviceModel isEqual:@"iPhone2,1"]) return @"iPhone3GS";  //iPhone 3GS
    if ([sDeviceModel isEqual:@"iPhone3,1"]) return @"iPhone4 AT&T";  //iPhone 4 - AT&T
    if ([sDeviceModel isEqual:@"iPhone3,2"]) return @"iPhone4 Other";  //iPhone 4 - Other carrier
    if ([sDeviceModel isEqual:@"iPhone3,3"]) return @"iPhone4";    //iPhone 4 - Other carrier
    if ([sDeviceModel isEqual:@"iPhone4,1"]) return @"iPhone4S";   //iPhone 4S
    if ([sDeviceModel isEqual:@"iPhone5,1"]) return @"iPhone5";    //iPhone 5 (GSM)
    if ([sDeviceModel isEqual:@"iPod1,1"])   return @"iPod1stGen"; //iPod Touch 1G
    if ([sDeviceModel isEqual:@"iPod2,1"])   return @"iPod2ndGen"; //iPod Touch 2G
    if ([sDeviceModel isEqual:@"iPod3,1"])   return @"iPod3rdGen"; //iPod Touch 3G
    if ([sDeviceModel isEqual:@"iPod4,1"])   return @"iPod4thGen"; //iPod Touch 4G
    if ([sDeviceModel isEqual:@"iPad1,1"])   return @"iPadWiFi";   //iPad Wifi
    if ([sDeviceModel isEqual:@"iPad1,2"])   return @"iPad3G";     //iPad 3G
    if ([sDeviceModel isEqual:@"iPad2,1"])   return @"iPad2";      //iPad 2 (WiFi)
    if ([sDeviceModel isEqual:@"iPad2,2"])   return @"iPad2";      //iPad 2 (GSM)
    if ([sDeviceModel isEqual:@"iPad2,3"])   return @"iPad2";      //iPad 2 (CDMA)

    NSString *aux = [[sDeviceModel componentsSeparatedByString:@","] objectAtIndex:0];

//If a newer version exist
    if ([aux rangeOfString:@"iPhone"].location!=NSNotFound) {
        int version = [[aux stringByReplacingOccurrencesOfString:@"iPhone" withString:@""] intValue];
        if (version == 3) return @"iPhone4"
        if (version >= 4) return @"iPhone4s";

    }
    if ([aux rangeOfString:@"iPod"].location!=NSNotFound) {
        int version = [[aux stringByReplacingOccurrencesOfString:@"iPod" withString:@""] intValue];
        if (version >=4) return @"iPod4thGen";
    }
    if ([aux rangeOfString:@"iPad"].location!=NSNotFound) {
        int version = [[aux stringByReplacingOccurrencesOfString:@"iPad" withString:@""] intValue];
        if (version ==1) return @"iPad3G";
        if (version >=2) return @"iPad2";
    }
    //If none was found, send the original string
    return sDeviceModel;
}
票数 23
EN

Stack Overflow用户

发布于 2010-12-04 21:01:10

代码语言:javascript
复制
BOOL hasHighResScreen = NO;
if ([UIScreen instancesRespondToSelector:@selector(scale)]) {
    CGFloat scale = [[UIScreen mainScreen] scale];
    if (scale > 1.0) {
        hasHighResScreen = YES;
    }
}
票数 4
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/1108859

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