我试过了:
UPDATE closure JOIN item ON ( item_id = id )
SET checked = 0
WHERE ancestor_id = 1
和:
UPDATE closure, item
SET checked = 0
WHERE ancestor_id = 1 AND item_id = id
这两种方法都适用于MySQL,但是在SQLite中出现了语法错误。
如何使此更新/加入与SQLite版本3.5.9一起工作?
发布于 2009-04-21 19:51:23
你不能,SQLite doesn't support JOINs in UPDATE statements。
但是,您可能可以使用子查询来完成此操作:
UPDATE closure SET checked = 0
WHERE item_id IN (SELECT id FROM item WHERE ancestor_id = 1);
或者类似的东西;还不清楚您的模式到底是什么。
发布于 2016-01-13 20:19:49
你也可以使用REPLACE,然后你就可以使用selection和joins了。如下所示:
REPLACE INTO clusure
SELECT sel.col1,sel.col2,....,sel.checked --checked should correspond to column that you want to change
FROM (
SELECT *,0 as checked FROM closure LEFT JOIN item ON (item_id = id)
WHERE ancestor_id = 1) sel
https://stackoverflow.com/questions/773441
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