blocks|key|261612|text|下面是一个帮助你起步的例子。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|261613|for+f+in+*.jpg;+do+mv+"$f"+"$(echo+"$f"+%7C+sed+s/IMG/VACATION/)";+done|code-block|syntax|javascript|261614|在本例中，我假设您的所有图像文件都包含字符串IMG，并且您希望用VACATION替换IMG。|offset|length|style|CODE|261615|外壳程序会自动对所有匹配的文件执行*.jpg。|261616|mv+(文件的新名称)的第二个参数是sed命令的输出，该命令将IMG替换为VACATION。|261617|如果您的文件名包含空格，请仔细注意"$f"表示法。您需要使用双引号来保留空格。|261618|entityMap^0|0|0|M|3|W|8|16|3|0|H|5|0|0|2|I|3|V|3|11|8|0|H|4|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@$I|X|J|Y|K|L]|$I|Z|J|10|K|L]|$I|11|J|12|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|13|8|@$I|14|J|15|K|L]]|9|@]|A|$]]|$1|O|3|P|5|6|7|16|8|@$I|17|J|18|K|L]|$I|19|J|1A|K|L]|$I|1B|J|1C|K|L]|$I|1D|J|1E|K|L]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1F|8|@$I|1G|J|1H|K|L]]|9|@]|A|$]]|$1|S|3|-4|5|6|7|1I|8|@]|9|@]|A|$]]]|T|$]]

An example to help you get off the ground.
<pre><code>for f in *.jpg; do mv &quot;$f&quot; &quot;$(echo &quot;$f&quot; | sed s/IMG/VACATION/)&quot;; done
</code></pre>
In this example, I am assuming that all your image files contain the string <code>IMG</code> and you want to replace <code>IMG</code> with <code>VACATION</code>.
The shell automatically evaluates <code>*.jpg</code> to all the matching files.
The second argument of <code>mv</code> (the new name of the file) is the output of the <code>sed</code> command that replaces <code>IMG</code> with <code>VACATION</code>.
If your filenames include whitespace pay careful attention to the <code>&quot;$f&quot;</code> notation. You need the double-quotes to preserve the whitespace.

blocks|key|3163009|text|您可以使用+rename+实用程序按模式重命名多个文件。例如，下面的命令将字符串MyVacation2011_添加到所有扩展名为jpg的文件前面。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|3163010|rename+'s/%5E/MyVacation2011_/g'+*.jpg|code-block|syntax|javascript|3163011|或|3163012|rename+<pattern>+<replacement>+<file-list>|3163013|entityMap^0|5|8|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

You can use rename utility to rename multiple files by a pattern. For example following command will prepend string MyVacation2011_ to all the files with jpg extension. 

<pre><code>rename 's/^/MyVacation2011_/g' *.jpg
</code></pre>

or

<pre><code>rename &lt;pattern&gt; &lt;replacement&gt; &lt;file-list&gt;
</code></pre>

blocks|key|3163157|text|在这个例子中，我假设你所有的图像文件都以"IMG“开头，而你想把"IMG”替换成“”。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3163158|解决方案:首先识别所有jpg文件，然后替换关键字|3163159|find+.+-name+'*jpg'+-exec+bash+-c+'echo+mv+$0+${0/IMG/VACATION}'+{}+\;+|code-block|syntax|javascript|3163160|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

this example, I am assuming that all your image files begin with "IMG" and you want to replace "IMG" with "VACATION"

solution : first identified all jpg files and then replace keyword 

<pre><code>find . -name '*jpg' -exec bash -c 'echo mv $0 ${0/IMG/VACATION}' {} \; 
</code></pre>

blocks|key|2949152|text|for+file+in+*.jpg+;+do+mv+$file+${file//IMG/myVacation}+;+done|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2949153|再次假设您的所有图像文件都具有字符串"IMG“，并且您希望将"IMG”替换为"myVacation“。|unstyled|2949154|使用bash，您可以使用parameter+expansion直接转换字符串。|offset|length|2949155|示例:如果文件为IMG_327.jpg，则将像执行mv+IMG_327.jpg+myVacation_327.jpg一样执行mv命令。这将对在与*.jpg匹配的目录中找到的每个文件执行此操作。|style|CODE|2949156|IMG_001.jpg+->+myVacation_001.jpg|2949157|IMG_002.jpg+->+myVacation_002.jpg|2949158|IMG_1023.jpg+->+myVacation_1023.jpg|2949159|等等..。|2949160|entityMap|0|LINK|mutability|MUTABLE|url|http://www.linuxjournal.com/content/bash-parameter-expansion^0|0|0|C|J|0|0|P|X|1Q|2|20|5|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|15|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|16|8|@]|9|@$I|17|J|18|1|19]]|A|$]]|$1|K|3|L|5|F|7|1A|8|@$I|1B|J|1C|M|N]|$I|1D|J|1E|M|N]|$I|1F|J|1G|M|N]]|9|@]|A|$]]|$1|O|3|P|5|F|7|1H|8|@]|9|@]|A|$]]|$1|Q|3|R|5|F|7|1I|8|@]|9|@]|A|$]]|$1|S|3|T|5|F|7|1J|8|@]|9|@]|A|$]]|$1|U|3|V|5|F|7|1K|8|@]|9|@]|A|$]]|$1|W|3|-4|5|F|7|1L|8|@]|9|@]|A|$]]]|X|$Y|$5|Z|10|11|A|$12|13]]]]

<pre><code>for file in *.jpg ; do mv $file ${file//IMG/myVacation} ; done
</code></pre>

Again assuming that all your image files have the string "IMG" and you want to replace "IMG" with "myVacation".

With bash you can directly convert the string with <a href="http://www.linuxjournal.com/content/bash-parameter-expansion" rel="noreferrer">parameter expansion</a>.

Example: if the file is IMG_327.jpg, the <code>mv</code> command will be executed as if you do <code>mv IMG_327.jpg myVacation_327.jpg</code>. And this will be done for each file found in the directory matching <code>*.jpg</code>.

IMG_001.jpg -> myVacation_001.jpg 
IMG_002.jpg -> myVacation_002.jpg 
IMG_1023.jpg -> myVacation_1023.jpg 
etcetera...

blocks|key|3163082|text|另一种选择是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3163083|for+i+in+*001.jpg
do
++echo+"mv+$i+yourstring${i#*001.jpg}"
done|code-block|syntax|javascript|3163084|正确使用echo后，将其删除。|offset|length|style|CODE|3163085|使用#进行参数替换将只保留最后一部分，因此您可以更改其名称。|3163086|entityMap^0|0|0|4|4|0|2|1|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|V|8|@$I|W|J|X|K|L]]|9|@]|A|$]]|$1|O|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|P|$]]

Another option is:

<pre><code>for i in *001.jpg
do
 echo "mv $i yourstring${i#*001.jpg}"
done
</code></pre>

remove <code>echo</code> after you have it right.

Parameter substitution with <code>#</code> will keep only the last part, so you can change its name.

blocks|key|261771|text|find+.+-type+f+%7C+
sed+-n+"s/$.*$factory\.py$/&+\1service\.py/p"+%7C+
xargs+-p+-n+2+mv|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|261772|eg会将cwd中所有以"factory.py“结尾的文件重命名为以"service.py”结尾的文件。|unstyled|261773|解释：|261774|1)在sed+cmd中，在应用s/命令后，-n标志将禁止将输入回显到输出的正常行为，如果进行了替换，则s/上的p选项将强制写入输出。由于sub仅在匹配时生成，因此sed将只输出以"factory.py“结尾的文件。|261775|2)在s/替换字符串中，我们使用"&“将整个匹配字符串插入到替换字符串中，后跟一个空格字符。正因为如此，我们的RE必须匹配整个文件名。在空格字符之后，我们使用"\1service.py“插入在"factory.py”之前吞噬的字符串，然后使用"service.py“替换它。因此，对于更复杂的转换，您必须将args更改为s/(其中re仍与整个文件名匹配)|261776|输出示例：|261777|foo_factory.py+foo_service.py
bar_factory.py+bar_service.py|261778|3)我们使用xargs和-n+2一次使用sed2分隔字符串的输出，并将这些字符串传递给mv+(我还在其中放入了-p选项，以便您在运行此命令时可以放心)。瞧。|261779|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|V|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|F|7|X|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|Y|8|@]|9|@]|A|$]]|$1|M|3|N|5|F|7|Z|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$B|C]]|$1|Q|3|R|5|F|7|11|8|@]|9|@]|A|$]]|$1|S|3|-4|5|F|7|12|8|@]|9|@]|A|$]]]|T|$]]

<pre><code>find . -type f | 
sed -n "s/$.*$factory\.py$/&amp; \1service\.py/p" | 
xargs -p -n 2 mv
</code></pre>

eg will rename all files in the cwd with names ending in "factory.py" to be replaced with names ending in "service.py"

explanation:

1) in the sed cmd, the -n flag will suppress normal behavior of echoing input to output after the s/// command is applied, and the p option on s/// will force writing to output if a substitution is made. since a sub will only be made on match, sed will only have output for files ending in "factory.py"

2) in the s/// replacement string, we use "&amp; " to interpolate the entire matching string, followed by a space character, into the replacement. because of this, it's vital that our RE matches the entire filename. after the space char, we use "\1service.py" to interpolate the string we gulped before "factory.py", followed by "service.py", replacing it. So for more complex transformations youll have to change the args to s/// (with an re still matching the entire filename)

example output:

<pre><code>foo_factory.py foo_service.py
bar_factory.py bar_service.py
</code></pre>

3) we use xargs with -n 2 to consume the output of sed 2 delimited strings at a time, passing these to mv (i also put the -p option in there so you can feel safe when running this). voila.

blocks|key|259818|text|您可以尝试这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|259819|for+file+in+*.jpg;
do
++mv+$file+$somestring_${file:((-7))}
done|code-block|syntax|javascript|259820|您可以在man+bash中查看“参数扩展”，以便更好地理解以上内容。|offset|length|style|CODE|259821|entityMap^0|0|0|4|8|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

You can try this:

<pre><code>for file in *.jpg;
do
 mv $file $somestring_${file:((-7))}
done
</code></pre>

You can see "parameter expansion" in <code>man bash</code> to understand the above better.

blocks|key|257534|text|不能评论Susam+Pal的回答，但如果你处理的是空格，我会用引号括起来：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|257535|for+f+in+*.jpg;+do+mv+"$f"+"`echo+$f+%7C+sed+s/\+/\-/g`";+done;|code-block|syntax|javascript|257536|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Can't comment on Susam Pal's answer but if you're dealing with spaces, I'd surround with quotes:

<pre><code>for f in *.jpg; do mv "$f" "`echo $f | sed s/\ /\-/g`"; done;
</code></pre>

<blockquote>
 Write a simple script that will automatically rename a number of files. As an example we want the file *001.jpg renamed to user defined string + 001.jpg (ex: MyVacation20110725_001.jpg) The usage for this script is to get the digital camera photos to have file names that make some sense.
</blockquote>

I need to write a shell script for this. Can someone suggest how to begin?

Rename multiple files by replacing a particular pattern in the filenames using a shell script

编写一个简单的脚本，它将自动重命名许多文件。例如，我们希望将文件*001.jpg重命名为用户定义的字符串+ 001.jpg (例如: MyVacation20110725_001.jpg)此脚本的用法是让数码相机照片具有一些有意义的文件名。我需要为此编写一个shell脚本。有人能建议一下如何开始吗？

问通过使用shell脚本替换文件名中的特定模式来重命名多个文件
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