blocks|key|1141551|text|我可能会使用类似这样的东西：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1141552|string+path+=+"C:/folder1/folder2/file.txt";
string+lastFolderName+=+Path.GetFileName(+Path.GetDirectoryName(+path+)+);|code-block|syntax|javascript|1141553|对GetDirectoryName的内部调用将返回完整路径，而对GetFileName()的外部调用将返回最后一个路径组件-即文件夹名称。|offset|length|style|CODE|1141554|无论路径是否实际存在，此方法都有效。但是，这种方法依赖于最初以文件名结尾的路径。如果不知道路径是否以文件名或文件夹名结尾-那么它要求您首先检查实际路径，看看文件/文件夹是否存在于该位置。在这种情况下，Dan+Dimitru的答案可能更合适。|1141555|entityMap^0|0|0|1|G|W|D|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]|$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|P|$]]

I would probably use something like:

<pre><code>string path = "C:/folder1/folder2/file.txt";
string lastFolderName = Path.GetFileName( Path.GetDirectoryName( path ) );
</code></pre>

The inner call to <code>GetDirectoryName</code> will return the full path, while the outer call to <code>GetFileName()</code> will return the last path component - which will be the folder name.

This approach works whether or not the path actually exists. This approach, does however, rely on the path initially ending in a filename. If it's unknown whether the path ends in a filename or folder name - then it requires that you check the actual path to see if a file/folder exists at the location first. In that case, Dan Dimitru's answer may be more appropriate.

blocks|key|1141570|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1141571|string+filename+=+@"C:/folder1/folder2/file.txt";
string+FolderName+=+new+DirectoryInfo(System.IO.Path.GetDirectoryName(filename)).Name;|code-block|syntax|javascript|1141572|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this:

<pre><code>string filename = @"C:/folder1/folder2/file.txt";
string FolderName = new DirectoryInfo(System.IO.Path.GetDirectoryName(filename)).Name;
</code></pre>

blocks|key|927136|text|简单明了。只使用System.IO.FileSystem+-效果很好：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|927137|string+path+=+"C:/folder1/folder2/file.txt";
string+folder+=+new+DirectoryInfo(path).Name;|code-block|syntax|javascript|927138|entityMap^0|8|K|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Simple &amp; clean. Only uses <code>System.IO.FileSystem</code> - works like a charm:

<pre><code>string path = "C:/folder1/folder2/file.txt";
string folder = new DirectoryInfo(path).Name;
</code></pre>

blocks|key|927042|text|var+fullPath+=+@"C:\folder1\folder2\file.txt";
var+lastDirectory+=+Path.GetDirectoryName(fullPath).Split('\\').LastOrDefault();|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|927043|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>var fullPath = @"C:\folder1\folder2\file.txt";
var lastDirectory = Path.GetDirectoryName(fullPath).Split('\\').LastOrDefault();
</code></pre>

blocks|key|1141806|text|string+Folder+=+Directory.GetParent(path).Name;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1141807|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>string Folder = Directory.GetParent(path).Name;
</code></pre>

blocks|key|1141782|text|同样重要的是要注意，在循环中获取目录名的列表时，DirectoryInfo类被初始化一次，因此只允许第一次调用。为了绕过这一限制，请确保在循环中使用变量来存储任何单个目录的名称。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1141783|例如，此示例代码循环遍历任何父目录中的目录列表，同时在字符串类型列表中添加每个找到的目录名：|1141784|C#|1141785|string[]+parentDirectory+=+Directory.GetDirectories("/yourpath");
List<string>+directories+=+new+List<string>();

foreach+(var+directory+in+parentDirectory)
{
++++//+Notice+I've+created+a+DirectoryInfo+variable.
++++DirectoryInfo+dirInfo+=+new+DirectoryInfo(directory);

++++//+And+likewise+a+name+variable+for+storing+the+name.
++++//+If+this+is+not+added,+only+the+first+directory+will
++++//+be+captured+in+the+loop;+the+rest+won't.
++++string+name+=+dirInfo.Name;

++++//+Finally+we+add+the+directory+name+to+our+defined+List.
++++directories.Add(name);
}|code-block|syntax|javascript|1141786|VB.NET|1141787|Dim+parentDirectory()+As+String+=+Directory.GetDirectories("/yourpath")
Dim+directories+As+New+List(Of+String)()

For+Each+directory+In+parentDirectory

++++'+Notice+I've+created+a+DirectoryInfo+variable.
++++Dim+dirInfo+As+New+DirectoryInfo(directory)

++++'+And+likewise+a+name+variable+for+storing+the+name.
++++'+If+this+is+not+added,+only+the+first+directory+will
++++'+be+captured+in+the+loop;+the+rest+won't.
++++Dim+name+As+String+=+dirInfo.Name

++++'+Finally+we+add+the+directory+name+to+our+defined+List.
++++directories.Add(name)

Next+directory|1141788|entityMap^0|O|D|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|X|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|Y|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|Z|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|10|8|@]|D|@]|E|$]]|$1|Q|3|R|5|L|7|11|8|@]|D|@]|E|$M|N]]|$1|S|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|T|$]]

It's also important to note that while getting a list of directory names in a loop, the <code>DirectoryInfo</code> class gets initialized once thus allowing only first-time call. In order to bypass this limitation, ensure you use variables within your loop to store any individual directory's name.

For example, this sample code loops through a list of directories within any parent directory while adding each found directory-name inside a List of string type:

[C#]

<pre><code>string[] parentDirectory = Directory.GetDirectories("/yourpath");
List&lt;string&gt; directories = new List&lt;string&gt;();

foreach (var directory in parentDirectory)
{
 // Notice I've created a DirectoryInfo variable.
 DirectoryInfo dirInfo = new DirectoryInfo(directory);

 // And likewise a name variable for storing the name.
 // If this is not added, only the first directory will
 // be captured in the loop; the rest won't.
 string name = dirInfo.Name;

 // Finally we add the directory name to our defined List.
 directories.Add(name);
}
</code></pre>

[VB.NET]

<pre><code>Dim parentDirectory() As String = Directory.GetDirectories("/yourpath")
Dim directories As New List(Of String)()

For Each directory In parentDirectory

 ' Notice I've created a DirectoryInfo variable.
 Dim dirInfo As New DirectoryInfo(directory)

 ' And likewise a name variable for storing the name.
 ' If this is not added, only the first directory will
 ' be captured in the loop; the rest won't.
 Dim name As String = dirInfo.Name

 ' Finally we add the directory name to our defined List.
 directories.Add(name)

Next directory
</code></pre>

blocks|key|927350|text|您好，我的工作很好，您的工作是什么？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|927351|using+System;
using+System.IO;
using+System.Collections.Generic;

class+AudioMerge{

++++static+void+Main(){
++++++++string+destino="";
++++++++Console.WriteLine("Digite+a+pasta+de+origem+dos+arquivos+a+serem+mesclados:+");
++++++++string+origem+=+Console.ReadLine();
++++++++Console.WriteLine("Insira+o+nome+do+arquivo+resultado+da+mescla+dos+arquivos:+");
++++++++string+arquivo_mesclado+=+Console.ReadLine();
++++++++Console.WriteLine("Deseja+copiar+os+arquivos+antes+de+terem+sido+mesclados?+[s/n]");
++++++++char+opcao+=+char.Parse(Console.ReadLine());
++++++++opção:
++++++++switch(opcao){
++++++++++++case+'s':
++++++++++++case+'S':
++++++++++++++++Console.WriteLine("Agora,+digite+a+pasta+de+destino+dos+arquivos+que+serão+mesclados,+para+saber+a+ordem+deles:+");
++++++++++++++++destino+=+Console.ReadLine();
++++++++++++++++break;
++++++++++++case+'n':
++++++++++++case+'N':
++++++++++++++++Console.WriteLine("Os+arquivos+mesclados+não+serão+copiados.");
++++++++++++++++break;
++++++++++++default:
++++++++++++++++Console.WriteLine("A+opção+não+foi+escolhida+corretamente");
++++++++++++++++goto+opção;
++++++++}
++++++++
++++++++arquivo_mesclado+=+origem+%2B+@"\"+%2B+arquivo_mesclado+%2B+@".mp3";
++++++++MergeAudio(origem,+arquivo_mesclado,+destino,+opcao);
++++}
++++static+void+MergeAudio(string+origem,+string+arquivo_mesclado,+string+destino,+char+opcao){
++++++++//string+path+=+@"C:\Users\Josileissu\Desktop\teste";
++++++++string+[]+filePaths+=+Directory.GetFiles(origem,+"*.*",+SearchOption.AllDirectories);
++++++++int+count+=+0;

++++++++using+(var+w+=+new++BinaryWriter(File.Create(arquivo_mesclado))){
++++++++++++new+List<string>(filePaths).ForEach(f+=>+w.Write(File.ReadAllBytes(f)));
++++++++}
++++++++
+++++++++//copia+arquivo+na+pasta+output;
++++++++opção:
++++++++switch(opcao){
++++++++++++case+'s':
++++++++++++case+'S':
++++++++++++++++foreach(string+n+in+filePaths){
++++++++++++++++++++count%2B%2B;+//contagem+de+arquivos
++++++++++++++++++++string+nomepasta+=+new+DirectoryInfo(System.IO.Path.GetDirectoryName(n)).Name;+//cd00_início
++++++++++++++++++++string+nomearquivo+=+new+DirectoryInfo(n).Name;+//faixa01.mp3
++++++++++++++++++++nomearquivo+=+nomepasta+%2B+"_"+%2B+nomearquivo;
++++++++++++++++++++string+str+=+(destino+%2B+@"\"+%2B+nomearquivo);
++++++++++++++++++++if+(!File.Exists(str)){
++++++++++++++++++++++++File.Copy(n+,+str);
++++++++++++++++++++++++Console.WriteLine(n+%2B+"copiado+para+->"+%2B+str);
++++++++++++++++++++}
++++++++++++++++}
++++++++++++++++Console.WriteLine("A+quantidade+de+arquivos+copiados+foram:+Pelo+contador+{0},+e+pelo+tamanho+do+array+{1}",count,+filePaths.Length);
++++++++++++++++break;
++++++++++++case+'n':
++++++++++++case+'N':
++++++++++++++++break;
++++++++++++default:
++++++++++++++++Console.WriteLine("A+opção+não+foi+escolhida+corretamente");
++++++++++++++++goto+opção;
++++++++}
++++++++Console.WriteLine("O+arquivo+final+foi+destinado+a+pasta+{0}",arquivo_mesclado);
++++}
}|code-block|syntax|javascript|927352|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Ainda estou aprendendo a como usar o c#, mas fui pegando uns códigos de uns e de outros, espero que te ajude...
<pre><code>using System;
using System.IO;
using System.Collections.Generic;

class AudioMerge{

 static void Main(){
 string destino=&quot;&quot;;
 Console.WriteLine(&quot;Digite a pasta de origem dos arquivos a serem mesclados: &quot;);
 string origem = Console.ReadLine();
 Console.WriteLine(&quot;Insira o nome do arquivo resultado da mescla dos arquivos: &quot;);
 string arquivo_mesclado = Console.ReadLine();
 Console.WriteLine(&quot;Deseja copiar os arquivos antes de terem sido mesclados? [s/n]&quot;);
 char opcao = char.Parse(Console.ReadLine());
 opção:
 switch(opcao){
 case 's':
 case 'S':
 Console.WriteLine(&quot;Agora, digite a pasta de destino dos arquivos que serão mesclados, para saber a ordem deles: &quot;);
 destino = Console.ReadLine();
 break;
 case 'n':
 case 'N':
 Console.WriteLine(&quot;Os arquivos mesclados não serão copiados.&quot;);
 break;
 default:
 Console.WriteLine(&quot;A opção não foi escolhida corretamente&quot;);
 goto opção;
 }
 
 arquivo_mesclado = origem + @&quot;\&quot; + arquivo_mesclado + @&quot;.mp3&quot;;
 MergeAudio(origem, arquivo_mesclado, destino, opcao);
 }
 static void MergeAudio(string origem, string arquivo_mesclado, string destino, char opcao){
 //string path = @&quot;C:\Users\Josileissu\Desktop\teste&quot;;
 string [] filePaths = Directory.GetFiles(origem, &quot;*.*&quot;, SearchOption.AllDirectories);
 int count = 0;

 using (var w = new BinaryWriter(File.Create(arquivo_mesclado))){
 new List&lt;string&gt;(filePaths).ForEach(f =&gt; w.Write(File.ReadAllBytes(f)));
 }
 
 //copia arquivo na pasta output;
 opção:
 switch(opcao){
 case 's':
 case 'S':
 foreach(string n in filePaths){
 count++; //contagem de arquivos
 string nomepasta = new DirectoryInfo(System.IO.Path.GetDirectoryName(n)).Name; //cd00_início
 string nomearquivo = new DirectoryInfo(n).Name; //faixa01.mp3
 nomearquivo = nomepasta + &quot;_&quot; + nomearquivo;
 string str = (destino + @&quot;\&quot; + nomearquivo);
 if (!File.Exists(str)){
 File.Copy(n , str);
 Console.WriteLine(n + &quot;copiado para -&gt;&quot; + str);
 }
 }
 Console.WriteLine(&quot;A quantidade de arquivos copiados foram: Pelo contador {0}, e pelo tamanho do array {1}&quot;,count, filePaths.Length);
 break;
 case 'n':
 case 'N':
 break;
 default:
 Console.WriteLine(&quot;A opção não foi escolhida corretamente&quot;);
 goto opção;
 }
 Console.WriteLine(&quot;O arquivo final foi destinado a pasta {0}&quot;,arquivo_mesclado);
 }
}
</code></pre>

blocks|key|1141627|text|这很难看，但避免了分配：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1141628|private+static+string+GetFolderName(string+path)
{
++++var+end+=+-1;
++++for+(var+i+=+path.Length;+--i+>=+0;)
++++{
++++++++var+ch+=+path[i];
++++++++if+(ch+==+System.IO.Path.DirectorySeparatorChar+%7C%7C
++++++++++++ch+==+System.IO.Path.AltDirectorySeparatorChar+%7C%7C
++++++++++++ch+==+System.IO.Path.VolumeSeparatorChar)
++++++++{
++++++++++++if+(end+>+0)
++++++++++++{
++++++++++++++++return+path.Substring(i+%2B+1,+end+-+i+-+1);
++++++++++++}

++++++++++++end+=+i;
++++++++}
++++}

++++if+(end+>+0)
++++{
++++++++return+path.Substring(0,+end);
++++}

++++return+path;
}|code-block|syntax|javascript|1141629|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is ugly but avoids allocations:

<pre><code>private static string GetFolderName(string path)
{
 var end = -1;
 for (var i = path.Length; --i &gt;= 0;)
 {
 var ch = path[i];
 if (ch == System.IO.Path.DirectorySeparatorChar ||
 ch == System.IO.Path.AltDirectorySeparatorChar ||
 ch == System.IO.Path.VolumeSeparatorChar)
 {
 if (end &gt; 0)
 {
 return path.Substring(i + 1, end - i - 1);
 }

 end = i;
 }
 }

 if (end &gt; 0)
 {
 return path.Substring(0, end);
 }

 return path;
}
</code></pre>

<pre><code>string path = &quot;C:\folder1\folder2\file.txt&quot;;
</code></pre>
What objects or methods could I use that would give me a result of <code>folder2</code>?

Getting the folder name from a full filename path

string path = "C:\folder1\folder2\file.txt";我可以使用哪些对象或方法来获得folder2的结果

问从完整文件名路径中获取文件夹名称
EN

回答 8

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问从完整文件名路径中获取文件夹名称EN

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问从完整文件名路径中获取文件夹名称
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