使用python生成重复日期？
使用python生成重复日期？
提问于 2010-02-19 19:03:17
如何使用Python生成循环日期？例如，我想为“每隔一个月的第三个星期五”生成循环日期。我想生成每天、每周、每月、每年的定期日期(即，与Outlook Express中的定期功能相同)。
回答 2
Stack Overflow用户
发布于 2010-02-19 19:10:23
你可以试一试dateutil --尤其是它的relativedelta和rrule fetures。
Stack Overflow用户
发布于 2010-02-19 21:36:24
你可以尝试自己写这篇文章。您首先需要一个迭代器，该迭代器生成由给定间隔分隔的日期：
import datetime
def dateiter(start, resolution):
date = start
while True:
yield date
date += resolution现在，您可以生成日期并对其进行过滤：
# generate a list of every tuesday of february
# this iterates over every day from now, and filtered according to the rules
# warning: infinite generator below, there is nothing to end the iteration
tuesdays_of_february = (date for date in dateiter(datetime.datetime.now(), datetime.timedelta(days=1)) if date.weekday() == 4 and date.month == 2)您可以自己调用迭代器，直到您有足够的日期：
>>> next(tuesdays_of_february)
datetime.datetime(2010, 2, 19, 14, 25, 46, 171000)现在，您需要限制结果：
>>> from itertools import *
>>>
>>> # get the five next valid dates:
>>> list(islice(tuesdays_of_february),5)
[datetime.datetime(2010, 2,26, 14, 25, 46, 171000), datetime.datetime(2011, 2, 4
, 14, 25, 46, 171000), datetime.datetime(2011, 2, 11, 14, 25, 46, 171000), datet
ime.datetime(2011, 2, 18, 1 4, 25, 46, 171000), datetime.datetime(2011, 2, 25
, 14, 25, 46, 171000)]
>>>
>>> # or until a condition is met:
>>> list(takewhile( lambda date: date.year < 2014, tuesdays_of_february ))
[datetime.datetime(2012, 2, 3, 14, 25, 46, 171000), datetime.datetime(2012, 2, 1
0, 14, 25, 46, 171000), datetime.datetime(2012, 2, 17, 14, 25, 46, 171000), date
time.datetime(2012, 2, 24, 14, 25, 46, 171000), datetime.datetime(2013, 2, 1, 14
, 25, 46, 171000), datetime.datetime(2013, 2, 8, 14, 25, 46, 171000), datetime.d
atetime(2013, 2, 15, 14, 25, 46, 171000), datetime.datetime(2013, 2, 22, 14, 25,
46, 171000)]不要忘记查看datetime模块的文档。
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原文链接：
https://stackoverflow.com/questions/2295765
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