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社区首页 >问答首页 >Python解析来自多个txt文件文本

Python解析来自多个txt文件文本
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Stack Overflow用户
提问于 2017-04-25 04:00:52
回答 2查看 2.5K关注 0票数 15

寻求有关如何从多个文本文件中挖掘项目以构建字典的建议。

此文本文件:https://pastebin.com/Npcp3HCM

被手动转换为所需的数据结构:https://drive.google.com/file/d/0B2AJ7rliSQubV0J2Z0d0eXF3bW8/view

有数千个这样的文本文件,它们可能具有不同的部分标题,如以下示例所示:

  1. https://pastebin.com/wWSPGaLX
  2. https://pastebin.com/9Up4RWHu

我从阅读文件开始

from glob import glob

txtPth = '../tr-txt/*.txt'
txtFiles = glob(txtPth)

with open(txtFiles[0],'r') as tf:
    allLines = [line.rstrip() for line in tf]

sectionHeading = ['Corporate Participants',
                  'Conference Call Participiants',
                  'Presentation',
                  'Questions and Answers']

for lineNum, line in enumerate(allLines):
    if line in sectionHeading:
        print(lineNum,allLines[lineNum])

我的想法是查找存在部分标题的行号,并尝试提取这些行号之间的内容,然后去掉像破折号这样的分隔符。这不起作用,我被困在试图创建一种字典,这样我以后就可以在采石项目上运行各种自然语言处理算法。

{file-name1:{
    {date-time:[string]},
    {corporate-name:[string]},
    {corporate-participants:[name1,name2,name3]},
    {call-participants:[name4,name5]},
    {section-headings:{
        {heading1:[
            {name1:[speechOrderNum, text-content]},
            {name2:[speechOrderNum, text-content]},
            {name3:[speechOrderNum, text-content]}],
        {heading2:[
            {name1:[speechOrderNum, text-content]},
            {name2:[speechOrderNum, text-content]},
            {name3:[speechOrderNum, text-content]},
            {name2:[speechOrderNum, text-content]},
            {name1:[speechOrderNum, text-content]},
            {name4:[speechOrderNum, text-content]}],
        {heading3:[text-content]},
        {heading4:[text-content]}
        }
    }
}

挑战在于不同的文件可能有不同的标题和标题数量。但总会有一个叫做“演示文稿”的部分,并且很可能有“问答”部分。这些部分标题始终由等号字符串分隔。并且不同说话者的内容总是由短划线串分隔。问答部分的“发言顺序”用一个方括号中的数字表示。参与者总是在文档的开头用星号标记在他们的名字之前,并且他们的磁贴总是在下一行。

任何关于如何解析文本文件的建议都将受到欢迎。理想的帮助应该是提供指导,指导如何为每个文件生成这样的字典(或其他合适的数据结构),然后可以将这些文件写入数据库。

谢谢

-编辑--

其中一个文件如下所示:https://pastebin.com/MSvmHb2e

其中“问题和回答”部分被错误地标记为“演示”,并且没有其他“问题和回答”部分。

和最终样本文本:https://pastebin.com/jr9WfpV8

EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2017-05-01 13:36:53

代码中的注释应该可以解释一切。请让我知道,如果有什么是低于指定,并需要更多的意见。

简而言之,我利用正则表达式找到'=‘分隔符行,将整个文本细分为子部分,然后为了清晰起见分别处理每种类型的部分(这样您就可以知道我是如何处理每种情况的)。

附注:我将“与会者”和“作者”这两个词互换使用。

编辑:更新了代码,以根据在演示文稿/QA部分中的与会者/作者旁边找到的'x‘模式进行排序。我还更改了漂亮的打印部分,因为pprint不能很好地处理OrderedDict。

要去掉字符串中任意位置包含\n的任何其他空格,只需执行str.strip()。如果您特别需要只剥离\n,那么只需执行str.strip('\n')

我已经修改了代码,去掉了对话中的所有空格。

import json
import re
from collections import OrderedDict
from pprint import pprint


# Subdivides a collection of lines based on the delimiting regular expression.
# >>> example_string =' =============================
#                       asdfasdfasdf
#                       sdfasdfdfsdfsdf
#                       =============================
#                       asdfsdfasdfasd
#                       =============================
# >>> subdivide(example_string, "^=+")
# >>> ['asdfasdfasdf\nsdfasdfdfsdfsdf\n', 'asdfsdfasdfasd\n']
def subdivide(lines, regex):
    equ_pattern = re.compile(regex, re.MULTILINE)
    sections = equ_pattern.split(lines)
    sections = [section.strip('\n') for section in sections]
    return sections


# for processing sections with dashes in them, returns the heading of the section along with
# a dictionary where each key is the subsection's header, and each value is the text in the subsection.
def process_dashed_sections(section):

    subsections = subdivide(section, "^-+")
    heading = subsections[0]  # header of the section.
    d = {key: value for key, value in zip(subsections[1::2], subsections[2::2])}
    index_pattern = re.compile("\[(.+)\]", re.MULTILINE)

    # sort the dictionary by first capturing the pattern '[x]' and extracting 'x' number.
    # Then this is passed as a compare function to 'sorted' to sort based on 'x'.
    def cmp(d):
        mat = index_pattern.findall(d[0])
        if mat:
            print(mat[0])
            return int(mat[0])
        # There are issues when dealing with subsections containing '-'s but not containing '[x]' pattern.
        # This is just to deal with that small issue.
        else:
            return 0

    o_d = OrderedDict(sorted(d.items(), key=cmp))
    return heading, o_d


# this is to rename the keys of 'd' dictionary to the proper names present in the attendees.
# it searches for the best match for the key in the 'attendees' list, and replaces the corresponding key.
# >>> d = {'mr. man   ceo of company   [1]' : ' This is talk a' ,
#  ...     'ms. woman  ceo of company    [2]' : ' This is talk b'}
# >>> l = ['mr. man', 'ms. woman']
# >>> new_d = assign_attendee(d, l)
# new_d = {'mr. man': 'This is talk a', 'ms. woman': 'This is talk b'}
def assign_attendee(d, attendees):
    new_d = OrderedDict()
    for key, value in d.items():
        a = [a for a in attendees if a in key]
        if len(a) == 1:
            # to strip out any additional whitespace anywhere in the text including '\n'.
            new_d[a[0]] = value.strip()
        elif len(a) == 0:
            # to strip out any additional whitespace anywhere in the text including '\n'.
            new_d[key] = value.strip()
    return new_d


if __name__ == '__main__':
    with open('input.txt', 'r') as input:
        lines = input.read()

        # regex pattern for matching headers of each section
        header_pattern = re.compile("^.*[^\n]", re.MULTILINE)

        # regex pattern for matching the sections that contains
        # the list of attendee's (those that start with asterisks )
        ppl_pattern = re.compile("^(\s+\*)(.+)(\s.*)", re.MULTILINE)

        # regex pattern for matching sections with subsections in them.
        dash_pattern = re.compile("^-+", re.MULTILINE)

        ppl_d = dict()
        talks_d = dict()

        # Step1. Divide the the entire document into sections using the '=' divider
        sections = subdivide(lines, "^=+")
        header = []
        print(sections)
        # Step2. Handle each section like a switch case
        for section in sections:

            # Handle headers
            if len(section.split('\n')) == 1:  # likely to match only a header (assuming )
                header = header_pattern.match(section).string

            # Handle attendees/authors
            elif ppl_pattern.match(section):
                ppls = ppl_pattern.findall(section)
                d = {key.strip(): value.strip() for (_, key, value) in ppls}
                ppl_d.update(d)

                # assuming that if the previous section was detected as a header, then this section will relate
                # to that header
                if header:
                    talks_d.update({header: ppl_d})

            # Handle subsections
            elif dash_pattern.findall(section):
                heading, d = process_dashed_sections(section)

                talks_d.update({heading: d})

            # Else its just some random text.
            else:

                # assuming that if the previous section was detected as a header, then this section will relate
                # to that header
                if header:
                    talks_d.update({header: section})

        #pprint(talks_d)
        # To assign the talks material to the appropriate attendee/author. Still works if no match found.
        for key, value in talks_d.items():
            talks_d[key] = assign_attendee(value, ppl_d.keys())

        # ordered dict does not pretty print using 'pprint'. So a small hack to make use of json output to pretty print.
        print(json.dumps(talks_d, indent=4))
票数 8
EN

Stack Overflow用户

发布于 2017-05-03 01:09:17

能否请您确认您是否只需要“演示文稿”和“问答”部分?另外,关于输出,是否可以将CSV格式转储为类似于您“手动转换”的格式。

更新了解决方案,以适用于您提供的每个示例文件。

根据共享的"Parsed-transcript“文件,从单元格"D:H”输出。

#state = ["other", "head", "present", "qa", "speaker", "data"]
# codes : 0, 1, 2, 3, 4, 5
def writecell(out, data):
    out.write(data)
    out.write(",")

def readfile(fname, outname):
    initstate = 0
    f = open(fname, "r")
    out = open(outname, "w")
    head = ""
    head_written = 0
    quotes = 0
    had_speaker = 0
    for line in f:
        line = line.strip()
        if not line: continue
        if initstate in [0,5] and not any([s for s in line if "=" != s]):
            if initstate == 5:
                out.write('"')
                quotes = 0
                out.write("\n")
            initstate = 1
        elif initstate in [0,5] and not any([s for s in line if "-" != s]):
            if initstate == 5:
                out.write('"')
                quotes = 0
                out.write("\n")
                initstate = 4
        elif initstate == 1 and line == "Presentation":
            initstate = 2
            head = "Presentation"
            head_written = 0
        elif initstate == 1 and line == "Questions and Answers":
            initstate = 3
            head = "Questions and Answers"
            head_written = 0
        elif initstate == 1 and not any([s for s in line if "=" != s]):
            initstate = 0
        elif initstate in [2, 3] and not any([s for s in line if ("=" != s and "-" != s)]):
            initstate = 4
        elif initstate == 4 and '[' in line and ']' in line:
            comma = line.find(',')
            speech_st = line.find('[')
            speech_end = line.find(']')
            if speech_st == -1:
                initstate = 0
                continue
            if comma == -1:
                firm = ""
                speaker = line[:speech_st].strip()
            else:
                speaker = line[:comma].strip()
                firm = line[comma+1:speech_st].strip()
            head_written = 1
            if head_written:
                writecell(out, head)
                head_written = 0
            order = line[speech_st+1:speech_end]
            writecell(out, speaker)
            writecell(out, firm)
            writecell(out, order)
            had_speaker = 1
        elif initstate == 4 and not any([s for s in line if ("=" != s and "-" != s)]):
            if had_speaker:
                initstate = 5
                out.write('"')
                quotes = 1
            had_speaker = 0
        elif initstate == 5:
            line = line.replace('"', '""')
            out.write(line)
        elif initstate == 0:
            continue
        else:
            continue
    f.close()
    if quotes:
        out.write('"')
    out.close()

readfile("Sample1.txt", "out1.csv")
readfile("Sample2.txt", "out2.csv")
readfile("Sample3.txt", "out3.csv")

详细信息

在这个解决方案中有一个状态机,它的工作原理如下: 1.检测是否存在标题,如果存在,则将其写入2.在写入标题后检测扬声器3.为该扬声器写入备注4.切换到下一个扬声器,依此类推...

您可以稍后根据需要处理csv文件。在完成基本处理后,您还可以使用所需的任何格式填充数据。

编辑:

请替换"writecell“函数

def writecell(out, data):
    data = data.replace('"', '""')
    out.write('"')
    out.write(data)
    out.write('"')
    out.write(",")
票数 3
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/43596745

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