blocks|key|2884365|text|string+a+=+"/foo/bar/target";
string+words+=+a.Split("/")
string+target+=+words[words.length-1]|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2884366|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>string a = "/foo/bar/target";
string words = a.Split("/")
string target = words[words.length-1]
</code></pre>

blocks|key|3098332|text|如果你从一个"File“对象中获取If，你可以用下面的方法获取它：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3098333|String+fileName+=+myFile.getName();|code-block|syntax|javascript|3098334|如果你从一个简单的字符串中获得它，你可以使用|3098335|String+fileName+=+myString.substring(myString.lastIndexOf("/")%2B1);|3098336|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

If you got if from a "File" object, you can get it with the method:

<pre><code>String fileName = myFile.getName();
</code></pre>

If you got it from a simple String, you can use

<pre><code>String fileName = myString.substring(myString.lastIndexOf("/")+1);
</code></pre>

blocks|key|2884410|text|您应该通过File应用程序接口进行操作。引用自File.getName()文档：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2884411|2884412|返回由该抽象路径名表示的文件或目录的名称。这只是路径名名称序列中的最后一个名称。如果路径名的名称序列为空，则返回空字符串。|blockquote|2884413|2884414|2884415|示例：|2884416|String+name+=+new+File("/mnt/sdcard/Videos/Videoname").getName();|code-block|syntax|javascript|2884417|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/6/docs/api/java/io/File.html|1|http://docs.oracle.com/javase/6/docs/api/java/io/File.html#getName%2528%2529^0|5|4|N|E|5|4|0|N|E|1|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@$9|13|A|14|B|C]|$9|15|A|16|B|C]]|D|@$9|17|A|18|1|19]|$9|1A|A|1B|1|1C]]|E|$]]|$1|F|3|-4|5|6|7|1D|8|@]|D|@]|E|$]]|$1|G|3|H|5|I|7|1E|8|@]|D|@]|E|$]]|$1|J|3|-4|5|6|7|1F|8|@]|D|@]|E|$]]|$1|K|3|-4|5|6|7|1G|8|@]|D|@]|E|$]]|$1|L|3|M|5|6|7|1H|8|@]|D|@]|E|$]]|$1|N|3|O|5|P|7|1I|8|@]|D|@]|E|$Q|R]]|$1|S|3|-4|5|6|7|1J|8|@]|D|@]|E|$]]]|T|$U|$5|V|W|X|E|$Y|Z]]|10|$5|V|W|X|E|$Y|11]]]]

You should go via the <a href="http://docs.oracle.com/javase/6/docs/api/java/io/File.html"><code>File</code></a> api. Quoted from the <a href="http://docs.oracle.com/javase/6/docs/api/java/io/File.html#getName%28%29"><code>File.getName()</code></a> documentation:

<blockquote>
 Returns the name of the file or directory denoted by this abstract pathname. This is just the last name in the pathname's name sequence. If the pathname's name sequence is empty, then the empty string is returned. 
</blockquote>

Example:

<pre><code>String name = new File("/mnt/sdcard/Videos/Videoname").getName();
</code></pre>

blocks|key|3098372|text|但是，通过更多的研究，下面的代码可以工作...|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3098373|String[]+Tokens+=+stringPath.split("\\\\");|code-block|syntax|javascript|3098374|你需要转义"\“两次。|3098375|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

But with a little more research, the following code works...

<pre><code>String[] Tokens = stringPath.split("\\\\");
</code></pre>

You need to escape the "\" twice.

blocks|key|3098377|text|String+path+=+"/mnt/sdcard/Videos/Videoname";+//+Your+path

String+fileName+=+new+File(path).getName();+//+you+file+name|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3098378|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>String path = "/mnt/sdcard/Videos/Videoname"; // Your path

String fileName = new File(path).getName(); // you file name
</code></pre>

blocks|key|3098402|text|最简单的方法是|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3098403|String+path+="AnyDirectory/subFolder/last.htm";
int+pos+=+path.lastIndexOf("/")+%2B+1;

path.substring(pos,+path.length()-pos);|code-block|syntax|javascript|3098404|现在您在路径字符串中有了last.htm。|3098405|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Easiest way is 

<pre><code>String path ="AnyDirectory/subFolder/last.htm";
int pos = path.lastIndexOf("/") + 1;

path.substring(pos, path.length()-pos);
</code></pre>

Now you have the last.htm in the path string.

I want to extract the name of an absolute path. If I have a string with the value /mnt/sdcard/Videos/Videoname, I want to save a string with the value Videoname.

The string is changing and I can't obtain previously the number of slashes. How could I split a substring from the last slash?

<blockquote>
 /mnt/sdcard/Videos/Videoname --> Videnoname
</blockquote>

Obtain name from absolute path, substring from last slash, java android

我想提取绝对路径的名称。如果我有一个值为/mnt/sdcard/Videos/Videoname的字符串，我想保存一个值为Videoname的字符串。字符串正在改变，我之前无法获得斜杠的数量。如何从最后一个斜杠中拆分子字符串？ /mnt/sdcard/Videos/Videoname --> Videnoname

问从绝对路径获取名称，从最后一个斜杠获取子字符串，java android
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问从绝对路径获取名称，从最后一个斜杠获取子字符串，java androidEN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问从绝对路径获取名称，从最后一个斜杠获取子字符串，java android
EN