blocks|key|1401983|text|给定一个字符串str：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1401984|str+=+str.replaceAll("\\\\r","")
str+=+str.replaceAll("\\\\n","")|code-block|syntax|javascript|1401985|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Given a String str:

<pre><code>str = str.replaceAll("\\\\r","")
str = str.replaceAll("\\\\n","")
</code></pre>

blocks|key|1402022|text|您是否尝试过使用replaceAll方法将出现的\n或\r替换为空字符串？|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1402023|entityMap|0|LINK|mutability|MUTABLE|url|http://java.sun.com/j2se/1.5.0/docs/api/java/lang/String.html#replaceAll(java.lang.String,%2520java.lang.String)^0|8|A|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

Have you tried using the <a href="http://java.sun.com/j2se/1.5.0/docs/api/java/lang/String.html#replaceAll(java.lang.String,%20java.lang.String)" rel="nofollow noreferrer">replaceAll</a> method to replace any occurence of \n or \r with the empty String?

blocks|key|1402052|text|正则表达式和replaceAll。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1402053|public+class+Main
{
++++public+static+void+main(final+String[]+argv)+
++++{
++++++++String+str;

++++++++str+=+"hello\r\njava\r\nbook";
++++++++str+=+str.replaceAll("(\\r%7C\\n)",+"");
++++++++System.out.println(str);
++++}
}|code-block|syntax|javascript|1402054|如果您只想删除成对的\r\n+(上面的代码删除了\r或\n)，请执行以下操作：|1402055|str+=+str.replaceAll("\\r\\n",+"");|1402056|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Regex with replaceAll.

<pre><code>public class Main
{
 public static void main(final String[] argv) 
 {
 String str;

 str = "hello\r\njava\r\nbook";
 str = str.replaceAll("(\\r|\\n)", "");
 System.out.println(str);
 }
}
</code></pre>

If you only want to remove \r\n when they are pairs (the above code removes either \r or \n) do this instead:

<pre><code>str = str.replaceAll("\\r\\n", "");
</code></pre>

blocks|key|1616852|text|如果您想要避免正则表达式，或者必须针对较早的JVM，String.replace()将执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1616853|str=str.replace("\r","").replace("\n","");|code-block|syntax|javascript|1616854|和删除CRLF对：|1616855|str=str.replace("\r\n","");|1616856|后者比构建正则表达式来做同样的事情更有效。但我认为前者作为正则表达式会更快，因为字符串只被解析一次。|1616857|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

If you want to avoid the regex, or must target an earlier JVM, String.replace() will do:

<pre><code>str=str.replace("\r","").replace("\n","");
</code></pre>

And to remove a CRLF pair:

<pre><code>str=str.replace("\r\n","");
</code></pre>

The latter is more efficient than building a regex to do the same thing. But I think the former will be faster as a regex since the string is only parsed once.

blocks|key|1616885|text|static+byte[]+discardWhitespace(byte[]+data)+{
++++byte+groomedData[]+=+new+byte[data.length];
++++int+bytesCopied+=+0;

++++for+(int+i+=+0;+i+<+data.length;+i%2B%2B)+{
++++++++switch+(data[i])+{
++++++++++++case+(byte)+'\n'+:
++++++++++++case+(byte)+'\r'+:
++++++++++++++++break;
++++++++++++default:
++++++++++++++++groomedData[bytesCopied%2B%2B]+=+data[i];
++++++++}
++++}

++++byte+packedData[]+=+new+byte[bytesCopied];

++++System.arraycopy(groomedData,+0,+packedData,+0,+bytesCopied);

++++return+packedData;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1616886|在commons-codec项目中找到的代码。|unstyled|1616887|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>static byte[] discardWhitespace(byte[] data) {
 byte groomedData[] = new byte[data.length];
 int bytesCopied = 0;

 for (int i = 0; i &lt; data.length; i++) {
 switch (data[i]) {
 case (byte) '\n' :
 case (byte) '\r' :
 break;
 default:
 groomedData[bytesCopied++] = data[i];
 }
 }

 byte packedData[] = new byte[bytesCopied];

 System.arraycopy(groomedData, 0, packedData, 0, bytesCopied);

 return packedData;
}
</code></pre>

Code found on commons-codec project.

blocks|key|1402179|text|你试过了吗|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1402180|string.trim();+|code-block|syntax|javascript|1402181|这意味着要修剪字符串中的所有前导和倾斜空格。希望这能有所帮助。|1402182|编辑：(我说得不够明确)|1402183|因此，当您使用string.split()时，您将拥有一个string[]+-对于数组中的每个字符串，执行一个string.trim()，然后将其追加。|1402184|String[]+tokens+=+yourString.split("+");
StringBuffer+buff+=+new+StringBuffer();
for+(String+token+:+tokens)
{
++buff.append(token.trim());
}|1402185|使用stringBuffer/Builder，而不是附加在相同的字符串中。|1402186|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|V|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|W|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

Did you try

<pre><code>string.trim(); 
</code></pre>

This is meant to trim all leading and leaning while spaces in the string. Hope this helps.

Edit: (I was not explicit enough)

So, when you string.split(), you will have a string[] - for each of the strings in the array, do a string.trim() and then append it.

<pre><code>String[] tokens = yourString.split(" ");
StringBuffer buff = new StringBuffer();
for (String token : tokens)
{
 buff.append(token.trim());
}
</code></pre>

Use stringBuffer/Builder instead of appending in the same string.

blocks|key|1402215|text|public+static+void+main(final+String[]+argv)+
{
++++String+str;

++++str+=+"hello\r\n\tjava\r\nbook";
++++str+=+str.replaceAll("(\\r%7C\\n%7C\\t)",+"");
++++System.out.println(str);
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1402216|在正则表达式中添加制表也会很有用。|unstyled|1402217|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>public static void main(final String[] argv) 
{
 String str;

 str = "hello\r\n\tjava\r\nbook";
 str = str.replaceAll("(\\r|\\n|\\t)", "");
 System.out.println(str);
}
</code></pre>

It would be useful to add the tabulation in regex too.

blocks|key|1617029|text|如果您知道Windows、Mac或UNIX中的行终止符，则可以直接传递行终止符，例如\n。或者，您可以使用以下代码来替换三种主要操作系统中的换行符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1617030|str+=+str.replaceAll("\\r\\n%7C\\r%7C\\n",+"+");|code-block|syntax|javascript|1617031|在Mac、Windows和Linux中，上述代码行将用空格替换换行符。你也可以使用行分隔符。它将适用于所有操作系统。下面是行分隔符的代码片段。|1617032|String+lineSeparator=System.lineSeparator();
String+newString=yourString.replace(lineSeparator,+"");|1617033|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You can either directly pass line terminator e.g. \n, if you know the line terminator in Windows, Mac or UNIX. Alternatively you can use following code to replace line breaks in either of three major operating system.

<pre><code>str = str.replaceAll("\\r\\n|\\r|\\n", " ");
</code></pre>

Above code line will replace line breaks with space in Mac, Windows and Linux.
Also you can use line-separator. It will work for all OS. Below is the code snippet for line-separator.

<pre><code>String lineSeparator=System.lineSeparator();
String newString=yourString.replace(lineSeparator, "");
</code></pre>

blocks|key|1402298|text|您可以使用org.apache.commons.text.StringEscapeUtils中的unescapeJava，如下所示|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1402299|str+=+"hello\r\njava\r\nbook";
StringEscapeUtils.unescapeJava(str);|code-block|syntax|javascript|1402300|entityMap^0|5|15|1C|C|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

You can use <code>unescapeJava</code> from <code>org.apache.commons.text.StringEscapeUtils</code> like below 

<pre><code>str = "hello\r\njava\r\nbook";
StringEscapeUtils.unescapeJava(str);
</code></pre>

blocks|key|1402348|text|嘿，我们也可以使用这个正则表达式解决方案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1402349|String+chomp+=+StringUtils.normalizeSpace(sentence.replaceAll("[\\r\\n]","+"));|code-block|syntax|javascript|1402350|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Hey we can also use this regex solution.

<pre><code>String chomp = StringUtils.normalizeSpace(sentence.replaceAll("[\\r\\n]"," "));
</code></pre>

blocks|key|1617109|text|试试下面的代码。这对我很管用。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1617110|str+=+str.replaceAll("\\r",+"");
str+=+str.replaceAll("\\n",+"");|code-block|syntax|javascript|1617111|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try below code. It worked for me.
<pre><code>str = str.replaceAll(&quot;\\r&quot;, &quot;&quot;);
str = str.replaceAll(&quot;\\n&quot;, &quot;&quot;);
</code></pre>

I have string like this

<pre><code>"hello
java
book"
</code></pre>

I want remove <code>\r</code> and <code>\n</code> from <code>String(hello\r\njava\r\nbook)</code>. I want the result to be <code>"hellojavabook"</code>. How can I do this?

Remove end of line characters from Java string

Windows

Linux

我有这样的字符串"hellojavabook"我想从String(hello\r\njava\r\nbook)中删除\r和\n。我希望结果是"hellojavabook"。我该怎么做呢？

问从Java字符串中删除行尾字符
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