blocks|key|1001890|text|两行算吗？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1001891|awk+'{+sum+%2B=+$1;+}
+++++END+{+print+sum;+}'+"$@"|code-block|syntax|javascript|1001892|然后你可以不用多余的‘cat’来使用它：|1001893|sum+<+FileWithColumnOfNumbers.txt
sum+++FileWithColumnOfNumbers.txt|1001894|FWIW:在MacOS+X上，你可以使用一行代码：|1001895|awk+'{+sum+%2B=+$1;+}+END+{+print+sum;+}'+"$@"|1001896|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Does two lines count?

<pre><code>awk '{ sum += $1; }
 END { print sum; }' "$@"
</code></pre>

You can then use it without the superfluous 'cat':

<pre><code>sum &lt; FileWithColumnOfNumbers.txt
sum FileWithColumnOfNumbers.txt
</code></pre>

FWIW: on MacOS X, you can do it with a one-liner:

<pre><code>awk '{ sum += $1; } END { print sum; }' "$@"
</code></pre>

blocks|key|1001942|text|你可以使用bc+(计算器)。假设您的带有#s的文件名为"n"：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1001943|$+cat+n
1
2
3
$+(cat+n+%7C+tr+"\012"+"%2B"+;+echo+"0")+%7C+bc+
6|code-block|syntax|javascript|1001944|tr将所有新行都改为"%2B"；然后我们在最后一个加号后面附加0，然后通过管道将表达式(1%2B2%2B3%2B0)传递给计算器|offset|length|style|CODE|1001945|或者，如果您可以使用awk或perl，这里有一个Perl一行程序：|1001946|$perl+-nle+'$sum+%2B=+$_+}+END+{+print+$sum'+n
6|1001947|entityMap^0|0|0|0|2|16|7|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]|$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|Z|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|Q|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|R|$]]

You can use bc (calculator). Assuming your file with #s is called "n":

<pre><code>$ cat n
1
2
3
$ (cat n | tr "\012" "+" ; echo "0") | bc 
6
</code></pre>

The <code>tr</code> changes all newlines to "+"; then we append 0 after the last plus, then we pipe the expression (<code>1+2+3+0</code>) to the calculator

Or, if you are OK with using awk or perl, here's a Perl one-liner:

<pre><code>$perl -nle '$sum += $_ } END { print $sum' n
6
</code></pre>

blocks|key|1001990|text|使用for循环遍历文件…|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1001991|sum=0;+for+x+in+`cat+<your-file>`;+do+let+sum%2B=x;+done;+echo+$sum|code-block|syntax|javascript|1001992|entityMap^0|2|3|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Use a <code>for</code> loop to iterate over your file …

<pre><code>sum=0; for x in `cat &lt;your-file&gt;`; do let sum+=x; done; echo $sum
</code></pre>

blocks|key|1002007|text|while+read+-r+num;+do+((sum+%2B=+num));+done+<+inputfile;+echo+$sum|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1002008|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>while read -r num; do ((sum += num)); done &lt; inputfile; echo $sum
</code></pre>

blocks|key|1002057|text|我喜欢你选择的答案。然而，它往往比awk慢，因为需要2个工具来完成这项工作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1002058|$+wc+-l+file
49999998+file

$+time+paste+-sd%2B+file+%7C+bc
1448700364

real++++1m36.960s
user++++1m24.515s
sys+++++0m1.772s

$+time+awk+'{s%2B=$1}END{print+s}'+file
1448700364

real++++0m45.476s
user++++0m40.756s
sys+++++0m0.287s|code-block|syntax|javascript|1002059|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I like the chosen answer. However, it tends to be slower than awk since 2 tools are needed to do the job. 

<pre><code>$ wc -l file
49999998 file

$ time paste -sd+ file | bc
1448700364

real 1m36.960s
user 1m24.515s
sys 0m1.772s

$ time awk '{s+=$1}END{print s}' file
1448700364

real 0m45.476s
user 0m40.756s
sys 0m0.287s
</code></pre>

blocks|key|1002080|text|ghostdog74s评论的后续|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1002081|bash-2.03$+uname+-sr
SunOS+5.8

bash-2.03$+perl+-le+'print+for+1..49999998'+>+infile

bash-2.03$+wc+-l+infile
+49999998+infile

bash-2.03$++time+paste+-sd%2B+infile+%7C+bc
bundling+space+exceeded+on+line+1,+teletype
Broken+Pipe

real++++0m0.062s
user++++0m0.010s
sys+++++0m0.010s

bash-2.03$+time+nawk+'{s%2B=$1}END{print+s}'+infile
1249999925000001

real++++2m0.042s
user++++1m59.220s
sys+++++0m0.590s
bash-2.03$+time+/usr/xpg4/bin/awk+'{s%2B=$1}END{print+s}'+infile
1249999925000001

real++++2m27.260s
user++++2m26.230s
sys+++++0m0.660s

bash-2.03$+time+perl+-nle'
++$s+%2B=+$_;+END+{+print+$s+}
+++'+infile
1.249999925e%2B15

real++++1m34.663s
user++++1m33.710s
sys+++++0m0.650s|code-block|syntax|javascript|1002082|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

[a followup to ghostdog74s comments]

<pre><code>bash-2.03$ uname -sr
SunOS 5.8

bash-2.03$ perl -le 'print for 1..49999998' &gt; infile

bash-2.03$ wc -l infile
 49999998 infile

bash-2.03$ time paste -sd+ infile | bc
bundling space exceeded on line 1, teletype
Broken Pipe

real 0m0.062s
user 0m0.010s
sys 0m0.010s

bash-2.03$ time nawk '{s+=$1}END{print s}' infile
1249999925000001

real 2m0.042s
user 1m59.220s
sys 0m0.590s
bash-2.03$ time /usr/xpg4/bin/awk '{s+=$1}END{print s}' infile
1249999925000001

real 2m27.260s
user 2m26.230s
sys 0m0.660s

bash-2.03$ time perl -nle'
 $s += $_; END { print $s }
 ' infile
1.249999925e+15

real 1m34.663s
user 1m33.710s
sys 0m0.650s
</code></pre>

blocks|key|1002116|text|以下命令将添加所有行(+awk输出的第一个字段)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1002117|awk+'{s%2B=$1}+END+{print+s}'+filename|code-block|syntax|javascript|1002118|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The following command will add all the lines(first field of the awk output)

<pre><code>awk '{s+=$1} END {print s}' filename
</code></pre>

blocks|key|1002157|text|如果您安装了ruby|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1002158|cat+FileWithColumnOfNumbers.txt+%7C+xargs+ruby+-e+"puts+ARGV.map(&:to_i).inject(&:%2B)"|code-block|syntax|javascript|1002159|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you have ruby installed

<pre><code>cat FileWithColumnOfNumbers.txt | xargs ruby -e "puts ARGV.map(&amp;:to_i).inject(&amp;:+)"
</code></pre>

blocks|key|1002161|text|[root@pentest3r+~]#+(find+/+-xdev+-size+%2B1024M)+%7C+(while+read+a+;+do+aa=$(du+-sh+$a+%7C+cut+-d+"."+-f1+);+o=$((+$o%2B$aa+));+done;+echo+"$o";)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1002162|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>[root@pentest3r ~]# (find / -xdev -size +1024M) | (while read a ; do aa=$(du -sh $a | cut -d "." -f1 ); o=$(( $o+$aa )); done; echo "$o";)
</code></pre>

I want a bash command that I can pipe into that will sum a column of numbers. I just want a quick one liner that will do something essentially like this:

<pre><code>cat FileWithColumnOfNumbers.txt | sum
</code></pre>

Bash command to sum a column of numbers

MacOS

Perl

我想要一个bash命令，我可以通过管道输入它来对一列数字求和。我只想要一个快速的线性，它将做一些事情，基本上像这样：cat FileWithColumnOfNumbers.txt | sum

问用于对一列数字求和的Bash命令
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