blocks|key|905851|text|find+$directory+-type+f+-name+"*.in"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|905852|比整个代码要短一点(而且更安全--处理文件名和目录名中的空格)。|unstyled|905853|对于名称中没有.的条目，脚本可能会失败，从而使$extension为空。|offset|length|style|CODE|905854|entityMap^0|0|0|7|1|N|A|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|P|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|N|$]]

<pre><code>find $directory -type f -name "*.in"
</code></pre>

is a bit shorter than that whole thing (and safer - deals with whitespace in filenames and directory names).

Your script is probably failing for entries that don't have a <code>.</code> in their name, making <code>$extension</code> empty.

blocks|key|905890|text|我使用的语法与@Matt建议的稍有不同：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|905891|find+$directory+-type+f+-name+\*.in|code-block|syntax|javascript|905892|(减少了一次击键操作)。|905893|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

The syntax I use is a bit different than what @Matt suggested: 

<pre><code>find $directory -type f -name \*.in
</code></pre>

(it's one less keystroke).

blocks|key|689708|text|要查找当前目录中的所有pom.xml文件并打印它们，您可以使用：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|689709|find+.+-name+'pom.xml'+-print|code-block|syntax|javascript|689710|entityMap^0|B|7|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

To find all the <code>pom.xml</code> files in your current directory and print them, you can use:

<pre><code>find . -name 'pom.xml' -print
</code></pre>

blocks|key|905971|text|find+$directory+-type+f+-name+"*.in"%7Cgrep+$substring|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|905972|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>find $directory -type f -name "*.in"|grep $substring
</code></pre>

blocks|key|689772|text|不使用find|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|689773|du+-a+$directory+%7C+awk+'{print+$2}'+%7C+grep+'\.in$'|code-block|syntax|javascript|689774|entityMap^0|3|4|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Without using <code>find</code>:

<pre><code>du -a $directory | awk '{print $2}' | grep '\.in$'
</code></pre>

blocks|key|689785|text|for+file+in+"${LOCATION_VAR}"/*.zip
do
++echo+"$file"
done+|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|689786|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>for file in "${LOCATION_VAR}"/*.zip
do
 echo "$file"
done 
</code></pre>

blocks|key|689860|text|尽管在这里使用find命令可能很有用，但shell本身提供了一些选项来实现这一要求，而不需要任何第三方工具。bash+shell提供了一个扩展的glob支持选项，您可以使用该选项获取与您想要的扩展名匹配的递归路径下的文件名。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|689861|扩展选项是extglob，需要使用shopt选项进行设置，如下所示。这些选项使用-s支持启用，使用-u标志禁用。此外，您可以使用更多的几个选项，例如nullglob，其中不匹配的glob被完全扫除，代之以一组零单词。以及允许递归遍历所有目录的globstar|689862|shopt+-s+extglob+nullglob+globstar|code-block|syntax|javascript|689863|现在，您所需要做的就是形成glob表达式，以包含具有特定扩展名的文件，您可以执行以下操作。我们使用一个数组来填充glob结果，因为当正确引用和展开时，带有特殊字符的文件名将保持不变，也不会因为shell的分词而中断。|689864|例如，列出递归路径中的所有*.csv文件|689865|fileList=(**/*.csv)|689866|选项**是递归通过子文件夹，而*.csv是全局扩展，以包括所提到的扩展名的任何文件。现在要打印实际的文件，只需执行以下操作|689867|printf+'%25s\n'+"${fileList[@]}"|689868|在shell脚本中使用数组并进行适当的带引号的扩展是正确的方法，但是对于交互式使用，您可以简单地将ls与glob表达式一起使用，如下所示|689869|ls+-1+--+**/*.csv|689870|这可以很好地扩展以匹配多个文件，即以多个扩展名结尾的文件(即类似于在find命令中添加多个标志)。例如，考虑一个需要获取所有递归图像文件的情况，即扩展名为*.gif、*.png和*.jpg的文件，您需要做的就是|689871|ls+-1+--+**/%2B(*.jpg%7C*.gif%7C*.png)|689872|这可以很好地扩展到也有否定的结果。使用相同的语法，可以使用glob的结果来排除某些类型的文件。假设您想要排除具有上述扩展名的文件名，您可以这样做|689873|excludeResults=()
excludeResults=(**/!(*.jpg%7C*.gif%7C*.png))
printf+'%25s\n'+"${excludeResults[@]}"|689874|构造!()是一个求反操作，不包括其中列出的任何文件扩展名，而%7C是一个交替操作符，就像在扩展正则表达式库中用来对globs进行OR匹配一样。|689875|请注意，这些扩展的glob支持在POSIX+bourne+shell中不可用，它纯粹特定于bash的最新版本。因此，如果您正在考虑跨POSIX和bash+shell运行的脚本的可移植性，那么这个选项是不正确的。|689876|entityMap^0|7|4|1I|4|0|5|7|H|5|14|2|1D|2|22|8|3D|8|0|0|0|D|5|0|0|2|2|F|5|0|0|1D|2|0|0|Y|4|25|5|2B|5|2H|5|0|0|0|0|2|3|U|1|0|19|4|20|4|0^^$0|@$1|2|3|4|5|6|7|1E|8|@$9|1F|A|1G|B|C]|$9|1H|A|1I|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1J|8|@$9|1K|A|1L|B|C]|$9|1M|A|1N|B|C]|$9|1O|A|1P|B|C]|$9|1Q|A|1R|B|C]|$9|1S|A|1T|B|C]|$9|1U|A|1V|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|1W|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1X|8|@]|D|@]|E|$]]|$1|O|3|P|5|6|7|1Y|8|@$9|1Z|A|20|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|J|7|21|8|@]|D|@]|E|$K|L]]|$1|S|3|T|5|6|7|22|8|@$9|23|A|24|B|C]|$9|25|A|26|B|C]]|D|@]|E|$]]|$1|U|3|V|5|J|7|27|8|@]|D|@]|E|$K|L]]|$1|W|3|X|5|6|7|28|8|@$9|29|A|2A|B|C]]|D|@]|E|$]]|$1|Y|3|Z|5|J|7|2B|8|@]|D|@]|E|$K|L]]|$1|10|3|11|5|6|7|2C|8|@$9|2D|A|2E|B|C]|$9|2F|A|2G|B|C]|$9|2H|A|2I|B|C]|$9|2J|A|2K|B|C]]|D|@]|E|$]]|$1|12|3|13|5|J|7|2L|8|@]|D|@]|E|$K|L]]|$1|14|3|15|5|6|7|2M|8|@]|D|@]|E|$]]|$1|16|3|17|5|J|7|2N|8|@]|D|@]|E|$K|L]]|$1|18|3|19|5|6|7|2O|8|@$9|2P|A|2Q|B|C]|$9|2R|A|2S|B|C]]|D|@]|E|$]]|$1|1A|3|1B|5|6|7|2T|8|@$9|2U|A|2V|B|C]|$9|2W|A|2X|B|C]]|D|@]|E|$]]|$1|1C|3|-4|5|6|7|2Y|8|@]|D|@]|E|$]]]|1D|$]]

Though using <code>find</code> command can be useful here, the shell itself provides options to achieve this requirement without any third party tools. The <code>bash</code> shell provides an extended glob support option using which you can get the file names under recursive paths that match with the extensions you want.

The extended option is <code>extglob</code> which needs to be set using the <code>shopt</code> option as below. The options are enabled with the <code>-s</code> support and disabled with he <code>-u</code> flag. Additionally you could use couple of options more i.e. <code>nullglob</code> in which an unmatched glob is swept away entirely, replaced with a set of zero words. And <code>globstar</code> that allows to recurse through all the directories

<pre><code>shopt -s extglob nullglob globstar
</code></pre>

Now all you need to do is form the glob expression to include the files of a certain extension which you can do as below. We use an array to populate the glob results because when quoted properly and expanded, the filenames with special characters would remain intact and not get broken due to word-splitting by the shell. 

For example to list all the <code>*.csv</code> files in the recursive paths 

<pre><code>fileList=(**/*.csv)
</code></pre>

The option <code>**</code> is to recurse through the sub-folders and <code>*.csv</code> is glob expansion to include any file of the extensions mentioned. Now for printing the actual files, just do

<pre><code>printf '%s\n' "${fileList[@]}"
</code></pre>

Using an array and doing a proper quoted expansion is the right way when used in shell scripts, but for interactive use, you could simply use <code>ls</code> with the glob expression as 

<pre><code>ls -1 -- **/*.csv
</code></pre>

This could very well be expanded to match multiple files i.e. file ending with multiple extension (i.e. similar to adding multiple flags in <code>find</code> command). For example consider a case of needing to get all recursive image files i.e. of extensions <code>*.gif</code>, <code>*.png</code> and <code>*.jpg</code>, all you need to is

<pre><code>ls -1 -- **/+(*.jpg|*.gif|*.png)
</code></pre>

This could very well be expanded to have negate results also. With the same syntax, one could use the results of the glob to exclude files of certain type. Assume you want to exclude file names with the extensions above, you could do

<pre><code>excludeResults=()
excludeResults=(**/!(*.jpg|*.gif|*.png))
printf '%s\n' "${excludeResults[@]}"
</code></pre>

The construct <code>!()</code> is a negate operation to not include any of the file extensions listed inside and <code>|</code> is an alternation operator just as used in the Extended Regular Expressions library to do an OR match of the globs.

Note that these extended glob support is not available in the POSIX bourne shell and its purely specific to recent versions of <code>bash</code>. So if your are considering portability of the scripts running across POSIX and <code>bash</code> shells, this option wouldn't be right.

blocks|key|689881|text|find+"$PWD"+-type+f+-name+"*.in"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|689882|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

I'm trying to find all files with a specific extension in a directory and its subdirectories with my bash (Latest Ubuntu LTS Release).

This is what's written in a script file:

<pre><code>#!/bin/bash

directory="/home/flip/Desktop"
suffix="in"

browsefolders ()
 for i in "$1"/*; 
 do
 echo "dir :$directory"
 echo "filename: $i"
 # echo ${i#*.}
 extension=`echo "$i" | cut -d'.' -f2`
 echo "Erweiterung $extension"
 if [ -f "$i" ]; then 

 if [ $extension == $suffix ]; then
 echo "$i ends with $in"

 else
 echo "$i does NOT end with $in"
 fi
 elif [ -d "$i" ]; then 
 browsefolders "$i"
 fi
 done
}
browsefolders "$directory"
</code></pre>

Unfortunately, when I start this script in terminal, it says:

<pre><code>[: 29: in: unexpected operator
</code></pre>

(with <code>$extension</code> instead of <code>'in'</code>)

What's going on here, where's the error?
But this curly brace

Recursively look for files with a specific extension

Ubuntu

我正在尝试用我的bash (最新的Ubuntu LTS版本)在一个目录及其子目录中查找具有特定扩展名的所有文件。下面是脚本文件中写的内容：#!/bin/bashdirectory="/home/flip/Desktop"suffix="in"browsefolders ()  for i in "$1"/*;   do...

问递归查找具有特定扩展名的文件
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