blocks|key|42979|text|事实证明，Java不接受纯日期值作为DateTime。使用LocalDate而不是LocalDateTime解决了这个问题：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|42980|DateTimeFormatter+formatter+=+DateTimeFormatter.ofPattern("yyyyMMdd");
LocalDate+dt+=+LocalDate.parse("20140218",+formatter);|code-block|syntax|javascript|42981|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

It turns out Java does not accept a bare Date value as DateTime. Using LocalDate instead of LocalDateTime solves the issue:

<pre><code>DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMdd");
LocalDate dt = LocalDate.parse("20140218", formatter);
</code></pre>

blocks|key|43019|text|这是一个非常不清楚和没有帮助的错误消息。经过多次尝试和错误，我发现如果您不尝试解析时间，LocalDateTime会给出上述错误。通过使用LocalDate，它可以在不出错的情况下工作。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|43020|这方面的文档很少，相关的异常也没有多大帮助。|43021|entityMap^0|18|D|1X|9|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|O|8|@]|D|@]|E|$]]|$1|H|3|-4|5|6|7|P|8|@]|D|@]|E|$]]]|I|$]]

This is a really unclear and unhelpful error message. After much trial and error I found that <code>LocalDateTime</code> will give the above error if you do not attempt to parse a time. By using <code>LocalDate</code> instead, it works without erroring.

This is poorly documented and the related exception is very unhelpful.

blocks|key|43045|text|如果确实需要将日期转换为LocalDateTime对象，可以使用LocalDate.atStartOfDay()。这将为您提供一个指定日期的LocalDateTime对象，其中的小时、分钟和秒字段设置为0：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|43046|final+DateTimeFormatter+formatter+=+DateTimeFormatter.ofPattern("yyyyMMdd");
LocalDateTime+time+=+LocalDate.parse("20140218",+formatter).atStartOfDay();|code-block|syntax|javascript|43047|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you really need to transform a date to a LocalDateTime object, you could use the LocalDate.atStartOfDay(). This will give you a LocalDateTime object at the specified date, having the hour, minute and second fields set to 0: 

<pre><code>final DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMdd");
LocalDateTime time = LocalDate.parse("20140218", formatter).atStartOfDay();
</code></pre>

blocks|key|4549873|text|如果有人(像我一样)应该再读一遍这个主题，那么正确的答案应该是DateTimeFormatter定义，例如：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4549874|private+static+DateTimeFormatter+DATE_FORMAT+=++
++++++++++++new+DateTimeFormatterBuilder().appendPattern("dd/MM/yyyy[+[HH][:mm][:ss][.SSS]]")
++++++++++++.parseDefaulting(ChronoField.HOUR_OF_DAY,+0)
++++++++++++.parseDefaulting(ChronoField.MINUTE_OF_HOUR,+0)
++++++++++++.parseDefaulting(ChronoField.SECOND_OF_MINUTE,+0)
++++++++++++.toFormatter();+|code-block|syntax|javascript|4549875|如果要显示可选字段，则应设置这些字段。其余的代码应该完全相同。|4549876|entityMap^0|V|H|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

For what is worth if anyone should read again this topic(like me) the correct answer would be in <code>DateTimeFormatter</code> definition, e.g.:

<pre><code>private static DateTimeFormatter DATE_FORMAT = 
 new DateTimeFormatterBuilder().appendPattern("dd/MM/yyyy[ [HH][:mm][:ss][.SSS]]")
 .parseDefaulting(ChronoField.HOUR_OF_DAY, 0)
 .parseDefaulting(ChronoField.MINUTE_OF_HOUR, 0)
 .parseDefaulting(ChronoField.SECOND_OF_MINUTE, 0)
 .toFormatter(); 
</code></pre>

One should set the optional fields if they will appear. And the rest of code should be exactly the same.

blocks|key|43087|text|在retrography's+answer上扩展:即使在使用LocalDate而不是LocalDateTime时，我也遇到了同样的问题。问题是我使用.withResolverStyle(ResolverStyle.STRICT);创建了我的DateTimeFormatter，所以我不得不使用日期模式uuuuMMdd而不是yyyyMMdd+(即"year“而不是"year-+of+-era")！|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|43088|DateTimeFormatter+formatter+=+new+DateTimeFormatterBuilder()
++.parseStrict()
++.appendPattern("uuuuMMdd")
++.toFormatter()
++.withResolverStyle(ResolverStyle.STRICT);
LocalDate+dt+=+LocalDate.parse("20140218",+formatter);|code-block|syntax|javascript|43089|(这个解决方案最初是对retrography的答案的一种评论，但我被鼓励将其作为一个独立的答案发布，因为它显然对许多人都很有效。)|43090|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/27454146/1333157^0|U|9|16|D|22|15|3C|H|46|8|4H|8|1|K|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]|$9|13|A|14|B|C]|$9|15|A|16|B|C]]|D|@$9|17|A|18|1|19]]|E|$]]|$1|F|3|G|5|H|7|1A|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1B|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|1C|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

Expanding on <a href="https://stackoverflow.com/a/27454146/1333157">retrography's answer</a>..: I had this same problem even when using <code>LocalDate</code> and not <code>LocalDateTime</code>. The issue was that I had created my <code>DateTimeFormatter</code> using <code>.withResolverStyle(ResolverStyle.STRICT);</code>, so I had to use date pattern <code>uuuuMMdd</code> instead of <code>yyyyMMdd</code> (i.e. "year" instead of "year-of-era")!

<pre><code>DateTimeFormatter formatter = new DateTimeFormatterBuilder()
 .parseStrict()
 .appendPattern("uuuuMMdd")
 .toFormatter()
 .withResolverStyle(ResolverStyle.STRICT);
LocalDate dt = LocalDate.parse("20140218", formatter);
</code></pre>

(This solution was originally a comment to retrography's answer, but I was encouraged to post it as a stand-alone answer because it apparently works really well for many people.)

blocks|key|4549916|text|对于任何带着这个错误登陆的人，就像我一样：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4549917|Unable+to+obtain+LocalDateTime+from+TemporalAccessor:+{HourOfAmPm=0,+MinuteOfHour=0}|offset|length|style|CODE|4549918|它来自下面的一句话：|4549919|LocalDateTime.parse(date,+DateTimeFormatter.ofPattern("M/d/yy+h:mm"));|code-block|syntax|javascript|4549920|事实证明，这是因为我在0小时上使用了12小时模式，而不是24小时模式。|4549921|通过使用大写H将小时模式更改为24小时模式可以解决此问题：|4549922|LocalDateTime.parse(date,+DateTimeFormatter.ofPattern("M/d/yy+H:mm"));|4549923|entityMap^0|0|0|2C|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@$D|Y|E|Z|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|10|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|11|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|12|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|13|8|@]|9|@]|A|$]]|$1|S|3|T|5|L|7|14|8|@]|9|@]|A|$M|N]]|$1|U|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|V|$]]

For anyone who landed here with this error, like I did:

<code>Unable to obtain LocalDateTime from TemporalAccessor: {HourOfAmPm=0, MinuteOfHour=0}</code>

It came from a the following line: 

<pre><code>LocalDateTime.parse(date, DateTimeFormatter.ofPattern("M/d/yy h:mm"));
</code></pre>

It turned out that it was because I was using a 12hr Hour pattern on a 0 hour, instead of a 24hr pattern. 

Changing the hour to 24hr pattern by using a capital H fixes it:

<pre><code>LocalDateTime.parse(date, DateTimeFormatter.ofPattern("M/d/yy H:mm"));
</code></pre>

blocks|key|43178|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|43179|DateTimeFormatter+dateTimeFormatter+=+DateTimeFormatter.ofPattern("MM-dd-yyyy");+
LocalDate+fromLocalDate+=+LocalDate.parse(fromdstrong+textate,+dateTimeFormatter);|code-block|syntax|javascript|43180|您可以添加所需的任何格式。这对我很有效！|43181|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Try this one:

<pre><code>DateTimeFormatter dateTimeFormatter = DateTimeFormatter.ofPattern("MM-dd-yyyy"); 
LocalDate fromLocalDate = LocalDate.parse(fromdstrong textate, dateTimeFormatter);
</code></pre>

You can add any format you want. That works for me!

blocks|key|43248|text|这个很好用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|43249|public+class+DateDemo+{
++++public+static+void+main(String[]+args)+{
++++++++DateTimeFormatter+formatter+=+DateTimeFormatter.ofPattern("dd-MM-yyyy+hh:mm");
++++++++String+date+=+"16-08-2018+12:10";
++++++++LocalDate+localDate+=+LocalDate.parse(date,+formatter);
++++++++System.out.println("VALUE="%2BlocalDate);

++++++++DateTimeFormatter+formatter1+=+DateTimeFormatter.ofPattern("dd-MM-yyyy+HH:mm");
++++++++LocalDateTime+parse+=+LocalDateTime.parse(date,+formatter1);
++++++++System.out.println("VALUE1="%2Bparse);
++++}
}|code-block|syntax|javascript|43250|输出：|43251|VALUE=2018-08-16
VALUE1=2018-08-16T12:10|43252|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

This works fine

<pre><code>public class DateDemo {
 public static void main(String[] args) {
 DateTimeFormatter formatter = DateTimeFormatter.ofPattern("dd-MM-yyyy hh:mm");
 String date = "16-08-2018 12:10";
 LocalDate localDate = LocalDate.parse(date, formatter);
 System.out.println("VALUE="+localDate);

 DateTimeFormatter formatter1 = DateTimeFormatter.ofPattern("dd-MM-yyyy HH:mm");
 LocalDateTime parse = LocalDateTime.parse(date, formatter1);
 System.out.println("VALUE1="+parse);
 }
}
</code></pre>

output:

<pre><code>VALUE=2018-08-16
VALUE1=2018-08-16T12:10
</code></pre>

blocks|key|4549972|text|我遇到这个问题是因为我的输入字符串中没有年份：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4549973|输入字符串：Tuesday,+June+8+at+10:00+PM|offset|length|style|CODE|4549974|格式化程序：DateTimeFormatter.ofPattern("EEEE,+MMMM+d+'at'+h:mm+a",+Locale.US);|4549975|我知道年份，所以我只需将其附加到get：|4549976|输入字符串：Tuesday,+June+8+at+6:30+PM+2021|4549977|格式化程序：DateTimeFormatter.ofPattern("EEEE,+MMMM+d+'at'+h:mm+a+uuuu",+Locale.US);|4549978|entityMap^0|0|6|R|0|6|1V|0|0|6|V|0|6|20|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@$D|T|E|U|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|V|8|@$D|W|E|X|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|Y|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|Z|8|@$D|10|E|11|F|G]]|9|@]|A|$]]|$1|N|3|O|5|6|7|12|8|@$D|13|E|14|F|G]]|9|@]|A|$]]|$1|P|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|Q|$]]

I arrived at this problem because my input string didn't have a year in it:
input string: <code>Tuesday, June 8 at 10:00 PM</code> 
formatter: <code>DateTimeFormatter.ofPattern(&quot;EEEE, MMMM d 'at' h:mm a&quot;, Locale.US);</code>
I knew the year so I just appended it to get:
input string: <code>Tuesday, June 8 at 6:30 PM 2021</code> 
formatter: <code>DateTimeFormatter.ofPattern(&quot;EEEE, MMMM d 'at' h:mm a uuuu&quot;, Locale.US);</code>

blocks|key|43279|text|+DateTimeFormatter+format+=+new+DateTimeFormatterBuilder()
++++++++++++++++++++++++++++.appendPattern("yyyy-MM-dd")
++++++++++++++++++++++++++++.parseDefaulting(ChronoField.HOUR_OF_DAY,+0)
++++++++++++++++++++++++++++.parseDefaulting(ChronoField.MINUTE_OF_HOUR,+0)
++++++++++++++++++++++++++++.parseDefaulting(ChronoField.SECOND_OF_MINUTE,+0)
++++++++++++++++++++++++++++.parseDefaulting(ChronoField.MILLI_OF_SECOND,+0)
++++++++++++++++++++++++++++.toFormatter();|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|43280|对我很管用|unstyled|43281|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code> DateTimeFormatter format = new DateTimeFormatterBuilder()
 .appendPattern(&quot;yyyy-MM-dd&quot;)
 .parseDefaulting(ChronoField.HOUR_OF_DAY, 0)
 .parseDefaulting(ChronoField.MINUTE_OF_HOUR, 0)
 .parseDefaulting(ChronoField.SECOND_OF_MINUTE, 0)
 .parseDefaulting(ChronoField.MILLI_OF_SECOND, 0)
 .toFormatter();
</code></pre>
Works for me

blocks|key|4550000|text|如果您只是想采用一种格式(不管它是否有时间)并希望解析为LocalDateTime，您可以执行以下操作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4550001|LocalDateTime+parseDateTime(String+dateTime,+DateTimeFormatter+fmt)+{
++return+fmt.parse(dateTime,+t+->+{
++++LocalDate+date+=+t.query(TemporalQueries.localDate());
++++LocalTime+time+=+t.query(TemporalQueries.localTime());
++++return+LocalDateTime.of(date,+time+!=+null+?+time+:+LocalTime.MIDNIGHT);
++});
}|code-block|syntax|javascript|4550002|我需要它，因为我要将日期/时间模式作为自定义Spark+UDF的参数。|4550003|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

In cases where you simply want to take a format (whether or not it has time) and want to parse to a LocalDateTime, you can do the following.
<pre class="lang-java prettyprint-override"><code>LocalDateTime parseDateTime(String dateTime, DateTimeFormatter fmt) {
 return fmt.parse(dateTime, t -&gt; {
 LocalDate date = t.query(TemporalQueries.localDate());
 LocalTime time = t.query(TemporalQueries.localTime());
 return LocalDateTime.of(date, time != null ? time : LocalTime.MIDNIGHT);
 });
}
</code></pre>
I needed this because I was getting the date/time pattern as a parameter for a custom Spark UDF.

I am simply trying to convert a date string into a DateTime object in Java 8. Upon running the following lines:

<pre><code>DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMdd");
LocalDateTime dt = LocalDateTime.parse("20140218", formatter);
</code></pre>

I get the following error:

<pre><code>Exception in thread "main" java.time.format.DateTimeParseException: 
Text '20140218' could not be parsed: 
Unable to obtain LocalDateTime from TemporalAccessor: 
{},ISO resolved to 2014-02-18 of type java.time.format.Parsed
 at java.time.format.DateTimeFormatter.createError(DateTimeFormatter.java:1918)
 at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1853)
 at java.time.LocalDateTime.parse(LocalDateTime.java:492)
</code></pre>

The syntax is identical to what has been suggested <a href="https://stackoverflow.com/questions/22463062/how-to-parse-format-dates-with-localdatetime-java-8">here</a>, yet I am served with an exception. I am using <code>JDK-8u25</code>.

Unable to obtain LocalDateTime from TemporalAccessor when parsing LocalDateTime (Java 8)

Spark 

Java

我只是尝试在Java8中将日期字符串转换为DateTime对象。DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMdd");LocalDateTime dt = LocalDateTime.parse("20140218", formatt...

问解析LocalDateTime时无法从TemporalAccessor获取LocalDateTime (Java8)
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