blocks|key|868265|text|DateTime+nextTuesday+=+DateTime.Today.AddDays(((int)DateTime.Today.DayOfWeek+-+(int)DayOfWeek.Tuesday)+%2B+7);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|868266|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>DateTime nextTuesday = DateTime.Today.AddDays(((int)DateTime.Today.DayOfWeek - (int)DayOfWeek.Tuesday) + 7);
</code></pre>

blocks|key|650917|text|这应该能起到作用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|650918|static+DateTime+GetNextWeekday(DayOfWeek+day)
{
++++DateTime+result+=+DateTime.Now.AddDays(1);
++++while(+result.DayOfWeek+!=+day+)
++++++++result+=+result.AddDays(1);
++++return+result;
}|code-block|syntax|javascript|650919|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This should do the trick:

<pre><code>static DateTime GetNextWeekday(DayOfWeek day)
{
 DateTime result = DateTime.Now.AddDays(1);
 while( result.DayOfWeek != day )
 result = result.AddDays(1);
 return result;
}
</code></pre>

blocks|key|650921|text|DateTime+nexttuesday=DateTime.Today.AddDays(1);

while(nexttuesday.DayOfWeek!=DayOfWeek.Tuesday)
+++nexttuesday+=+nexttuesday.AddDays(1);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|650922|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>DateTime nexttuesday=DateTime.Today.AddDays(1);

while(nexttuesday.DayOfWeek!=DayOfWeek.Tuesday)
 nexttuesday = nexttuesday.AddDays(1);
</code></pre>

blocks|key|868331|text|正如我在评论中提到的，你可以用“下周二”来表示各种事情，但这段代码给了你“下一个星期二发生的时间，或者如果已经是星期二的话就是今天”：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|868332|DateTime+today+=+DateTime.Today;
//+The+(...+%2B+7)+%25+7+ensures+we+end+up+with+a+value+in+the+range+[0,+6]
int+daysUntilTuesday+=+((int)+DayOfWeek.Tuesday+-+(int)+today.DayOfWeek+%2B+7)+%25+7;
DateTime+nextTuesday+=+today.AddDays(daysUntilTuesday);|code-block|syntax|javascript|868333|如果你想给出“一周的时间”，如果已经是星期二了，你可以使用：|868334|//+This+finds+the+next+Monday+(or+today+if+it's+Monday)+and+then+adds+a+day...+so+the
//+result+is+in+the+range+[1-7]
int+daysUntilTuesday+=+(((int)+DayOfWeek.Monday+-+(int)+today.DayOfWeek+%2B+7)+%25+7)+%2B+1;|868335|..。或者你可以使用原来的公式，但从明天开始：|868336|DateTime+tomorrow+=+DateTime.Today.AddDays(1);
//+The+(...+%2B+7)+%25+7+ensures+we+end+up+with+a+value+in+the+range+[0,+6]
int+daysUntilTuesday+=+((int)+DayOfWeek.Tuesday+-+(int)+tomorrow.DayOfWeek+%2B+7)+%25+7;
DateTime+nextTuesday+=+tomorrow.AddDays(daysUntilTuesday);|868337|编辑:只是为了让它变得更好更通用：|868338|public+static+DateTime+GetNextWeekday(DateTime+start,+DayOfWeek+day)
{
++++//+The+(...+%2B+7)+%25+7+ensures+we+end+up+with+a+value+in+the+range+[0,+6]
++++int+daysToAdd+=+((int)+day+-+(int)+start.DayOfWeek+%2B+7)+%25+7;
++++return+start.AddDays(daysToAdd);
}|868339|因此，要获取“今天或未来6天”的值：|868340|DateTime+nextTuesday+=+GetNextWeekday(DateTime.Today,+DayOfWeek.Tuesday);|868341|要获取“不包括今天的下周二”的值：|868342|DateTime+nextTuesday+=+GetNextWeekday(DateTime.Today.AddDays(1),+DayOfWeek.Tuesday);|868343|entityMap^0|0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|14|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|16|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|18|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|1A|8|@]|9|@]|A|$]]|$1|U|3|V|5|D|7|1B|8|@]|9|@]|A|$E|F]]|$1|W|3|X|5|6|7|1C|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|D|7|1D|8|@]|9|@]|A|$E|F]]|$1|10|3|-4|5|6|7|1E|8|@]|9|@]|A|$]]]|11|$]]

As I've mentioned in the comments, there are various things you could mean by "next Tuesday", but this code gives you "the next Tuesday to occur, or today if it's already Tuesday":

<pre><code>DateTime today = DateTime.Today;
// The (... + 7) % 7 ensures we end up with a value in the range [0, 6]
int daysUntilTuesday = ((int) DayOfWeek.Tuesday - (int) today.DayOfWeek + 7) % 7;
DateTime nextTuesday = today.AddDays(daysUntilTuesday);
</code></pre>

If you want to give "a week's time" if it's already Tuesday, you can use:

<pre><code>// This finds the next Monday (or today if it's Monday) and then adds a day... so the
// result is in the range [1-7]
int daysUntilTuesday = (((int) DayOfWeek.Monday - (int) today.DayOfWeek + 7) % 7) + 1;
</code></pre>

... or you could use the original formula, but from tomorrow:

<pre><code>DateTime tomorrow = DateTime.Today.AddDays(1);
// The (... + 7) % 7 ensures we end up with a value in the range [0, 6]
int daysUntilTuesday = ((int) DayOfWeek.Tuesday - (int) tomorrow.DayOfWeek + 7) % 7;
DateTime nextTuesday = tomorrow.AddDays(daysUntilTuesday);
</code></pre>

EDIT: Just to make this nice and versatile:

<pre><code>public static DateTime GetNextWeekday(DateTime start, DayOfWeek day)
{
 // The (... + 7) % 7 ensures we end up with a value in the range [0, 6]
 int daysToAdd = ((int) day - (int) start.DayOfWeek + 7) % 7;
 return start.AddDays(daysToAdd);
}
</code></pre>

So to get the value for "today or in the next 6 days":

<pre><code>DateTime nextTuesday = GetNextWeekday(DateTime.Today, DayOfWeek.Tuesday);
</code></pre>

To get the value for "the next Tuesday excluding today":

<pre><code>DateTime nextTuesday = GetNextWeekday(DateTime.Today.AddDays(1), DayOfWeek.Tuesday);
</code></pre>

blocks|key|651003|text|对于这个问题，有一些不太冗长、更聪明、更优雅的解决方案，但下面的C#函数在许多情况下都能很好地工作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|651004|///+<summary>
///+Find+the+closest+weekday+to+the+given+date
///+</summary>
///+<param+name="includeStartDate">if+the+supplied+date+is+on+the+specified+day+of+the+week,+return+that+date+or+continue+to+the+next+date</param>
///+<param+name="searchForward">search+forward+or+backward+from+the+supplied+date.+if+a+null+parameter+is+given,+the+closest+weekday+(ie+in+either+direction)+is+returned</param>
public+static+DateTime+ClosestWeekDay(this+DateTime+date,+DayOfWeek+weekday,+bool+includeStartDate+=+true,+bool?+searchForward=true)
{
++++if+(!searchForward.HasValue+&&+!includeStartDate)+
++++{
++++++++throw+new+ArgumentException("if+searching+in+both+directions,+start+date+must+be+a+valid+result");
++++}
++++var+day+=+date.DayOfWeek;
++++int+add+=+((int)weekday+-+(int)day);
++++if+(searchForward.HasValue)
++++{
++++++++if+(add+<+0+&&+searchForward.Value)
++++++++{
++++++++++++add+%2B=+7;
++++++++}
++++++++else+if+(add+>+0+&&+!searchForward.Value)
++++++++{
++++++++++++add+-=+7;
++++++++}
++++++++else+if+(add+==+0+&&+!includeStartDate)
++++++++{
++++++++++++add+=+searchForward.Value+?+7+:+-7;
++++++++}
++++}
++++else+if+(add+<+-3)+
++++{
++++++++add+%2B=+7;+
++++}
++++else+if+(add+>+3)
++++{
++++++++add+-=+7;
++++}
++++return+date.AddDays(add);
}|code-block|syntax|javascript|651005|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

There are less verbose and more clever/elegant solutions to this problem, but the following C# function works really well for a number of situations.

<pre><code>/// &lt;summary&gt;
/// Find the closest weekday to the given date
/// &lt;/summary&gt;
/// &lt;param name="includeStartDate"&gt;if the supplied date is on the specified day of the week, return that date or continue to the next date&lt;/param&gt;
/// &lt;param name="searchForward"&gt;search forward or backward from the supplied date. if a null parameter is given, the closest weekday (ie in either direction) is returned&lt;/param&gt;
public static DateTime ClosestWeekDay(this DateTime date, DayOfWeek weekday, bool includeStartDate = true, bool? searchForward=true)
{
 if (!searchForward.HasValue &amp;&amp; !includeStartDate) 
 {
 throw new ArgumentException("if searching in both directions, start date must be a valid result");
 }
 var day = date.DayOfWeek;
 int add = ((int)weekday - (int)day);
 if (searchForward.HasValue)
 {
 if (add &lt; 0 &amp;&amp; searchForward.Value)
 {
 add += 7;
 }
 else if (add &gt; 0 &amp;&amp; !searchForward.Value)
 {
 add -= 7;
 }
 else if (add == 0 &amp;&amp; !includeStartDate)
 {
 add = searchForward.Value ? 7 : -7;
 }
 }
 else if (add &lt; -3) 
 {
 add += 7; 
 }
 else if (add &gt; 3)
 {
 add -= 7;
 }
 return date.AddDays(add);
}
</code></pre>

blocks|key|651050|text|@Jon+Skeet回答得很好。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|651051|对于前一天：|651052|private+DateTime+GetPrevWeekday(DateTime+start,+DayOfWeek+day)+{
++++//+The+(...+-+7)+%25+7+ensures+we+end+up+with+a+value+in+the+range+[0,+6]
++++int+daysToRemove+=+((int)+day+-+(int)+start.DayOfWeek+-+7)+%25+7;
++++return+start.AddDays(daysToRemove);
}|code-block|syntax|javascript|651053|谢谢！！|651054|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

@Jon Skeet good answer.

For previous Day:

<pre><code>private DateTime GetPrevWeekday(DateTime start, DayOfWeek day) {
 // The (... - 7) % 7 ensures we end up with a value in the range [0, 6]
 int daysToRemove = ((int) day - (int) start.DayOfWeek - 7) % 7;
 return start.AddDays(daysToRemove);
}
</code></pre>

Thanks!!

blocks|key|868418|text|现在是oneliner风格--以防你需要将它作为参数传递到某个机制中。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|868419|DateTime.Now.AddDays(((int)yourDate.DayOfWeek+-+(int)DateTime.Now.DayOfWeek+%2B+7)+%25+7).Day|code-block|syntax|javascript|868420|在此特定情况下：|868421|DateTime.Now.AddDays(((int)DayOfWeek.Tuesday+-+(int)DateTime.Now.DayOfWeek+%2B+7)+%25+7).Day|868422|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Now in oneliner flavor - in case you need to pass it as parameter into some mechanism.

<pre><code>DateTime.Now.AddDays(((int)yourDate.DayOfWeek - (int)DateTime.Now.DayOfWeek + 7) % 7).Day
</code></pre>

In this specific case:

<pre><code>DateTime.Now.AddDays(((int)DayOfWeek.Tuesday - (int)DateTime.Now.DayOfWeek + 7) % 7).Day
</code></pre>

blocks|key|651109|text|Objective+C版本：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|651110|%2B(NSInteger)+daysUntilNextWeekday:+(NSDate*)startDate+withTargetWeekday:+(NSInteger)+targetWeekday
{
++++NSInteger+startWeekday+=+[[NSCalendar+currentCalendar]+component:NSCalendarUnitWeekday+fromDate:startDate];
++++return+(targetWeekday+-+startWeekday+%2B+7)+%25+7;
}|code-block|syntax|javascript|651111|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Objective C Version:

<pre><code>+(NSInteger) daysUntilNextWeekday: (NSDate*)startDate withTargetWeekday: (NSInteger) targetWeekday
{
 NSInteger startWeekday = [[NSCalendar currentCalendar] component:NSCalendarUnitWeekday fromDate:startDate];
 return (targetWeekday - startWeekday + 7) % 7;
}
</code></pre>

blocks|key|868502|text|非常简单的示例要包括或排除当前日期，您需要指定感兴趣的日期和星期几。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|868503|public+static+class+DateTimeExtensions
{
++++///+<summary>
++++///+Gets+the+next+date.
++++///+</summary>
++++///+<param+name="date">The+date+to+inspected.</param>
++++///+<param+name="dayOfWeek">The+day+of+week+you+want+to+get.</param>
++++///+<param+name="exclDate">if+set+to+<c>true</c>+the+current+date+will+be+excluded+and+include+next+occurrence.</param>
++++///+<returns></returns>
++++public+static+DateTime+GetNextDate(this+DateTime+date,+DayOfWeek+dayOfWeek,+bool+exclDate+=+true)
++++{
++++++++//note:+first+we+need+to+check+if+the+date+wants+to+move+back+by+date+-+Today,+%2B+diff+might+move+it+forward+or+backwards+to+Today
++++++++//eg:+date+-+Today+=+0+-+1+=+-1,+so+have+to+move+it+forward
++++++++var+diff+=+dayOfWeek+-+date.DayOfWeek;
++++++++var+ddiff+=+date.Date.Subtract(DateTime.Today).Days+%2B+diff;

++++++++//note:+ddiff+<+0+:+date+calculates+to+past,+so+move+forward,+even+if+the+date+is+really+old,+it+will+just+move+7+days+from+date+passed+in
++++++++//note:+ddiff+>=+(exclDate+?+6+:+7)+&&+diff+<+0+:+date+is+into+the+future,+so+calculated+future+weekday,+based+on+date
++++++++if+(ddiff+<+0+%7C%7C+ddiff+>=+(exclDate+?+6+:+7)+&&+diff+<+0)
++++++++++++diff+%2B=+7;+

++++++++//note:+now+we+can+get+safe+values+between+0+-+6,+especially+if+past+dates+is+being+used
++++++++diff+=+diff+%25+7;

++++++++//note:+if+diff+is+0+and+we+are+excluding+the+date+passed,+we+will+add+7+days,+eg:+1+week
++++++++diff+%2B=+diff+==+0+&+exclDate+?+7+:+0;

++++++++return+date.AddDays(diff);
++++}
}|code-block|syntax|javascript|868504|一些测试用例|868505|[TestMethod]
++++public+void+TestNextDate()
++++{
++++++++var+date+=+new+DateTime(2013,+7,+15);
++++++++var+start+=+date;
++++++++//testing+same+month+-+forwardOnly
++++++++Assert.AreEqual(start+=+start.AddDays(1),+date.GetNextDate(DayOfWeek.Tuesday));+//16
++++++++Assert.AreEqual(start+=+start.AddDays(1),+date.GetNextDate(DayOfWeek.Wednesday));+//17
++++++++Assert.AreEqual(start+=+start.AddDays(1),+date.GetNextDate(DayOfWeek.Thursday));+//18
++++++++Assert.AreEqual(start+=+start.AddDays(1),+date.GetNextDate(DayOfWeek.Friday));+//19
++++++++Assert.AreEqual(start+=+start.AddDays(1),+date.GetNextDate(DayOfWeek.Saturday));+//20
++++++++Assert.AreEqual(start+=+start.AddDays(1),+date.GetNextDate(DayOfWeek.Sunday));+//21
++++++++Assert.AreEqual(start.AddDays(1),+date.GetNextDate(DayOfWeek.Monday));+//22

++++++++//testing+same+month+-+include+date
++++++++Assert.AreEqual(start+=+date,+date.GetNextDate(DayOfWeek.Monday,+false));+//15
++++++++Assert.AreEqual(start+=+start.AddDays(1),+date.GetNextDate(DayOfWeek.Tuesday,+false));+//16
++++++++Assert.AreEqual(start.AddDays(1),+date.GetNextDate(DayOfWeek.Wednesday,+false));+//17

++++++++//testing+month+change+-+forwardOnly
++++++++date+=+new+DateTime(2013,+7,+29);
++++++++start+=+date;
++++++++Assert.AreEqual(start+=+start.AddDays(1),+date.GetNextDate(DayOfWeek.Tuesday));+//30
++++++++Assert.AreEqual(start+=+start.AddDays(1),+date.GetNextDate(DayOfWeek.Wednesday));+//31
++++++++Assert.AreEqual(start+=+start.AddDays(1),+date.GetNextDate(DayOfWeek.Thursday));+//2013/09/01-month+increased
++++++++Assert.AreEqual(start.AddDays(1),+date.GetNextDate(DayOfWeek.Friday));+//02

++++++++//testing+year+change
++++++++date+=+new+DateTime(2013,+12,+30);
++++++++start+=+date;
++++++++Assert.AreEqual(start+=+start.AddDays(1),+date.GetNextDate(DayOfWeek.Tuesday));+//31
++++++++Assert.AreEqual(start+=+start.AddDays(1),+date.GetNextDate(DayOfWeek.Wednesday));+//2014/01/01+-+year+increased
++++++++Assert.AreEqual(start+=+start.AddDays(1),+date.GetNextDate(DayOfWeek.Thursday));+//02
++++}|868506|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Very simple sample to include or exclude current date, you specify the date and the day the week you are interested in.

<pre><code>public static class DateTimeExtensions
{
 /// &lt;summary&gt;
 /// Gets the next date.
 /// &lt;/summary&gt;
 /// &lt;param name="date"&gt;The date to inspected.&lt;/param&gt;
 /// &lt;param name="dayOfWeek"&gt;The day of week you want to get.&lt;/param&gt;
 /// &lt;param name="exclDate"&gt;if set to &lt;c&gt;true&lt;/c&gt; the current date will be excluded and include next occurrence.&lt;/param&gt;
 /// &lt;returns&gt;&lt;/returns&gt;
 public static DateTime GetNextDate(this DateTime date, DayOfWeek dayOfWeek, bool exclDate = true)
 {
 //note: first we need to check if the date wants to move back by date - Today, + diff might move it forward or backwards to Today
 //eg: date - Today = 0 - 1 = -1, so have to move it forward
 var diff = dayOfWeek - date.DayOfWeek;
 var ddiff = date.Date.Subtract(DateTime.Today).Days + diff;

 //note: ddiff &lt; 0 : date calculates to past, so move forward, even if the date is really old, it will just move 7 days from date passed in
 //note: ddiff &gt;= (exclDate ? 6 : 7) &amp;&amp; diff &lt; 0 : date is into the future, so calculated future weekday, based on date
 if (ddiff &lt; 0 || ddiff &gt;= (exclDate ? 6 : 7) &amp;&amp; diff &lt; 0)
 diff += 7; 

 //note: now we can get safe values between 0 - 6, especially if past dates is being used
 diff = diff % 7;

 //note: if diff is 0 and we are excluding the date passed, we will add 7 days, eg: 1 week
 diff += diff == 0 &amp; exclDate ? 7 : 0;

 return date.AddDays(diff);
 }
}
</code></pre>

some test cases

<pre><code>[TestMethod]
 public void TestNextDate()
 {
 var date = new DateTime(2013, 7, 15);
 var start = date;
 //testing same month - forwardOnly
 Assert.AreEqual(start = start.AddDays(1), date.GetNextDate(DayOfWeek.Tuesday)); //16
 Assert.AreEqual(start = start.AddDays(1), date.GetNextDate(DayOfWeek.Wednesday)); //17
 Assert.AreEqual(start = start.AddDays(1), date.GetNextDate(DayOfWeek.Thursday)); //18
 Assert.AreEqual(start = start.AddDays(1), date.GetNextDate(DayOfWeek.Friday)); //19
 Assert.AreEqual(start = start.AddDays(1), date.GetNextDate(DayOfWeek.Saturday)); //20
 Assert.AreEqual(start = start.AddDays(1), date.GetNextDate(DayOfWeek.Sunday)); //21
 Assert.AreEqual(start.AddDays(1), date.GetNextDate(DayOfWeek.Monday)); //22

 //testing same month - include date
 Assert.AreEqual(start = date, date.GetNextDate(DayOfWeek.Monday, false)); //15
 Assert.AreEqual(start = start.AddDays(1), date.GetNextDate(DayOfWeek.Tuesday, false)); //16
 Assert.AreEqual(start.AddDays(1), date.GetNextDate(DayOfWeek.Wednesday, false)); //17

 //testing month change - forwardOnly
 date = new DateTime(2013, 7, 29);
 start = date;
 Assert.AreEqual(start = start.AddDays(1), date.GetNextDate(DayOfWeek.Tuesday)); //30
 Assert.AreEqual(start = start.AddDays(1), date.GetNextDate(DayOfWeek.Wednesday)); //31
 Assert.AreEqual(start = start.AddDays(1), date.GetNextDate(DayOfWeek.Thursday)); //2013/09/01-month increased
 Assert.AreEqual(start.AddDays(1), date.GetNextDate(DayOfWeek.Friday)); //02

 //testing year change
 date = new DateTime(2013, 12, 30);
 start = date;
 Assert.AreEqual(start = start.AddDays(1), date.GetNextDate(DayOfWeek.Tuesday)); //31
 Assert.AreEqual(start = start.AddDays(1), date.GetNextDate(DayOfWeek.Wednesday)); //2014/01/01 - year increased
 Assert.AreEqual(start = start.AddDays(1), date.GetNextDate(DayOfWeek.Thursday)); //02
 }
</code></pre>

How can I get the date of next Tuesday? 

In PHP, it's as simple as <code>strtotime('next tuesday');</code>. 

How can I achieve something similar in .NET

Datetime - Get next tuesday

我怎样才能知道下周二的日期？在PHP中，它和strtotime('next tuesday');一样简单。如何在.NET中实现类似的功能？

问Datetime -获取下周二
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问Datetime -获取下周二EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问Datetime -获取下周二
EN