blocks|key|1613179|text|这应该可以解决这个问题(我将把错误处理留给你)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1613180|int+slashIndex+=+url.lastIndexOf('/');
int+dotIndex+=+url.lastIndexOf('.',+slashIndex);
String+filenameWithoutExtension;
if+(dotIndex+==+-1)+{
++filenameWithoutExtension+=+url.substring(slashIndex+%2B+1);
}+else+{
++filenameWithoutExtension+=+url.substring(slashIndex+%2B+1,+dotIndex);
}|code-block|syntax|javascript|1613181|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This should about cut it (i'll leave the error handling to you):

<pre><code>int slashIndex = url.lastIndexOf('/');
int dotIndex = url.lastIndexOf('.', slashIndex);
String filenameWithoutExtension;
if (dotIndex == -1) {
 filenameWithoutExtension = url.substring(slashIndex + 1);
} else {
 filenameWithoutExtension = url.substring(slashIndex + 1, dotIndex);
}
</code></pre>

blocks|key|1398475|text|我想出了这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1398476|String+url+=+"http://www.example.com/some/path/to/a/file.xml";
String+file+=+url.substring(url.lastIndexOf('/')%2B1,+url.lastIndexOf('.'));|code-block|syntax|javascript|1398477|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I've come up with this:

<pre><code>String url = "http://www.example.com/some/path/to/a/file.xml";
String file = url.substring(url.lastIndexOf('/')+1, url.lastIndexOf('.'));
</code></pre>

blocks|key|1398481|text|String+fileName+=+url.substring(+url.lastIndexOf('/')%2B1,+url.length()+);

String+fileNameWithoutExtn+=+fileName.substring(0,+fileName.lastIndexOf('.'));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1398482|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>String fileName = url.substring( url.lastIndexOf('/')+1, url.length() );

String fileNameWithoutExtn = fileName.substring(0, fileName.lastIndexOf('.'));
</code></pre>

blocks|key|1398491|text|导入java.io.*；|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1398492|import+java.net.*;

public+class+ConvertURLToFileName{


+++public+static+void+main(String[]+args)throws+IOException{
+++BufferedReader+in+=+new+BufferedReader(new+InputStreamReader(System.in));
+++System.out.print("Please+enter+the+URL+:+");

+++String+str+=+in.readLine();


+++try{

+++++URL+url+=+new+URL(str);

+++++System.out.println("File+:+"%2B+url.getFile());
+++++System.out.println("Converting+process+Successfully");

+++}++
+++catch+(MalformedURLException+me){

++++++System.out.println("Converting+process+error");

+}|code-block|syntax|javascript|1398493|我希望这能对你有所帮助。|1398494|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

import java.io.*;

<pre><code>import java.net.*;

public class ConvertURLToFileName{


 public static void main(String[] args)throws IOException{
 BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
 System.out.print("Please enter the URL : ");

 String str = in.readLine();


 try{

 URL url = new URL(str);

 System.out.println("File : "+ url.getFile());
 System.out.println("Converting process Successfully");

 } 
 catch (MalformedURLException me){

 System.out.println("Converting process error");

 }
</code></pre>

I hope this will help you.

blocks|key|1613262|text|从字符串创建一个URL对象。首先，当您有一个URL对象时，有一些方法可以轻松地提取所需的任何信息片段。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1613263|我可以强烈推荐Javaalmanac网站，它有大量的例子，但后来发生了变化。您可能会发现http://exampledepot.8waytrips.com/egs/java.io/File2Uri.html很有趣：|offset|length|1613264|//+Create+a+file+object
File+file+=+new+File("filename");

//+Convert+the+file+object+to+a+URL
URL+url+=+null;
try+{
++++//+The+file+need+not+exist.+It+is+made+into+an+absolute+path
++++//+by+prefixing+the+current+working+directory
++++url+=+file.toURL();++++++++++//+file:/d:/almanac1.4/java.io/filename
}+catch+(MalformedURLException+e)+{
}

//+Convert+the+URL+to+a+file+object
file+=+new+File(url.getFile());++//+d:/almanac1.4/java.io/filename

//+Read+the+file+contents+using+the+URL
try+{
++++//+Open+an+input+stream
++++InputStream+is+=+url.openStream();

++++//+Read+from+is

++++is.close();
}+catch+(IOException+e)+{
++++//+Could+not+open+the+file
}|code-block|syntax|javascript|1613265|entityMap|0|LINK|mutability|MUTABLE|url|http://exampledepot.8waytrips.com/egs/java.io/File2Uri.html^0|0|18|1N|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@$D|U|E|V|1|W]]|A|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|A|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Create an URL object from the String. When first you have an URL object there are methods to easily pull out just about any snippet of information you need.

I can strongly recommend the Javaalmanac web site which has tons of examples, but which has since moved. You might find <a href="http://exampledepot.8waytrips.com/egs/java.io/File2Uri.html" rel="nofollow noreferrer">http://exampledepot.8waytrips.com/egs/java.io/File2Uri.html</a> interesting:

<pre><code>// Create a file object
File file = new File("filename");

// Convert the file object to a URL
URL url = null;
try {
 // The file need not exist. It is made into an absolute path
 // by prefixing the current working directory
 url = file.toURL(); // file:/d:/almanac1.4/java.io/filename
} catch (MalformedURLException e) {
}

// Convert the URL to a file object
file = new File(url.getFile()); // d:/almanac1.4/java.io/filename

// Read the file contents using the URL
try {
 // Open an input stream
 InputStream is = url.openStream();

 // Read from is

 is.close();
} catch (IOException e) {
 // Could not open the file
}
</code></pre>

blocks|key|1398612|text|andy的答案是使用split()重做的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1398613|Url+u=+...;
String[]+pathparts=+u.getPath().split("\\/");
String+filename=+pathparts[pathparts.length-1].split("\\.",+1)[0];|code-block|syntax|javascript|1398614|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

andy's answer redone using split():

<pre><code>Url u= ...;
String[] pathparts= u.getPath().split("\\/");
String filename= pathparts[pathparts.length-1].split("\\.", 1)[0];
</code></pre>

blocks|key|1398619|text|public+static+String+getFileName(URL+extUrl)+{
++++++++//URL:+"http://photosaaaaa.net/photos-ak-snc1/v315/224/13/659629384/s659629384_752969_4472.jpg"
++++++++String+filename+=+"";
++++++++//PATH:+/photos-ak-snc1/v315/224/13/659629384/s659629384_752969_4472.jpg
++++++++String+path+=+extUrl.getPath();
++++++++//Checks+for+both+forward+and/or+backslash+
++++++++//NOTE:**While+backslashes+are+not+supported+in+URL's+
++++++++//most+browsers+will+autoreplace+them+with+forward+slashes
++++++++//So+technically+if+you're+parsing+an+html+page+you+could+run+into+
++++++++//a+backslash+,+so+i'm+accounting+for+them+here;
++++++++String[]+pathContents+=+path.split("[\\\\/]");
++++++++if(pathContents+!=+null){
++++++++++++int+pathContentsLength+=+pathContents.length;
++++++++++++System.out.println("Path+Contents+Length:+"+%2B+pathContentsLength);
++++++++++++for+(int+i+=+0;+i+<+pathContents.length;+i%2B%2B)+{
++++++++++++++++System.out.println("Path+"+%2B+i+%2B+":+"+%2B+pathContents[i]);
++++++++++++}
++++++++++++//lastPart:+s659629384_752969_4472.jpg
++++++++++++String+lastPart+=+pathContents[pathContentsLength-1];
++++++++++++String[]+lastPartContents+=+lastPart.split("\\.");
++++++++++++if(lastPartContents+!=+null+&&+lastPartContents.length+>+1){
++++++++++++++++int+lastPartContentLength+=+lastPartContents.length;
++++++++++++++++System.out.println("Last+Part+Length:+"+%2B+lastPartContentLength);
++++++++++++++++//filenames+can+contain+.+,+so+we+assume+everything+before
++++++++++++++++//the+last+.+is+the+name,+everything+after+the+last+.+is+the+
++++++++++++++++//extension
++++++++++++++++String+name+=+"";
++++++++++++++++for+(int+i+=+0;+i+<+lastPartContentLength;+i%2B%2B)+{
++++++++++++++++++++System.out.println("Last+Part+"+%2B+i+%2B+":+"%2B+lastPartContents[i]);
++++++++++++++++++++if(i+<+(lastPartContents.length+-1)){
++++++++++++++++++++++++name+%2B=+lastPartContents[i]+;
++++++++++++++++++++++++if(i+<+(lastPartContentLength+-2)){
++++++++++++++++++++++++++++name+%2B=+".";
++++++++++++++++++++++++}
++++++++++++++++++++}
++++++++++++++++}
++++++++++++++++String+extension+=+lastPartContents[lastPartContentLength+-1];
++++++++++++++++filename+=+name+%2B+"."+%2Bextension;
++++++++++++++++System.out.println("Name:+"+%2B+name);
++++++++++++++++System.out.println("Extension:+"+%2B+extension);
++++++++++++++++System.out.println("Filename:+"+%2B+filename);
++++++++++++}
++++++++}
++++++++return+filename;
++++}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1398620|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>public static String getFileName(URL extUrl) {
 //URL: "http://photosaaaaa.net/photos-ak-snc1/v315/224/13/659629384/s659629384_752969_4472.jpg"
 String filename = "";
 //PATH: /photos-ak-snc1/v315/224/13/659629384/s659629384_752969_4472.jpg
 String path = extUrl.getPath();
 //Checks for both forward and/or backslash 
 //NOTE:**While backslashes are not supported in URL's 
 //most browsers will autoreplace them with forward slashes
 //So technically if you're parsing an html page you could run into 
 //a backslash , so i'm accounting for them here;
 String[] pathContents = path.split("[\\\\/]");
 if(pathContents != null){
 int pathContentsLength = pathContents.length;
 System.out.println("Path Contents Length: " + pathContentsLength);
 for (int i = 0; i &lt; pathContents.length; i++) {
 System.out.println("Path " + i + ": " + pathContents[i]);
 }
 //lastPart: s659629384_752969_4472.jpg
 String lastPart = pathContents[pathContentsLength-1];
 String[] lastPartContents = lastPart.split("\\.");
 if(lastPartContents != null &amp;&amp; lastPartContents.length &gt; 1){
 int lastPartContentLength = lastPartContents.length;
 System.out.println("Last Part Length: " + lastPartContentLength);
 //filenames can contain . , so we assume everything before
 //the last . is the name, everything after the last . is the 
 //extension
 String name = "";
 for (int i = 0; i &lt; lastPartContentLength; i++) {
 System.out.println("Last Part " + i + ": "+ lastPartContents[i]);
 if(i &lt; (lastPartContents.length -1)){
 name += lastPartContents[i] ;
 if(i &lt; (lastPartContentLength -2)){
 name += ".";
 }
 }
 }
 String extension = lastPartContents[lastPartContentLength -1];
 filename = name + "." +extension;
 System.out.println("Name: " + name);
 System.out.println("Extension: " + extension);
 System.out.println("Filename: " + filename);
 }
 }
 return filename;
 }
</code></pre>

blocks|key|1398637|text|public+String+getFileNameWithoutExtension(URL+url)+{
++++String+path+=+url.getPath();

++++if+(StringUtils.isBlank(path))+{
++++++++return+null;
++++}
++++if+(StringUtils.endsWith(path,+"/"))+{
++++++++//is+a+directory+..
++++++++return+null;
++++}

++++File+file+=+new+File(url.getPath());
++++String+fileNameWithExt+=+file.getName();

++++int+sepPosition+=+fileNameWithExt.lastIndexOf(".");
++++String+fileNameWithOutExt+=+null;
++++if+(sepPosition+>=+0)+{
++++++++fileNameWithOutExt+=+fileNameWithExt.substring(0,sepPosition);
++++}else{
++++++++fileNameWithOutExt+=+fileNameWithExt;
++++}

++++return+fileNameWithOutExt;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1398638|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>public String getFileNameWithoutExtension(URL url) {
 String path = url.getPath();

 if (StringUtils.isBlank(path)) {
 return null;
 }
 if (StringUtils.endsWith(path, "/")) {
 //is a directory ..
 return null;
 }

 File file = new File(url.getPath());
 String fileNameWithExt = file.getName();

 int sepPosition = fileNameWithExt.lastIndexOf(".");
 String fileNameWithOutExt = null;
 if (sepPosition &gt;= 0) {
 fileNameWithOutExt = fileNameWithExt.substring(0,sepPosition);
 }else{
 fileNameWithOutExt = fileNameWithExt;
 }

 return fileNameWithOutExt;
}
</code></pre>

blocks|key|1613342|text|这样如何：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1613343|String+filenameWithoutExtension+=+null;
String+fullname+=+new+File(
++++new+URI("http://www.xyz.com/some/deep/path/to/abc.png").getPath()).getName();

int+lastIndexOfDot+=+fullname.lastIndexOf('.');
filenameWithoutExtension+=+fullname.substring(0,+
++++lastIndexOfDot+==+-1+?+fullname.length()+:+lastIndexOfDot);|code-block|syntax|javascript|1613344|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

How about this:

<pre><code>String filenameWithoutExtension = null;
String fullname = new File(
 new URI("http://www.xyz.com/some/deep/path/to/abc.png").getPath()).getName();

int lastIndexOfDot = fullname.lastIndexOf('.');
filenameWithoutExtension = fullname.substring(0, 
 lastIndexOfDot == -1 ? fullname.length() : lastIndexOfDot);
</code></pre>

blocks|key|1398671|text|与其重新发明轮子，不如使用Apache+commons-io。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1398672|import+org.apache.commons.io.FilenameUtils;

public+class+FilenameUtilTest+{

++++public+static+void+main(String[]+args)+throws+Exception+{
++++++++URL+url+=+new+URL("http://www.example.com/some/path/to/a/file.xml?foo=bar#test");

++++++++System.out.println(FilenameUtils.getBaseName(url.getPath()));+//+->+file
++++++++System.out.println(FilenameUtils.getExtension(url.getPath()));+//+->+xml
++++++++System.out.println(FilenameUtils.getName(url.getPath()));+//+->+file.xml
++++}

}|code-block|syntax|javascript|1398673|entityMap|0|LINK|mutability|MUTABLE|url|http://commons.apache.org/proper/commons-io/^0|K|A|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Instead of reinventing the wheel, how about using Apache <a href="http://commons.apache.org/proper/commons-io/" rel="noreferrer">commons-io</a>:

<pre><code>import org.apache.commons.io.FilenameUtils;

public class FilenameUtilTest {

 public static void main(String[] args) throws Exception {
 URL url = new URL("http://www.example.com/some/path/to/a/file.xml?foo=bar#test");

 System.out.println(FilenameUtils.getBaseName(url.getPath())); // -&gt; file
 System.out.println(FilenameUtils.getExtension(url.getPath())); // -&gt; xml
 System.out.println(FilenameUtils.getName(url.getPath())); // -&gt; file.xml
 }

}
</code></pre>

blocks|key|1613429|text|以下是在Android中实现这一点的最简单方法。我知道它不会在Java中工作，但它可能会帮助Android应用程序开发人员。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1613430|import+android.webkit.URLUtil;

public+String+getFileNameFromURL(String+url)+{
++++String+fileNameWithExtension+=+null;
++++String+fileNameWithoutExtension+=+null;
++++if+(URLUtil.isValidUrl(url))+{
++++++++fileNameWithExtension+=+URLUtil.guessFileName(url,+null,+null);
++++++++if+(fileNameWithExtension+!=+null+&&+!fileNameWithExtension.isEmpty())+{
++++++++++++String[]+f+=+fileNameWithExtension.split(".");
++++++++++++if+(f+!=+null+&+f.length+>+1)+{
++++++++++++++++fileNameWithoutExtension+=+f[0];
++++++++++++}
++++++++}
++++}
++++return+fileNameWithoutExtension;
}|code-block|syntax|javascript|1613431|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here is the simplest way to do it in Android. I know it will not work in Java but It may help Android application developer.

<pre><code>import android.webkit.URLUtil;

public String getFileNameFromURL(String url) {
 String fileNameWithExtension = null;
 String fileNameWithoutExtension = null;
 if (URLUtil.isValidUrl(url)) {
 fileNameWithExtension = URLUtil.guessFileName(url, null, null);
 if (fileNameWithExtension != null &amp;&amp; !fileNameWithExtension.isEmpty()) {
 String[] f = fileNameWithExtension.split(".");
 if (f != null &amp; f.length &gt; 1) {
 fileNameWithoutExtension = f[0];
 }
 }
 }
 return fileNameWithoutExtension;
}
</code></pre>

blocks|key|1398752|text|Urls的末尾可以有参数，这是|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1398753|+/**
+*+Getting+file+name+from+url+without+extension
+*+@param+url+string
+*+@return+file+name
+*/
public+static+String+getFileName(String+url)+{
++++String+fileName;
++++int+slashIndex+=+url.lastIndexOf("/");
++++int+qIndex+=+url.lastIndexOf("?");
++++if+(qIndex+>+slashIndex)+{//if+has+parameters
++++++++fileName+=+url.substring(slashIndex+%2B+1,+qIndex);
++++}+else+{
++++++++fileName+=+url.substring(slashIndex+%2B+1);
++++}
++++if+(fileName.contains("."))+{
++++++++fileName+=+fileName.substring(0,+fileName.lastIndexOf("."));
++++}

++++return+fileName;
}|code-block|syntax|javascript|1398754|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Urls can have parameters in the end, this

<pre><code> /**
 * Getting file name from url without extension
 * @param url string
 * @return file name
 */
public static String getFileName(String url) {
 String fileName;
 int slashIndex = url.lastIndexOf("/");
 int qIndex = url.lastIndexOf("?");
 if (qIndex &gt; slashIndex) {//if has parameters
 fileName = url.substring(slashIndex + 1, qIndex);
 } else {
 fileName = url.substring(slashIndex + 1);
 }
 if (fileName.contains(".")) {
 fileName = fileName.substring(0, fileName.lastIndexOf("."));
 }

 return fileName;
}
</code></pre>

blocks|key|1398759|text|保持简单：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1398760|/**
+*+This+function+will+take+an+URL+as+input+and+return+the+file+name.
+*+Examples+:
+*+<ul>
+*+<li>http://example.com/a/b/c/test.txt+->+test.txt</li>
+*+<li>http://example.com/+->+an+empty+string+</li>
+*+<li>http://example.com/test.txt?param=value+->+test.txt</li>
+*+<li>http://example.com/test.txt#anchor+->+test.txt</li>
+*+</ul>
+*+
+*+@param+url+The+input+URL
+*+@return+The+URL+file+name
+*/
public+static+String+getFileNameFromUrl(URL+url)+{

++++String+urlString+=+url.getFile();

++++return+urlString.substring(urlString.lastIndexOf('/')+%2B+1).split("\\?")[0].split("#")[0];
}|code-block|syntax|javascript|1398761|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Keep it simple :

<pre><code>/**
 * This function will take an URL as input and return the file name.
 * &lt;p&gt;Examples :&lt;/p&gt;
 * &lt;ul&gt;
 * &lt;li&gt;http://example.com/a/b/c/test.txt -&gt; test.txt&lt;/li&gt;
 * &lt;li&gt;http://example.com/ -&gt; an empty string &lt;/li&gt;
 * &lt;li&gt;http://example.com/test.txt?param=value -&gt; test.txt&lt;/li&gt;
 * &lt;li&gt;http://example.com/test.txt#anchor -&gt; test.txt&lt;/li&gt;
 * &lt;/ul&gt;
 * 
 * @param url The input URL
 * @return The URL file name
 */
public static String getFileNameFromUrl(URL url) {

 String urlString = url.getFile();

 return urlString.substring(urlString.lastIndexOf('/') + 1).split("\\?")[0].split("#")[0];
}
</code></pre>

blocks|key|1613512|text|create+a+new+file+with+string+image+path

++++String+imagePath;
++++File+test+=+new+File(imagePath);
++++test.getName();
++++test.getPath();
++++getExtension(test.getName());


++++public+static+String+getExtension(String+uri)+{
++++++++++++if+(uri+==+null)+{
++++++++++++++++return+null;
++++++++++++}

++++++++++++int+dot+=+uri.lastIndexOf(".");
++++++++++++if+(dot+>=+0)+{
++++++++++++++++return+uri.substring(dot);
++++++++++++}+else+{
++++++++++++++++//+No+extension.
++++++++++++++++return+"";
++++++++++++}
++++++++}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1613513|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>create a new file with string image path

 String imagePath;
 File test = new File(imagePath);
 test.getName();
 test.getPath();
 getExtension(test.getName());


 public static String getExtension(String uri) {
 if (uri == null) {
 return null;
 }

 int dot = uri.lastIndexOf(".");
 if (dot &gt;= 0) {
 return uri.substring(dot);
 } else {
 // No extension.
 return "";
 }
 }
</code></pre>

blocks|key|1398829|text|如果您不需要去掉文件扩展名，这里有一种方法可以做到这一点，而不需要求助于容易出错的字符串操作，也不需要使用外部库。与Java+1.7%2B配合使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1398830|import+java.net.URI
import+java.nio.file.Paths

String+url+=+"http://example.org/file?p=foo&q=bar"
String+filename+=+Paths.get(new+URI(url).getPath()).getFileName().toString()|code-block|syntax|javascript|1398831|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you don't need to get rid of the file extension, here's a way to do it without resorting to error-prone String manipulation and without using external libraries. Works with Java 1.7+:

<pre><code>import java.net.URI
import java.nio.file.Paths

String url = "http://example.org/file?p=foo&amp;q=bar"
String filename = Paths.get(new URI(url).getPath()).getFileName().toString()
</code></pre>

blocks|key|1613575|text|String+fileName+=+url.substring(url.lastIndexOf('/')+%2B+1);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1613576|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>String fileName = url.substring(url.lastIndexOf('/') + 1);
</code></pre>

blocks|key|1613626|text|如果您只想从java.net.URL获取文件名(不包括任何查询参数)，则可以使用以下函数：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1613627|public+static+String+getFilenameFromURL(URL+url)+{
++++return+new+File(url.getPath().toString()).getName();
}|code-block|syntax|javascript|1613628|例如，此输入URL：|1613629|"http://example.com/image.png?version=2&amp;modificationDate=1449846324000"|1613630|将被转换为以下输出字符串：|1613631|image.png|1613632|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

If you want to get only the filename from a java.net.URL (not including any query parameters), you could use the following function:

<pre><code>public static String getFilenameFromURL(URL url) {
 return new File(url.getPath().toString()).getName();
}
</code></pre>

For example, this input URL:

<pre><code>"http://example.com/image.png?version=2&amp;amp;modificationDate=1449846324000"
</code></pre>

Would be translated to this output String:

<pre><code>image.png
</code></pre>

blocks|key|1613662|text|除了所有高级方法之外，我的简单技巧是StringTokenizer|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1613663|import+java.util.ArrayList;
import+java.util.StringTokenizer;

public+class+URLName+{
++++public+static+void+main(String+args[]){
++++++++String+url+=+"http://www.example.com/some/path/to/a/file.xml";
++++++++StringTokenizer+tokens+=+new+StringTokenizer(url,+"/");

++++++++ArrayList<String>+parts+=+new+ArrayList<>();

++++++++while(tokens.hasMoreTokens()){
++++++++++++parts.add(tokens.nextToken());
++++++++}
++++++++String+file+=+parts.get(parts.size()+-1);
++++++++int+dot+=+file.indexOf(".");
++++++++String+fileName+=+file.substring(0,+dot);
++++++++System.out.println(fileName);
++++}
}|code-block|syntax|javascript|1613664|entityMap^0|I|F|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Beyond the all advanced methods, my simple trick is <code>StringTokenizer</code>:

<pre><code>import java.util.ArrayList;
import java.util.StringTokenizer;

public class URLName {
 public static void main(String args[]){
 String url = "http://www.example.com/some/path/to/a/file.xml";
 StringTokenizer tokens = new StringTokenizer(url, "/");

 ArrayList&lt;String&gt; parts = new ArrayList&lt;&gt;();

 while(tokens.hasMoreTokens()){
 parts.add(tokens.nextToken());
 }
 String file = parts.get(parts.size() -1);
 int dot = file.indexOf(".");
 String fileName = file.substring(0, dot);
 System.out.println(fileName);
 }
}
</code></pre>

blocks|key|1398977|text|urllib中的Url对象允许您访问路径的未转义文件名。下面是一些示例：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1398978|String+raw+=+"http://www.example.com/some/path/to/a/file.xml";
assertEquals("file.xml",+Url.parse(raw).path().filename());

raw+=+"http://www.example.com/files/r%25C3%25A9sum%25C3%25A9.pdf";
assertEquals("résumé.pdf",+Url.parse(raw).path().filename());|code-block|syntax|javascript|1398979|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/EricEdens/urllib^0|8|3|0|6|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@$9|V|A|W|1|X]]|E|$]]|$1|F|3|G|5|H|7|Y|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

The <code>Url</code> object in <a href="https://github.com/EricEdens/urllib" rel="nofollow noreferrer">urllib</a> allows you to access the path's unescaped filename. Here are some examples:

<pre><code>String raw = "http://www.example.com/some/path/to/a/file.xml";
assertEquals("file.xml", Url.parse(raw).path().filename());

raw = "http://www.example.com/files/r%C3%A9sum%C3%A9.pdf";
assertEquals("résumé.pdf", Url.parse(raw).path().filename());
</code></pre>

blocks|key|1399009|text|我和你也有同样的问题。我通过以下方式解决了这个问题：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1399010|var+URL+=+window.location.pathname;+//+Gets+page+name
var+page+=+URL.substring(URL.lastIndexOf('/')+%2B+1);+
console.info(page)|code-block|syntax|javascript|1399011|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I have the same problem, with yours. I solved it by this:

<pre><code>var URL = window.location.pathname; // Gets page name
var page = URL.substring(URL.lastIndexOf('/') + 1); 
console.info(page)
</code></pre>

blocks|key|1613793|text|返回新文件(Uri.parse(Url).getPath()).getName()|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1613794|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

return new File(Uri.parse(url).getPath()).getName()

In Java, given a <code>java.net.URL</code> or a <code>String</code> in the form of <code>http://www.example.com/some/path/to/a/file.xml</code> , what is the easiest way to get the file name, minus the extension? So, in this example, I'm looking for something that returns <code>"file"</code>. 

I can think of several ways to do this, but I'm looking for something that's easy to read and short.

Get file name from URL

Android

Java

在Java语言中，给定一个java.net.URL或http://www.example.com/some/path/to/a/file.xml形式的String，获得不带扩展名的文件名的最简单方法是什么？因此，在本例中，我要查找返回"file"的内容。我可以想出几种方法来做到这一点，但我正在寻找一种易于阅读和简短的东...

问从URL获取文件名
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