blocks|key|1355077|text|看看这里：Format+phone+number|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1355078|function+format_phone($phone)
{
++++$phone+=+preg_replace("/%5E\d/",+"",+$phone);

++++if(strlen($phone)+==+7)
++++++++return+preg_replace("/(\d{3})(\d{4})/",+"$1-$2",+$phone);
++++elseif(strlen($phone)+==+10)
++++++++return+preg_replace("/(\d{3})(\d{3})(\d{4})/",+"($1)+$2-$3",+$phone);
++++else
++++++++return+$phone;
}|code-block|syntax|javascript|1355079|entityMap|0|LINK|mutability|MUTABLE|url|http://snipplr.com/view/25/format-phone-number/^0|5|J|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Take a look here: <a href="http://snipplr.com/view/25/format-phone-number/" rel="noreferrer">Format phone number</a>

<pre><code>function format_phone($phone)
{
 $phone = preg_replace("/^\d/", "", $phone);

 if(strlen($phone) == 7)
 return preg_replace("/(\d{3})(\d{4})/", "$1-$2", $phone);
 elseif(strlen($phone) == 10)
 return preg_replace("/(\d{3})(\d{3})(\d{4})/", "($1) $2-$3", $phone);
 else
 return $phone;
}
</code></pre>

blocks|key|1140041|text|对于这种情况，正则表达式绝对是大材小用了。如果您想获取一个“电话号码”并将其规范化为10位数，那么使用正则表达式将是一个很好的选择。要做你所要求的事情，只需做如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1140042|echo+'('.substr($data,+0,+3).')+'.substr($data,+3,+3).'-'.substr($data,6);|code-block|syntax|javascript|1140043|因为您已经知道如何划分数据，所以可以只使用substr或类似的东西来获取您想要的部分。RegEx对于匹配并不总是具有严格格式的字符串非常有用。(比如可变数量的空格，前后可变的东西，额外的破折号，等等)。但是在本例中，输入始终是严格格式化的10位数字，没有其他内容，因此格式化它不需要额外的RegEx开销。|1140044|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

A regex is definitely overkill for this one. If you wanted to take a "phone number" and normalize it to 10 digits, that would be a good use for a regex. To do what you're asking, just do something like:

<pre><code>echo '('.substr($data, 0, 3).') '.substr($data, 3, 3).'-'.substr($data,6);
</code></pre>

Since you already know how to divide up your data, you can just use substr or something similar to grab the parts you want. RegEx is useful for matching strings which don't always have a strict format. (Like variable numbers of spaces, variable stuff before or after it, extra dashes, etc). But in your case the input is always strictly formatted 10 digits, nothing else, so you don't need the extra overhead of a RegEx to format it.

blocks|key|1140109|text|简单地说，你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1140110|$\d\{3\}$$\d\{3\}$$\d\{4\}$|code-block|syntax|javascript|1140111|要将10位数字匹配为3个子组表达式，然后使用每个子组将其打印出来：|1140112|"(\1)+\2-\3|1140113|但在实践中，自由格式数据通常要稍微复杂一些。|1140114|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Trivially you could do something like:

<pre><code>$\d\{3\}$$\d\{3\}$$\d\{4\}$
</code></pre>

To match the 10 digits into 3 subgroup expressions, and then print them out using each subgroup:

<pre><code>"(\1) \2-\3
</code></pre>

But in practice free form data is usually a little trickier

blocks|key|1140169|text|我可能会选择|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1140170|$num+=+"4085551234";++//+given++++++++++++++++++++++++++++++++++++++++++++++++++
$formatted+=+"(".substr($num,0,3).")+".substr($num,3,3)."-".substr($num,6);|code-block|syntax|javascript|1140171|正则表达式在这里并不是很合适。|1140172|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I'd probably go with

<pre><code>$num = "4085551234"; // given 
$formatted = "(".substr($num,0,3).") ".substr($num,3,3)."-".substr($num,6);
</code></pre>

Regex isn't really appropriate here.

I have database records in the form of 10 character long strings, such as 4085551234. 

I wish to format these into this format: (408) 555-1234.

I think this is regex related. I'm new to programming and completely self-taught here, so any sort of resource relating to performing text processing would be appreciated as well. Thanks!

How do you format a 10 digit string into a phone number?

数据库

我有10个字符长的字符串形式的数据库记录，例如4085551234。我希望将它们格式化为以下格式：(408) 555-1234。我认为这与正则表达式相关。我是编程新手，在这里完全自学，所以任何与执行文本处理相关的资源都将受到欢迎。谢谢!

问如何将10位数字字符串格式化为电话号码？
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问如何将10位数字字符串格式化为电话号码？EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问如何将10位数字字符串格式化为电话号码？
EN