blocks|key|1275172|text|您正在寻找dir来返回目录内容。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1275173|要遍历结果，只需执行以下操作：|1275174|dirlist+=+dir('.');
for+i+=+1:length(dirlist)
++++dirlist(i)
end|code-block|syntax|javascript|1275175|这将给出以下格式的输出，例如：|1275176|name:+'my_file'
date:+'01-Jan-2010+12:00:00'
bytes:+56
isdir:+0
datenum:+[]|1275177|entityMap|0|LINK|mutability|MUTABLE|url|http://www.mathworks.com/help/techdoc/ref/dir.html^0|5|3|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|6|7|10|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|11|8|@]|9|@]|C|$I|J]]|$1|K|3|L|5|6|7|12|8|@]|9|@]|C|$]]|$1|M|3|N|5|H|7|13|8|@]|9|@]|C|$I|J]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]]]

You're looking for <a href="http://www.mathworks.com/help/techdoc/ref/dir.html" rel="noreferrer">dir</a> to return the directory contents.

To loop over the results, you can simply do the following:

<pre><code>dirlist = dir('.');
for i = 1:length(dirlist)
 dirlist(i)
end
</code></pre>

This should give you output in the following format, e.g.:

<pre><code>name: 'my_file'
date: '01-Jan-2010 12:00:00'
bytes: 56
isdir: 0
datenum: []
</code></pre>

blocks|key|1275248|text|您可以使用regexp或strcmp来消除.和..，或者，如果只希望目录中的文件而不是文件夹中的文件，则可以使用isdir字段。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1275249|list=dir(pwd);++%25get+info+of+files/folders+in+current+directory
isfile=~[list.isdir];+%25determine+index+of+files+vs+folders
filenames={list(isfile).name};+%25create+cell+array+of+file+names|code-block|syntax|javascript|1275250|或者将最后两行合并：|1275251|filenames={list(~[list.isdir]).name};|1275252|有关目录中不包括的文件夹的列表。然后..。|1275253|dirnames={list([list.isdir]).name};
dirnames=dirnames(~(strcmp('.',dirnames)%7Cstrcmp('..',dirnames)));|1275254|至此，您应该能够将代码抛入嵌套的for循环中，并继续搜索每个子文件夹，直到您的dirname为每个子目录返回一个空单元格。|1275255|entityMap^0|L|1|N|2|1K|5|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|14|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|16|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|S|3|T|5|6|7|18|8|@]|D|@]|E|$]]|$1|U|3|-4|5|6|7|19|8|@]|D|@]|E|$]]]|V|$]]

You can use regexp or strcmp to eliminate <code>.</code> and <code>..</code> 
Or you could use the <code>isdir</code> field if you only want files in the directory, not folders.

<pre><code>list=dir(pwd); %get info of files/folders in current directory
isfile=~[list.isdir]; %determine index of files vs folders
filenames={list(isfile).name}; %create cell array of file names
</code></pre>

or combine the last two lines:

<pre><code>filenames={list(~[list.isdir]).name};
</code></pre>

For a list of folders in the directory excluding . and ..

<pre><code>dirnames={list([list.isdir]).name};
dirnames=dirnames(~(strcmp('.',dirnames)|strcmp('..',dirnames)));
</code></pre>

From this point, you should be able to throw the code in a nested for loop, and continue searching each subfolder until your dirnames returns an empty cell for each subdirectory.

blocks|key|1275310|text|我使用了this+great+answer中提到的代码，并对其进行了扩展，以支持我在本例中需要的两个附加参数。这些参数是要筛选的文件扩展名，以及指示是否将完整路径连接到文件名的标志。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1275311|我希望它足够清楚，有人会发现它是有益的。|1275312|function+fileList+=+getAllFiles(dirName,+fileExtension,+appendFullPath)

++dirData+=+dir([dirName+'/'+fileExtension]);++++++%25#+Get+the+data+for+the+current+directory
++dirWithSubFolders+=+dir(dirName);
++dirIndex+=+[dirWithSubFolders.isdir];++%25#+Find+the+index+for+directories
++fileList+=+{dirData.name}';++%25'#+Get+a+list+of+the+files
++if+~isempty(fileList)
++++if+appendFullPath
++++++fileList+=+cellfun(@(x)+fullfile(dirName,x),...++%25#+Prepend+path+to+files
+++++++++++++++++++++++fileList,'UniformOutput',false);
++++end
++end
++subDirs+=+{dirWithSubFolders(dirIndex).name};++%25#+Get+a+list+of+the+subdirectories
++validIndex+=+~ismember(subDirs,{'.','..'});++%25#+Find+index+of+subdirectories
+++++++++++++++++++++++++++++++++++++++++++++++%25#+++that+are+not+'.'+or+'..'
++for+iDir+=+find(validIndex)++++++++++++++++++%25#+Loop+over+valid+subdirectories
++++nextDir+=+fullfile(dirName,subDirs{iDir});++++%25#+Get+the+subdirectory+path
++++fileList+=+[fileList;+getAllFiles(nextDir,+fileExtension,+appendFullPath)];++%25#+Recursively+call+getAllFiles
++end

end|code-block|syntax|javascript|1275313|运行代码的示例：|1275314|fileList+=+getAllFiles(dirName,+'*.xml',+0);+%25#0+is+false+obviously|1275315|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/2654459/69555^0|4|H|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|6|7|10|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|11|8|@]|9|@]|C|$I|J]]|$1|K|3|L|5|6|7|12|8|@]|9|@]|C|$]]|$1|M|3|N|5|H|7|13|8|@]|9|@]|C|$I|J]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]]]

I used the code mentioned in <a href="https://stackoverflow.com/a/2654459/69555">this great answer</a> and expanded it to support 2 additional parameters which I needed in my case. The parameters are file extensions to filter on and a flag indicating whether to concatenate the full path to the name of the file or not.

I hope it is clear enough and someone will finds it beneficial.

<pre><code>function fileList = getAllFiles(dirName, fileExtension, appendFullPath)

 dirData = dir([dirName '/' fileExtension]); %# Get the data for the current directory
 dirWithSubFolders = dir(dirName);
 dirIndex = [dirWithSubFolders.isdir]; %# Find the index for directories
 fileList = {dirData.name}'; %'# Get a list of the files
 if ~isempty(fileList)
 if appendFullPath
 fileList = cellfun(@(x) fullfile(dirName,x),... %# Prepend path to files
 fileList,'UniformOutput',false);
 end
 end
 subDirs = {dirWithSubFolders(dirIndex).name}; %# Get a list of the subdirectories
 validIndex = ~ismember(subDirs,{'.','..'}); %# Find index of subdirectories
 %# that are not '.' or '..'
 for iDir = find(validIndex) %# Loop over valid subdirectories
 nextDir = fullfile(dirName,subDirs{iDir}); %# Get the subdirectory path
 fileList = [fileList; getAllFiles(nextDir, fileExtension, appendFullPath)]; %# Recursively call getAllFiles
 end

end
</code></pre>

Example for running the code:

<pre><code>fileList = getAllFiles(dirName, '*.xml', 0); %#0 is false obviously
</code></pre>

blocks|key|1275337|text|这是一个方便的函数，用于获取根文件夹中指定格式(通常为.mat)的文件名！|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1275338|++++function+filenames+=+getFilenames(rootDir,+format)
++++++++%25+Get+filenames+with+specified+`format`+in+given+`foler`+
++++++++%25
++++++++%25+Parameters
++++++++%25+----------
++++++++%25+-+rootDir:+char+vector
++++++++%25+++Target+folder
++++++++%25+-+format:+char+vector+=+'mat'
++++++++%25+++File+foramt

++++++++%25+default+values
++++++++if+~exist('format',+'var')
++++++++++++format+=+'mat';
++++++++end

++++++++format+=+['*.',+format];
++++++++filenames+=+dir(fullfile(rootDir,+format));
++++++++filenames+=+arrayfun(...
++++++++++++@(x)+fullfile(x.folder,+x.name),+...
++++++++++++filenames,+...
++++++++++++'UniformOutput',+false+...
++++++++);
++++end|code-block|syntax|javascript|1275339|在您的示例中，您可以使用以下代码片段:)|1275340|filenames+=+getFilenames('D:/dic/**');
for+i+=+1:numel(filenames)
++++filename+=+filenames{i};
++++%25+do+your+job!
end|1275341|entityMap^0|R|4|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

This is a handy function for getting filenames, with the specified format (usually <code>.mat</code>) in a root folder!

<pre><code> function filenames = getFilenames(rootDir, format)
 % Get filenames with specified `format` in given `foler` 
 %
 % Parameters
 % ----------
 % - rootDir: char vector
 % Target folder
 % - format: char vector = 'mat'
 % File foramt

 % default values
 if ~exist('format', 'var')
 format = 'mat';
 end

 format = ['*.', format];
 filenames = dir(fullfile(rootDir, format));
 filenames = arrayfun(...
 @(x) fullfile(x.folder, x.name), ...
 filenames, ...
 'UniformOutput', false ...
 );
 end
</code></pre>

In your case, you can use the following snippet :)

<pre><code>filenames = getFilenames('D:/dic/**');
for i = 1:numel(filenames)
 filename = filenames{i};
 % do your job!
end
</code></pre>

blocks|key|1275386|text|只需很少的修改，但几乎类似的方法即可获得每个子文件夹的完整文件路径|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1275387|dataFolderPath+=+'UCR_TS_Archive_2015/';

dirData+=+dir(dataFolderPath);++++++%25#+Get+the+data+for+the+current+directory
dirIndex+=+[dirData.isdir];++%25#+Find+the+index+for+directories
fileList+=+{dirData(~dirIndex).name}';++%25'#+Get+a+list+of+the+files
if+~isempty(fileList)
++++fileList+=+cellfun(@(x)+fullfile(dataFolderPath,x),...++%25#+Prepend+path+to+files
++++++++fileList,'UniformOutput',false);
end
subDirs+=+{dirData(dirIndex).name};++%25#+Get+a+list+of+the+subdirectories
validIndex+=+~ismember(subDirs,{'.','..'});++%25#+Find+index+of+subdirectories
%25#+++that+are+not+'.'+or+'..'
for+iDir+=+find(validIndex)++++++++++++++++++%25#+Loop+over+valid+subdirectories
++++nextDir+=+fullfile(dataFolderPath,subDirs{iDir});++++%25#+Get+the+subdirectory+path
++++getAllFiles+=+dir(nextDir);
++++for+k+=+1:1:size(getAllFiles,1)
++++++++validFileIndex+=+~ismember(getAllFiles(k,1).name,{'.','..'});
++++++++if(validFileIndex)
++++++++++++filePathComplete+=+fullfile(nextDir,getAllFiles(k,1).name);
++++++++++++fprintf('The+Complete+File+Path:+%25s\n',+filePathComplete);
++++++++end
++++end
end++|code-block|syntax|javascript|1275388|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

With little modification but almost similar approach to get the full file path of each sub folder

<pre><code>dataFolderPath = 'UCR_TS_Archive_2015/';

dirData = dir(dataFolderPath); %# Get the data for the current directory
dirIndex = [dirData.isdir]; %# Find the index for directories
fileList = {dirData(~dirIndex).name}'; %'# Get a list of the files
if ~isempty(fileList)
 fileList = cellfun(@(x) fullfile(dataFolderPath,x),... %# Prepend path to files
 fileList,'UniformOutput',false);
end
subDirs = {dirData(dirIndex).name}; %# Get a list of the subdirectories
validIndex = ~ismember(subDirs,{'.','..'}); %# Find index of subdirectories
%# that are not '.' or '..'
for iDir = find(validIndex) %# Loop over valid subdirectories
 nextDir = fullfile(dataFolderPath,subDirs{iDir}); %# Get the subdirectory path
 getAllFiles = dir(nextDir);
 for k = 1:1:size(getAllFiles,1)
 validFileIndex = ~ismember(getAllFiles(k,1).name,{'.','..'});
 if(validFileIndex)
 filePathComplete = fullfile(nextDir,getAllFiles(k,1).name);
 fprintf('The Complete File Path: %s\n', filePathComplete);
 end
 end
end 
</code></pre>

I need to get all those files under <code>D:\dic</code> and loop over them to further process individually.

Does MATLAB support this kind of operations?

It can be done in other scripts like PHP,Python...

How to get all files under a specific directory in MATLAB?

Python

我需要将所有这些文件放在D:\dic下，并循环遍历它们，以便进一步单独处理。MATLAB支持这种操作吗？它可以在其他脚本中完成，如PHP、Python…

问如何在MATLAB中获取特定目录下的所有文件？
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