blocks|key|900847|text|我刚刚了解了“str_trim”包，它使用side=(，string“both”)删除字符串开头和结尾的空格，但它也有一个替换函数，因此：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|900848|a+<-+"+xx+yy+11+22+33+"+
str_replace_all(string=a,+pattern="+",+repl="")

[1]+"xxyy112233"|code-block|syntax|javascript|900849|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I just learned about the "stringr" package to remove white space from the beginning and end of a string with str_trim( , side="both") but it also has a replacement function so that:

<pre><code>a &lt;- " xx yy 11 22 33 " 
str_replace_all(string=a, pattern=" ", repl="")

[1] "xxyy112233"
</code></pre>

blocks|key|900898|text|请注意，上面写的soultions只删除空格。如果您还想删除制表符或新行，请使用stringi包中stri_replace_all_charclass。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|900899|library(stringi)
stri_replace_all_charclass("+++ala+\t++ma+\n+kota++",+"\\p{WHITE_SPACE}",+"")
##+[1]+"alamakota"|code-block|syntax|javascript|900900|entityMap^0|14|7|1D|Q|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

Please note that soultions written above removes only space. If you want also to remove tab or new line use <code>stri_replace_all_charclass</code> from <code>stringi</code> package.

<pre><code>library(stringi)
stri_replace_all_charclass(" ala \t ma \n kota ", "\\p{WHITE_SPACE}", "")
## [1] "alamakota"
</code></pre>

blocks|key|684424|text|使用[[:blank:]]匹配任何类型的水平white_space字符。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|684425|gsub("[[:blank:]]",+"",+"+xx+yy+11+22++33+")
#+[1]+"xxyy112233"|code-block|syntax|javascript|684426|entityMap^0|2|B|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Use <code>[[:blank:]]</code> to match any kind of horizontal white_space characters.

<pre><code>gsub("[[:blank:]]", "", " xx yy 11 22 33 ")
# [1] "xxyy112233"
</code></pre>

blocks|key|900960|text|x+=+"xx+yy+11+22+33"

gsub("+",+"",+x)

>+[1]+"xxyy112233"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|900961|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

blocks|key|901003|text|tidyverse的stringr包中的函数str_squish()做到了这一点！|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|901004|library(dplyr)
library(stringr)

df+<-+data.frame(a+=+c("++aZe++aze+s",+"wxc++s+++++aze+++"),+
+++++++++++++++++b+=+c("++12++++12+",+"34e+e4++"),+
+++++++++++++++++stringsAsFactors+=+FALSE)
df+<-+df+%25>%25
++rowwise()+%25>%25
++mutate_all(funs(str_squish(.)))+%25>%25
++ungroup()
df

#+A+tibble:+2+x+2
++a+++++++++b+++++
++<chr>+++++<chr>+
1+aZe+aze+s+12+12+
2+wxc+s+aze+34e+e4|code-block|syntax|javascript|901005|entityMap^0|A|7|M|C|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

The function <code>str_squish()</code> from package <code>stringr</code> of tidyverse does the magic!

<pre><code>library(dplyr)
library(stringr)

df &lt;- data.frame(a = c(" aZe aze s", "wxc s aze "), 
 b = c(" 12 12 ", "34e e4 "), 
 stringsAsFactors = FALSE)
df &lt;- df %&gt;%
 rowwise() %&gt;%
 mutate_all(funs(str_squish(.))) %&gt;%
 ungroup()
df

# A tibble: 2 x 2
 a b 
 &lt;chr&gt; &lt;chr&gt; 
1 aZe aze s 12 12 
2 wxc s aze 34e e4
</code></pre>

blocks|key|684572|text|income<-c("$98,000.00+",+"$90,000.00+",+"$18,000.00+",+"")|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|684573|要删除.00后的空格，请使用trimws()函数。|unstyled|offset|length|style|CODE|684574|income<-trimws(income)|684575|entityMap^0|0|3|3|E|8|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|P|8|@$G|Q|H|R|I|J]|$G|S|H|T|I|J]]|9|@]|A|$]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$B|C]]|$1|M|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|N|$]]

<pre><code>income&lt;-c(&quot;$98,000.00 &quot;, &quot;$90,000.00 &quot;, &quot;$18,000.00 &quot;, &quot;&quot;)
</code></pre>
To remove space after <code>.00</code> use the <code>trimws()</code> function.
<pre><code>income&lt;-trimws(income)
</code></pre>

So <code>" xx yy 11 22 33 "</code> will become <code>"xxyy112233"</code>. How can I achieve this?

How to remove all whitespace from a string?

因此，" xx yy 11 22  33 "将成为"xxyy112233"。我如何才能做到这一点？

问如何删除字符串中的所有空格？
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