blocks|key|348567|text|试试$_SERVER['SERVER_NAME']。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|348568|提示:创建一个调用函数phpinfo()的PHP文件，并查看"PHP变量“一节。有一堆有用的变量，我们从来没有想过。|348569|entityMap^0|2|N|0|B|9|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|P|8|@]|D|@]|E|$]]]|I|$]]

Try <code>$_SERVER['SERVER_NAME']</code>.

Tips: Create a PHP file that calls the function <code>phpinfo()</code> and see the "PHP Variables" section. There are a bunch of useful variables we never think of there.

blocks|key|564710|text|使用$_SERVER['HTTP_HOST']获取(子域)maindomain.extension。对我来说，这似乎是最简单的解决方案。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|564711|如果你实际上是通过iFrame“重定向”，你可以添加一个声明域名的GET参数。|564712|<iframe+src="myserver.uk.com?domain=one.com"/>|code-block|syntax|javascript|564713|然后，您可以设置一个会话变量，该变量在整个应用程序中保留此数据。|564714|entityMap|0|LINK|mutability|MUTABLE|url|https://en.wikipedia.org/wiki/Hypertext_Transfer_Protocol#Request_methods^0|2|L|0|X|3|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Z|8|@]|D|@$9|10|A|11|1|12]]|E|$]]|$1|H|3|I|5|J|7|13|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|14|8|@]|D|@]|E|$]]|$1|O|3|-4|5|6|7|15|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

Using <code>$_SERVER['HTTP_HOST']</code> gets me (subdomain.)maindomain.extension. It seems like the easiest solution to me.

If you're actually 'redirecting' through an iFrame, you could add a <a href="https://en.wikipedia.org/wiki/Hypertext_Transfer_Protocol#Request_methods" rel="nofollow noreferrer">GET</a> parameter which states the domain.

<pre><code>&lt;iframe src="myserver.uk.com?domain=one.com"/&gt;
</code></pre>

And then you could set a session variable that persists this data throughout your application.

blocks|key|348692|text|最好的用法是|type|unstyled|depth|inlineStyleRanges|entityRanges|data|348693|echo+$_SERVER['HTTP_HOST'];|code-block|syntax|javascript|348694|它可以像这样使用：|348695|if+(strpos($_SERVER['HTTP_HOST'],+'banana.com')+!==+false)+{
++++echo+"Yes+this+is+indeed+the+banana.com+domain";
}|348696|下面的代码是一个很好的方法，可以在结构化的$_SERVER输出中查看所有变量，并突出显示在执行后立即停止的关键字。因为我有时会忘记使用哪一个--我认为这很好用。|348697|<?php
++++//+Change+banana.com+to+the+domain+you+were+looking+for..
++++$wordToHighlight+=+"banana.com";
++++$serverVarHighlighted+=+str_replace(+$wordToHighlight,+'<span+style=\'background-color:#883399;+color:+#FFFFFF;\'>'.+$wordToHighlight+.'',++$_SERVER+);
++++echo+"<pre>";
++++print_r($serverVarHighlighted);
++++echo+"</pre>";
++++exit();
?>|348698|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

The best use would be

<pre><code>echo $_SERVER['HTTP_HOST'];
</code></pre>

And it can be used like this:

<pre><code>if (strpos($_SERVER['HTTP_HOST'], 'banana.com') !== false) {
 echo "Yes this is indeed the banana.com domain";
}
</code></pre>

This code below is a good way to see all the variables in $_SERVER in a structured HTML output with your keywords highlighted that halts directly after execution. Since I do sometimes forget which one to use myself - I think this can be nifty.

<pre><code>&lt;?php
 // Change banana.com to the domain you were looking for..
 $wordToHighlight = "banana.com";
 $serverVarHighlighted = str_replace( $wordToHighlight, '&lt;span style=\'background-color:#883399; color: #FFFFFF;\'&gt;'. $wordToHighlight .'&lt;/span&gt;', $_SERVER );
 echo "&lt;pre&gt;";
 print_r($serverVarHighlighted);
 echo "&lt;/pre&gt;";
 exit();
?&gt;
</code></pre>

blocks|key|348744|text|只需尝试：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|348745|echo+apache_request_headers()[3];|code-block|syntax|javascript|348746|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Simply try:

<pre><code>echo apache_request_headers()[3];
</code></pre>

blocks|key|348785|text|每个人都在使用parse_url函数，但有时用户可能会以不同的格式传递参数。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|348786|为了解决这个问题，我创建了一个函数。看看这个：|348787|function+fixDomainName($url='')
{
++++$strToLower+=+strtolower(trim($url));
++++$httpPregReplace+=+preg_replace('/%5Ehttp:\/\//i',+'',+$strToLower);
++++$httpsPregReplace+=+preg_replace('/%5Ehttps:\/\//i',+'',+$httpPregReplace);
++++$wwwPregReplace+=+preg_replace('/%5Ewww\./i',+'',+$httpsPregReplace);
++++$explodeToArray+=+explode('/',+$wwwPregReplace);
++++$finalDomainName+=+trim($explodeToArray[0]);
++++return+$finalDomainName;
}|code-block|syntax|javascript|348788|只需传递URL并获取域名即可。|348789|例如,|348790|echo+fixDomainName('https://stackoverflow.com');|348791|将返回：|348792|stackoverflow.com|348793|在某些情况下：|348794|echo+fixDomainName('stackoverflow.com/questions/id/slug');|348795|它还将返回stackoverflow.com。|348796|entityMap^0|7|9|0|0|0|0|0|0|0|0|0|0|5|H|0^^$0|@$1|2|3|4|5|6|7|14|8|@$9|15|A|16|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|17|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|18|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|19|8|@]|D|@]|E|$]]|$1|O|3|P|5|6|7|1A|8|@]|D|@]|E|$]]|$1|Q|3|R|5|J|7|1B|8|@]|D|@]|E|$K|L]]|$1|S|3|T|5|6|7|1C|8|@]|D|@]|E|$]]|$1|U|3|V|5|J|7|1D|8|@]|D|@]|E|$K|L]]|$1|W|3|X|5|6|7|1E|8|@]|D|@]|E|$]]|$1|Y|3|Z|5|J|7|1F|8|@]|D|@]|E|$K|L]]|$1|10|3|11|5|6|7|1G|8|@$9|1H|A|1I|B|C]]|D|@]|E|$]]|$1|12|3|-4|5|6|7|1J|8|@]|D|@]|E|$]]]|13|$]]

Everybody is using the <code>parse_url</code> function, but sometimes a user may pass the argument in different formats.
So as to fix that, I have created a function. Check this out:
<pre><code>function fixDomainName($url='')
{
 $strToLower = strtolower(trim($url));
 $httpPregReplace = preg_replace('/^http:\/\//i', '', $strToLower);
 $httpsPregReplace = preg_replace('/^https:\/\//i', '', $httpPregReplace);
 $wwwPregReplace = preg_replace('/^www\./i', '', $httpsPregReplace);
 $explodeToArray = explode('/', $wwwPregReplace);
 $finalDomainName = trim($explodeToArray[0]);
 return $finalDomainName;
}
</code></pre>
Just pass the URL and get the domain.
For example,
<pre><code>echo fixDomainName('https://stackoverflow.com');
</code></pre>
will return:
<pre><code>stackoverflow.com
</code></pre>
And in some situation:
<pre><code>echo fixDomainName('stackoverflow.com/questions/id/slug');
</code></pre>
And it will also return <code>stackoverflow.com</code>.

blocks|key|564886|text|获取域名的步骤：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|564887|$_SERVER['HTTP_HOST']+|code-block|syntax|javascript|564888|使用协议的域：|564889|$protocol+=+strpos(strtolower($_SERVER['SERVER_PROTOCOL']),+'https')+===+FALSE+?+'http'+:+'https';
$domainLink+=+$protocol+.+'://'+.+$_SERVER['HTTP_HOST'];|564890|协议、域和queryString合计：|564891|$url+=+$protocol+.+'://'+.+$_SERVER['HTTP_HOST']+.+'?'+.+$_SERVER['QUERY_STRING'];|564892|**As+$_SERVER'SERVER_NAME‘对于多域托管是不可靠的！|564893|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|W|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

To get the domain:
<pre><code>$_SERVER['HTTP_HOST'] 
</code></pre>
Domain with protocol:
<pre><code>$protocol = strpos(strtolower($_SERVER['SERVER_PROTOCOL']), 'https') === FALSE ? 'http' : 'https';
$domainLink = $protocol . '://' . $_SERVER['HTTP_HOST'];
</code></pre>
Protocol, domain, and queryString total:
<pre><code>$url = $protocol . '://' . $_SERVER['HTTP_HOST'] . '?' . $_SERVER['QUERY_STRING'];
</code></pre>
**As the $_SERVER['SERVER_NAME'] is not reliable for multi-domain hosting!

I have my site on the server <code>http://www.myserver.uk.com</code>.
On this server I have two domains:
<pre class="lang-none prettyprint-override"><code>one.com and two.com
</code></pre>
I would like to get the current domain using PHP, but if I use <code>$_SERVER['HTTP_HOST']</code> then it is showing me
<pre class="lang-none prettyprint-override"><code>myserver.uk.com
</code></pre>
instead of:
<pre class="lang-none prettyprint-override"><code>one.com or two.com
</code></pre>
How can I get the domain, and not the server name?

Get current domain

服务器

我在服务器http://www.myserver.uk.com上有我的网站。在此服务器上，我有两个域：one.com and two.com我想获得当前的域名使用PHP，但如果我使用$_SERVER['HTTP_HOST']，那么它会显示我myserver.uk.com而不是：one.com or two.com如何获...

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