blocks|key|1379471|text|因为Django只希望视图是一个可调用的对象，所以你可以在你的PYTHONPATH中把它放在你喜欢的任何地方。例如，您可以只创建一个新的包myapp.views，并将视图放入多个模块中。您自然需要更新引用这些视图可调用的urls.py和其他模块。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1379472|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Since Django just expects a view to be a callable object, you can put then wherever you like in your PYTHONPATH. So you could for instance just make a new package myapp.views and put views into multiple modules there. You will naturally have to update your urls.py and other modules that reference these view callables.

blocks|key|1379501|text|答案很简单:是的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1379502|最好的方法是创建一个名为views的目录，然后在urls.py中执行以下操作：|1379503|import+views
...
url(r'%5Eclassroom$',+views.school.klass,+name="classroom"),|code-block|syntax|javascript|1379504|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Simple answer: Yes.

Best is to make a directory called views and then in your urls.py do:

<pre><code>import views
...
url(r'^classroom$', views.school.klass, name="classroom"),
</code></pre>

blocks|key|1379595|text|我以前也这样做过(为了澄清)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1379596|我的方法是创建一个views目录，然后创建一个名为__init__.py的文件|offset|length|style|CODE|1379597|现在，当您调用urls.py时，只需添加另一个部件|1379598|例如，以前您可能调用过：-|1379599|url(r'%5Ecalendar/(?P<year>\d\d\d\d)/$',+'myproject.calendar.views.year')
url(r'%5Ecalendar/(?P<year>\d\d\d\d)/(?P<user>[a-z]%2B)/$',+'myproject.calendar.views.year_by_user')|code-block|syntax|javascript|1379600|现在，您可以调用类似于|1379601|url(r'%5Ecalendar/(?P<year>\d\d\d\d)/$',+'myproject.calendar.views.year.index')
url(r'%5Ecalendar/(?P<year>\d\d\d\d)/(?P<user>[a-z]%2B)/$',+'myproject.calendar.views.year.user')|1379602|当然，这是假设您有包含函数index和user的views/year.py+;)|1379603|entityMap^0|0|9|5|P|B|0|7|7|0|0|0|0|0|D|5|J|4|O|D|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Z|8|@$D|10|E|11|F|G]|$D|12|E|13|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|14|8|@$D|15|E|16|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|17|8|@]|9|@]|A|$]]|$1|L|3|M|5|N|7|18|8|@]|9|@]|A|$O|P]]|$1|Q|3|R|5|6|7|19|8|@]|9|@]|A|$]]|$1|S|3|T|5|N|7|1A|8|@]|9|@]|A|$O|P]]|$1|U|3|V|5|6|7|1B|8|@$D|1C|E|1D|F|G]|$D|1E|E|1F|F|G]|$D|1G|E|1H|F|G]]|9|@]|A|$]]|$1|W|3|-4|5|6|7|1I|8|@]|9|@]|A|$]]]|X|$]]

I've had to do this before (for clarities sake)

The way I did this was to create a <code>views</code> directory, then, in that, create a file called <code>__init__.py</code>

Now, when you're calling in your <code>urls.py</code>, you simply need to add another part

For example, previously, you may have called:-

<pre><code>url(r'^calendar/(?P&lt;year&gt;\d\d\d\d)/$', 'myproject.calendar.views.year')
url(r'^calendar/(?P&lt;year&gt;\d\d\d\d)/(?P&lt;user&gt;[a-z]+)/$', 'myproject.calendar.views.year_by_user')
</code></pre>

You can now call something along the lines of

<pre><code>url(r'^calendar/(?P&lt;year&gt;\d\d\d\d)/$', 'myproject.calendar.views.year.index')
url(r'^calendar/(?P&lt;year&gt;\d\d\d\d)/(?P&lt;user&gt;[a-z]+)/$', 'myproject.calendar.views.year.user')
</code></pre>

This is, of course, assuming that you had <code>views/year.py</code> containing the functions <code>index</code> and <code>user</code> ;)

blocks|key|1379654|text|假设您有一个名为：password_generator.py的文件，然后在views.py中添加：from+password_generator+import+*|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1379655|然后，您可以从views.py调用该模块的函数。|1379656|entityMap^0|9|L|11|8|1D|W|0|7|8|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|I|$]]

Suppose if you have a file named: <code>password_generator.py</code> then inside <code>views.py</code> add: <code>from password_generator import *</code>

Then you can call that module's function from <code>views.py</code>.

My <code>views.py</code> has become too big and it's hard to find the right view.

How do I split it in several files and then import it? Does it involve any speed loss?

Can I do the same with <code>models.py</code>?

Split views.py in several files

Django

我的views.py变得太大了，很难找到合适的视图。如何将其拆分成多个文件，然后导入？它是否涉及到速度损失？我可以对models.py执行相同的操作吗

问将views.py拆分为几个文件
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问将views.py拆分为几个文件EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问将views.py拆分为几个文件
EN