SQL阶梯查询
SQL阶梯查询
提问于 2012-06-27 05:02:48
我需要一些帮助，以产生一个MS SQL 2012查询，将匹配所需的阶梯输出。行按一个日期范围(帐户提交日期月)汇总数据，列按另一个日期范围(付款日期月)汇总数据
表1： accounts 跟踪为收集而放置的帐户。
CREATE TABLE [dbo].[Accounts](
[AccountID] [nchar](10) NOT NULL,
[SubmissionDate] [date] NOT NULL,
[Amount] [money] NOT NULL,
CONSTRAINT [PK_Accounts] PRIMARY KEY CLUSTERED (AccountID ASC))
INSERT INTO [dbo].[Accounts] VALUES ('1000', '2012-01-01', 1999.00)
INSERT INTO [dbo].[Accounts] VALUES ('1001', '2012-01-02', 100.00)
INSERT INTO [dbo].[Accounts] VALUES ('1002', '2012-02-05', 350.00)
INSERT INTO [dbo].[Accounts] VALUES ('1003', '2012-03-01', 625.00)
INSERT INTO [dbo].[Accounts] VALUES ('1004', '2012-03-10', 50.00)
INSERT INTO [dbo].[Accounts] VALUES ('1005', '2012-03-10', 10.00)表2：Trans跟踪付款
CREATE TABLE [dbo].[Trans](
[TranID] [int] IDENTITY(1,1) NOT NULL,
[AccountID] [nchar](10) NOT NULL,
[TranDate] [date] NOT NULL,
[TranAmount] [money] NOT NULL,
CONSTRAINT [PK_Trans] PRIMARY KEY CLUSTERED (TranID ASC))
INSERT INTO [dbo].[Trans] VALUES (1000, '2012-01-15', 300.00)
INSERT INTO [dbo].[Trans] VALUES (1000, '2012-02-15', 300.00)
INSERT INTO [dbo].[Trans] VALUES (1000, '2012-03-15', 300.00)
INSERT INTO [dbo].[Trans] VALUES (1002, '2012-02-20', 325.00)
INSERT INTO [dbo].[Trans] VALUES (1002, '2012-04-20', 25.00)
INSERT INTO [dbo].[Trans] VALUES (1003, '2012-03-24', 625.00)
INSERT INTO [dbo].[Trans] VALUES (1004, '2012-03-28', 31.00)
INSERT INTO [dbo].[Trans] VALUES (1004, '2012-04-12', 5.00)
INSERT INTO [dbo].[Trans] VALUES (1005, '2012-04-08', 7.00)
INSERT INTO [dbo].[Trans] VALUES (1005, '2012-04-28', 3.00)下面是期望的输出应该是什么样子
*Total Payments in Each Month*
SubmissionYearMonth TotalAmount | 2012-01 2012-02 2012-03 2012-04
--------------------------------------------------------------------
2012-01 2099.00 | 300.00 300.00 300.00 0.00
2012-02 350.00 | 325.00 0.00 25.00
2012-03 685.00 | 656.00 15.00前两列按月份对Account.Amount分组求和。
最后4列按月对当前行的给定月份中的帐户的Tran.TranAmount求和。
我一直在处理的查询感觉很接近。我只是不知道延迟是否正确。到目前为止，我正在使用的查询如下：
Select SubmissionYearMonth,
TotalAmount,
pt.[0] AS MonthOld0,
pt.[1] AS MonthOld1,
pt.[2] AS MonthOld2,
pt.[3] AS MonthOld3,
pt.[4] AS MonthOld4,
pt.[5] AS MonthOld5,
pt.[6] AS MonthOld6,
pt.[7] AS MonthOld7,
pt.[8] AS MonthOld8,
pt.[9] AS MonthOld9,
pt.[10] AS MonthOld10,
pt.[11] AS MonthOld11,
pt.[12] AS MonthOld12,
pt.[13] AS MonthOld13
From (
SELECT Convert(Char(4),Year(SubmissionDate)) + '-' + Right('00' + Convert(VarChar(2), DatePart(Month, SubmissionDate)),2) AS SubmissionYearMonth,
SUM(Amount) AS TotalAmount
FROM Accounts
GROUP BY Convert(Char(4),Year(SubmissionDate)) + '-' + Right('00' + Convert(VarChar(2), DatePart(Month, SubmissionDate)),2)
)
AS AccountSummary
OUTER APPLY
(
SELECT *
FROM (
SELECT CASE WHEN DATEDIFF(Month, SubmissionDate, TranDate) < 13
THEN DATEDIFF(Month, SubmissionDate, TranDate)
ELSE 13
END AS PaymentMonthAge,
TranAmount
FROM Trans INNER JOIN Accounts ON Trans.AccountID = Accounts.AccountID
Where Convert(Char(4),Year(TranDate)) + '-' + Right('00' + Convert(VarChar(2), DatePart(Month, TranDate)),2)
= AccountSummary.SubmissionYearMonth
) as TransTemp
PIVOT (SUM(TranAmount)
FOR PaymentMonthAge IN ([0],
[1],
[2],
[3],
[4],
[5],
[6],
[7],
[8],
[9],
[10],
[11],
[12],
[13])) as TransPivot
) as pt它会产生以下输出：
SubmissionYearMonth TotalAmount MonthOld0 MonthOld1 MonthOld2 MonthOld3 ...
2012-01 2099.00 300.00 NULL NULL NULL ...
2012-02 350.00 325.00 300.00 NULL NULL ...
2012-03 685.00 656.00 NULL 300.00 NULL ...至于列日期标题。我不确定最好的选择是什么。我可以添加一组额外的列，并创建一个可以在结果报告中使用的计算值。
SQL Fiddle：http://www.sqlfiddle.com/#!6/272e5/1/0
回答 4
Stack Overflow用户
回答已采纳
发布于 2012-07-02 23:24:01
Thomas，我将您的回复作为我最终使用的解决方案的灵感来源。
我首先创建了一个SubmissionDate，TranDate交叉连接框架日期矩阵，稍后我将使用它来连接AccountSummary和TranSummary数据。
生成的查询输出不是按TranDate月份按列格式化的。相反，我使用SQL Server Reporting Services矩阵中的输出，并使用基于TranSummaryMonthNum列的列分组来获得所需的格式化输出。
;
WITH
--Generate a list of Dates, from the first SubmissionDate, through today.
--Note: Requires the use of: 'OPTION (MAXRECURSION 0)' to generate a list with more than 100 dates.
CTE_AutoDates AS
( Select Min(SubmissionDate) as FiscalDate
From Accounts
UNION ALL
SELECT DATEADD(Day, 1, FiscalDate)
FROM CTE_AutoDates
WHERE DATEADD(Day, 1, FiscalDate) <= GetDate()
),
FiscalDates As
( SELECT FiscalDate,
DATEFROMPARTS(Year(FiscalDate), Month(FiscalDate), 1) as FiscalMonthStartDate
FROM CTE_AutoDates
--Optionaly filter Fiscal Dates by the last known Math.Max(SubmissionDate, TranDate)
Where FiscalDate <= (Select Max(MaxDate)
From (Select Max(SubmissionDate) as MaxDate From Accounts
Union All
Select Max(TranDate) as MaxDate From Trans
) as MaxDates
)
),
FiscalMonths as
( SELECT Distinct FiscalMonthStartDate
FROM FiscalDates
),
--Matrix to store the reporting date groupings for the Account submission and payment periods.
SubmissionAndTranMonths AS
( Select AM.FiscalMonthStartDate as SubmissionMonthStartDate,
TM.FiscalMonthStartDate as TransMonthStartDate,
DateDiff(Month, (Select Min(FiscalMonthStartDate) From FiscalMonths), TM.FiscalMonthStartDate) as TranSummaryMonthNum
From FiscalMonths AS AM
Join FiscalMonths AS TM
ON TM.FiscalMonthStartDate >= AM.FiscalMonthStartDate
),
AccountData as
( Select A.AccountID,
A.Amount,
FD.FiscalMonthStartDate as SubmissionMonthStartDate
From Accounts as A
Inner Join FiscalDates as FD
ON A.SubmissionDate = FD.FiscalDate
),
TranData as
( Select T.AccountID,
T.TranAmount,
AD.SubmissionMonthStartDate,
FD.FiscalMonthStartDate as TranMonthStartDate
From Trans as T
Inner Join AccountData as AD
ON T.AccountID = AD.AccountID
Inner Join FiscalDates AS FD
ON T.TranDate = FD.FiscalDate
),
AccountSummaryByMonth As
( Select ASM.FiscalMonthStartDate,
Sum(AD.Amount) as TotalSubmissionAmount
From FiscalMonths as ASM
Inner Join AccountData as AD
ON ASM.FiscalMonthStartDate = AD.SubmissionMonthStartDate
Group By
ASM.FiscalMonthStartDate
),
TranSummaryByMonth As
( Select STM.SubmissionMonthStartDate,
STM.TransMonthStartDate,
STM.TranSummaryMonthNum,
Sum(TD.TranAmount) as TotalTranAmount
From SubmissionAndTranMonths as STM
Inner Join TranData as TD
ON STM.SubmissionMonthStartDate = TD.SubmissionMonthStartDate
AND STM.TransMonthStartDate = TD.TranMonthStartDate
Group By
STM.SubmissionMonthStartDate,
STM.TransMonthStartDate,
STM.TranSummaryMonthNum
)
--#Inspect 1
--Select * From SubmissionAndTranMonths
--OPTION (MAXRECURSION 0)
--#Inspect 1 Results
--SubmissionMonthStartDate TransMonthStartDate TranSummaryMonthNum
--2012-01-01 2012-01-01 0
--2012-01-01 2012-02-01 1
--2012-01-01 2012-03-01 2
--2012-01-01 2012-04-01 3
--2012-02-01 2012-02-01 1
--2012-02-01 2012-03-01 2
--2012-02-01 2012-04-01 3
--2012-03-01 2012-03-01 2
--2012-03-01 2012-04-01 3
--2012-04-01 2012-04-01 3
--#Inspect 2
--Select * From AccountSummaryByMonth
--OPTION (MAXRECURSION 0)
--#Inspect 2 Results
--FiscalMonthStartDate TotalSubmissionAmount
--2012-01-01 2099.00
--2012-02-01 350.00
--2012-03-01 685.00
--#Inspect 3
--Select * From TranSummaryByMonth
--OPTION (MAXRECURSION 0)
--#Inspect 3 Results
--SubmissionMonthStartDate TransMonthStartDate TranSummaryMonthNum TotalTranAmount
--2012-01-01 2012-01-01 0 300.00
--2012-01-01 2012-02-01 1 300.00
--2012-01-01 2012-03-01 2 300.00
--2012-02-01 2012-02-01 1 325.00
--2012-02-01 2012-04-01 3 25.00
--2012-03-01 2012-03-01 2 656.00
--2012-03-01 2012-04-01 3 15.00
Select STM.SubmissionMonthStartDate,
ASM.TotalSubmissionAmount,
STM.TransMonthStartDate,
STM.TranSummaryMonthNum,
TSM.TotalTranAmount
From SubmissionAndTranMonths as STM
Inner Join AccountSummaryByMonth as ASM
ON STM.SubmissionMonthStartDate = ASM.FiscalMonthStartDate
Left Join TranSummaryByMonth AS TSM
ON STM.SubmissionMonthStartDate = TSM.SubmissionMonthStartDate
AND STM.TransMonthStartDate = TSM.TransMonthStartDate
Order By STM.SubmissionMonthStartDate, STM.TranSummaryMonthNum
OPTION (MAXRECURSION 0)
--#Results
--SubmissionMonthStartDate TotalSubmissionAmount TransMonthStartDate TranSummaryMonthNum TotalTranAmount
--2012-01-01 2099.00 2012-01-01 0 300.00
--2012-01-01 2099.00 2012-02-01 1 300.00
--2012-01-01 2099.00 2012-03-01 2 300.00
--2012-01-01 2099.00 2012-04-01 3 NULL
--2012-02-01 350.00 2012-02-01 1 325.00
--2012-02-01 350.00 2012-03-01 2 NULL
--2012-02-01 350.00 2012-04-01 3 25.00
--2012-03-01 685.00 2012-03-01 2 656.00
--2012-03-01 685.00 2012-04-01 3 15.00Stack Overflow用户
发布于 2012-06-27 23:57:47
由于您使用的是SQL Server 2012，因此我们可以使用Format函数来美化日期。不需要按字符串分组。相反，我发现尽可能长时间地使用适当的数据类型是有用的，并且只在显示时使用Format或Convert (或者根本不使用，让中间层处理显示)。
在这个解决方案中，我随意假设了最早的TransDate并从中提取出来，也就是那个月的第一天。然而，人们可以很容易地将该表达式替换为所需的开始日期的静态值，并且此解决方案将花费该时间和接下来的12个月。
With SubmissionMonths As
(
Select DateAdd(d, -Day(A.SubmissionDate) + 1, A.SubmissionDate) As SubmissionMonth
, A.Amount
From dbo.Accounts As A
)
, TranMonths As
(
Select DateAdd(d, -Day(Min( T.TranDate )) + 1, Min( T.TranDate )) As TranMonth
, 1 As MonthNum
From dbo.Accounts As A
Join dbo.Trans As T
On T.AccountId = A.AccountId
Join SubmissionMonths As M
On A.SubmissionDate >= M.SubmissionMonth
And A.SubmissionDate < DateAdd(m,1,SubmissionMonth)
Union All
Select DateAdd(m, 1, TranMonth), MonthNum + 1
From TranMonths
Where MonthNum < 12
)
, TotalBySubmissionMonth As
(
Select M.SubmissionMonth, Sum( M.Amount ) As Total
From SubmissionMonths As M
Group By M.SubmissionMonth
)
Select Format(SMT.SubmissionMonth,'yyyy-MM') As SubmissionMonth, SMT.Total
, Sum( Case When TM.MonthNum = 1 Then T.TranAmount End ) As Month1
, Sum( Case When TM.MonthNum = 2 Then T.TranAmount End ) As Month2
, Sum( Case When TM.MonthNum = 3 Then T.TranAmount End ) As Month3
, Sum( Case When TM.MonthNum = 4 Then T.TranAmount End ) As Month4
, Sum( Case When TM.MonthNum = 5 Then T.TranAmount End ) As Month5
, Sum( Case When TM.MonthNum = 6 Then T.TranAmount End ) As Month6
, Sum( Case When TM.MonthNum = 7 Then T.TranAmount End ) As Month7
, Sum( Case When TM.MonthNum = 8 Then T.TranAmount End ) As Month8
, Sum( Case When TM.MonthNum = 9 Then T.TranAmount End ) As Month9
, Sum( Case When TM.MonthNum = 10 Then T.TranAmount End ) As Month10
, Sum( Case When TM.MonthNum = 11 Then T.TranAmount End ) As Month11
, Sum( Case When TM.MonthNum = 12 Then T.TranAmount End ) As Month12
From TotalBySubmissionMonth As SMT
Join dbo.Accounts As A
On A.SubmissionDate >= SMT.SubmissionMonth
And A.SubmissionDate < DateAdd(m,1,SMT.SubmissionMonth)
Join dbo.Trans As T
On T.AccountId = A.AccountId
Join TranMonths As TM
On T.TranDate >= TM.TranMonth
And T.TranDate < DateAdd(m,1,TM.TranMonth)
Group By SMT.SubmissionMonth, SMT.TotalStack Overflow用户
发布于 2012-06-27 05:34:11
下面的查询几乎返回了您想要的结果。您需要单独执行to操作。我只是将结果合并在一起：
select a.yyyymm, a.Amount,
t201201, t201202, t201203, t201204
from (select LEFT(convert(varchar(255), a.submissiondate, 121), 7) as yyyymm,
SUM(a.Amount) as amount
from Accounts a
group by LEFT(convert(varchar(255), a.submissiondate, 121), 7)
) a left outer join
(select LEFT(convert(varchar(255), a.submissiondate, 121), 7) as yyyymm,
sum(case when trans_yyyymm = '2012-01' then tranamount end) as t201201,
sum(case when trans_yyyymm = '2012-02' then tranamount end) as t201202,
sum(case when trans_yyyymm = '2012-03' then tranamount end) as t201203,
sum(case when trans_yyyymm = '2012-04' then tranamount end) as t201204
from Accounts a join
(select t.*, LEFT(convert(varchar(255), t.trandate, 121), 7) as trans_yyyymm
from trans t
) t
on a.accountid = t.accountid
group by LEFT(convert(varchar(255), a.submissiondate, 121), 7)
) t
on a.yyyymm = t.yyyymm
order by 1我得到了一个NULL，你在两个单元格中有一个0.00。
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https://stackoverflow.com/questions/11215878
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