blocks|key|1454928|text|尝试从第二个Time.now中减去第一个。如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1454929|a+=+Time.now
sleep(3)
puts+Time.now+-+a+#+about+3.0|code-block|syntax|javascript|1454930|这为您提供了两次之间的浮点数秒数(以及毫秒)。|1454931|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Try subtracting the first Time.now from the second. Like so:

<pre><code>a = Time.now
sleep(3)
puts Time.now - a # about 3.0
</code></pre>

This gives you a floating-point number of the seconds between the two times (and with that, the milliseconds).

blocks|key|1454964|text|如前所述，您可以像操作数值(或浮点)值一样对Time对象进行操作。这些操作会产生第二个分辨率，可以很容易地转换。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1454965|例如：|1454966|def+time_diff_milli(start,+finish)
+++(finish+-+start)+*+1000.0
end

t1+=+Time.now
#+arbitrary+elapsed+time
t2+=+Time.now

msecs+=+time_diff_milli+t1,+t2|code-block|syntax|javascript|1454967|您将需要决定是否将其截断。|1454968|entityMap^0|M|4|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|T|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|U|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|V|8|@]|D|@]|E|$]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

As stated already, you can operate on <code>Time</code> objects as if they were numeric (or floating point) values. These operations result in second resolution which can easily be converted. 

For example:

<pre><code>def time_diff_milli(start, finish)
 (finish - start) * 1000.0
end

t1 = Time.now
# arbitrary elapsed time
t2 = Time.now

msecs = time_diff_milli t1, t2
</code></pre>

You will need to decide whether to truncate that or not.

blocks|key|1240098|text|您可以使用以下内容在上面的解决方案中添加一些语法糖：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1240099|class+Time
++def+to_ms
++++(self.to_f+*+1000.0).to_i
++end
end

start_time+=+Time.now
sleep(3)
end_time+=+Time.now
elapsed_time+=+end_time.to_ms+-+start_time.to_ms++#+=>+3004|code-block|syntax|javascript|1240100|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can add a little syntax sugar to the above solution with the following:

<pre><code>class Time
 def to_ms
 (self.to_f * 1000.0).to_i
 end
end

start_time = Time.now
sleep(3)
end_time = Time.now
elapsed_time = end_time.to_ms - start_time.to_ms # =&gt; 3004
</code></pre>

blocks|key|1240163|text|我认为答案选错了，这种方法给出的是秒，而不是毫秒。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1240164|t+=+Time.now.t­o_f
=>+1382471965.146|code-block|syntax|javascript|1240165|这里我假设浮点值是毫秒|1240166|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I think the answer is incorrectly chosen, that method gives seconds, not milliseconds.

<pre><code>t = Time.now.t­o_f
=&gt; 1382471965.146
</code></pre>

Here I suppose the floating value are the milliseconds

blocks|key|1455110|text|要以毫秒为单位获取时间，最好加上.round(3)，这样在某些情况下会更准确：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1455111|puts+Time.now.to_f+#+=>+1453402722.577573

(Time.now.to_f.round(3)*1000).to_i++#+=>+1453402722578|code-block|syntax|javascript|1455112|entityMap^0|G|9|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

To get time in milliseconds, it's better to add <code>.round(3)</code>, so it will be more accurate in some cases:

<pre><code>puts Time.now.to_f # =&gt; 1453402722.577573

(Time.now.to_f.round(3)*1000).to_i # =&gt; 1453402722578
</code></pre>

blocks|key|1240264|text|%25L以拼音表示毫秒|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1240265|require+'time'
puts+Time.now.strftime("%25Y-%25m-%25dT%25H:%25M:%25S.%25L")|code-block|syntax|javascript|1240266|或|1240267|puts+Time.now.strftime("%25Y-%25m-%25d+%25H:%25M:%25S.%25L")|1240268|会给你当前的时间戳，单位是毫秒。|1240269|entityMap^0|0|2|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|Y|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|R|$]]

<code>%L</code> gives milliseconds in ruby

<pre><code>require 'time'
puts Time.now.strftime("%Y-%m-%dT%H:%M:%S.%L")
</code></pre>

or

<pre><code>puts Time.now.strftime("%Y-%m-%d %H:%M:%S.%L")
</code></pre>

will give you current timestamp in milliseconds.

blocks|key|1455174|text|DateTime.now.strftime("%25Q")|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1455175|示例用法：|unstyled|1455176|>>+DateTime.now.strftime("%25Q")
=>+"1541433332357"

>>+DateTime.now.strftime("%25Q").to_i
=>+1541433332357|1455177|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>DateTime.now.strftime("%Q")
</code></pre>

Example usage:

<pre><code>&gt;&gt; DateTime.now.strftime("%Q")
=&gt; "1541433332357"

&gt;&gt; DateTime.now.strftime("%Q").to_i
=&gt; 1541433332357
</code></pre>

blocks|key|1455265|text|如果你想要一些精确的东西，不受应用程序(Timecop)或其他程序(如NTP)的其他部分的影响，可以结合使用Process#clock_gettime和Process::CLOCK_MONOTONIC来直接获取处理器时间。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1455266|t1+=+Process.clock_gettime(Process::CLOCK_MONOTONIC)
#+other+code
t2+=+Process.clock_gettime(Process::CLOCK_MONOTONIC)|code-block|syntax|javascript|1455267|此外，如果您正在尝试对一些代码进行基准测试，也可以使用Benchmark模块！|1455268|require+"benchmark"

time+=+Benchmark.realtime+do
++#+code+to+measure
end|1455269|entityMap|0|LINK|mutability|MUTABLE|url|https://ruby-doc.org/core-3.0.2/Process.html#method-c-clock_gettime|1|https://ruby-doc.org/stdlib-3.0.2/libdoc/benchmark/rdoc/Benchmark.html#method-c-realtime^0|K|7|1I|L|24|O|1I|L|0|0|0|R|9|R|9|1|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]|$9|13|A|14|B|C]]|D|@$9|15|A|16|1|17]]|E|$]]|$1|F|3|G|5|H|7|18|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|19|8|@$9|1A|A|1B|B|C]]|D|@$9|1C|A|1D|1|1E]]|E|$]]|$1|M|3|N|5|H|7|1F|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|1G|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]|W|$5|R|S|T|E|$U|X]]]]

If you want something precise, unaffected by other part of your app (<code>Timecop</code>) or other programs (like NTP), use <a href="https://ruby-doc.org/core-3.0.2/Process.html#method-c-clock_gettime" rel="nofollow noreferrer"><code>Process#clock_gettime</code></a> with <code>Process::CLOCK_MONOTONIC</code> to directly get the processor time.
<pre class="lang-rb prettyprint-override"><code>t1 = Process.clock_gettime(Process::CLOCK_MONOTONIC)
# other code
t2 = Process.clock_gettime(Process::CLOCK_MONOTONIC)
</code></pre>
Also, if you are trying to benchmark some code tho, there is the <a href="https://ruby-doc.org/stdlib-3.0.2/libdoc/benchmark/rdoc/Benchmark.html#method-c-realtime" rel="nofollow noreferrer"><code>Benchmark</code></a> module for that!
<pre class="lang-rb prettyprint-override"><code>require &quot;benchmark&quot;

time = Benchmark.realtime do
 # code to measure
end
</code></pre>

If I have a <code>Time</code> object got from :

<pre><code>Time.now
</code></pre>

and later I instantiate another object with that same line, how can I see how many milliseconds have passed? The second object may be created that same minute, over the next minutes or even hours.

How do I get elapsed time in milliseconds in Ruby?

如果我有一个从下面获取的Time对象：Time.now后来我用同一行实例化了另一个对象，我怎么能看到多少毫秒已经过去了呢？第二个对象可以在同一分钟、在接下来的几分钟甚至几个小时内创建。

问如何在Ruby中获得以毫秒为单位的运行时间？
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问如何在Ruby中获得以毫秒为单位的运行时间？EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问如何在Ruby中获得以毫秒为单位的运行时间？
EN