blocks|key|1975306|text|您还可以将enumerable包装在一个类中：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1975307|class+Wrapper
{
++++IEnumerable<BaseClass>+classes;
}|code-block|syntax|javascript|1975308|然后对其进行序列化和反序列化。|1975309|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You could also wrap the enumerable in a class:

<pre><code>class Wrapper
{
 IEnumerable&lt;BaseClass&gt; classes;
}
</code></pre>

then serialize and deserialize this.

blocks|key|1761651|text|反序列化时使用以下JsonSerializerSettings结构：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1761652|new+JsonSerializerSettings()
{
++++TypeNameHandling+=+TypeNameHandling.Objects
})|code-block|syntax|javascript|1761653|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

use the following JsonSerializerSettings construct while deserializing :

<pre><code>new JsonSerializerSettings()
{
 TypeNameHandling = TypeNameHandling.Objects
})
</code></pre>

blocks|key|1761708|text|这里有一种不需要在json中填充$type的方法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1761709|一个Json转换器：|1761710|public+class+FooConverter+:+JsonConverter
{
++++public+override+bool+CanConvert(Type+objectType)
++++{
++++++++return+(objectType+==+typeof(BaseFoo));
++++}

++++public+override+object+ReadJson(JsonReader+reader,+Type+objectType,+object+existingValue,+JsonSerializer+serializer)
++++{
++++++++JObject+jo+=+JObject.Load(reader);
++++++++if+(jo["FooBarBuzz"].Value<string>()+==+"A")
++++++++++++return+jo.ToObject<AFoo>(serializer);

++++++++if+(jo["FooBarBuzz"].Value<string>()+==+"B")
++++++++++++return+jo.ToObject<BFoo>(serializer);

++++++++return+null;
++++}

++++public+override+bool+CanWrite
++++{
++++++++get+{+return+false;+}
++++}

++++public+override+void+WriteJson(JsonWriter+writer,+object+value,+JsonSerializer+serializer)
++++{
++++++++throw+new+NotImplementedException();
++++}
}|code-block|syntax|javascript|1761711|使用它：|1761712|var+test+=+JsonConvert.DeserializeObject<List<BaseFoo>>(result,+new+JsonSerializerSettings()+
{+
++++Converters+=+{+new+FooConverter()+}
});|1761713|摘自here|offset|length|1761714|entityMap|0|LINK|mutability|MUTABLE|url|https://blog.codeinside.eu/2015/03/30/json-dotnet-deserialize-to-abstract-class-or-interface/^0|0|0|0|0|0|2|4|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Z|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|10|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|11|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|12|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|13|8|@]|9|@$O|14|P|15|1|16]]|A|$]]|$1|Q|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|R|$S|$5|T|U|V|A|$W|X]]]]

Here is a way to do it without populating $type in the json.

A Json Converter:

<pre><code>public class FooConverter : JsonConverter
{
 public override bool CanConvert(Type objectType)
 {
 return (objectType == typeof(BaseFoo));
 }

 public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
 {
 JObject jo = JObject.Load(reader);
 if (jo["FooBarBuzz"].Value&lt;string&gt;() == "A")
 return jo.ToObject&lt;AFoo&gt;(serializer);

 if (jo["FooBarBuzz"].Value&lt;string&gt;() == "B")
 return jo.ToObject&lt;BFoo&gt;(serializer);

 return null;
 }

 public override bool CanWrite
 {
 get { return false; }
 }

 public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
 {
 throw new NotImplementedException();
 }
}
</code></pre>

using it:

<pre><code>var test = JsonConvert.DeserializeObject&lt;List&lt;BaseFoo&gt;&gt;(result, new JsonSerializerSettings() 
{ 
 Converters = { new FooConverter() }
});
</code></pre>

taken from <a href="https://blog.codeinside.eu/2015/03/30/json-dotnet-deserialize-to-abstract-class-or-interface/" rel="noreferrer">here</a>

blocks|key|1761744|text|因为我只需要特定基类的单端序列化程序(使API返回派生类属性)，所以我提出了当前的解决方案|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1761745|public+class+CustomConverter+:+JsonConverter<BaseClass>
{
++++private+readonly+JsonSerializerOptions+_serializerOptions;

++++public+CustomConverter()
++++{
++++++++_serializerOptions+=+new+JsonSerializerOptions
++++++++{
++++++++++++PropertyNamingPolicy+=+JsonNamingPolicy.CamelCase,
++++++++++++IgnoreNullValues+=+true,
++++++++};
++++}

++++public+override+bool+CanConvert(Type+objectType)
++++{
++++++++return+(objectType+==+typeof(BaseClass));
++++}

++++public+override+BaseClass+Read(ref+Utf8JsonReader+reader,+Type+typeToConvert,+JsonSerializerOptions+options)
++++{
++++++++throw+new+NotImplementedException();
++++}

++++public+override+void+Write(Utf8JsonWriter+writer,+BaseClass+value,+JsonSerializerOptions+options)
++++{
++++++++writer.WriteStringValue(JsonSerializer.SerializeToUtf8Bytes(value,+value.GetType(),+_serializerOptions));
++++}
}|code-block|syntax|javascript|1761746|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

As I needed only one-side serializer for specific base class (to make API return derived classes properties), I came up with current solution

<pre><code>public class CustomConverter : JsonConverter&lt;BaseClass&gt;
{
 private readonly JsonSerializerOptions _serializerOptions;

 public CustomConverter()
 {
 _serializerOptions = new JsonSerializerOptions
 {
 PropertyNamingPolicy = JsonNamingPolicy.CamelCase,
 IgnoreNullValues = true,
 };
 }

 public override bool CanConvert(Type objectType)
 {
 return (objectType == typeof(BaseClass));
 }

 public override BaseClass Read(ref Utf8JsonReader reader, Type typeToConvert, JsonSerializerOptions options)
 {
 throw new NotImplementedException();
 }

 public override void Write(Utf8JsonWriter writer, BaseClass value, JsonSerializerOptions options)
 {
 writer.WriteStringValue(JsonSerializer.SerializeToUtf8Bytes(value, value.GetType(), _serializerOptions));
 }
}
</code></pre>

given this JSON:

<pre><code>[
 {
 "$id": "1",
 "$type": "MyAssembly.ClassA, MyAssembly",
 "Email": "me@here.com",
 },
 {
 "$id": "2",
 "$type": "MyAssembly.ClassB, MyAssembly",
 "Email": "me@here.com",
 }
]
</code></pre>

and these classes:

<pre><code>public abstract class BaseClass
{
 public string Email;
}
public class ClassA : BaseClass
{
}
public class ClassB : BaseClass
{
}
</code></pre>

How can I deserialize the JSON into:

<pre><code>IEnumerable&lt;BaseClass&gt; deserialized;
</code></pre>

I can't use <code>JsonConvert.Deserialize&lt;IEnumerable&lt;BaseClass&gt;&gt;()</code> because it complains that <code>BaseClass</code> is abstract.

how to deserialize JSON into IEnumerable<BaseType> with Newtonsoft JSON.NET

JSON

给定此JSON：[  {    "$id": "1",    "$type": "MyAssembly.ClassA, MyAssembly",    "Email": "me@here.com",  },  {    "$id": "2",    "$type": "MyAssembly.ClassB, MyAsse...

问如何用Newtonsoft JSON.NET将JSON反序列化为IEnumerable<BaseType>
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