blocks|key|849037|text|Calendar+API|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|849038|由此可以看出，calendar.month_name[3]将返回March，而0的数组索引是空字符串，因此也无需担心零索引。|style|CODE|849039|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.python.org/library/calendar.html#calendar.month_name^0|0|C|0|0|7|M|W|5|13|1|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@$A|Q|B|R|1|S]]|C|$]]|$1|D|3|E|5|6|7|T|8|@$A|U|B|V|F|G]|$A|W|B|X|F|G]|$A|Y|B|Z|F|G]]|9|@]|C|$]]|$1|H|3|-4|5|6|7|10|8|@]|9|@]|C|$]]]|I|$J|$5|K|L|M|C|$N|O]]]]

<a href="http://docs.python.org/library/calendar.html#calendar.month_name" rel="noreferrer">Calendar API</a>

From that you can see that <code>calendar.month_name[3]</code> would return <code>March</code>, and the array index of <code>0</code> is the empty string, so there's no need to worry about zero-indexing either.

blocks|key|849053|text|import+datetime
mydate+=+datetime.datetime.now()
mydate.strftime("%25B")+#+'December'
mydate.strftime("%25b")+#+'dec'|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|849054|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import datetime
mydate = datetime.datetime.now()
mydate.strftime("%B") # 'December'
mydate.strftime("%b") # 'dec'
</code></pre>

blocks|key|849082|text|如果您(像我一样)在数据框中有一列月份数字，我将提供以下内容：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|849083|df['monthName']+=+df['monthNumer'].apply(lambda+x:+calendar.month_name[x])|code-block|syntax|javascript|849084|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I'll offer this in case (like me) you have a column of month numbers in a dataframe:

<pre><code>df['monthName'] = df['monthNumer'].apply(lambda x: calendar.month_name[x])
</code></pre>

blocks|key|849141|text|如果您只需要知道给定数字(1+-+12)的月份名称，这就没有太大帮助，因为当前日期并不重要。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|849142|calendar.month_name[i]|offset|length|style|CODE|849143|或|849144|calendar.month_abbr[i]|849145|在这里更有用。|849146|下面是一个示例：|849147|import+calendar

for+month_idx+in+range(1,+13):
++++print+(calendar.month_name[month_idx])
++++print+(calendar.month_abbr[month_idx])
++++print+("")|code-block|syntax|javascript|849148|示例输出：|849149|January
Jan

February
Feb

March
Mar

...|849150|entityMap^0|0|0|M|0|0|0|M|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|11|8|@$D|12|E|13|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|14|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|15|8|@$D|16|E|17|F|G]]|9|@]|A|$]]|$1|L|3|M|5|6|7|18|8|@]|9|@]|A|$]]|$1|N|3|O|5|6|7|19|8|@]|9|@]|A|$]]|$1|P|3|Q|5|R|7|1A|8|@]|9|@]|A|$S|T]]|$1|U|3|V|5|6|7|1B|8|@]|9|@]|A|$]]|$1|W|3|X|5|R|7|1C|8|@]|9|@]|A|$S|T]]|$1|Y|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]]|Z|$]]

This is not so helpful if you need to just know the month name for a given number (1 - 12), as the current day doesn't matter. 

<code>calendar.month_name[i]</code> 

or 

<code>calendar.month_abbr[i]</code> 

are more useful here. 

Here is an example:

<pre><code>import calendar

for month_idx in range(1, 13):
 print (calendar.month_name[month_idx])
 print (calendar.month_abbr[month_idx])
 print ("")
</code></pre>

Sample output:

<pre><code>January
Jan

February
Feb

March
Mar

...
</code></pre>

blocks|key|632744|text|这就是我要做的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|632745|from+datetime+import+*

months+=+["Unknown",
++++++++++"January",
++++++++++"Febuary",
++++++++++"March",
++++++++++"April",
++++++++++"May",
++++++++++"June",
++++++++++"July",
++++++++++"August",
++++++++++"September",
++++++++++"October",
++++++++++"November",
++++++++++"December"]

now+=+(datetime.now())
year+=+(now.year)
month+=+(months[now.month])
print(month)|code-block|syntax|javascript|632746|它输出：|632747|>>>+September|632748|(这是我写这篇文章的真实日期)|632749|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

This Is What I Would Do:

<pre><code>from datetime import *

months = ["Unknown",
 "January",
 "Febuary",
 "March",
 "April",
 "May",
 "June",
 "July",
 "August",
 "September",
 "October",
 "November",
 "December"]

now = (datetime.now())
year = (now.year)
month = (months[now.month])
print(month)
</code></pre>

It Outputs:

<pre><code>&gt;&gt;&gt; September
</code></pre>

(This Was The Real Date When I Wrote This)

blocks|key|632784|text|我创建了自己的函数，将数字转换为相应的月份。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|632785|def+month_name+(number):
++++if+number+==+1:
++++++++return+"January"
++++elif+number+==+2:
++++++++return+"February"
++++elif+number+==+3:
++++++++return+"March"
++++elif+number+==+4:
++++++++return+"April"
++++elif+number+==+5:
++++++++return+"May"
++++elif+number+==+6:
++++++++return+"June"
++++elif+number+==+7:
++++++++return+"July"
++++elif+number+==+8:
++++++++return+"August"
++++elif+number+==+9:
++++++++return+"September"
++++elif+number+==+10:
++++++++return+"October"
++++elif+number+==+11:
++++++++return+"November"
++++elif+number+==+12:
++++++++return+"December"|code-block|syntax|javascript|632786|然后我就可以调用函数了。例如：|632787|print+(month_name+(12))|632788|输出：|632789|>>>+December|632790|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

I created my own function converting numbers to their corresponding month.

<pre><code>def month_name (number):
 if number == 1:
 return "January"
 elif number == 2:
 return "February"
 elif number == 3:
 return "March"
 elif number == 4:
 return "April"
 elif number == 5:
 return "May"
 elif number == 6:
 return "June"
 elif number == 7:
 return "July"
 elif number == 8:
 return "August"
 elif number == 9:
 return "September"
 elif number == 10:
 return "October"
 elif number == 11:
 return "November"
 elif number == 12:
 return "December"
</code></pre>

Then I can call the function. For example:

<pre><code>print (month_name (12))
</code></pre>

Outputs:

<pre><code>&gt;&gt;&gt; December
</code></pre>

blocks|key|849300|text|用于月份数字的套利范围|type|unstyled|depth|inlineStyleRanges|entityRanges|data|849301|month_integer=range(0,100)
map(lambda+x:+calendar.month_name[x%2512%2Bstart],month_integer)|code-block|syntax|javascript|849302|将产生正确的列表。从月份-整数列表中一月开始的位置调整start-parameter。|offset|length|style|CODE|849303|entityMap^0|0|0|R|5|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

For arbitaray range of month numbers 

<pre><code>month_integer=range(0,100)
map(lambda x: calendar.month_name[x%12+start],month_integer)
</code></pre>

will yield correct list. Adjust <code>start</code>-parameter from where January begins in the month-integer list.

blocks|key|632924|text|8.1。datetime+-基本日期和时间类型-Python2.7.17文档https://docs.python.org/2/library/datetime.html#strftime-strptime-behavior|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|632925|所有strftime参数的列表。月份的名称和一些不错的东西，比如格式化，留下了零填充。请阅读完整的页面，了解“天真”论点的规则。下面是简短的列表：%25a+Sun，Mon，…，Sat|632926|%25A周日、周一、…，星期六|632927|%25w工作日作为数字，其中0表示周日|632928|%25d日期01，02，…，31|632929|%25b+1月、2月、…，12月|632930|%25B+1月、2月、…，12月|632931|%25m月份数字，以填零的01，02，…表示，12|632932|%25y+2位年份-填充零00，01，…，99|632933|%25Y+4位数字年份1970、1988、2001、2013|632934|%25H小时(24小时制)填零00，01，…，23|632935|%25I小时(12小时时钟)填零01，02，…，12|632936|%25p+AM或PM|632937|%25M分钟-填零00，01，…，59|632938|%25S秒填零00，01，…，59|632939|%25f微秒填充零000000,000001，…，999999|632940|%25z+UTC偏移量，格式为%2BHHMM或-HHMM+%2B0000，-0400，%2B1030|632941|%25Z时区名称UTC，EST，CST|632942|%25j一年中的第几天-填充零的001,002，…，366|632943|%25U年的周数为零填充，第一个星期日之前的天数为第0周|632944|一年中的%25W周数(星期一为第一天)|632945|%25c区域设置的日期和时间表示。Tue+Aug+16+21:30:00+1988|632946|%25x区域设置的日期表示。08/16/1988+(en_US)|632947|%25X区域设置的时间表示。21:30:00|632948|%25%25文字'%25‘字符。|632949|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/2/library/datetime.html#strftime-strptime-behavior^0|12|22|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|1X|8|@]|9|@$A|1Y|B|1Z|1|20]]|C|$]]|$1|D|3|E|5|6|7|21|8|@]|9|@]|C|$]]|$1|F|3|G|5|6|7|22|8|@]|9|@]|C|$]]|$1|H|3|I|5|6|7|23|8|@]|9|@]|C|$]]|$1|J|3|K|5|6|7|24|8|@]|9|@]|C|$]]|$1|L|3|M|5|6|7|25|8|@]|9|@]|C|$]]|$1|N|3|O|5|6|7|26|8|@]|9|@]|C|$]]|$1|P|3|Q|5|6|7|27|8|@]|9|@]|C|$]]|$1|R|3|S|5|6|7|28|8|@]|9|@]|C|$]]|$1|T|3|U|5|6|7|29|8|@]|9|@]|C|$]]|$1|V|3|W|5|6|7|2A|8|@]|9|@]|C|$]]|$1|X|3|Y|5|6|7|2B|8|@]|9|@]|C|$]]|$1|Z|3|10|5|6|7|2C|8|@]|9|@]|C|$]]|$1|11|3|12|5|6|7|2D|8|@]|9|@]|C|$]]|$1|13|3|14|5|6|7|2E|8|@]|9|@]|C|$]]|$1|15|3|16|5|6|7|2F|8|@]|9|@]|C|$]]|$1|17|3|18|5|6|7|2G|8|@]|9|@]|C|$]]|$1|19|3|1A|5|6|7|2H|8|@]|9|@]|C|$]]|$1|1B|3|1C|5|6|7|2I|8|@]|9|@]|C|$]]|$1|1D|3|1E|5|6|7|2J|8|@]|9|@]|C|$]]|$1|1F|3|1G|5|6|7|2K|8|@]|9|@]|C|$]]|$1|1H|3|1I|5|6|7|2L|8|@]|9|@]|C|$]]|$1|1J|3|1K|5|6|7|2M|8|@]|9|@]|C|$]]|$1|1L|3|1M|5|6|7|2N|8|@]|9|@]|C|$]]|$1|1N|3|1O|5|6|7|2O|8|@]|9|@]|C|$]]|$1|1P|3|-4|5|6|7|2P|8|@]|9|@]|C|$]]]|1Q|$1R|$5|1S|1T|1U|C|$1V|1W]]]]

8.1. datetime — Basic date and time types — Python 2.7.17 documentation
<a href="https://docs.python.org/2/library/datetime.html#strftime-strptime-behavior" rel="noreferrer">https://docs.python.org/2/library/datetime.html#strftime-strptime-behavior</a>

A list of all the strftime arguments. Names of months and nice stuff like formatting left zero fill. Read the full page for stuff like rules for "naive" arguments. Here is the list in brief:
%a Sun, Mon, …, Sat 

%A Sunday, Monday, …, Saturday 

%w Weekday as number, where 0 is Sunday 

%d Day of the month 01, 02, …, 31

%b Jan, Feb, …, Dec

%B January, February, …, December

%m Month number as a zero-padded 01, 02, …, 12

%y 2 digit year zero-padded 00, 01, …, 99

%Y 4 digit Year 1970, 1988, 2001, 2013

%H Hour (24-hour clock) zero-padded 00, 01, …, 23

%I Hour (12-hour clock) zero-padded 01, 02, …, 12

%p AM or PM.

%M Minute zero-padded 00, 01, …, 59

%S Second zero-padded 00, 01, …, 59

%f Microsecond zero-padded 000000, 000001, …, 999999

%z UTC offset in the form +HHMM or -HHMM +0000, -0400, +1030

%Z Time zone name UTC, EST, CST

%j Day of the year zero-padded 001, 002, …, 366

%U Week number of the year zero padded, Days before the first Sunday are week 0

%W Week number of the year (Monday as first day)

%c Locale’s date and time representation. Tue Aug 16 21:30:00 1988

%x Locale’s date representation. 08/16/1988 (en_US)

%X Locale’s time representation. 21:30:00 

%% literal '%' character.

blocks|key|849439|text|要一次性打印所有月份，请执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|849440|+import+datetime

+monthint+=+list(range(1,13))

+for+X+in+monthint:
+++++month+=+datetime.date(1900,+X+,+1).strftime('%25B')
+++++print(month)|code-block|syntax|javascript|849441|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To print all months at once:
<pre><code> import datetime

 monthint = list(range(1,13))

 for X in monthint:
 month = datetime.date(1900, X , 1).strftime('%B')
 print(month)
</code></pre>

blocks|key|633047|text|此脚本用于展示如何在数据框中获取月份变量/列的日历月份缩写。请注意，假设month列/变量的值都是数字，可能会有一些缺失值。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|633048|#+Import+the+calendar+module
++import+calendar
++++
#+Extract+month+as+a+number+from+the+date+column
++df['Month']=pd.DatetimeIndex(df['Date']).month

#+Using+list+comprehension+extract+month+abbreviations+for+each+month+number
+df['Month_abbr']=[calendar.month_abbr[int(i)]+if+pd.notna(i)+else+i+for+i+in+df['Month']]|code-block|syntax|javascript|633049|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This script is to show how to get calendar month abbreviations for a month variable/column in a data frame. Note that the assumption is that the values of the month column/variable are all numbers and maybe there might be some missing values.
<pre><code># Import the calendar module
 import calendar
 
# Extract month as a number from the date column
 df['Month']=pd.DatetimeIndex(df['Date']).month

# Using list comprehension extract month abbreviations for each month number
 df['Month_abbr']=[calendar.month_abbr[int(i)] if pd.notna(i) else i for i in df['Month']]
</code></pre>

blocks|key|849553|text|您可以使用我的手动函数，而不是导入或下载新的库：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|849554|将代码复制到新的.py文件并运行它|849555|快速解释：|849556|更改your_number并打印month_from_number，您将获得月份|849557|++++your_number+=+10

++++def+num_to_month(*args,+**kwargs):

++++++++num+=+kwargs.get("num",+None)

++++++++if+int(num)+<=+12+and+int(num)+>+0:

++++++++++++list_of_months+=+{'1':+'January',+'2':+'February',+'3':+'March',
++++++++++++++++++++++++++++++'4':+'April',+'5':+'May',+'6':+'June',+'7':+'July',
++++++++++++++++++++++++++++++'8':+'August',+'9':+'September',+'10':+'October',
++++++++++++++++++++++++++++++'11':+'November',+'12':+'December'}

++++++++++++return+list_of_months[num]

++++++++else:

++++++++++++print('num_to_month+function+error:+"num='+%2B+str(num)+%2B+'"')

++++month_from_num+=+num_to_month(num=str(your_number))

++++print(month_from_number)|code-block|syntax|javascript|849558|结果将是10月份|849559|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|S|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|T|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|U|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

instead of import or downloading a new lib, you can use my manual function:
copy the code to a new .py file and run it
quick explanation:
change your_number and print month_from_number, you will get the month
<pre><code> your_number = 10

 def num_to_month(*args, **kwargs):

 num = kwargs.get(&quot;num&quot;, None)

 if int(num) &lt;= 12 and int(num) &gt; 0:

 list_of_months = {'1': 'January', '2': 'February', '3': 'March',
 '4': 'April', '5': 'May', '6': 'June', '7': 'July',
 '8': 'August', '9': 'September', '10': 'October',
 '11': 'November', '12': 'December'}

 return list_of_months[num]

 else:

 print('num_to_month function error: &quot;num=' + str(num) + '&quot;')

 month_from_num = num_to_month(num=str(your_number))

 print(month_from_number)
</code></pre>
the result will be October

blocks|key|633120|text|'01‘到'Jan’|type|unstyled|depth|inlineStyleRanges|entityRanges|data|633121|from+datetime+import+datetime

datetime.strptime('01',+"%25m").strftime("%25b")++++|code-block|syntax|javascript|633122|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

'01' to 'Jan'
<pre><code>from datetime import datetime

datetime.strptime('01', &quot;%m&quot;).strftime(&quot;%b&quot;) 
</code></pre>

How can I get the month name from the month number?

For instance, if I have <code>3</code>, I want to return <code>march</code> 

<pre><code>date.tm_month()
</code></pre>

How to get the string <code>march</code>?

Get month name from number

如何从月份编号中获取月份名称？例如，如果我有3，我想返回marchdate.tm_month()如何获取字符串march

问从数字中获取月份名称
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