blocks|key|672137|text|你确定你不能这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|672138|{%25+for+item+in+mylist+%25}
++++{{+item+}}
{%25+endfor+%25}|code-block|syntax|javascript|672139|使用切片过滤器，您甚至可以进行一些自定义。|672140|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Are you sure you can't just do:

<pre><code>{% for item in mylist %}
 {{ item }}
{% endfor %}
</code></pre>

With the slice filter, you can even do some customisation.

blocks|key|457952|text|我注意到@e-satis提到了它，但我认为内置的切片模板标签值得一些喜爱。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|457953|{{+item+%7C+slice:"2"+}}+#gets+the+third+element+of+the+list|code-block|syntax|javascript|457954|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I notice that @e-satis mentioned it, but I think the built-in slice template tag deserves some love.

<pre><code>{{ item | slice:"2" }} #gets the third element of the list
</code></pre>

blocks|key|672254|text|Django模板中的切片标记可能使用python的切片代码，但语法明显不同。例如，如果你想获取一个序列的一个元素，在python中，你可以写类似下面这样的代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|672255|>>>mylist+=+["0th+Element",+"1th+Element"]
>>>zero,+one+=+0,+1
>>>mylist[zero]
"0th+Element"
>>>mylist[one]
"1th+Element"|code-block|syntax|javascript|672256|将此语法与Django切片模板标记一起使用将在每种情况下返回切片列表，用于获取已知索引的项的可疑实用程序：|672257|{%25+with+"0"+as+zero+%25}
{%25+with+"1"+as+one+%25}
{%25+with+"2"+as+two+%25}

{{mylist%7Cslice:zero}}+{{mylist%7Cslice:one}}+{{mylist%7Cslice:two}}

{%25+endwith+%25}
{%25+endwith+%25}
{%25+endwith+%25}|672258|呈现到html：|672259|[]+["0th+Element"]+["0th+Element",+"1th+Element"]|672260|注意不同之处:您得到的结果是mylist[:x]而不是mylist[x]。|offset|length|style|CODE|672261|Django提供了足够的工具来解决这个问题。第一个技巧是对索引使用显式切片(如0:1+)，然后将结果列表%7Cjoin:""到单个元素中。如下所示：|672262|{%25+with+"0:1"+as+zero+%25}
{{mylist%7Cslice:zero%7Cjoin:""}}
{%25+endwith+%25}|672263|收益率：|672264|0th+Element|672265|如果在处理子循环中的迭代器时需要访问父循环的索引，这会特别方便：|672266|{%25+for+parent+in+parent_loop+%25}
++++{%25+cycle+"0:1"+"1:2"+"2:3"+as+parent_loop_index+silent+%25}
++++{%25+for+child+in+child_loop+%25}
++++++++{{child%7Cslice:parent_loop_index%7Cjoin:""}}
++++{%25+endfor+%25}
{%25+endfor+%25}|672267|虽然我认为Django还没有实现成就，但只用了库存部件就完成了。|672268|entityMap^0|0|0|0|0|0|0|E|A|R|9|0|13|3|1G|8|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|1A|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|1B|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1C|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|1D|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|1E|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|1F|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|1G|8|@$Q|1H|R|1I|S|T]|$Q|1J|R|1K|S|T]]|9|@]|A|$]]|$1|U|3|V|5|6|7|1L|8|@$Q|1M|R|1N|S|T]|$Q|1O|R|1P|S|T]]|9|@]|A|$]]|$1|W|3|X|5|D|7|1Q|8|@]|9|@]|A|$E|F]]|$1|Y|3|Z|5|6|7|1R|8|@]|9|@]|A|$]]|$1|10|3|11|5|D|7|1S|8|@]|9|@]|A|$E|F]]|$1|12|3|13|5|6|7|1T|8|@]|9|@]|A|$]]|$1|14|3|15|5|D|7|1U|8|@]|9|@]|A|$E|F]]|$1|16|3|17|5|6|7|1V|8|@]|9|@]|A|$]]|$1|18|3|-4|5|6|7|1W|8|@]|9|@]|A|$]]]|19|$]]

The slice tag in Django templates may use python's slicing code, but the syntax is unmistakably different. For instance, if you wanted to get an element of a sequence with a variable, in python you'd write something similar to the following:

<pre><code>&gt;&gt;&gt;mylist = ["0th Element", "1th Element"]
&gt;&gt;&gt;zero, one = 0, 1
&gt;&gt;&gt;mylist[zero]
"0th Element"
&gt;&gt;&gt;mylist[one]
"1th Element"
</code></pre>

Using this syntax with the Django slice template tag will return a sliced list in every case, of dubious utility for getting an item of known index:

<pre><code>{% with "0" as zero %}
{% with "1" as one %}
{% with "2" as two %}

{{mylist|slice:zero}} {{mylist|slice:one}} {{mylist|slice:two}}

{% endwith %}
{% endwith %}
{% endwith %}
</code></pre>

Renders to the html:

<pre><code>[] ["0th Element"] ["0th Element", "1th Element"]
</code></pre>

Note the differences: you are getting the result of <code>mylist[:x]</code> instead of <code>mylist[x]</code>.

Django provides enough tools to work around this. The first trick is to use explicit slices like <code>0:1</code> for your indices, and then <code>|join:""</code> the resultant list into a single element. Like so:

<pre><code>{% with "0:1" as zero %}
{{mylist|slice:zero|join:""}}
{% endwith %}
</code></pre>

Yields:

<pre><code>0th Element
</code></pre>

This comes in particularly handy if you need to access a parent loop's index when dealing with an iterable inside a child loop:

<pre><code>{% for parent in parent_loop %}
 {% cycle "0:1" "1:2" "2:3" as parent_loop_index silent %}
 {% for child in child_loop %}
 {{child|slice:parent_loop_index|join:""}}
 {% endfor %}
{% endfor %}
</code></pre>

Completed with nothing but stock parts, although I don't think Django has implemented achievements yet.

blocks|key|672312|text|下面的内容对我很有效|type|unstyled|depth|inlineStyleRanges|entityRanges|data|672313|{%25+for+1,2,3+in+mylist+%25}
#+do+stuff|code-block|syntax|javascript|672314|不要在1,2,3两边使用括号|672315|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Following worked for me
<pre><code>{% for 1,2,3 in mylist %}
# do stuff
</code></pre>
Just don't use brackets around 1,2,3

I have some loop on the page and need list item depending from loop number. 

When I call:

<pre><code>{{ mylist.1 }}
{{ mylist.2 }}
{{ mylist.3 }}
</code></pre>

all works fine but what I really need is something like:

<pre><code>{% for x in somenumber|MyCustomRangeTag %}
 {{ mylist.x }}
{% endfor %}
</code></pre>

MyCustomRangeTag gives me Python <code>range()</code> it works and I already have <code>x</code> as number. So <code>x</code> is 1, 2, 3 etc. depending from loop number.
Is this possible and how?

Get list item dynamically in django templates

Django

Python

我在页面上有一些循环，需要根据循环数量列表项。当我调用时：{{ mylist.1 }}{{ mylist.2 }}{{ mylist.3 }}一切都很好，但我真正需要的是：{% for x in somenumber|MyCustomRangeTag %}    {{ mylist.x }}{% endfor %}My...

问在django模板中动态获取列表项
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