blocks|key|476641|text|Integer.toHexString(42);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|476642|Javadoc：http://docs.oracle.com/javase/6/docs/api/java/lang/Integer.html#toHexString(int)|unstyled|offset|length|476643|请注意，这可能会给你两个以上的数字，但是！(+Integer是4个字节，因此可能会返回8个字符。)|476644|这里有一个小技巧来获得你的填充，只要你绝对确定你只处理单字节的值(255或更小)：|476645|Integer.toHexString(0x100+%7C+42).substring(1)|476646|Left+padding+integers+(non-decimal+format)+with+zeros+in+Java上有更多(也更好)的解决方案。|476647|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/6/docs/api/java/lang/Integer.html#toHexString(int)|1|https://stackoverflow.com/questions/3149692/left-padding-integers-non-decimal-format-with-zeros-in-java^0|0|8|28|0|0|0|0|0|0|1P|1|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|11|8|@]|9|@$G|12|H|13|1|14]]|A|$]]|$1|I|3|J|5|F|7|15|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|16|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|17|8|@]|9|@]|A|$B|C]]|$1|O|3|P|5|F|7|18|8|@]|9|@$G|19|H|1A|1|1B]]|A|$]]|$1|Q|3|-4|5|F|7|1C|8|@]|9|@]|A|$]]]|R|$S|$5|T|U|V|A|$W|X]]|Y|$5|T|U|V|A|$W|Z]]]]

<pre><code>Integer.toHexString(42);
</code></pre>

Javadoc: <a href="http://docs.oracle.com/javase/6/docs/api/java/lang/Integer.html#toHexString(int)" rel="noreferrer">http://docs.oracle.com/javase/6/docs/api/java/lang/Integer.html#toHexString(int)</a>

Note that this may give you more than 2 digits, however! (An Integer is 4 bytes, so you could potentially get back 8 characters.)

Here's a bit of a hack to get your padding, as long as you are absolutely sure that you're only dealing with single-byte values (255 or less):

<pre><code>Integer.toHexString(0x100 | 42).substring(1)
</code></pre>

Many more (and better) solutions at <a href="https://stackoverflow.com/questions/3149692/left-padding-integers-non-decimal-format-with-zeros-in-java">Left padding integers (non-decimal format) with zeros in Java</a>.

blocks|key|476690|text|使用Integer.toHexString()。如果只有一个数字结束，不要忘记填充前导零。如果你的整数大于255，你会得到2个以上的数字。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|476691|StringBuilder+sb+=+new+StringBuilder();
sb.append(Integer.toHexString(myInt));
if+(sb.length()+<+2)+{
++++sb.insert(0,+'0');+//+pad+with+leading+zero+if+needed
}
String+hex+=+sb.toString();|code-block|syntax|javascript|476692|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/6/docs/api/java/lang/Integer.html#toHexString%2528int%2529^0|2|L|2|L|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@$9|V|A|W|1|X]]|E|$]]|$1|F|3|G|5|H|7|Y|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

Use <a href="http://docs.oracle.com/javase/6/docs/api/java/lang/Integer.html#toHexString%28int%29"><code>Integer.toHexString()</code></a>. Dont forget to pad with a leading zero if you only end up with one digit. If your integer is greater than 255 you'll get more than 2 digits.

<pre><code>StringBuilder sb = new StringBuilder();
sb.append(Integer.toHexString(myInt));
if (sb.length() &lt; 2) {
 sb.insert(0, '0'); // pad with leading zero if needed
}
String hex = sb.toString();
</code></pre>

blocks|key|692794|text|如果你只需要打印它们，试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|692795|for(int+a+=+0;+a+<+255;+a%2B%2B){
++++if(+a+%25+16+==+0){
++++++++System.out.println();
++++}
++++System.out.printf("%2502x+",+a);
}|code-block|syntax|javascript|692796|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you just need to print them try this: 

<pre><code>for(int a = 0; a &lt; 255; a++){
 if( a % 16 == 0){
 System.out.println();
 }
 System.out.printf("%02x ", a);
}
</code></pre>

blocks|key|476721|text|String.format("%2502X",+(0xFF+&+value));++++|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|476722|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>String.format("%02X", (0xFF &amp; value)); 
</code></pre>

blocks|key|476735|text|String.format("%2502X",+value);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|476736|如果您使用X而不是x+as+suggested+by+aristar，那么就不需要使用.toUpperCase()。|unstyled|offset|length|style|CODE|476737|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/16705696/109618^0|0|5|1|9|1|17|E|B|N|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|T|8|@$G|U|H|V|I|J]|$G|W|H|X|I|J]|$G|Y|H|Z|I|J]]|9|@$G|10|H|11|1|12]]|A|$]]|$1|K|3|-4|5|F|7|13|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

<pre><code>String.format("%02X", value);
</code></pre>

If you use <code>X</code> instead of <code>x</code> <a href="https://stackoverflow.com/a/16705696/109618">as suggested by aristar</a>, then you don't need to use <code>.toUpperCase()</code>.

blocks|key|476764|text|根据GabrielOshiro的说法，如果您希望将整数格式设置为长度为8，请尝试以下方法|type|unstyled|depth|inlineStyleRanges|entityRanges|data|476765|String.format("0x%2508X",+20)+//print+0x00000014|code-block|syntax|javascript|476766|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

According to GabrielOshiro, If you want format integer to length 8, try this
<pre><code>String.format(&quot;0x%08X&quot;, 20) //print 0x00000014
</code></pre>

I need to change a integer value into 2-digit hex value in Java.Is there any way for this.
Thanks

My biggest number will be 63 and smallest will be 0.
I want a leading zero for small values.

Integer to two digits hex in Java

Java

我需要在Java.Is中将一个整数值更改为两位十六进制值，有任何方法可以做到这一点。谢谢我最大的数字是63，最小的数字是0。对于较小的值，我需要一个前导零。

问Java中的整数到两位十六进制
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