blocks|key|332838|text|使用-F+[field+separator]拆分"上的行：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|332839|awk+-F+'"'+'{print+$2}'+your_input_file|code-block|syntax|javascript|332840|或者用于来自管道的输入|332841|<some_command>+%7C+awk+-F+'"'+'{print+$2}'|332842|输出：|332843|A+B
C
D|332844|entityMap^0|2|K|O|1|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|12|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|T|$]]

Use <code>-F [field separator]</code> to split the lines on <code>"</code>s:

<pre><code>awk -F '"' '{print $2}' your_input_file
</code></pre>

or for input from pipe

<pre><code>&lt;some_command&gt; | awk -F '"' '{print $2}'
</code></pre>

output:

<pre><code>A B
C
D
</code></pre>

blocks|key|332890|text|或者使用sed+&+regex。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|332891|<some_command>+%7C+sed+'s/%5E.*+$".*"$$/\1/'|code-block|syntax|javascript|332892|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Or use sed &amp; regex.

<pre><code>&lt;some_command&gt; | sed 's/^.* $".*"$$/\1/'
</code></pre>

blocks|key|332938|text|如果你有GNU+awk，这就是你想要的解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|332939|$+awk+'{print+$1}'+FPAT='"[%5E"]%2B"'+file
"A+B"
"C"
"D"|code-block|syntax|javascript|332940|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you have GNU awk this is the solution you want:

<pre><code>$ awk '{print $1}' FPAT='"[^"]+"' file
"A B"
"C"
"D"
</code></pre>

blocks|key|115491|text|awk+-F"%7C"+'{gsub(/\"/,"%7C");print+"\""$2"\""}'+your_file|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|115492|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>awk -F"|" '{gsub(/\"/,"|");print "\""$2"\""}' your_file
</code></pre>

blocks|key|115520|text|你不需要awk来做这件事。在Bash+shell中使用read就足够了，例如|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|115521|some_command+%7C+while+read+c1+c2;+do+echo+$c2;+done|code-block|syntax|javascript|115522|或者：|115523|while+read+c1+c2;+do+echo+$c2;+done+<+in.txt|115524|entityMap^0|R|4|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

You don't need awk for that. Using <code>read</code> in Bash shell should be enough, e.g.

<pre><code>some_command | while read c1 c2; do echo $c2; done
</code></pre>

or:

<pre><code>while read c1 c2; do echo $c2; done &lt; in.txt
</code></pre>

blocks|key|115538|text|这应该可以从命令输出"docker+images“中获得特定的列：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|115539|REPOSITORY++++++++++++++++++++++++++TAG+++++++++++++++++IMAGE+ID++++++++++++CREATED+++++++++++++SIZE
ubuntu++++++++++++++++++++++++++++++16.04+++++++++++++++12543ced0f6f++++++++10+months+ago+++++++122+MB
ubuntu++++++++++++++++++++++++++++++latest++++++++++++++12543ced0f6f++++++++10+months+ago+++++++122+MB
selenium/standalone-firefox-debug+++2.53.0++++++++++++++9f3bab6e046f++++++++12+months+ago+++++++613+MB
selenium/node-firefox-debug+++++++++2.53.0++++++++++++++d82f2ab74db7++++++++12+months+ago+++++++613+MB


docker+images+%7C+awk+'{print+$3}'

IMAGE
12543ced0f6f
12543ced0f6f
9f3bab6e046f
d82f2ab74db7|code-block|syntax|javascript|115540|这将打印第三列|115541|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

This should work to get a specific column out of the command output "docker images":

<pre><code>REPOSITORY TAG IMAGE ID CREATED SIZE
ubuntu 16.04 12543ced0f6f 10 months ago 122 MB
ubuntu latest 12543ced0f6f 10 months ago 122 MB
selenium/standalone-firefox-debug 2.53.0 9f3bab6e046f 12 months ago 613 MB
selenium/node-firefox-debug 2.53.0 d82f2ab74db7 12 months ago 613 MB


docker images | awk '{print $3}'

IMAGE
12543ced0f6f
12543ced0f6f
9f3bab6e046f
d82f2ab74db7
</code></pre>

This is going to print the third column

blocks|key|115581|text|#!/usr/bin/python
import+sys+

col+=+int(sys.argv[1])+-+1

for+line+in+sys.stdin:
++++columns+=+line.split()

++++try:
++++++++print(columns[col])
++++except+IndexError:
++++++++#+ignore
++++++++pass|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|115582|然后，假设您将脚本命名为co，例如，执行以下操作来获取文件的大小(该示例假设您使用的是Linux，但脚本本身是独立于操作系统的)+:-|unstyled|115583|ls+-lh+%7C+co+5|offset|length|style|CODE|115584|entityMap^0|0|0|0|D|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|P|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|F|7|T|8|@]|9|@]|A|$]]]|N|$]]

<pre class="lang-py prettyprint-override"><code>#!/usr/bin/python
import sys 

col = int(sys.argv[1]) - 1

for line in sys.stdin:
 columns = line.split()

 try:
 print(columns[col])
 except IndexError:
 # ignore
 pass
</code></pre>

Then, supposing you name the script as co, say, do something like this to get the sizes of files (the example assumes you're using Linux, but the script itself is OS-independent) :-

<code>ls -lh | co 5</code>

My command's output is something like:

<pre><code>1540 "A B"
 6 "C"
 119 "D"
</code></pre>

The first column is always a number, followed by a space, then a double-quoted string.

My purpose is to get the second column only, like:

<pre><code>"A B"
"C"
"D"
</code></pre>

I intended to use <code>&lt;some_command&gt; | awk '{print $2}'</code> to accomplish this. But the question is, some values in the second column contain space(s), which happens to be the default delimiter for <code>awk</code> to separate the fields. Therefore, the output is messed up:

<pre><code>"A
"C"
"D"
</code></pre>

How do I get the second column's value (with paired quotes) cleanly?

How to get the second column from command output?

Docker

Linux

我的命令的输出类似于：1540 "A B" 6 "C" 119 "D"第一列始终是一个数字，后跟一个空格，然后是一个双引号字符串。我的目的是只获取第二列，例如："A B""C""D"我打算使用<some_command> | awk '{print $2}'来实现这一点。但问题是，第二列中的一些值包含空格，这恰好是...

问如何从命令输出中获取第二列？
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