blocks|key|461115|text|您可以简单地执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|461116|$fi+=+new+FilesystemIterator(__DIR__,+FilesystemIterator::SKIP_DOTS);
printf("There+were+%25d+Files",+iterator_count($fi));|code-block|syntax|javascript|461117|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can simply do the following :

<pre><code>$fi = new FilesystemIterator(__DIR__, FilesystemIterator::SKIP_DOTS);
printf("There were %d Files", iterator_count($fi));
</code></pre>

blocks|key|461078|text|您可以像这样获取文件计数：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|461079|$directory+=+"/path/to/dir/";
$filecount+=+0;
$files+=+glob($directory+.+"*");
if+($files){
+$filecount+=+count($files);
}
echo+"There+were+$filecount+files";|code-block|syntax|javascript|461080|在"*"所在的位置，您可以像"*.jpg"一样将其更改为特定的文件类型，也可以执行多种文件类型，如下所示：|offset|length|style|CODE|461081|glob($directory+.+"*.{jpg,png,gif}",GLOB_BRACE)|461082|GLOB_BRACE标志扩展{a，b，c}以匹配'a‘、'b’或'c‘|461083|entityMap^0|0|0|1|3|E|7|0|0|0|A|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]|$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|10|8|@$I|11|J|12|K|L]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|13|8|@]|9|@]|A|$]]]|R|$]]

You can get the filecount like so:

<pre><code>$directory = "/path/to/dir/";
$filecount = 0;
$files = glob($directory . "*");
if ($files){
 $filecount = count($files);
}
echo "There were $filecount files";
</code></pre>

where the <code>"*"</code> is you can change that to a specific filetype if you want like <code>"*.jpg"</code> or you could do multiple filetypes like this:

<pre><code>glob($directory . "*.{jpg,png,gif}",GLOB_BRACE)
</code></pre>

the <code>GLOB_BRACE</code> flag expands {a,b,c} to match 'a', 'b', or 'c'

blocks|key|244347|text|尝尝这个。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|244348|//+Directory
$directory+=+"/dir";

//+Returns+an+array+of+files
$files+=+scandir($directory);

//+Count+the+number+of+files+and+store+them+inside+the+variable..
//+Removing+2+because+we+do+not+count+'.'+and+'..'.
$num_files+=+count($files)-2);|code-block|syntax|javascript|244349|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this.
<pre><code>// Directory
$directory = &quot;/dir&quot;;

// Returns an array of files
$files = scandir($directory);

// Count the number of files and store them inside the variable..
// Removing 2 because we do not count '.' and '..'.
$num_files = count($files)-2);
</code></pre>

blocks|key|461051|text|你应该有：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|461052|<div+id="header">
<?php+
++++//+integer+starts+at+0+before+counting
++++$i+=+0;+
++++$dir+=+'uploads/';
++++if+($handle+=+opendir($dir))+{
++++++++while+(($file+=+readdir($handle))+!==+false){
++++++++++++if+(!in_array($file,+array('.',+'..'))+&&+!is_dir($dir.$file))+
++++++++++++++++$i%2B%2B;
++++++++}
++++}
++++//+prints+out+how+many+were+in+the+directory
++++echo+"There+were+$i+files";
?>
</div>|code-block|syntax|javascript|461053|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You should have : 

<pre><code>&lt;div id="header"&gt;
&lt;?php 
 // integer starts at 0 before counting
 $i = 0; 
 $dir = 'uploads/';
 if ($handle = opendir($dir)) {
 while (($file = readdir($handle)) !== false){
 if (!in_array($file, array('.', '..')) &amp;&amp; !is_dir($dir.$file)) 
 $i++;
 }
 }
 // prints out how many were in the directory
 echo "There were $i files";
?&gt;
&lt;/div&gt;
</code></pre>

blocks|key|244489|text|工作演示|type|unstyled|depth|inlineStyleRanges|entityRanges|data|244490|<?php

$directory+=+"../images/team/harry/";+//+dir+location
if+(glob($directory+.+"*.*")+!=+false)
{
+$filecount+=+count(glob($directory+.+"*.*"));
+echo+$filecount;
}
else
{
+echo+0;
}

?>|code-block|syntax|javascript|244491|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Working Demo

<pre><code>&lt;?php

$directory = "../images/team/harry/"; // dir location
if (glob($directory . "*.*") != false)
{
 $filecount = count(glob($directory . "*.*"));
 echo $filecount;
}
else
{
 echo 0;
}

?&gt;
</code></pre>

blocks|key|244529|text|我使用的是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|244530|count(glob("yourdir/*",GLOB_BRACE))|code-block|syntax|javascript|244531|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I use this:

<pre><code>count(glob("yourdir/*",GLOB_BRACE))
</code></pre>

blocks|key|244697|text|<?php+echo(count(array_slice(scandir($directory),2)));+?>|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|244698|array_slice的工作原理类似于substr函数，只是它可以处理数组。|unstyled|offset|length|style|CODE|244699|例如，这将从array中去掉前两个数组键：|244700|$key_zero_one+=+array_slice($someArray,+0,+2);|244701|如果省略第一个参数，就像第一个示例一样，数组将不包含前两个键/值对*(‘’。和'..')。|244702|entityMap^0|0|0|B|J|6|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|T|8|@$G|U|H|V|I|J]|$G|W|H|X|I|J]]|9|@]|A|$]]|$1|K|3|L|5|F|7|Y|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|Z|8|@]|9|@]|A|$B|C]]|$1|O|3|P|5|F|7|10|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|F|7|11|8|@]|9|@]|A|$]]]|R|$]]

<pre><code>&lt;?php echo(count(array_slice(scandir($directory),2))); ?&gt;
</code></pre>

<code>array_slice</code> works similary like <code>substr</code> function, only it works with arrays. 

For example, this would chop out first two array keys from array:

<pre><code>$key_zero_one = array_slice($someArray, 0, 2);
</code></pre>

And if You ommit the first parameter, like in first example, array will not contain first two key/value pairs *('.' and '..').

blocks|key|461283|text|也许对某些人有用。在Windows系统上，您可以通过调用dir-命令让Windows完成这项工作。我使用绝对路径，比如E:/mydir/mysubdir。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|461284|<?php+
$mydir='E:/mydir/mysubdir';
$dir=str_replace('/','\\',$mydir);
$total+=+exec('dir+'.$dir.'+/b/a-d+%7C+find+/v+/c+"::"');|code-block|syntax|javascript|461285|entityMap^0|1N|H|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Maybe usefull to someone. On a Windows system, you can let Windows do the job by calling the dir-command. I use an absolute path, like <code>E:/mydir/mysubdir</code>.

<pre><code>&lt;?php 
$mydir='E:/mydir/mysubdir';
$dir=str_replace('/','\\',$mydir);
$total = exec('dir '.$dir.' /b/a-d | find /v /c "::"');
</code></pre>

blocks|key|461184|text|$it+=+new+filesystemiterator(dirname("Enter+directory+here"));
printf("There+were+%25d+Files",+iterator_count($it));
echo(" ");
++++foreach+($it+as+$fileinfo)+{
++++++++echo+$fileinfo->getFilename()+.+" \n";
++++}+|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|461185|这应该可以在dirname中输入目录。让魔法发生吧。|unstyled|461186|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>$it = new filesystemiterator(dirname("Enter directory here"));
printf("There were %d Files", iterator_count($it));
echo("&lt;br/&gt;");
 foreach ($it as $fileinfo) {
 echo $fileinfo-&gt;getFilename() . "&lt;br/&gt;\n";
 } 
</code></pre>

This should work
enter the directory in dirname. and let the magic happen.

blocks|key|461325|text|$files+=+glob('uploads/*');
$count+=+0;
$totalCount+=+0;
$subFileCount+=+0;
foreach+($files+as+$file)+
{++
++++global+$count,+$totalCount;
++++if(is_dir($file))
++++{
++++++++$totalCount+%2B=+getFileCount($file);
++++}
++++if(is_file($file))
++++{
++++++++$count%2B%2B;++
++++}++
}

function+getFileCount($dir)
{
++++global+$subFileCount;
++++if(is_dir($dir))
++++{
++++++++$subfiles+=+glob($dir.'/*');
++++++++if(count($subfiles))
++++++++{++++++
++++++++++++foreach+($subfiles+as+$file)+
++++++++++++{
++++++++++++++++getFileCount($file);
++++++++++++}
++++++++}
++++}
++++if(is_file($dir))
++++{
++++++++$subFileCount%2B%2B;
++++}
++++return+$subFileCount;
}

$totalFilesCount+=+$count+%2B+$totalCount;+
echo+'Total+Files+Count+'+.+$totalFilesCount;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|461326|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$files = glob('uploads/*');
$count = 0;
$totalCount = 0;
$subFileCount = 0;
foreach ($files as $file) 
{ 
 global $count, $totalCount;
 if(is_dir($file))
 {
 $totalCount += getFileCount($file);
 }
 if(is_file($file))
 {
 $count++; 
 } 
}

function getFileCount($dir)
{
 global $subFileCount;
 if(is_dir($dir))
 {
 $subfiles = glob($dir.'/*');
 if(count($subfiles))
 { 
 foreach ($subfiles as $file) 
 {
 getFileCount($file);
 }
 }
 }
 if(is_file($dir))
 {
 $subFileCount++;
 }
 return $subFileCount;
}

$totalFilesCount = $count + $totalCount; 
echo 'Total Files Count ' . $totalFilesCount;
</code></pre>

blocks|key|244809|text|根据公认的答案，下面是递归计算目录中所有文件的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|244810|iterator_count(
++++new+\RecursiveIteratorIterator(
++++++++new+\RecursiveDirectoryIterator('/your/directory/here/',+\FilesystemIterator::SKIP_DOTS)
++++)
)|code-block|syntax|javascript|244811|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Based on the accepted answer, here is a way to count all files in a directory RECURSIVELY:

<pre><code>iterator_count(
 new \RecursiveIteratorIterator(
 new \RecursiveDirectoryIterator('/your/directory/here/', \FilesystemIterator::SKIP_DOTS)
 )
)
</code></pre>

blocks|key|244903|text|下面是一个速度相当快的PHP+Linux函数。有点脏，但它能完成工作！|type|unstyled|depth|inlineStyleRanges|entityRanges|data|244904|$dir+-目录的路径|244905|$type+-+f、d或false+(默认情况下)|244906|F-仅返回文件数|244907|D-仅返回文件夹计数|244908|false+-返回文件和文件夹总数|244909|function+folderfiles($dir,+$type=false)+{
++++$f+=+escapeshellarg($dir);
++++if($type+==+'f')+{
++++++++$io+=+popen+(+'/usr/bin/find+'+.+$f+.+'+-type+f+%7C+wc+-l',+'r'+);
++++}+elseif($type+==+'d')+{
++++++++$io+=+popen+(+'/usr/bin/find+'+.+$f+.+'+-type+d+%7C+wc+-l',+'r'+);
++++}+else+{
++++++++$io+=+popen+(+'/usr/bin/find+'+.+$f+.+'+%7C+wc+-l',+'r'+);
++++}

++++$size+=+fgets+(+$io,+4096);
++++pclose+(+$io+);
++++return+$size;
}|code-block|syntax|javascript|244910|您可以根据自己的需要进行调整。|244911|请注意，这在Windows上不起作用。|244912|entityMap^0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|Y|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|Z|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|10|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|11|8|@]|9|@]|A|$]]|$1|L|3|M|5|N|7|12|8|@]|9|@]|A|$O|P]]|$1|Q|3|R|5|6|7|13|8|@]|9|@]|A|$]]|$1|S|3|T|5|6|7|14|8|@]|9|@]|A|$]]|$1|U|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|V|$]]

Here's a PHP Linux function that's considerably fast. A bit dirty, but it gets the job done!

$dir - path to directory

$type - f, d or false (by default)

f - returns only files count

d - returns only folders count

false - returns total files and folders count

<pre><code>function folderfiles($dir, $type=false) {
 $f = escapeshellarg($dir);
 if($type == 'f') {
 $io = popen ( '/usr/bin/find ' . $f . ' -type f | wc -l', 'r' );
 } elseif($type == 'd') {
 $io = popen ( '/usr/bin/find ' . $f . ' -type d | wc -l', 'r' );
 } else {
 $io = popen ( '/usr/bin/find ' . $f . ' | wc -l', 'r' );
 }

 $size = fgets ( $io, 4096);
 pclose ( $io );
 return $size;
}
</code></pre>

You can tweak to fit your needs.

Please note that this will not work on Windows.

blocks|key|461140|text|++simple+code+add+for+file+.php+then+your+folder+which+number+of+file+to+count+its++++++

++++$directory+=+"images/icons";
++++$files+=+scandir($directory);
++++for($i+=+0+;+$i+<+count($files)+;+$i%2B%2B){
++++++++if($files[$i]+!='.'+&&+$files[$i]+!='..')
++++++++{+echo+$files[$i];+echo+" ";
++++++++++++$file_new[]+=+$files[$i];
++++++++}
++++}
++++echo+$num_files+=+count($file_new);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|461141|简单地加上它的完成....|unstyled|461142|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code> simple code add for file .php then your folder which number of file to count its 

 $directory = "images/icons";
 $files = scandir($directory);
 for($i = 0 ; $i &lt; count($files) ; $i++){
 if($files[$i] !='.' &amp;&amp; $files[$i] !='..')
 { echo $files[$i]; echo "&lt;br&gt;";
 $file_new[] = $files[$i];
 }
 }
 echo $num_files = count($file_new);
</code></pre>

simple add its done ....

I'm working on a slightly new project. I wanted to know how many files are in a certain directory.

<pre><code>&lt;div id="header"&gt;
&lt;?php 
 $dir = opendir('uploads/'); # This is the directory it will count from
 $i = 0; # Integer starts at 0 before counting

 # While false is not equal to the filedirectory
 while (false !== ($file = readdir($dir))) { 
 if (!in_array($file, array('.', '..') and !is_dir($file)) $i++;
 }

 echo "There were $i files"; # Prints out how many were in the directory
?&gt;
&lt;/div&gt;
</code></pre>

This is what I have so far (from searching). However, it is not appearing properly? I have added a few notes so feel free to remove them, they are just so I can understand it as best as I can.

If you require some more information or feel as if I haven't described this enough please feel free to state so.

Count how many files in directory PHP

Windows

Linux

我正在做一个稍微新的项目。我想知道某个目录中有多少个文件。<div id="header"><?php $dir = opendir('uploads/'); # This is the directory it will count from $i = 0; # Integer starts at 0 before counting # While false is not

问统计PHP目录中有多少个文件
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回答 13

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