blocks|key|610456|text|def+get_code(str)
++str.sub(/%5E(Z_.*):+.*/,+'\1')
end
get_code('Z_foo:+bar!')+#+=>+"Z_foo"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|610457|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

blocks|key|394416|text|需要对双引号中的\1进行转义。所以你想要|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|394417|"Z_sdsd:+sdsd".gsub(/%5E(Z_.*):+.*/,+"\\1")|code-block|syntax|javascript|394418|或|394419|"Z_sdsd:+sdsd".gsub(/%5E(Z_.*):+.*/,+'\1')|394420|参见the+docs+on+gsub，其中显示“如果是双引号字符串，则两个反向引用的前面都必须有一个额外的反斜杠。”|394421|也就是说，如果你只是想要比赛的结果，你可以这样做：|394422|"Z_sdsd:+sdsd".scan(/%5EZ_.*(?=:)/)|394423|394424|"Z_sdsd:+sdsd"[/%5EZ_.*(?=:)/]|394425|请注意，(?=:)是一个非捕获组，因此:不会出现在您的比赛中。|394426|entityMap|0|LINK|mutability|MUTABLE|url|http://ruby-doc.org/core-1.9.3/String.html#method-i-gsub^0|8|2|0|0|0|0|2|G|0|0|0|0|0|0|4|5|J|1|0^^$0|@$1|2|3|4|5|6|7|17|8|@$9|18|A|19|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1A|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1B|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|1C|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1D|8|@]|D|@$9|1E|A|1F|1|1G]]|E|$]]|$1|Q|3|R|5|6|7|1H|8|@]|D|@]|E|$]]|$1|S|3|T|5|H|7|1I|8|@]|D|@]|E|$I|J]]|$1|U|3|L|5|6|7|1J|8|@]|D|@]|E|$]]|$1|V|3|W|5|H|7|1K|8|@]|D|@]|E|$I|J]]|$1|X|3|Y|5|6|7|1L|8|@$9|1M|A|1N|B|C]|$9|1O|A|1P|B|C]]|D|@]|E|$]]|$1|Z|3|-4|5|6|7|1Q|8|@]|D|@]|E|$]]]|10|$11|$5|12|13|14|E|$15|16]]]]

<code>\1</code> in double quotes needs to be escaped. So you want either

<pre><code>"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/, "\\1")
</code></pre>

or

<pre><code>"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/, '\1')
</code></pre>

see <a href="http://ruby-doc.org/core-1.9.3/String.html#method-i-gsub" rel="noreferrer">the docs on gsub</a> where it says "If it is a double-quoted string, both back-references must be preceded by an additional backslash."

That being said, if you just want the result of the match you can do:

<pre><code>"Z_sdsd: sdsd".scan(/^Z_.*(?=:)/)
</code></pre>

or

<pre><code>"Z_sdsd: sdsd"[/^Z_.*(?=:)/]
</code></pre>

Note that the <code>(?=:)</code> is a non-capturing group so that the <code>:</code> doesn't show up in your match.

blocks|key|394432|text|+"foobar".gsub(/(o%2B)/){%7Cs%7Cs%2B'ball'}
+#=>+"fooballbar"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|394433|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code> "foobar".gsub(/(o+)/){|s|s+'ball'}
 #=&gt; "fooballbar"
</code></pre>

blocks|key|610533|text|如果您需要使用正则表达式来过滤某些结果，然后仅使用捕获组，则可以执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|610534|str+=+"Leesburg,+Virginia++20176"
state_regex+=+Regexp.new(/,\s*([A-Za-z]{2,})\s*\d{5,}/)
#+looks+for+the+comma,+possible+whitespace,+captures+alpha,
#+looks+for+possible+whitespace,+looks+for+zip

>+str[state_regex]
=>+",+Virginia++20176"

>+str[state_regex,+1]+#+use+the+capture+group
=>+"Virginia"|code-block|syntax|javascript|610535|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you need to use a regex to filter some results, and THEN use only the capture group, you can do the following:

<pre><code>str = "Leesburg, Virginia 20176"
state_regex = Regexp.new(/,\s*([A-Za-z]{2,})\s*\d{5,}/)
# looks for the comma, possible whitespace, captures alpha,
# looks for possible whitespace, looks for zip

&gt; str[state_regex]
=&gt; ", Virginia 20176"

&gt; str[state_regex, 1] # use the capture group
=&gt; "Virginia"
</code></pre>

blocks|key|610548|text|$变量仅设置为匹配到块中：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|610549|"Z_sdsd:+sdsd".gsub(/%5E(Z_.*):+.*/)+{+"#{+$1.strip+}"+}|code-block|syntax|javascript|610550|这也是在匹配时调用方法的唯一方法。这不会更改匹配，只会更改strip+"\1“(保持不变)：|610551|"Z_sdsd:+sdsd".gsub(/%5E(Z_.*):+.*/,+"\\1".strip)|610552|entityMap^0|0|1|0|0|T|5|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|P|$]]

<code>$</code> variables are only set to matches into the block:

<pre><code>"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/) { "#{ $1.strip }" }
</code></pre>

This is also the only way to call a method on the match. This will not change the match, only <code>strip</code> "\1" (leaving it unchanged):

<pre><code>"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/, "\\1".strip)
</code></pre>

I am having trouble translating this into Ruby.

Here is a piece of JavaScript that does exactly what I want to do:

<pre><code>function get_code(str){
 return str.replace(/^(Z_.*): .*/,"$1")​​​​​​​​​​​​​​​​​​​​​​​​​​​;
}
</code></pre>

I have tried <a href="http://ruby-doc.org/core-1.9.3/String.html#method-i-gsub">gsub</a>, <a href="http://ruby-doc.org/core-1.9.3/String.html#method-i-sub">sub</a>, and <a href="http://ruby-doc.org/core-1.9.3/String.html#method-i-replace">replace</a> but none seem to do what I am expecting.

Here are examples of things I have tried:

<pre><code>"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/) { |capture| capture }
"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/, "$1")
"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/, "#{$1}")
"Z_sdsd: sdsd".gsub(/^(Z_.*): .*/, "\1")
"Z_sdsd: sdsd".gsub(/(.).*/) { |capture| capture }
</code></pre>

Ruby replace string with captured regex pattern

我在把它翻译成Ruby时遇到了麻烦。下面是一段JavaScript，它做的正是我想做的事情：function get_code(str){    return str.replace(/^(Z_.*): .*/,"$1")​​​​​​​​​​​​​​​​​​​​​​​​​​​;}我已经尝试过、和，但似乎都不能满足我的期...

问Ruby用捕获的正则表达式模式替换字符串
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