报错:Unable to locate Spring NamespaceHandler for XML schema namespace [http://www.springframework.org/schema/security]?

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我的application Context-security.xml文件如下所示:

<?xml version="1.0" encoding="UTF-8"?>

<!--
  -  Namespace-based OpenID configuration
  -->

<b:beans xmlns="http://www.springframework.org/schema/security"
    xmlns:b="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
                        http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd">

    <http>
        <intercept-url pattern="/**" access="ROLE_USER"/>
        <intercept-url pattern="/index.xhtml*" filters="none"/>
        <logout/>
        <openid-login login-page="/index.xhtml" authentication-failure-url="/index.xhtml?login_error=true">
            <attribute-exchange>
                <openid-attribute name="email" type="http://schema.openid.net/contact/email" required="true" count="2"/>
                <openid-attribute name="name" type="http://schema.openid.net/namePerson/friendly" />
            </attribute-exchange>
        </openid-login>
        <remember-me token-repository-ref="tokenRepo"/>
    </http>

    <b:bean id="tokenRepo"
            class="org.springframework.security.web.authentication.rememberme.InMemoryTokenRepositoryImpl" />

    <authentication-manager alias="authenticationManager"/>

    <user-service id="userService">
        <user name="http://user.myopenid.com/" authorities="ROLE_SUPERVISOR,ROLE_USER" />
    </user-service>

</b:beans>

而Web.xml文件是:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4">

    <display-name>Spring Security OpenID Demo Application</display-name>

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
            /WEB-INF/applicationContext-security.xml
        </param-value>
    </context-param>

    <context-param>
        <param-name>log4jConfigLocation</param-name>
        <param-value>/WEB-INF/classes/log4j.properties</param-value>
    </context-param>

    <context-param>
        <param-name>webAppRootKey</param-name>
        <param-value>openid.root</param-value>
    </context-param>

    <filter>
        <filter-name>springSecurityFilterChain</filter-name>
        <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
    </filter>

    <filter-mapping>
      <filter-name>springSecurityFilterChain</filter-name>
      <url-pattern>/*</url-pattern>
    </filter-mapping>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <listener>
        <listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
    </listener>
     <welcome-file-list>
        <welcome-file>faces/index.xhtml</welcome-file>
    </welcome-file-list>
</web-app>

应用程序的清理和构建是成功的,但是当我尝试部署应用程序时,Jetty 7给出了以下错误:

SEVERE: Context initialization failed

提问于
用户回答回答于

你需要一个spring-security-config.jar在你的类路径上。

security:XML名称转义不能由Spring“解析器”处理。

它们是NamespaceHandler接口,因此您需要一个知道如何处理的处理程序。<security:标签。那是SecurityNamespaceHandler位于spring-security-config。

用户回答回答于

解决这个问题的唯一办法是将每个SpringJAR文件的meta-INF/Spring.处理程序和meta-INF/Spring.模式合并到我的meta-INF项目下的相同文件名中。

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