如何在Android中模拟触摸事件?

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如何在手动输入X和Y坐标的同时用Android模拟触摸事件?

提问于
用户回答回答于

这里是一个monkeyrunner脚本,用于将触摸和拖动到应用程序。我一直在使用它来测试我的应用程序可以处理快速重复的滑动手势:

# This is a monkeyrunner jython script that opens a connection to an Android
# device and continually sends a stream of swipe and touch gestures.
#
# See http://developer.android.com/guide/developing/tools/monkeyrunner_concepts.html
#
# usage: monkeyrunner swipe_monkey.py
#

# Imports the monkeyrunner modules used by this program
from com.android.monkeyrunner import MonkeyRunner, MonkeyDevice

# Connects to the current device
device = MonkeyRunner.waitForConnection()

# A swipe left from (x1, y) to (x2, y) in 2 steps
y = 400
x1 = 100
x2 = 300
start = (x1, y)
end = (x2, y)
duration = 0.2
steps = 2
pause = 0.2

for i in range(1, 250):
    # Every so often inject a touch to spice things up!
    if i % 9 == 0:
        device.touch(x2, y, 'DOWN_AND_UP')
        MonkeyRunner.sleep(pause)
    # Swipe right
    device.drag(start, end, duration, steps)
    MonkeyRunner.sleep(pause)
    # Swipe left
    device.drag(end, start, duration, steps)
    MonkeyRunner.sleep(pause)
用户回答回答于

如果你扩展了视图,则Valentin Rocher的方法有效,但如果你使用的是事件侦听器,请使用以下命令:

view.setOnTouchListener(new OnTouchListener()
{
    public boolean onTouch(View v, MotionEvent event)
    {
        Toast toast = Toast.makeText(
            getApplicationContext(), 
            "View touched", 
            Toast.LENGTH_LONG
        );
        toast.show();

        return true;
    }
});


// Obtain MotionEvent object
long downTime = SystemClock.uptimeMillis();
long eventTime = SystemClock.uptimeMillis() + 100;
float x = 0.0f;
float y = 0.0f;
// List of meta states found here: developer.android.com/reference/android/view/KeyEvent.html#getMetaState()
int metaState = 0;
MotionEvent motionEvent = MotionEvent.obtain(
    downTime, 
    eventTime, 
    MotionEvent.ACTION_UP, 
    x, 
    y, 
    metaState
);

// Dispatch touch event to view
view.dispatchTouchEvent(motionEvent);

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