如何使用KSOAP 2从Android调用.NET Webservice?

内容来源于 Stack Overflow,并遵循CC BY-SA 3.0许可协议进行翻译与使用

  • 回答 (2)
  • 关注 (0)
  • 查看 (35)

我在调用web服务时遇到问题。我在服务器上有一个.NET Web服务,我在Android中使用KSOAP2(ksoap2-j2se-full-2.1.2)。运行程序时,我得到了一个运行时异常,如“org.ksoap2.serialization.SoapPrimitive”。我该怎么办?

这是我的代码。

package projects.ksoap2sample;

import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;

import android.app.*;
import android.os.*;
import android.widget.TextView;

public class ksoap2sample extends Activity {
    /** Called when the activity is first created. */
    private static final String SOAP_ACTION = "http://tempuri.org/HelloWorld";
    private static final String METHOD_NAME = "HelloWorld";
    private static final String NAMESPACE = "http://tempuri.org/";
    private static final String URL = "http://192.168.1.19/TestWeb/WebService.asmx";
    TextView tv;
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        tv=(TextView)findViewById(R.id.text1);

        try {
            SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

            //request.addProperty("prop1", "myprop");

            SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
            envelope.dotNet=true;
            envelope.setOutputSoapObject(request);

            HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

            androidHttpTransport.call(SOAP_ACTION, envelope);

            Object result = (Object)envelope.getResponse();

            String[] results = (String[])  result;
            tv.setText( ""+results[0]);
        }
        catch (Exception e) {
            tv.setText(e.getMessage());
        }
    }
}
提问于
用户回答回答于

你的.NET Webservice是怎样的?

我使用code.google.com中的ksoap 2.3获得了同样的效果。我按照The Code Project的教程(这是很棒的BTW)。

每次我使用

    Integer result = (Integer)envelope.getResponse();

得到我的web服务的结果(不管类型,我试过对象,字符串,int)我遇到了org.ksoap2.serialization.SoapPrimitive异常。

我找到了一个解决方案(解决方法)。我必须做的第一件事是从我的webservice方法中删除“SoapRpcMethod()属性。

    [SoapRpcMethod(), WebMethod]
    public Object GetInteger1(int i)
    {
        // android device will throw exception
        return 0;
    }

    [WebMethod]
    public Object GetInteger2(int i)
    {
        // android device will get the value
        return 0;
    }

然后我将我的Android代码更改为:

    SoapPrimitive result = (SoapPrimitive)envelope.getResponse();

但是,我得到一个SoapPrimitive对象,它有一个私有的“值”字段。幸运的是,该值通过该toString()方法传递,所以我用它Integer.parseInt(result.toString())来获取我的值,这对我来说已经足够了,因为我没有任何需要从Web服务获取的复杂类型。

这里是完整的来源:

private static final String SOAP_ACTION = "http://tempuri.org/GetInteger2";
private static final String METHOD_NAME = "GetInteger2";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://10.0.2.2:4711/Service1.asmx";

public int GetInteger2() throws IOException, XmlPullParserException {
    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

    PropertyInfo pi = new PropertyInfo();
    pi.setName("i");
    pi.setValue(123);
    request.addProperty(pi);

    SoapSerializationEnvelope envelope =
        new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.dotNet = true;
    envelope.setOutputSoapObject(request);

    AndroidHttpTransport androidHttpTransport = new AndroidHttpTransport(URL);
    androidHttpTransport.call(SOAP_ACTION, envelope);

    SoapPrimitive result = (SoapPrimitive)envelope.getResponse();
    return Integer.parseInt(result.toString());
}
用户回答回答于

这很简单。你将结果变成Object一个原始的结果。

你的代码:

Object result = (Object)envelope.getResponse();

正确的代码:

SoapObject result=(SoapObject)envelope.getResponse();

//To get the data.
String resultData=result.getProperty(0).toString();
// 0 is the first object of data.

我认为这应该肯定有效。

扫码关注云+社区