如何使用KSOAP2从安卓调用.NET Webservice？
我在调用while服务时遇到问题。我在服务器上有一个完整的web服务，并且我在.NET中使用KSOAP2 (ksoap2-j2se-full-2.1.2)。在运行该程序时，我得到了一个运行时异常，如"org.ksoap2.serialization.SoapPrimitive“。我该怎么办？
这是我的代码。
package projects.ksoap2sample;
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import android.app.*;
import android.os.*;
import android.widget.TextView;
public class ksoap2sample extends Activity {
/** Called when the activity is first created. */
private static final String SOAP_ACTION = "http://tempuri.org/HelloWorld";
private static final String METHOD_NAME = "HelloWorld";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://192.168.1.19/TestWeb/WebService.asmx";
TextView tv;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
tv=(TextView)findViewById(R.id.text1);
try {
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
//request.addProperty("prop1", "myprop");
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet=true;
envelope.setOutputSoapObject(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
androidHttpTransport.call(SOAP_ACTION, envelope);
Object result = (Object)envelope.getResponse();
String[] results = (String[]) result;
tv.setText( ""+results[0]);
}
catch (Exception e) {
tv.setText(e.getMessage());
}
}
}回答 5
Stack Overflow用户
发布于 2010-01-12 21:26:49
这很简单。您将把结果放入一个原始的Object中。
你的代码：
Object result = (Object)envelope.getResponse();正确的代码：
SoapObject result=(SoapObject)envelope.getResponse();
//To get the data.
String resultData=result.getProperty(0).toString();
// 0 is the first object of data.我想这肯定能行得通。
Stack Overflow用户
发布于 2009-10-05 17:15:09
你的.NET网络服务是什么样子的？
我使用ksoap 2.3 from code.google.com也有同样的效果。我遵循了The Code Project上的教程(这是一个很棒的BTW)。
每次我用
Integer result = (Integer)envelope.getResponse();为了获得my webservice的结果(不管类型如何，我尝试了Object、String、int)，我遇到了org.ksoap2.serialization.SoapPrimitive异常。
我找到了一个解决方案(变通方法)。我必须做的第一件事是从我的webservice方法中删除"SoapRpcMethod()“属性。
[SoapRpcMethod(), WebMethod]
public Object GetInteger1(int i)
{
// android device will throw exception
return 0;
}
[WebMethod]
public Object GetInteger2(int i)
{
// android device will get the value
return 0;
}然后，我将我的Android代码更改为：
SoapPrimitive result = (SoapPrimitive)envelope.getResponse();但是，我得到了一个SoapPrimitive对象，它有一个私有的"value“字段。幸运的是，这个值是通过toString()方法传递的，所以我使用Integer.parseInt(result.toString())来获取我的值，这对我来说已经足够了，因为我不需要从我的Web服务中获取任何复杂类型。
下面是完整的源代码：
private static final String SOAP_ACTION = "http://tempuri.org/GetInteger2";
private static final String METHOD_NAME = "GetInteger2";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://10.0.2.2:4711/Service1.asmx";
public int GetInteger2() throws IOException, XmlPullParserException {
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
PropertyInfo pi = new PropertyInfo();
pi.setName("i");
pi.setValue(123);
request.addProperty(pi);
SoapSerializationEnvelope envelope =
new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
AndroidHttpTransport androidHttpTransport = new AndroidHttpTransport(URL);
androidHttpTransport.call(SOAP_ACTION, envelope);
SoapPrimitive result = (SoapPrimitive)envelope.getResponse();
return Integer.parseInt(result.toString());
}Stack Overflow用户
发布于 2009-12-18 02:22:32
将信封类型转换为SoapPrimitive：
SoapPrimitive result = (SoapPrimitive)envelope.getResponse();
String strRes = result.toString();它会起作用的。
https://stackoverflow.com/questions/1052300
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