blocks|key|624257|text|您可以使用-j。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|624258|-j
--junk-paths
++++++++++Store+just+the+name+of+a+saved+file+(junk+the+path),+and+do++not
++++++++++store++directory+names.+By+default,+zip+will+store+the+full+path
++++++++++(relative+to+the+current+directory).|code-block|syntax|javascript|624259|entityMap^0|5|2|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You can use <code>-j</code>.

<pre><code>-j
--junk-paths
 Store just the name of a saved file (junk the path), and do not
 store directory names. By default, zip will store the full path
 (relative to the current directory).
</code></pre>

blocks|key|624269|text|使用-j选项：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|624270|+++-j+++++Store++just+the+name+of+a+saved+file+(junk+the+path),+and+do+not
++++++++++store+directory+names.+By+default,+zip+will+store+the+full++path
++++++++++(relative+to+the+current+path).|code-block|syntax|javascript|624271|entityMap^0|2|2|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Use the <code>-j</code> option:

<pre><code> -j Store just the name of a saved file (junk the path), and do not
 store directory names. By default, zip will store the full path
 (relative to the current path).
</code></pre>

blocks|key|624324|text|有些相关-我正在寻找一种解决方案来为目录做同样的事情。不幸的是，-j选项对此不起作用:(|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|624325|这里有一个很好的解决方案来解决这个问题：https://superuser.com/questions/119649/avoid-unwanted-path-in-zip-file|624326|entityMap|0|LINK|mutability|MUTABLE|url|https://superuser.com/questions/119649/avoid-unwanted-path-in-zip-file^0|W|2|0|K|1Y|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@]|D|@$9|T|A|U|1|V]]|E|$]]|$1|H|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]]]

Somewhat related - I was looking for a solution to do the same for directories.
Unfortunately the <code>-j</code> option does not work for this :(

Here is a good solution on how to get it done:
<a href="https://superuser.com/questions/119649/avoid-unwanted-path-in-zip-file">https://superuser.com/questions/119649/avoid-unwanted-path-in-zip-file</a>

blocks|key|409229|text|或者，您可以创建一个指向文件的临时符号链接：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|409230|ln+-s+/data/to/zip/data.txt+data.txt
zip+/dir/to/file/newZip+!$
rm+!$|code-block|syntax|javascript|409231|这也适用于目录。|409232|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Alternatively, you could create a temporary symbolic link to your file:

<pre><code>ln -s /data/to/zip/data.txt data.txt
zip /dir/to/file/newZip !$
rm !$
</code></pre>

This works also for a directory.

blocks|key|624401|text|在使用-r选项时，使用-j将不起作用。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|624402|因此，解决该问题的方法可以是：|624403|cd+path/to/parent/dir/;
zip+-r+complete/path/to/name.zip+./*+;
cd+-;|code-block|syntax|javascript|624404|或内联版本|624405|cd+path/to/parent/dir/+&&+zip+-r+complete/path/to/name.zip+./*+&&+cd+-|624406|如果不希望cd+-输出显示在屏幕上，可以将输出定向到/dev/null|624407|entityMap^0|3|2|B|2|0|0|0|0|0|5|4|Q|9|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Z|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|10|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|11|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|12|8|@]|D|@]|E|$K|L]]|$1|Q|3|R|5|6|7|13|8|@$9|14|A|15|B|C]|$9|16|A|17|B|C]]|D|@]|E|$]]|$1|S|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|T|$]]

Using <code>-j</code> won't work along with the <code>-r</code> option. 
So the work-around for it can be this:

<pre><code>cd path/to/parent/dir/;
zip -r complete/path/to/name.zip ./* ;
cd -;
</code></pre>

Or in-line version 

<pre><code>cd path/to/parent/dir/ &amp;&amp; zip -r complete/path/to/name.zip ./* &amp;&amp; cd -
</code></pre>

you can direct the output to <code>/dev/null</code> if you don't want the <code>cd -</code> output to appear on screen

blocks|key|409382|text|只需使用-jrm选项删除文件和目录结构|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|409383|zip+-jrm+/path/to/file.zip+/path/to/file|code-block|syntax|javascript|409384|entityMap^0|4|4|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Just use the <code>-jrm</code> option to remove the file and directory 
structures

<pre><code>zip -jrm /path/to/file.zip /path/to/file
</code></pre>

blocks|key|624550|text|保留父目录，这样unzip就不会将文件散布到各处|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|624551|压缩目录时，将父目录保留在归档文件中将有助于避免在以后解压缩归档文件时弄乱当前目录|624552|因此，为了避免保留所有路径，并且由于您不能同时使用-j和-r+(您将得到一个错误)，您可以这样做：|624553|cd+path/to/parent/dir/;
zip+-r+../my.zip+"../$(basename+"$PWD")"
cd+-;|code-block|syntax|javascript|624554|"../$(basename+"$PWD")"是保留父目录的魔法。|624555|所以现在unzip+my.zip会给出一个包含你所有文件的文件夹：|624556|parent-directory
├──+file1
├──+file2
├──+dir1
│+++├──+file3
│+++├──+file4|624557|而不是将解压缩后的文件散落在当前目录中：|624558|file1
file2
dir1
├──+file3
├──+file4|624559|entityMap^0|8|5|0|0|0|0|0|N|0|4|C|0|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|13|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|14|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|15|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|16|8|@$9|17|A|18|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|6|7|19|8|@$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|S|3|T|5|L|7|1C|8|@]|D|@]|E|$M|N]]|$1|U|3|V|5|6|7|1D|8|@]|D|@]|E|$]]|$1|W|3|X|5|L|7|1E|8|@]|D|@]|E|$M|N]]|$1|Y|3|-4|5|6|7|1F|8|@]|D|@]|E|$]]]|Z|$]]

<h2>Retain the parent directory so <code>unzip</code> doesn't spew files everywhere</h2>
When zipping directories, keeping the parent directory in the archive will help to avoid littering your current directory when you later unzip the archive file
So to avoid retaining all paths, and since you can't use -j and -r together ( you'll get an error ), you can do this instead:
<pre><code>cd path/to/parent/dir/;
zip -r ../my.zip &quot;../$(basename &quot;$PWD&quot;)&quot;
cd -;
</code></pre>
The <code>&quot;../$(basename &quot;$PWD&quot;)&quot;</code> is the magic that retains the parent directory.
So now <code>unzip my.zip</code> will give a folder containing all your files:
<pre><code>parent-directory
├── file1
├── file2
├── dir1
│ ├── file3
│ ├── file4
</code></pre>
Instead of littering the current directory with the unzipped files:
<pre><code>file1
file2
dir1
├── file3
├── file4
</code></pre>

I need to create a zip file using this command:

<pre><code>zip /dir/to/file/newZip /data/to/zip/data.txt
</code></pre>

This works, but the created zip file creates a directory structure mimicking the directory to the raw file. It is a lot of extra folders that I don't need. 

I didn't find an answer in a cursory glance over the man page or a Google hunt.

Create zip file and ignore directory structure

我需要使用以下命令创建一个zip文件：zip /dir/to/file/newZip /data/to/zip/data.txt这是可行的，但是创建的zip文件会创建一个目录结构，模仿原始文件的目录。有很多我不需要的额外文件夹。粗略地浏览一下手册页或谷歌搜索，我都没有找到答案。

问创建zip文件并忽略目录结构
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